#need help
71 messages · Page 1 of 1 (latest)
(a): y = 4x + 1
1 is the y intercept and it has to pass through the point (0, 1) so therefore y = mx + b | b needs to be 1 so it can pass through (0, 1)
and a parallel line is just a line that has the same slope of another line
@royal lance
(b):
x-3y=1
-3y = 1 - x
y = -1/3 + x/3
y = 1/3x - 1/3
How’d you get this?
does this make sense so far? @royal lance
when you have 1-x/3
you can break it apart
to 1/3 - x/3
because the goal is to rearrange it to slope intercept form
which is y = mx + b
Sort of
it's technically 1x
so that means we can rewrite it
like i did
x/3 -> 1/3x
and there is the checked work
@royal lance does this make sense so far?
yes omg thank u
okay so we're not done
because do you remember how to get the perpendicular line?
to get the perpendicular line you need to get the reciprocal of the slope then reverse the sign
so (b) final answer will be y = -3/1x - 1/3
@royal lance wait i forgot it needs to pass through the point
okurr
so to get a specific point
we need to set a variable in the function to that point
Thank y
so now x will be the slope of the new line @royal lance
i think
i have to double check
@royal lance wait nvm this isn't right
i haven't done this in a while sorry
okay scratch all the new stuff
with the putting in the point and stuff LOL
@royal lance
one sec
Tyt
@royal lance i think i'm dumb
one sec i figured it out
@royal lance okay i was overthinking it
we need to substitute y and x into the equation
for the point that we want it to pass through
so we have the perpendicular line
we just need it to pass through a point
does that make sense? @royal lance
okay here is the answer to b now
@royal lance