Simplifying radicals

[lost halo]

how do you begin by solving this?

[vapid igloo]

use that $\sqrt[3]{x} = x^{1/3}$

[robust obsidian]

Denascite

[vapid igloo]

and then use exponent properties

[lost halo]

i tried that

but didnt know where to go next

so I began with but after multiplying 2*4 i had no idea what to do it was mostly a dead end

[lost halo]

what is answer

[lost halo]

idk

that's why i asked?

[tiny solar]

answer is a solution to a problem.

[smoky scroll]

and then multiply all the exponents of each term by 1/3, since you're raising everything to the power of 1/3

[lost halo]

I was gonna do that

but here i was confused

do I do $(5^4)^\frac{1}{3}$ or do $5^4 = 625$ then do $625^\frac{1}{3}$

[robust obsidian]

miky

[lost halo]

wait nvm I forgot, either way it'll give me a decimal so again that's where i got confused i wasn't supposed to get a decimal

[white spear]

,,\sqrt[3]{5ab^2c}^4\
\sqrt[3]{5ab^2c}^3\sqrt[3]{5ab^2c}\
\boxed{5ab^2c\sqrt{5ab^2c}}

[robust obsidian]

mtt07734

[white spear]

.solved