#Does anyone know what type of factorization rule this exercise is?

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dusty bluff
shy steepleBOT
stiff prism
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but if you are asking how one might go about solving it

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one way is to look at the powers of a

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a^12, a^6, a^18

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you could find the hcf of the exponents

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which in this case

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is hcf of 6,12,18

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that being 6

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after that you could let a^6 = x

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and see what the equation morphs into

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you could then again plug a^6 = x

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that might be one way to gain an insight in the factoring when your exponents are huge, but can get simplified this way

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another way would be to notice that, a^18 + 3a^12 + 3a^6 + 1. a^18 and 1 are both cubes and there are 4 terms in the expression