#哪个大佬解一下这个,who can solve this question
5 messages · Page 1 of 1 (latest)
just multiply it lol
Step 1: Simplify both sides of the equation.
$$
\begin{aligned}
& \frac{2}{3}\left(\frac{x}{2}-6\left(\frac{1-x}{2}+\frac{2 x}{3}\right)\right)=\frac{x}{6}-5 \
& \left(\frac{2}{3}\right)\left(\frac{x}{2}\right)+\left(\frac{2}{3}\right)\left(-6\left(\frac{1-x}{2}+\frac{2 x}{3}\right)\right)=\frac{x}{6}+-5 \
& \frac{1}{3} x+\frac{-2}{3} x+-2=\frac{1}{6} x+-5 \
& \left(\frac{1}{3} x+\frac{-2}{3} x\right)+(-2)=\frac{1}{6} x-5 \text { (Combine Like Terms) } \
& \frac{-1}{3} x+-2=\frac{1}{6} x-5 \
& \frac{-1}{3} x-2=\frac{1}{6} x-5
\end{aligned}
$$
Step 2: Subtract 1/6x from both sides.
$$
\begin{aligned}
& \frac{-1}{3} x-2-\frac{1}{6} x=\frac{1}{6} x-5-\frac{1}{6} x \
& \frac{-1}{2} x-2=-5
\end{aligned}
$$
Step 3: Add 2 to both sides.
$$
\begin{aligned}
& \frac{-1}{2} x-2+2=-5+2 \
& \frac{-1}{2} x=-3
\end{aligned}
$$
Step 4: Multiply both sides by $2 /(-1)$.
$$
\begin{aligned}
& \left(\frac{2}{-1}\right) *\left(\frac{-1}{2} x\right)=\left(\frac{2}{-1}\right) *(-3) \
& x=6
\end{aligned}
$$
NightKing