#calc series geometric
formal rampartBOT
gusty ingot
3^n+1/2^3n+1
is the sequence it looks like
now try turning that into the form (x)^n, and use 1/1-x to solve for the sum
don't forget to multiply any coefficients tho
vapid jewel
hol up i almost got it
but like not really
bruv im getting 2.2 as and answer
lol
wait i gotta correct it
imma get the answer in 1 second hol up
its C
2.4
@astral mason
take the formula far the sum of a geometrycal thing idk what its called im croatian and then solve the limes of the sum of the geometrycal thing
formula for the sum is S = a1 * ( q^n - 1 ) / (q - 1)
and from the start you can see that a1 is 3/2 and q is 3/8
vapid jewel
and then you get -24/10 * -1 and you get 24/10 which is 2.4
what idk bro im croatian we have our own formula
the geometric is a1 + a1 * q + a1 * q^2 + a1 * q^3 ...... a1 * q^n
and the formula i know is the one i wrote
and then since we dont have the number n becouse n is infinity we gotta solve the limes of the sum formula
thats how i would do it
idk other wayus
ways
also what is a1/1-r
you mean a1 / q^1-r
astral mason
the geometric is a1 + a1 * q + a1 * q^2 + a1 * q^3 ...... a1 * q^n
Oh for the series ywah
astral mason
you mean a1 / q^1-r
Isn't a1/1-r the way to find the sum of the series
vapid jewel
yeah so you gotta realise in the question that its a gemetrical serias
astral mason
Yeah
vapid jewel
Isn't a1/1-r the way to find the sum of the series
how would that work
astral mason
Idk that's j how we learned to find the sum of the series but idk what the common ratio is
R is what is to the nth power in the geometric series
vapid jewel
you mean for this one for example r would be 3/8?
yeah so the q in my formula is ur r
?
vapid jewel
yeah u get it correct
yeah that formula is the sum if the series goes on infinitly
i forgot about that formula lol
i did it the long way
astral mason
loool