So basically I need to know how to do this problem. The problem is as following “The square of a number is 18 more than 3 times the number” (there are 2 answers to this question)
#Quadratic Equation Help
warm shard
native kelpBOT
dark olive
Let x be "a number".
So "the square of a number" would be x^2
x^2 is 18 more than 3 times "the number"
3 times "the number" is 3x, and if x^2 is 18 more than 3x, then
x^2 = 3x + 18
balances the equation. Now you just need to solve for x, do you know how to do this?
warm shard
Let x be "a number".
So "the square of a number" would be x^2
x^2 is 18 more tha...
Yesss thx
The answer would be 6 and -3 correct?
dark olive
correct
tidal vigil
.solved