#Geometry thales theorem
224 messages · Page 1 of 1 (latest)
Hi
Hi
Do u see that OF = OE?
So it comes to proving OA=OI
Yes?
Great
Since EF//AI
So we can apple thales
So
Apply*
Then:
OF/OI=OE/OA
Now we replace
3/OI=3/5
Now
3x5/3=OI
So
Yuss
Congrats
Ty

U see how AFO is a right angle
And same with FEI
FI isn't diameter
I mean in C'
?
No. OA is 5, OF is 3, so by pythagoras, AF is 4
What
BE is diameter
But we have to imagine it
But u need not use that for verifying AF=4
U just wanna find AF right?
Why do we care about AF
Nooooo
I said question 5 a
Ohh
Not b
Its ok
Is it like i said diameter??
U know how two lines from end point of diameter to the circumference make a right angle?
Yes
So u can assume AI to be diameter
Yes
And then we find AF with Pythagoras
Yes
Like u said
Yea
Is AI
Wait
What
On a circle
Oh
And same with the other point
_<
Its ok i knew it
I don't think it's sufficient proof
But how
Wiat u can do one thing
Since the anglea are right
Construct a mid point M of AI
Oh wait yes
Ok maybe what i said earlier was right
If its right angle
It has to lie on the circle with AI diameter
Ok
And 5 c is
Because
AI is diameter
Umm
We use Pythagoras
So
AF2 + FI2= AI2
So
Wait what
Is the Triangle Right Angled tho?
Give me a sec
Ok
But we dont have AI
.-.
-AF^2=-25+9
4
K
This
FO+OI
4 b)????
You already t
Found OI at 4.b)
Read it
$4 \sqrt(5)$
I have No User Name but I must
...
Ok...
Using thales theorem
I'm gonna leave
