help-43

[undone topaz]

just for triangles (values for sin, cos, tg, ctg for 30, 60, 90

[chrome harness]

without substitutions this question will be very long and honestly not worth it. i dont see how this is testing anything if youre supposed to sit down and calculate everything

[chrome harness]

alright, then forget what i said. lets try solving this without trig

[sullen canopy]

this is really difficult unless you know the substitution

[undone topaz]

i mean if it's possible it would be perfect

[undone topaz]

i will just drop it then, i have 0 ideas why my new teacher would give this as homework

[chrome harness]

it is, but we'll have to get into a lot of identities and new concepts

[undone topaz]

i think i will ask the teacher, because it's getting too confusing and it's too late in the night to try anything now

i appriciate

that you want to help me

[chrome harness]

man. i feel like we're missing a very easy substitution here tho

maybe we dont need trig

[undone topaz]

i've experienced this before

it seemed very complicated but it was a simple thing

i don't know if this is the case '

[chrome harness]

nvm

i tried it and its too long

i think the u substitution for 16-x^2 in root is the way to go but thats still rlly long

[undone topaz]

i give up for today

but again, thank you very much for trying

i will try again tomorrow, but if you couldn't, it's doubtful i will

[chrome harness]

youre welcome.

[chrome harness]

see, its not a hard problem. we're just missing some easier way to do it. and if there isnt an easy way then its a waste of time. dont spend time on problems that make u rationalize everything. theres 0 application of concept on them. u wont learn much.

have fun learning

[undone topaz]

thank you very much! have a nice day/night

.close

[compact pewter]

Channel closed

Closed by @undone topaz

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

[frigid furnace]

yo can someone check my mistake

for the record, initial line is js dy/dtheta = 0

I js think i messed up my differentiation somewhere?

[tulip spear]

i got it to the end

shall i dm?

[frigid furnace]

dang bruh

thanks for yr answer

<@&286206848099549185> \

this differentiation cant be that hard man

@mild sky slide thru

[compact pewter]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wintry knot]

how do we do this? i tried making cases but could not really find a pattern

[winged lion]

gcd of 3 and 15 isnt 1

Also maybe notice what if n and m are coprime

I think that should help

[wintry knot]

right, sorry

[wintry knot]

then gcd((2^m)-1, (2^n)-1) would be 1

but how do we generalize it for all numbers?

[winged lion]

A pattern I notice when m and n are not coprime is, you take the minimum, would you agree?

I would try maybe a few more examples tho, might be wrong

[wintry knot]

what if we take 6, 10

its gcd would be 3

i mean, of (2^m)-1 and (2^n)-1

[winged lion]

ah okay

[toxic cipher]

i dont know if this will help or not, but you can expand $2^n - 1$ as $2^{n - 1} + 2^{n - 2} + 2^{n - 3} + \ldots + 1$

[wintry knot]

so basically the idea is, if d | n then (2^d) - 1 | (2^n) - 1?

or is that incorrect?

[winged lion]

That seems actually to be the case now that I see your examples

Possibly, an iff

Have you tried Euclidean algorithm?

[wintry knot]

have not studied that

[winged lion]

Ah okay

[wintry knot]

but i think i have an idea now

[wintry knot]

but i would not be able to think of this when i saw the question

.close

[compact pewter]

Channel closed

Closed by @wintry knot

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[quiet lava]

cant solve this limit

[soft stone]

Why do you think your solution is incorrect?

You deleted your messages.

Your solution is correct.

[reef bronze]

the one on the right is a derivative

[compact pewter]

@quiet lava Has your question been resolved?

[quiet lava]

IS IT? OKAY!

[quiet lava]

ohhhh

thank you so much!

[compact pewter]

Channel closed

Closed by @quiet lava

Use .reopen if this was a mistake.

[compact pewter]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[subtle forge]

hi, can someone walk me through this?

[ivory lava]

do you know what a limit is

[subtle forge]

yes

[ivory lava]

take the limit as f(x) goes to +/- inf

see if it exists, if so that's the horizontal asymptotes

[subtle forge]

yes i have done this and i got zero

but it said my answer was incorrect

[ivory lava]

maybe write y = 0?

i did it in my head and i think y = 0 is right

[subtle forge]

hm youre probably right

[ivory lava]

cuz denominator grows faster than numerator

[subtle forge]

yup that's right sorry 😭

thanks sorry for the silly mistake

[ivory lava]

nw

that's annoying to be marked wrong for

but i think on calculus exams u will be expected to write x = and y = for equations of asymptotes

[subtle forge]

yeah but its deltamath so gotta be exact and all that jazz

[ivory lava]

to specify if it's vertical or horizontal

[subtle forge]

mhm i think we're supposed to do that on paper homework too, our teacher just doesnt mark us down

thank you so much! bye bye

.close

[compact pewter]

Channel closed

Closed by @subtle forge

Use .reopen if this was a mistake.

