#partition of [0,3]

28 messages · Page 1 of 1 (latest)

deft socket
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How partition the interval [0,3] into three intervals of the same length? Is [0,1],[1,2],[2,3] correct?

scenic merlinBOT
dusk cairn
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well if you write it like this, the 1 is included in 2 partitions

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same for the 2

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if that doesnt matter then it should be fine

deft socket
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How do I know if it matters or not ? Because in the midterm I took the teacher just said to partition it into three intervals of same distance

dusk cairn
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ok uhm, if you say the intervall [0,1), [1,2) , [2,3)

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they would have the same length but idk if that is what your teacher wants

ruby temple
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I think [0,1],[1,2],[2,3] is reasonable if you don't care about overlapping points. If you do, then there's 4 possible solutions depending on which of the two neighbouring intervals points 1 and 2 belong to.

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(I'd say [0,1), [1,2) , [2,3) isn't right because 3 isn't in it, whereas it is in the original.)

frozen willow
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Without overlapping points I think there are no solutions

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0<=x<1
1<=y<2 (<=2 not possible)
Same for z

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So we end up with a missing 3

deft socket
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He just said to partition it into three of the same distance

frozen willow
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@deft socket maybe send the exercise you were given?

deft socket
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I had to turn in the midterm

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It was on paper

ruby temple
deft socket
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But I remember he just said into 3 of the same distance

frozen willow
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It’s < 1 for the first 2 and 1 for the last

ruby temple
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Hmm, depends on the definition of length, I guess. I don't see obvious issues with considering (1,2) to have a length of 1.

frozen willow
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Yeah it’s very definition dependent

deft socket
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So which one is correct ?

frozen willow
frozen willow
deft socket
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But is the initial I gave wrong ?

frozen willow