Can someone help me set this up:
ysin6x = xcos6y
#Explicit Differentiation help
dire venture
vital trellisBOT
fierce marsh
Can someone help me set this up:
ysin6x = xcos6y
What is your question exactly ?
dire venture
It's asking me to use implicit differentiation to find an equation of the tangent line but I am confused on how to set up the first step.
I know I'm supposed to take the derivative from both sides with respect to x, so d/dx.
fierce marsh
Okay so you're considering the curve $C := { (x,y) \in \mathbb{R}^2 ; y \sin6x = x \cos6y}$ ?
clear apexBOT
Twenty
weary delta
are they asking for the differenciation of the equation and finding what dy/dx= smth?
which will be ur gradiend of tangent
dire venture
weary delta
oooooh
ok
so u will differenciation both y sin6x and xcos6y
so lets differenciate ysin6x first since there are 2 coeficient u will need to use product rule
dy/dx(sin6x)+6ycos6x
do u und how i got this?
dire venture
1 sec let me check my work
weary delta
ok
dire venture
Okay this step is where I am missing something
weary delta
which step?
dire venture
I got: (dy/dx) (6cosx)
weary delta
aaah
u cannot do tht
u must use the product rule
for tht kind of ques
x cos6y too u need to use product rule
because they are 2 diff coeficients
dire venture
Do you have a mic by chance?
weary delta
ye
dire venture
can I call you real quick?
weary delta
give me 3 min
dire venture
no problem thank you!
weary delta
I think I just need to clarify one step and I'll be good
i mean i can hear u i just wont be able to talk
dire venture
If you don't mind, I'd prefer to hear voice as It removes chances of confusion. Extrapolating from text is what's messing me up haha
weary delta
ok
dire venture
Where are you from?>
dire venture
you ready?