#Someone please solve and tell
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i mean the method of just dividing the highest degree terms since its a rational functions works here
so (1/2)^1
so 1/2
(2x+5)/(2x-7) = (1+5/(2x))/(1-7/(2x))
(x^2+2x-1)/(2x^2-3x-2) = (1+2/x-1/x^2)/(2-3/x-2/x^2)
so clearly when x goes infinity , the power thing turns into 1
and (1/2)^1
the limit of f(x)^g(x) is not (lim f)^(lim g)
in general