#80 year old trying math equation help!
24 messages · Page 1 of 1 (latest)
I'm no means an expert but I would put the y's on the LHS and all the X's on the RHS and integrate both sides
$\int -y^2 \cdot dy$
$\int -y^2 \cdot dy = \int x^2 dx$
Peachy
$\int -y^2 \cdot dy = \int x^2 dx$
Peachy
what are you doing
you can't just do that
so what
you have dy/dx - y^2 = x^2
and you're just going to integrate both sides?
how?
my bad, i thought u could do that lmao, but completely forgot about multiplying
its been a while since i touched maths , thats why im here for help lmao just looking through
lol
may I know if u are just trying to find y(x)[which seems to be some insane task to me] or something else from the de
ty very much folks I didn't expect so many answers. Merry Chritsmas to you all and thank you again
.close