#help me
51 messages · Page 1 of 1 (latest)
haven't tried the math at all cus I'm on my phone so idk if this will help but imma guess express the summands in terms of e cus euler's identity and tagged calculus and roots of unity, also maybe induction but good chance it doesn't require induction 
OK been trying it for a bit but can't get it to telescope or each summands to have a common denominator 
Roots of unity just has to come in at some point tho
facts
Tryna use the fact that all the roots of x^n - 1 besides x = 1 (I. E. the k = 0 case) satisfy the equation x^(n - 1)+ x^(n - 2) +... + 1 = 0
So in particular sum of those roots is (-1)^n and similar formulas for all the other symmetric sums
OK so this is what I mean with the symmetric sums. Basically you can get types of sums related to the roots in terms of the coefficients of the polynomial: https://artofproblemsolving.com/wiki/index.php/Vieta's_formulas
So like for instance (x - 1)(x - 2) = x^2 - 3x + 2
If we didn't know the factorization
We could still know the sum of the roots from the 2nd coefficient, which would be - 3/(-1)^1
And the product of the roots would be 2
Then these are the roots of unity https://brilliant.org/wiki/roots-of-unity/
The solutions to the equation x^n - 1 = 0
Which factors as (x - 1)(x^(n - 1) +..... + 1)
The roots are of the form e^(2 pi k i/n) for k = 1,....n - 1
k = 0 is just 1, so all the other ones make up the roots of the polynomial x^(n - 1) +... + 1
And we'll what's noice about that is then all the symmetric sums are just $\pm 1$
992qqoloy
Then sin(x) = (e^(ix) - e(-ix))/(2i)
Squaring for this instance you get [e^(2pi i k/n) + e^(-2pi i k/n) - 2] /(-4)
So that looks promising but idk where to go from there 
Bleh if you had the sin^2 in numerator instead it'd be so simple
aryanh143
I think I made huge blunders
You're close, should be - instead of + for sine
And dividing by 2i so squared makes -4
I didn't get that help me in further solution
yeah 😐
Sorry
Np
Tryna common denominator thing now 
Like I wonder if the product of sines or cosines of roots of unity has a nice formula
I don't know why but I didn't understand things from this
Like the formula for sin(x) is (e^(ix) - e^(-ix)) /(2i)
What I do wrong in this?
But you used the formula for cos when evaluating sin^2(x)
OK Jesus christ so I looked up the solution
None of them are remotely simple 
https://math.stackexchange.com/questions/544228/finite-sum-sum-limits-k-1m-1-frac1-sin2-frack-pim if you're curious
Dunno how you'd ever get it with just a basic knowledge of Calc and euler's identity
I mean you can understand the solution with those two
But they require tricks they dont teach in normal classes I think
A very big thanks
np
aryanh143