Differentiation | Mathematics | Page 1

ruby pilot Aug 28, 2023, 8:25 AM

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sly talonBOT Aug 28, 2023, 8:25 AM

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gentle nymph Aug 28, 2023, 8:33 AM

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the derivative of the arccos x or cos^{-1}(x) is -1/✓(1-x^2)

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use the chain rule after that [f(g)]'=f'(g(x))g'(x)

ruby pilot Aug 28, 2023, 8:34 AM

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Ans is one of them..can't simplyfy the resulting expression to match any of these

gentle nymph Aug 28, 2023, 8:35 AM

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what did you get?

ruby pilot Aug 28, 2023, 8:36 AM

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Wait

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@ruby pilot @gentle nymph

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gentle nymph Aug 28, 2023, 9:00 AM

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yeah, none of those seem to be anywhere near the correct answer...lol

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are you sure that those are the answers they give? 😅

gentle nymph Aug 28, 2023, 9:08 AM

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ruby pilot <@695195672517017653> <@1107025661203324938>

for reference, I got (1+x)/[2x✓(-x^2+6x-1)]

ruby pilot Aug 28, 2023, 9:15 AM

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gentle nymph are you sure that those are the answers they give? 😅

Yes

ruby pilot Aug 28, 2023, 9:21 AM

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gentle nymph for reference, I got (1+x)/[2x✓(-x^2+6x-1)]

Yes . .. I checked..I'm also getting the same

gentle nymph Aug 28, 2023, 9:23 AM

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ruby pilot Yes . .. I checked..I'm also getting the same

as far as I can tell there is no way to reduce this answer to any of the forms that you book is giving you

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Someone else might know how but I sort of doubt it's possible lol.

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If you do find out let me know

ruby pilot Aug 28, 2023, 9:24 AM

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Substitution of x to tan^2t is giving cot2t

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Which is of no use

inner temple Aug 28, 2023, 11:46 AM

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I got dy/dx=-(-x-1)/(4x√x √(1-((1-x)/(2√x))^2 ))

ruby pilot Aug 28, 2023, 2:29 PM

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Yes if you simplyfy it more you'll most prob arrive at @gentle nymph ans

#Differentiation