Basic Trigonometry quick question

[warm basalt]

Just a quick question from savemyexams.com I don’t rlly understand

[zealous parcel]

Do you remember your sohcahtoa?

[lyric talon]

consider a triangle rectangle a A so BC²=AC²+AB²

then

BC²=10²+18²

BC²=100+324

BC²=424

[cosmic breach]

You need to use an inverse trig function

[lyric talon]

could not he do it with cons and pythagore theory?

[cosmic breach]

I’m not sure how to find the angle using pythagoras

Using cones is an interesting idea though

I’ve never done it that way

[lyric talon]

no basically you will calculate the hypotenuse

and then we will use cos BCA=Hypotenuse/adjacent segment

im bad at english sorry

[cosmic breach]

It’s all good I can understand you just fine

[lyric talon]

and after we find the value of cos

[lyric talon]

we could use the function cos-1 i believe

[cosmic breach]

That’s an inverse trig function

[lyric talon]

oh i did not know sry i study in french so i dont know many english mathematical terms

[cosmic breach]

I was gonna say the tangent of BCA is opposite over adjacent and then use tan-1

[lyric talon]

we can use that too

[cosmic breach]

So arctan(1/1.8)

Cos works just as well

[lyric talon]

i love maths dude

[warm basalt]

Yeah I saw thanks

[warm basalt]

Nah it was just tan inverse

[lyric talon]

ok

[leaden nacelle]

Set it up like this: $\tan(x^\circ)=\frac{10}{18}$

[brittle verge]

m64sky

[leaden nacelle]

So $x=\tan^{-1}(\frac{10}{18})$

[brittle verge]

m64sky

[warm basalt]

yeah thanks

.solved