#ALGEBRA
137 messages · Page 1 of 1 (latest)
a (x + b) = 4x + 10
(a - 4) x = 10 - ab
you can not divide this equation by 0
because division by 0 is not defined.
in another words, if you allow 0 to be a divisor,
the situation will be chaotic and that is no good
but look at this equation
do you feel like dividing it by (a - 4), don't you?
at this very moment, you should stop and wait, and think carefully about how the situation is and what you should do to solve it
the question asks you to find the pairs (a, b), where any real number x will satisfy the equation.
in the equation you deal with, there are three variables, (a, b, x)
the question gives x, not c
if not x but c,
the equation becomes
a(b + c) = 4c + 10
well, i will stop here.
what I've said is only a hint,
ooooooooohhhh??>
lol
okay
well
you've got much nearer to the goal
As is always the case with communication in places like here
it is only a problem of how to say, how to express your thoughts.
it might be.
"if"
this is the key
let us return to the equation [ (a - 4) x = 10 - ab ]
please wait a moment
okay, you use c
a (b + c) = 4c + 10
first,
you said that "ab is essentially 4c.
could you explain what you meant by it?
good
Can I make another example whose essence is the same as this?
thank you
well,
if the problem is
solve these equations;
2x = 6
yes
then,
2x = b
right
but
ax = b
is it really okay?
remember that you cannot divide by 0
so,
but
if
if!!!!
if a is not 0
you can divide the equation with no worry
then,
let's get back to the first equation
oh sorry wait
before going back to the original problem,
we should understand how to deal with this type of questions
ax = b
if you understand how to solve it perfectly,
then the original one will become so easy for you
the key is [if]
if a = 0
0 = b
so, the answer is;
a = b = 0 and any x satisfies the equation.
it's ok
I just thought that [ax = b] is simple and easy to understand for you
a(b + x) = 4x + 10
the question doesn't use c but uses x is a hint.
when it's x and when it's c,
the equations look different a little bit for many people
when you look at x,
in the context like this,
you will be more inclined to look at x as a special variable than a, b
sorry, but
shall we return to [ax = b], please?
thanks
if i tell you to solve an equation [ax = b] for x,
that means, you are told to search and find x that satisfies [ax = b]
it is the point
"if ax = b, then x = b/a"
this is not correct
because there is a case where a = 0
if a = 0,
so,
you have to use "if"
or "when"
this is so easy.
I believe you always do many things like this
if it's rainy tomorrow, i don't want to go out,
but if it's sunny tomorrow, i want to go to that restaurant
here being discussed is not different from things like that at all
a can be 0
so,
it is necessary for you to divide the situation into two cases.
(i) a = 0
(ii) a ≠ 0
in the case (ii),
you don't have to worry at all about "no 0-divide rule"
because in the case (ii), a is not 0.
so you can conclude that x = b/a
but in the case (i),
the conclusion is very different from the one in the case (ii)
you can ask anything
when someone is thinking about something about which he/she has a question,
it's pretty hard to explain what he/she doesn't understand
and what you thought through tackling with something hard to understand... okay
oh
so nice
really nice
but wrong
but nice
it's so nice because you showed your thoughts
and the explanation you have created on your own
I marked two of your messages
of course you can do anything about equation "in this reality"
it's a little hard for me to explain, but
you can set a to 4
but in mathematics,
Yo
um... it's not a good choice of words
Yea it is
You're trying to isolate B
so you need to eliminate all other variables
how do you do this? by setting A to 4, then you get rid of both the A and the X
since A would just be 4, and 4-4=0, 0*x= 0 (no more X)
thanks, mpmc
ofc
I will take a rest
It's a daunting question I don't blame you, it's super sneaky
ok?
now can you solve [ax = b] perfectly?
there are other cases where you solve it as to x, but for now,
it is enough for you to solve [ax = b] with a viewpoint of the equation is an equation "of x"
in short, all you have to do is to search and find every x that satisfies [ax = b]