algebra,quadratics,parabolas, inequations, simultaneous equations etc

[torn lion]

@thin vapor

Here?

Wait I'll do what the help thing says

Or is this fine?

[thin vapor]

Yup

Can you just repost the screenshot so I have a reference?

[wooden ginkgo]

Sorry i tried to cram it all in

I was making it up as i went

[thin vapor]

Pretty good, I just think op needs more help for the parabolas and graphical représentation given a=1 b and c

[torn lion]

Oh so we first Identofy which is a,b,c.then we put it on the quadratic formula form

[thin vapor]

My bad I didn't see question 1 🙃

[wooden ginkgo]

Right and this is how you algebraically prove that the X-intercepts are 3 and 1

[wooden ginkgo]

Or (3,0) ; (1,0)

[torn lion]

Oh I get it

So the X intercepts are the 2 values of x

[thin vapor]

I agree with @wooden ginkgo but here since the intercepts are given you can just check that x=1 and x=3 nullify the y formula

[torn lion]

And using quadratic formula we can find that

[wooden ginkgo]

Right

[torn lion]

May I ask is it possible to find the values of X by factorizing?

[wooden ginkgo]

That will also work

,but I always resort to the quadratic formula since I have it memorized

[thin vapor]

In theory that's already what you're doing by using the quadratic formula, the proof involves factorizing

[torn lion]

Ok that makes sense

[wooden ginkgo]

Exactly

[torn lion]

So how would we answer the next part of the question

[thin vapor]

I'll let @wooden ginkgo finish this I got to go thanks guys

[wooden ginkgo]

and you can also see that were finding the x-intercepts because we’re setting the equation equal to 0

That helped me understand better when I was first learning

[wooden ginkgo]

No problem have a good one

[wooden ginkgo]

Let me see

[torn lion]

Thank you for your help

[wooden ginkgo]

and the quadratic formula will be useful later on down the road when you’re unable to factorize certain equations.

You’ll understand more in depth later

I hope

[torn lion]

Yeah it makes sense

Does this video accurately show how to plot quadratics?

[wooden ginkgo]

Yes

The rules are simple

When there is a negative in front of the equation the parabola flips upside down

[torn lion]

So for question six we start at (-1,-2),how do I plot next

[wooden ginkgo]

When the number in front of the x is greater than 1, the parabola will tighten

When it is less than one, it was compress

When i say compress i mean open up

[torn lion]

Yeah,I think at the moment we are doing when it's one as I am in year 10 ,the stuff I'm learning is year 11

[wooden ginkgo]

That’s good

It’s simple rules the only hard part is remembering them all

and learning how to apply them and where

that will come with practice

and you understand that when there is a positive number in the parenthesis that it with move towards the negative side?

“Shift left”

y=(x+5)^2

[torn lion]

Is this correct?

[wooden ginkgo]

It will move to the left 5 units

[wooden ginkgo]

What is the question

[torn lion]

y = (x + 2)²-1

[wooden ginkgo]

Correct

[torn lion]

Is it always better to draw a table?

Of X and y values?

[wooden ginkgo]

Thats personal preference

[torn lion]

Oh ok

[wooden ginkgo]

In college math you will hardly see it but it is a good way to get you to visualize the translation happening

[torn lion]

So when the x² is negative it goes downwards

[wooden ginkgo]

Right

You should also look into the other parent functions

The same rules apply but it is interesting to see how the graph reacts

[torn lion]

This was the top mark question I did learn how to solve it slightly by watching a video but it would be nice if you could give some tips for how to solve theese questions well

[wooden ginkgo]

I have to go sorry

[wooden ginkgo]

(x-3)(x-1)