#Can someone help me with number 8?
70 messages · Page 1 of 1 (latest)
Okay so
We are given that YX=ZX right?
So what type of triangle is YXZ?
Similarly, we are given that YO=ZO , so what type of triangle is YOZ?
Yeah, and do you remember that an isosceles triangle has equal angles at its base?
Idk if you have to prove this as a step but
That’s a new thing I learned lol
If you draw the height of an isosceles triangle, then since AC=AB, AD=AD, and D is a right angle, you know that right triangles ACD and ABD are congruent, so the angles DCA and DBA are equal
So you're given that YXZ is isosceles and that YOZ is isosceles
So looking at YXZ, the entire angle at Y is equal to the entire angle at Z, so (1+2)=(3+4) right
And also from isosceles triangle YOZ, the angle at 2 is equal to the angle at 3
so (<1+<2)=(<3+<4)
and <2=<3
So what can u do to those equations to get <1=<4
Subtraction property?
Yea
Can you check my proof when I am finished
ye
I think so if your teacher is fine with the the fact that isosceles means equal angles(proving this separately prob isn't necessary here)
Would my next statement be <2=<3 because of the base angles of isosceles triangle are congruent?
Yeah since OY,OZ= <2=<3
Wait can I just skip that and write <1=<4 instead?
Well how do you know that <1=<4 without subtracting the two equations
You prob need to justify why <2=<3
Yeah that should work
On a side note you should look up Art of problem solving intro to geometry if u would like to get better at geo and find some very cool problems
Ok thanks for the help
Can you also help with another problem? Its fine if you can't
Yes
Number 12
AB=AC so what kind of triangle is ABC?
Isosceles
Alright so maybe we want to show that triangle AXB is congruent to triangle AYC. We have AB=AC, and are given that <1=<3. Do you see another pair of angles that you could show are equal for these two triangles to use ASA congruence?(Recall ASA means two triangles are congruent if two angles and the side between them are equal)
Yes! Although make sure you see why we can't use <2 here. The triangles are AXB and AYC, and <2 is not an angle of either of these triangles
Ohh
So if we want to show that <b=<c, how does this help with that?
We can use the ASA congruence to say that triangle AXB is congruent to triangle AYC?
Yeah, but to show that <b=<c, we use the fact that AB=AC from the isosceles fact is what i meant, but yeah ASA for these triangles is what i was hinting at
Wait I'm still kind of confused why <B=<C
Can you explain a little bit more on that?
So we are given that AB=AC right? Remember from the last problem that an isosceles triangle means that its base angles are equal?
from this
yeah, you might want to include somewhere that you're using the fact that AB=AC, <b=<c, and <1=<3 for step 3, but this should work
Also finish the proof after step 3, we still need to show that ax=ay
Is it AX=AY because corresponding parts of congruent triangles are congruent?
Sorry if I'm a bother
Yes
u should check out this book also https://artofproblemsolving.com/store/book/intro-geometry
np bye
Ok