Value of landa (z is complex number)

[analog ruin]

i think -2

[night skiff]

isnt it 4 ?

[analog ruin]

i got

x=a3+3ab2

y=b3+3a2b

by cubing on both side

[night skiff]

but i got

x=a3-3ab2

y=b3-3a2b

isnt i^3= -i ?

so i got - instead of +

[nocturne sonnet]

isn't it x=a3 -3a2b ?

[night skiff]

a^2 term comes for y ig

i got x and y as above mentioned

and when we divide x by a and y by b

i got lamda as 4

[nocturne sonnet]

i got one

let me send an image

[night skiff]

okey

[analog ruin]

x will be the term with only real part

[night skiff]

yeh

u gotta seperate

[nocturne sonnet]

so x is a^3 - b^3

[night skiff]

real and imaginary parts

when u take cube , z = a3-3a2(ib)+3a(ib)2-b3

i.e

[nocturne sonnet]

let me try that again

[night skiff]

sure

[analog ruin]

z=a3-3a2bi+3ab2-ib3

x=a3+3ab2

y=-3a2b-b3

x/a=a2+3b2

y/b=-3a2-b2

[nocturne sonnet]

hold on a sec, if i2 is -1, shouldn't it be -3ab2?

oh i see it now

[night skiff]

yehh

[analog ruin]

ok

[nocturne sonnet]

you wrote it at y=

[night skiff]

b2 term comes for y right ?

[analog ruin]

??

are you sure the question is correct?

[nocturne sonnet]

so it s negative 2

but that isn't one of the alternatives

[analog ruin]

no it's not -2

4(a2+b2)=m(a2-b2)

[nocturne sonnet]

ohhh the m,inus

thank you

how do i mark this as solved

[forest tapir]

lambda

[nocturne sonnet]

wait i am confused again

if bi^2 is -b^2
why isn;t x=a3 - 3ab2

[night skiff]

this is how i did it

[analog ruin]

correct i think

[nocturne sonnet]

thank you, they match with mine now, i got a minus wrongly calculated

ok, how to mark this as solved

I am new here

[night skiff]

yehh