Analytical geometry
. Let D be the line with equation 2x+3y-1=0 and
A(-1,2) center of circle C.
Determine the coordinates of point H tangent D to the circle
#Analytical geometry
pure solstice
karmic steppeBOT
dusty lagoon
Analytical geometry
. Let D be the line with equation 2x+3y-1=0 and
A(-1,2) ce...
Unit circle?
limpid hinge
Is the line D tangent to the circle in H?
pure solstice
Yea
pure solstice
Is the line D tangent to the circle in H?
Yes
limpid hinge
You can use D to find the generic points of the line and find the distance between A and D
pure solstice
Did you answer mine? Unit circle?
Normal cercle
(x+1)+(y-2)=R^2
pure solstice
You can use D to find the generic points of the line and find the distance betwe...
I do that
Distance =1/2
dusty lagoon
Analytical geometry
. Let D be the line with equation 2x+3y-1=0 and
A(-1,2) ce...
So question asks the radius of the circle and D is tangent to the circle?
limpid hinge
Distance =1/2
Perfect, transform the equation of D to find the generic points of D
pure solstice
So question asks the radius of the circle and D is tangent to the circle?
I need to find H(x, y)
pure solstice
Perfect, transform the equation of D to find the generic points of D
How i can do that?
dusty lagoon
I need to find H(x, y)
And the line is a tangent of the circle?
limpid hinge
How i can do that?
Transform the equation of D in parametric form
pure solstice
Transform the equation of D in parametric form
What do u mean by parametric?
dusty lagoon
You could make the equations equal then use the derivative of circle to set it to line
Which would give two equations with two variables
dusty lagoon
Or maybe just use m1m2 = -1 formula to make a line in the center of the circle
pure solstice
You could make the equations equal then use the derivative of circle to set it t...
I still dont learn the derivate😅
dusty lagoon
Then use the distance formula
dusty lagoon
I still dont learn the derivate😅
You can use the second method
pure solstice
Or maybe just use m1m2 = -1 formula to make a line in the center of the circle
Yea but how exactly
limpid hinge
What do u mean by parametric?
limpid hinge
You have [3} instead of {3} @dusty lagoon
tall oasisBOT
Oğuzhan
dusty lagoon
The slope is -2/3
The new slope should be 3/2
And should pass (-1, 2)
So
$y = \frac{3}{2}x + b$
$2 = -\frac{3}{2} + b$
$2 + \frac{3}{2} = b$
tall oasisBOT
Oğuzhan
dusty lagoon
So our new equation is
$y = \frac{3x + 7}{2}$
tall oasisBOT
Oğuzhan
pure solstice
You can use the second method
Or I can make new line orthogonal in D and pass in A
So H be intersection of the two lines
dusty lagoon
Now use the following distance formula:
The distance between the line $ax + by + c = 0$ and point (d, f)
$\frac{|ad + bf + c|}{\sqrt{a^2 + b^2}}$
tall oasisBOT
Oğuzhan
dusty lagoon
Or I can make new line orthogonal in D and pass in A
So H be intersection of the...
What do you mean?
dusty lagoon
**Oğuzhan**
Oh wait I think you don't need this
