Im so lost on this

[cold beacon]

use this

you can rewrite $\log_{5}30$ as $\log_{5}(6\cdot5)$

[carmine wing]

m64sky

[dapper lodge]

but how would i do it with the values it gives me?

they are mad weird

[cold beacon]

and then you can use the product rule

to say that $\log_{5}6+\log_{5}5$

[carmine wing]

m64sky

[dapper lodge]

theres is no log 5 value...

[cold beacon]

then use the log_5 of 6 value which they gave u as around 1.1

[cold beacon]

but log_5 of 5 is 1

so it would be 1+1.1

2.1

[dapper lodge]

hmm

oh shoot

so i can assume log 5 5 is 1 if log 5 4 is 0.9 and log 5 6 is 1.1?

thanks for the help, i understand now

its so simple

[latent compass]

Look at the second property that m64sky send here. You dont just asume that log base 5 of 5 is one because of other values, but rather because thats a property of logarithms