#need help

71 messages · Page 1 of 1 (latest)

royal lance
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Anyone can help me with the first one? Not sure what they mean by this

eternal pelicanBOT
digital agate
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(a): y = 4x + 1

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1 is the y intercept and it has to pass through the point (0, 1) so therefore y = mx + b | b needs to be 1 so it can pass through (0, 1)

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and a parallel line is just a line that has the same slope of another line

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@royal lance

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(b):

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x-3y=1

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-3y = 1 - x

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y = -1/3 + x/3

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y = 1/3x - 1/3

royal lance
digital agate
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let me show work rq

royal lance
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I’m asking bc I just wanna know for future reference 😭😭

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Thank u so much

digital agate
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does this make sense so far? @royal lance

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when you have 1-x/3

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you can break it apart

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to 1/3 - x/3

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because the goal is to rearrange it to slope intercept form

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which is y = mx + b

royal lance
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Wouldn’t the x be a 1 technically though?

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or does it just stay as x

digital agate
digital agate
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so that means we can rewrite it

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like i did

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x/3 -> 1/3x

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and there is the checked work

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@royal lance does this make sense so far?

royal lance
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yes omg thank u

digital agate
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because do you remember how to get the perpendicular line?

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to get the perpendicular line you need to get the reciprocal of the slope then reverse the sign

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so (b) final answer will be y = -3/1x - 1/3

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@royal lance wait i forgot it needs to pass through the point

royal lance
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okurr

digital agate
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so to get a specific point

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we need to set a variable in the function to that point

royal lance
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Thank y

digital agate
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so now x will be the slope of the new line @royal lance

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i think

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i have to double check

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@royal lance wait nvm this isn't right

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i haven't done this in a while sorry

royal lance
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😭

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It’s ok

digital agate
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okay scratch all the new stuff

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with the putting in the point and stuff LOL

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@royal lance

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one sec

royal lance
digital agate
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@royal lance i think i'm dumb

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one sec i figured it out

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@royal lance okay i was overthinking it

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we need to substitute y and x into the equation

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for the point that we want it to pass through

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so we have the perpendicular line

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we just need it to pass through a point

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does that make sense? @royal lance

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okay here is the answer to b now

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@royal lance