#help me

51 messages · Page 1 of 1 (latest)

magic roverBOT
daring saffron
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haven't tried the math at all cus I'm on my phone so idk if this will help but imma guess express the summands in terms of e cus euler's identity and tagged calculus and roots of unity, also maybe induction but good chance it doesn't require induction hmmCat

daring saffron
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OK been trying it for a bit but can't get it to telescope or each summands to have a common denominator hmmCat

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Roots of unity just has to come in at some point tho

young kraken
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facts

daring saffron
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Tryna use the fact that all the roots of x^n - 1 besides x = 1 (I. E. the k = 0 case) satisfy the equation x^(n - 1)+ x^(n - 2) +... + 1 = 0

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So in particular sum of those roots is (-1)^n and similar formulas for all the other symmetric sums

short kraken
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I didn't understand

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Any written work?

daring saffron
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So like for instance (x - 1)(x - 2) = x^2 - 3x + 2

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If we didn't know the factorization

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We could still know the sum of the roots from the 2nd coefficient, which would be - 3/(-1)^1

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And the product of the roots would be 2

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The solutions to the equation x^n - 1 = 0

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Which factors as (x - 1)(x^(n - 1) +..... + 1)

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The roots are of the form e^(2 pi k i/n) for k = 1,....n - 1

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k = 0 is just 1, so all the other ones make up the roots of the polynomial x^(n - 1) +... + 1

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And we'll what's noice about that is then all the symmetric sums are just $\pm 1$

sinful pythonBOT
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992qqoloy

daring saffron
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Then sin(x) = (e^(ix) - e(-ix))/(2i)

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Squaring for this instance you get [e^(2pi i k/n) + e^(-2pi i k/n) - 2] /(-4)

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So that looks promising but idk where to go from there bleakkekw

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Bleh if you had the sin^2 in numerator instead it'd be so simple

sinful pythonBOT
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aryanh143

short kraken
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I think I made huge blunders

daring saffron
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You're close, should be - instead of + for sine

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And dividing by 2i so squared makes -4

short kraken
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I didn't get that help me in further solution

daring saffron
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yeah 😐

short kraken
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Sorry

daring saffron
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Np

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Tryna common denominator thing now hmmCat

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Like I wonder if the product of sines or cosines of roots of unity has a nice formula

short kraken
daring saffron
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Like the formula for sin(x) is (e^(ix) - e^(-ix)) /(2i)

short kraken
daring saffron
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But you used the formula for cos when evaluating sin^2(x)

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OK Jesus christ so I looked up the solution

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None of them are remotely simple devastation

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Dunno how you'd ever get it with just a basic knowledge of Calc and euler's identity

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I mean you can understand the solution with those two

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But they require tricks they dont teach in normal classes I think

short kraken
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A very big thanks

daring saffron
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np

short kraken
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Hey

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Please help me in this one also

sinful pythonBOT
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aryanh143