#finding angle
37 messages · Page 1 of 1 (latest)
Hi!
Have you tried anything?
Well
You see
Sum of angles in a triangle is 180 degrees
Also
Angles opposite to equal sides in a triangle are equal
Well
If you have an isosceles triangle
Like this
Then the angles opposite to the equal sides
Are also equal
So
Try creating a new overview of what you have
And see if you can figure out some angles
Angle (ACB) = 4*angle (BAC)
∠ACB=48°
Take better pictures 😐
Maybe you should try to explain things rather than give out answers
this is wrong
its 45 degrees
lets set ∠XAY=a°
then because AX=XY
∠XYA=a°
and so,
∠BXY=a+a°=2a°
and also since, XY=BY,
∠XBY also becomes 2a°
now, ∠XYB=(180-4a)°
so ∠BYC=3a°
and since BY=BC
∠BCY is also 3a°
and since ∠ABC=120°= ∠XBY+ ∠YBC=2a+(180-6a)°=180-4a
a=15
so ∠ACB=3a°=45°