Please am having a little problem with the last question. | Mathematics | Page 1

kindred panther Dec 31, 2022, 5:39 PM

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thorn compassBOT Dec 31, 2022, 5:39 PM

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opaque hull Dec 31, 2022, 7:36 PM

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I believe you use power series expansion on both functions. Taylor series.

feral oak Dec 31, 2022, 7:43 PM

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kindred panther

you can expand e^kx using taylor series, and you want k=lna

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2^(-3 * 4) = 2^-12 so so a^x = 2^-12

kindred panther Dec 31, 2022, 10:15 PM

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Miismi I will check it cause I have not been thought Taylor 🥲

feral oak Dec 31, 2022, 10:19 PM

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its not too hard

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this is the formula, and you form the series around a point x0, if x0 is zero then all the (x-x0)^n terms become x^n

kindred panther Dec 31, 2022, 10:23 PM

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Ok miss I will attempt it and any place I hang I let you know

kindred panther Dec 31, 2022, 10:26 PM

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feral oak its not too hard

I mean this

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To the 12 terms is this correct?

feral oak Dec 31, 2022, 10:41 PM

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thats the series for e^x

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and you want the series for e^(kx)

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so the derivatives are gonna have the constant k

kindred panther Dec 31, 2022, 11:27 PM

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Ok miss thank you very much

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Still on it well I send you what I did tomorrow

kindred panther Jan 1, 2023, 1:22 PM

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feral oak so the derivatives are gonna have the constant k

Miss I got it
e^-2.4 = 0.0902

feral oak Jan 1, 2023, 8:29 PM

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kindred panther Miss I got it e^-2.4 = 0.0902

well you need 2^(-3*4)

kindred panther Jan 2, 2023, 5:23 AM

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close

#Please am having a little problem with the last question.