#Derivative Rules

13 messages · Page 1 of 1 (latest)

foggy idol
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Im struggling to understand how they got this answer for this derivative

atomic larkBOT
foggy idol
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and also why is this right

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i guess i dont understand derivatives of ln as a whole

untold scroll
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just figure it our

foggy idol
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if you're not gonna provide actual help dont go in help channels

cyan fiber
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Hi!
it's just a product rule

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[2x⁵ · ln(x)]' =
= [2x⁵]' · ln(x) + [ln(x)]' · 2x⁴
= ...

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The product rule says that
(fg)' = f'g + g'f

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@foggy idol

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Oh I didn't notice the second image
That's a chain rule
ln(x^10) = f(g(x))
f(x) = || ln(x) ||
g(x) = || x^10 ||

Chain rule:
[f(g(x))'] = f'(g(x)) · g'(x)