#just something small
28 messages · Page 1 of 1 (latest)
What do you mean "the question is f(t) = 5t²+100" ? Do you have to find the roots of this polynomial ? Its maximum ? Or something else ?
No I have the Maximum and/or Vertex (10,500). I really should have been more specific but anyway, the question is just a simple function relating to the total amount of time a flare was in the air for, and the Parabolla goes from (0,0) to (10,500) to (20, 0)
Ill just send the question actually
And where im at
Yes, it'll be more clear 👍
I'm technically done the question, but I don't fully understand how to get to (20,0)
If it seems obvious then thats what I'm scared of. I have a test tmrw and I want to make sure I'm not missing any gaps on what we've learned
Okay so the vertex is indeed at (10,500)
So what gets you stuck is why (20,0) in on the curve of the function, right ?
Yeah
"(20,0) is on the curve on the function" actually means that f has value 0 at t=20, and if you try to compute f(20) you will indeed see that f takes value 0 at this point
Oh okay, I see.
So how would I go about figuring this out on my own. Should I just make a table all the way to 20?
In other words, the two roots of the polynomial f(t) are 0 and 20 (the two points where f takes value 0)
And any parabola has its vertex exactly at the middle of its two roots (this gives you a means to verify your answers)
Actually all you have to do is solve f(t) = 0 for t
Wait.. okay..
So
F(t)=0
Makes sense
So than
So okay, so lets say I already found out that 10 was the middle, and it started at 0. I could simply just double 10 or whatever the X value is in the vertex to get the other side?
I still feel like Im misunderstanding something.
Alright so I solve for f(t)=0 for t but how...
Bc on the table when f(t) or h = 0, t is also 0
You could also do that, yes !
You have 3 informations (2 roots and 1 vertex) and what I said here can help you find any of the three with only two
.close