Don't mind the pencil, it's just failed ideas. The fact that the angles CMD and BCP=90° could help

[cinder summit]

In the parallelogram ABCD the side AB is 2 times larger than the side AD. The point M is the midpoint of AB and the point P is the heel of the perpendicular descending from the vertex C to the extension of AD. Prove that the angle BMP=3MPA

[rustic kettle]

how about proving ADM is an equilateral triangle?

prove that uhhhh D is the mid point of AP yeah

wait

[rustic kettle]

my guy

alright so

basically we tryna prove BMP=3MPA right?

so therefore we tryna prove MPA is 30 degrees

so if we can prove that MAP is an equialteral triangle

that we are done right?

since AMP +MPA+PAM is 180 degrees

wait nvm

dawg we still havent proved ADB is a right triangle

im sorry man 💀 i tried

[cinder summit]

Nope

Don't worry my dad did it

He smort

[rustic kettle]

dawg i gotta pay some respect to ur dad fr

[cinder summit]

Frfr

[sand cedar]

.solved