I need a bit of help

[wide hearth]

This is a non calculator exam question. how would i solve this?

[old thicket]

Are you currently in giving the test?

[wide hearth]

nope, the professor gave us some homework for our upcoming mocks

it's an exam style question

[celest spire]

lmao

flip the 27^(-1/3) to make it positive

9^(1/4) make it like idk what’s it called in English

(3)^2(1/4)

[wide hearth]

Yeah i know but idk how to deal with 3^x+1

[celest spire]

log

[wide hearth]

Its a non calculator question

Did you even read the question before texting? Lmao

[celest spire]

ok? so?

you don’t need the exact value

[wide hearth]

It needs the exact value.

I'd advise you to read the questions people send here before trying to give reasonable hints/help which you are currently not doing.

[old thicket]

What do you have so far?

After all the simplifications Bandwidth suggested

[wide hearth]

what' i've done so far is
3^-1 = 3^1/2 / 3^(x+1)

[celest spire]

flip 3^(-1)

and I think you know where you’ll go from there

[old thicket]

Look at the quotient rule

[celest spire]

yup

[knotty fiber]

you dont need logs?

[celest spire]

correct I just looked at it, thought it needed it

[wild stirrup]

You gotta make all of the terms the same base

So make them all 3

And then 27 = 3^3 so then 27^-1/3 = 3^3(-1/3) which is 3^-1

Oh nvm you got that part

Yeah so using exponent rule you can do 3^-1 = 3^1/2 - x - 1

So then that means -1 = -x - 1/2

So then simplify to get x = 1/2

Oh wait bruh the guy on top already did it

nvm

[violet loom]

haha