#Calculus Infinite Limit
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I'm confused on the rationalization
My specific problem is that I don't know how this turns into this
This is an example of a similar problem
How does (x+sqrtx^2+1)(x-sqrtx^2+1) turns into 1
yeah im confused
I mean I know it does, I check it with mathway and verified it's true. But I need someone to help me work through this problem
its difference of squares
the two terms in the top are (-a+b)(a+b) = -a^2 +b^2 = -x
a is 8x and b is sqrt (64x^2 -x)
same idea, difference of squares
So how does it turn into x?
thats whats left over after stuff cancels
Do I have to go through the whole distribution and factoring?
its a frequently occuring identity
you could FOIL it if you wanted but it would be unnecessary
How can I determine that though?
you can foil it in the general case to prove it if you want
it would take like 3 lines
I put it through mathway and there were like 2 dozens steps
Is there an easier way?
forget the machines
by recognizing that its a^2 - b^2 and simplifying
Okay, so like can you walk me through the math? I feel like I still don't know what to do exactly
Sorry I'm asking alot
first if you have (a+b)(a-b)
= a^2 -ab +ab -b^2 = a^2 - b^2
so if youre multiplying two terms with the same stuff inside, except one is addition and the other is subtraction, you end up squaring both things
so you have sqrt(64x^2 -x) and 8x
you can see it has the same form as (a+b)(a-b)
Okay
8x is what changes signs, so its going to be (sqrt(64x^2 - x))^2 - (8x)^2
square and square root cancels so you get 64x^2 - x -64x^2 = -x
its the same idea for the second one
it helps if you do the simplication yourself on paper
Alright, when I get home I'll see if I can practice it right
Appreciate your help alot
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