log

[random valve]

would the first be =a/2 and the next just =a ?

[flat kiln]

uh so use the basic rules of logarithm, or, eexpress it as an exponential, and let $log_b c=k$ and solve for $c^k=b$

[vague mason]

tan g ent

[random valve]

the answer choices were like A) A B) A/2 C) 1/sqroot A D) 2/A I just don't understand how the answer is found

[flat kiln]

ill just use properties

try using these

[random valve]

so wouldnt it be as you put it before c^a = b