#Multiplying or factoring polynomials with two variables
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axy+bx+cy=d. I’ve seen it done as a binomial, (ax+c) (ay+b) = ad + bc
Not too sure if u can factor it as two polynomials though
@lucid sand
That is completing the rectangle
What I'm trying to do is factor Axy + Bx + Cy = D as such: (...)(...) = D, because in my case factors of D are known while ad + bc can be very large
Specifically, Axy + Bx + y = D because i will always have c=1 here
It is not possible at all.
that is not a way to solve it, the reason why we have to use =0 is because we know then the (ax+b)(cx+d) will the guarantee root of the function