Need help with limit | Mathematics | Page 1

strange dawnBOT Apr 5, 2023, 10:15 AM

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quiet lodge Apr 5, 2023, 3:43 PM

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you can 'simplify' the fraction

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Do you see how?

terse temple Apr 5, 2023, 5:08 PM

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nope...

quiet lodge Apr 5, 2023, 5:41 PM

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You can write e^-x as 1/e^x

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Does that help?

terse temple Apr 5, 2023, 6:50 PM

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now should i try hopital?

quiet lodge Apr 5, 2023, 7:08 PM

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No

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We won't use l'Hôpitals rule

quiet lodge Apr 5, 2023, 7:09 PM

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quiet lodge You can write e^-x as 1/e^x

If you wrote it like this you can write both the nominator and denominator as a fractions

terse temple Apr 6, 2023, 12:05 PM

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1/e^x and 1/e^4x goes to 0

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then i write logxe^x/e^2x

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logx/e^x is 0

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is it correct?

quiet lodge Apr 6, 2023, 12:18 PM

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Can you write it on paper?

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I can't really follow

terse temple Apr 6, 2023, 6:45 PM

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quiet lodge Apr 6, 2023, 8:32 PM

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Seems good

terse temple Apr 6, 2023, 11:13 PM

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thanks<3

proper berry Apr 5, 2024, 7:30 AM

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.close

#Need help with limit