#Geometry help

37 messages · Page 1 of 1 (latest)

dark gate
lone mangoBOT
dark gate
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<@&286206848099549185>

dark gate
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<@&286206848099549185>

jade zodiac
# dark gate

Do you know the relationship between central angles and inscribed angles? (Inscribed Angle Theorem)

dark gate
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no can u explain it to me please

jade zodiac
dark gate
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ok

jade zodiac
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Do you know how to use this information?

dark gate
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am i suppose to set them equal to each other?

jade zodiac
dark gate
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34x+4 = 18x-2

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like that?

jade zodiac
# dark gate 34x+4 = 18x-2

It's close, but you need to use the inscribed angle theorem. The arc with measure 34x+4 is opposite to a central angle, whereas the angle with measure 18x-2 is an inscribed angle.

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So there is a ratio between them.

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In short, because of the inscribed angle theorem, the ratio of 34x+4 to 18x-2 is equivalent to the ratio of 2 to 1. Do you see why that is?

dark gate
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no

jade zodiac
# dark gate no

Since central angles are 2 times their corresponding inscribed angles, and the angle opposite to 34x+4 is central, the 18x-4 angle is actually half of that.

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Because the 18x-4 angle is inscribed.

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Does that make sense?

dark gate
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so i multiply 18x-4 with 1/2 ?

midnight aurora
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You might want to start by setting up two equations, one for 2a and one for a

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2a = ????
a = ????

jade zodiac
dark gate
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so i multiply 18x-4 with 2?

jade zodiac
dark gate
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is it cause the arc is 2 times the angle?

jade zodiac
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So essentially 3x+4=2a, and 18x-4=a. @dark gate

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It's basically a system of equations here.

jade zodiac
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Ok I have to go, hopefully someone else can take over.

dark gate
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ok ok ty

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ty

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i get it now tysm

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.close