#l feel like lm loosing my mind can yall pls explain
deft treeBOT
obtuse breach
LIKE HOW
lofty beacon
There's a formula for the radius of a circle inscribed inside a right triangle. Do you know it?
obtuse breach
Noo can you tell me there was nothing about that in the rulebook :((
lofty beacon
Rulebook?
I'm pretty sure you need that formula, and I'm pretty sure that it's enough, but this is a weirdly specific question.
obtuse breach
Rulebook?
yeah in this book theres like first theories and examples and then there are equations
but there was no formula given about the radius of a circle inscribed inside a right triangle
obtuse breach
I'm pretty sure you need that formula, and I'm pretty sure that it's enough, but...
Alr ty ll see
lofty beacon
If you have a bunch of specific rules that you're supposed to use, you might need to post them so we know what you're working with.
obtuse breach
OH MY GOD I FINALLY GOT IT
obtuse breach
If you have a bunch of specific rules that you're supposed to use, you might nee...
unfortunately the book is not in english
TY FOR THE HELP UR THE BEST
lofty beacon
Well done. I'm curious how you did it? Did you use the formula? Or did you find something more helpful in the book?
No need to delete the question. It's a fine question. If you're done with this question, you can just type .solved
astral grotto
Well done. I'm curious how you did it? Did you use the formula? Or did you find ...
bro is my answer correct or u saying it to arson?
lofty beacon
To Arson. I haven't done the calculation.
I guess you could share your answer if you like
astral grotto
maybe this is right?
lofty beacon
Yeah, that looks good
obtuse breach
Well done. I'm curious how you did it? Did you use the formula? Or did you find ...
l remembered another rule about right triangles
whose like sidess are equal
if you draw a
idk whats it called in english
a median
that splits a side in half
ah hell nah im tripping wait
obtuse breach
maybe this is right?
:00
l used the one you sent me in another equation that was a reverse of this one
obtuse breach
so is your doubt solved right?
yessss tyy that was so clear and understandable 😄
obtuse breach
fell free to ask anything else 😄
YES
im tryna self study math this summer so l dont turn up to my teacher totally dumbfounded
but its kinda hard without someone instructing the ones you dont get :<<<<<
I have a couple
SO
In ABCD Rhombus, angle B is 120 degrees. Find the diagonal between the heights passed from an obtuse angle. If AC is 21 centimeters
So something like this
BD equals the sides but idk how to figure out its exact length
maybe im forgetting somethin
astral grotto
have you learnt trigonometry yet?
and the fact that rhomubus's diagnals bisect each other at right angle.
you can apply trigonometry in triangle ABG (G being the intersection of diagonals).
obtuse breach
uhhh
l think this is solvable without trigonometry because trigonometry comes in in later chapters
obtuse breach
and the fact that rhomubus's diagnals bisect each other at right angle.
yeah but l forgor to graph it💀
astral grotto
l think this is solvable without trigonometry because trigonometry comes in in l...
very well
see that area of rhombus = 1/2*(diagonal1)(diagonal2)
you can see as diagonals divide rhombus in 4 parts
so 4 ((1/2)(d1/2)(d2/2))
also area is equal to 2 equilateral triangles
ABD and CBD
area of equilateral triangle
sqrt(3)/4*(side^2)
equating
sqrt(3)/2*(d2^2)=1/2d1d2 (d1=21)
so d2=21/sqrt(3)