#inequalities
53 messages · Page 1 of 1 (latest)
x^2-(9/2)x=0
if you want to know how I did, here is what I did
I made the equation like this: (x-9/2)(x-0)=0
because the roots for the equation would be x=0 and x=9/2
so then simplifying it would be (x-9/2)(x)
They should be whole Numbers too so
oh yeah they are supposed to be integars
thank youuuu
do you guys happen to know any other servers like this?
like for biology
they should be integars
not whole numbers
or physics
i can invite u to a physics discord server
please do
question didnt specify?
or is that a rule for inequalities
they said write it in ax^2+bx+c form where a,b,c are integars
.solved
Post marked as solved by @waxen rover.
Use .unsolved if this was a mistake.
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What’s the difference?
whole numbers are 0, 1, 2, 3, 4, 5,...
integars are ...-5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5,...
What you describe are natural numbers
I can’t help. The way I’ve understood it Δ depends on x
natural numbers are {1, 2, 3, 4, 5,..}
i think u have to use b^2-4ac
so a=-1
b=2
c=-1
(2)^2-4(-1)(-1)
4-4(1)
4-4
0
so the discriminant is 0
@frank tuskwhat software do u use
I don’t see why you use the y value for the min/max point. Also I take a screenshot in my iPad and just draw over it
Bro
Do you not know the discriminant
Exactly
yes
if you are on pc/laptop right click on the forum channel and click unfollow post
visual representation
if i did do ypu think i would have opened this forum