#finding measures of the arcs and angles
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measures of the arcs and angles***
finding measures of the arcs and angles
Hey there!
One way we can find the measure of arc BD is by finding its corresponding central angle.
This is because the measure of the central angle is congruent to the arc it intercepts/corresponds to.
So which central angle intercepts arc BD? @icy spade
No. angle BOD is the central angle that intercepts arc BD.
But look at angle COB and angle BOD.
Notice how they lie next to each other on the diameter of the circle.
Therefore, angle COB and angle BOD are supplementary angles.
Hence: angle COB + angle BOD = 180
60 + angle BOD = 180
โด angle BOD = 120
The central angle is congruent to the arc it intercepts.
angle BOD is a central angle that intercepts arc BD.
Therefore, arc BD = 120 degrees.
Do you understand? @icy spade
Ohhh ya
Now look at arc CED.
Notice how it is intercepted by angle COD.
Segment COD cuts through the circle's center (O) and connects two endpoints that lies on the circumference of the circle (C & D).
So what kind of part of a circle is segment COD?
hint: ||chord, diameter, radius, secant, or tangent||
@icy spade
Secant
Hmm not quite. A secant is a line that cuts through two points that lies on the circle.
Oh wait diameter
Right!
segment COD is a diameter of the circle!
the diameter of a circle is 180 degrees
so this means that angle COD is 180 degrees
since central angle COD intercepts arc CD:
arc CD = 180 degrees
do you get that?
Ok ya
Now look at line AB and line CE.
Notice how line AB intersects circle O at exactly one point, which is at point B
Notice how line CE intersects circle O at exactly one point, which is at point C
So what kind of parts of a circle are lines AB and CE?
refer back to this hint if you are not sure
Hm tanget
Correct!
Line AB is tangent to circle O at point B, and line CE is tangent to circle O at point C
The tangent line is perpendicular to the radius that contains the point of tangency
So OB is a radius that contains point B. OC is a radius that contains point C.
Therefore:
Do you get it?
Ya
Ok so now look at figure ABOC
Notice how it has 4 sides
This means that figure ABOC is a quadrilateral (a 4-sided shape)
The sum of the interior angles of a quadrilateral is 360 degrees
So this means that:
angle COB + 90 + 90 + angle CAB = 360
60 + 90 + 90 + angle CAB = 360
From here, solve for angle CAB. Ping me when you get the answer.
OH SORRY
WAIT
I DIDNT SEE THE PROBLEM LOL
i thought we had to solve for angle CAB for some reason
angle ABO = 90 degrees
put that
sorry
idk why i saw angle CAB lol
@icy spade
๐ญ๐นok
oh shit ๐คฆโโ๏ธ
omg sorry
i just realised that CE is a secant
not tangent
omg sorry its like really late in the night for me
pls forgive me ๐
No worries
Okay so now look at angle DCE.
Notice how it is an inscribed angle.
The inscribed angle is **half ** the measure of the arc it intercepts.
So what arc does angle DCE intercept?
120?
60
Nope angle DCE intercepts arc DE
Because angle DCE is formed by chord CD and chord CE.
Oh
chord CD touches the circle at points ** D and C**. chord CE touches the circle at points E and C
you get it now?
it may help to trace where the inscribed angle touches the circle
to find the arc it intercepts
Ok
So from here, you utilise the Inscribed Angle Theorem
The inscribed angle theorem states that the inscribed angle is half the measure of the arc it intercepts
So:
angle DCE = 1/2(arc DE)
angle DCE = 1/2(70)
So what is angle DCE?
35
Wooo
๐ฅณ
Tysm ๐ญ๐ญ๐ญ๐งโโ๏ธ
of course! any time! โค๏ธ โค๏ธ โค๏ธ
.solved