#logarithms
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i taught of changing bases inside out but that did not work
what can you say of log_b(x) if x > b ?
the answer > 1
wait that won't be useful
sorry
when x is between b and b^2
what can you say about log_b(x) ?
not quite
what answer should I say?
log_b is the reciprocal of x -> b^x
so x will be between 1 and 2
you compare the exponents
so what x^2 equals is not defined here
so your original answer is correct
we'll get some log(negative) at some point
so x = 1?
we do not have to evaluate it we can just think about what values x have to be?
what.
oh wait nvm
it's not an integer
well log_6(7) is between 1 and 2
ooh
that makes sense
it looks complicated but now it seems a lot easier
so its not defined and there are no real values?
yes
so 0 is correct
well it could be defined in the complex world but real values cannot give complex numbers when squared
np ๐