#geometry
18 messages · Page 1 of 1 (latest)
oh dear god, i dont know how to solve that either
Can we assume the two triangles are congruent?
(Sorry Im not incredibly talented at math I was just looking at other questions while I was waiting for help and this looked kinda familiar)
If they are congruent we have 2 provided angles: 90 and 78, which means we have to use the sum to subtract from 180
becos thats the sum of a triangles interior angles
so 180-168=12
so the unknown angle marked with a sideways x is 12 I think
wait there ARE VARIABLESD
well if they are congruent
we have 2 sides so me can use this one thingy to determine the 3rd side
lemme look at my geometry notes
can't we use compound inequality? it sounds like it...
i jus dont know if it would work with a variable
i got to 2y-25.5 < x < 2y+23.5