Direction Angle

[open zenith]

how would i do this since we aren’t calculating from the origin

[open zenith]

i did this

i think it’s right

notation might be wrong

[grim creek]

thats so easy bro

[deep sluice]

i dont think your diagram is right

check the signs of your coordinates

anyway theyre bascially asking you for angle QPR

which is just the acute anlge PQ makes with the x axis

and the acute angle PR makes with the x axis

lets say for PQ

you can find the gradient and take tan^-1(gradient) to find the angle it makes

so for this case

gradient of PQ is -1.5

tan^-1(-1.5) = -56.3°

3.s.f

but we want a positive angle

so we just consider 56.3°

so use the same method to find the angle PR makes with the x axis

and add the two together

hope this helps

[open zenith]

!close

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