#Calculus Proof

18 messages · Page 1 of 1 (latest)

hushed onyxBOT
sudden trench
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<@&286206848099549185>

gaunt ore
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Factor the left hand side. One of the two factors is bounded by 2. To understand the other factor, apply MVT to the function sin(x) and see what it gives in the general case.

sudden trench
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Any <@&286206848099549185> know how to do this?

gaunt ore
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I just told you how to do it and you're gonna ignore me. smh

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If you want more help, you have to say what you know, what you've tried, and what your having trouble with

sudden trench
sudden trench
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<@&286206848099549185>

outer cape
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Please don’t spam ping helpers

sudden trench
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Sorry

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Could anyone check to see if this proof is correct?

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@gaunt ore is the proof valid?

gaunt ore
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I don't understand the => after the "such that". The sentence should end after (f(b)-f(a))/(b-a). Why is sin(2x) equal to what you say it is?

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The left hand side of the inequality that you want to prove is the expression that is on the left of the inequality. Namely, |sin^2(b)-sin^2(a)|. That is a difference of squares.

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It might actually be an okay proof. Though that one line has syntactic issues.

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It's surprising to me that they would give you a bound of 2|b-a| if |b-a| is also a bound, but I haven't found the counterexample yet.

sudden trench
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Well, I proved that it is less than or equal to
|b-a| so that automatically means it is less than or equal to
2 |b-a|.

coarse edge
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.solved