#solve for x

24 messages · Page 1 of 1 (latest)

low cosmos
halcyon hollyBOT
halcyon pier
low cosmos
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so z^2 - 12 x z + 32 ?

halcyon pier
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That's just a quadratic equation

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Solve for z

low cosmos
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im not sure what to do next

halcyon pier
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And then, you can solve for x in z = 2^x

halcyon pier
low cosmos
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yes

halcyon pier
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This is also a quadratic equation, just with z instead of x, which is I think more familiar to you

low cosmos
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ohh okay, let me try

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(z + 8)(z+4)=0. (2^x + 8)(2^x+4)=0 so x=2 and x=3

halcyon pier
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It should be (z-4)(z-8) = 0

low cosmos
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OHH

halcyon pier
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You could right away find z with the quadratic formula, too

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(Or with Vieta's formula, ...)

low cosmos
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OHHH I GET IT NOW

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THANK YOUUUU

halcyon pier
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But yes, x = 2 and x = 3 should be correct

low cosmos
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.solved