- Prove that the number 251 is prime. - analyze the number 2008 into prime factors , and deduced the natural numbers whose Cube divides each 2008. - Find the natural numbers a and b such that: m3 + 35d3 = 2008, note that :
d = PGCD ( a ; b ) and m = PPCM ( a ; b )
#helppp Last question help pleasee
hoary walrus
vivid hareBOT
kindred kernel
if a number cant be divided by the prime numbers smaller than the square root of it, then the number is prime
251 cant be divided by 2, 3, 5, 7, 11, 13 which is smaller than √(251)≒15.xx
so 251 is prime
2008 = 2^3 × 251 so the numbers would be 1 and 2
a=2, b=6
slim bridge
bruh dont give em the whole answer
it doesnt dont help their problem solving one bit
kindred kernel
Well i try to tell how at least
Or should i have started like
Asking where one is stuck?
slim bridge
Asking where one is stuck?
yes, and then offering the hint to the next step and see if they catch on
let them do most of the work