#Help Needed With Trig
20 messages · Page 1 of 1 (latest)
sin(x) = 0 has infinitely many solutions, that is
$$x = \pi\cdot k,; k \in \mathbb{Z}$$
Frogieder
So now, you just need to find the ones that lay on the given interval
Thus, you can see that $x \in \{ -\pi,\ 0,\ +\pi \} $
(come on, TeXit bot, why can't you compile?)
-pi, 0, pi
Oh, wait, I've just realised...
I did it wrong
Most of it should be right
However, I made a substitution, which was poorly denoted
sin(t) = 0
Thus, t = pi*k, where k is a whole number
But t = x - pi/3, so
x = t - pi/3
Thus, there are only two solutions for x
-pi/3 and pi/6
@static carbon