[compact pewter]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[odd jay]

can someone explain to me the utility of matrix transforming into higher dimensions? it seems kind of redundant because you can't actually span Rn. Its like adding a container to an existing vector space, except you can't actually fill that container

[odd jay]

with transforming into lower dimensions, you are basically compressing the vector, which loses data. so its actually doing something. but no information is gained or lost with matrix transformations into higher dimensions, right? or am i misunderstanding

[rigid perch]

well information can't be 'gained' but it still can be 'lost'

[odd jay]

how is that possible for when n > m

[rigid perch]

the trivial example would be the transformation which sends all vectors to 0

[odd jay]

well, any such transformation could be rewritten into a transformation going into a lower dimension

so i still don't get the purpose of transforming into higher dimensions

[rigid perch]

although a linear transformation might not 'reach' every vector in the codomain, it can be useful to consider how 'close' it can get

for example if b lives in higher dimensional space than x, then Ax = b likely doesn't have a solution, but trying to find the x such that Ax is as close as possible to b is actually quite a useful exercise

since it leads to linear regression

[odd jay]

ah, that makes sense

ty

.close

[compact pewter]

Channel closed

Closed by @odd jay

Use .reopen if this was a mistake.

[compact pewter]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lofty mountain]

did i do it right

[kind viper]

80% is 4/5 not 2/5.

also your equation should read as $\frac45 y - \frac12 x$ not $\frac12x - \frac45 y$

[boreal girder]

Ann

[kind viper]

"A is subtracted from B" means B - A. that's just english.

those are your mistakes. they happen in the first 2 lines. fix them. @lofty mountain

[lofty mountain]

ok

[potent berry]

chicken scratc

actually its pretty good this time

[lofty mountain]

?

.close

[compact pewter]

Channel closed

Closed by @lofty mountain

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[copper sandal]

Using the given x1 and x2 on the right, make a equation and check if its equal to the one on the left
Thing is if i use x^2 - p + q, where p = x1 + x2 and q = x1 * x2, im not sure what the sign is for p in the equation
Or in other words, would you get 8x^2 - or + 26x + 15

[kind viper]

can you share the original problem text

like in bulgarian

[kind viper]

x^2 - p + q
this is mistyped btw

[copper sandal]

is it with a plus?

[kind viper]

x^2 - px + q surely

[copper sandal]

oh yeah oops

[kind viper]

Using Vieta's theorems, check whether the given numbers are roots of the given quadratic equation.

i think it is easier to start your reasoning with the equation

namely, for an equation $ax^2 + bx + c = 0$ with roots $x_1, x_2$ Vieta's theorems state that:
\begin{itemize}
\item $x_1+x_2 = -\frac{b}{a}$ \
\item $x_1x_2 = \frac{c}{a}$
\end{itemize}

[boreal girder]

Ann

[kind viper]

so you look at your equation and ask yourself: ok, we don't know what its roots are (yet), but what is their sum?

and vieta says their sum is -26/8.

do your two numbers (5/2 and 3/4) have sum equal to -26/8?

[copper sandal]

no

they equal 26/8

but with the minus it is

[kind viper]

their sum equals 26/8

but no

and vieta says their sum is -26/8.
do your two numbers (5/2 and 3/4) have sum equal to -26/8?

the answer to this can be given without any calculations if you think for three seconds

"No, two positive numbers can't possibly sum to something negative."

they equal 26/8
but with the minus it is

this, however, is the road to sign-confusion hell.

[copper sandal]

Oh i think i get it

But what about the x^2 -px +q method, if the x's are 1 and 2, would it be x^2 -3 or +3?

looking through something ive gotten really confused and just want a direct answer

[kind viper]

if the roots are 1 and 2

then the equation will begin as x^2 - 3x + [censored]

[copper sandal]

ohh

[kind viper]

you can always re-check this by expanding (x - x1)(x - x2)

and in fact this should always always be your fallback

dont memorize shit blindly but like understand this factorization is the backbone of anything vieta

[copper sandal]

okayy

Huge thanks

ill be closing this if you have nothing else to sya

say

.close

[compact pewter]

Channel closed

Closed by @copper sandal

Use .reopen if this was a mistake.

[compact pewter]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[frigid furnace]

im rly lost on this question

[frigid furnace]

I dont get how PE loss is (a-acostheta)

acostheta is the height of OA

<@&286206848099549185>

[compact pewter]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[frigid furnace]

lol

civil service pigeon

i see you twin

[mossy island]

What have u tried?

[frigid furnace]

I legit just

dont get

why its a-acostheta

the gpe loss

everything else i got to

[mossy island]

Where??

Oh I see

[frigid furnace]

I have it written on paper

[mossy island]

This?

[frigid furnace]

yes i dont get that

i have mga + 1/2 (10ag/9) = (1/2)mv^2 and then i need the PE

i do it a bit differently i dont start off witht he loss

[mossy island]

Do you have the answer key?

[frigid furnace]

Yes

[mossy island]

Alright

Imma try first

Then see if I can help

[mossy island]

Ok so

You r having confusion

Why a-acostheta is the gpe loss

[frigid furnace]

yes

[mossy island]

From stage 1 to stage 2?

[frigid furnace]

Like

what does that mean

its 2 diff circles

[mossy island]

They r taking both of them separately

First from the point P to L they r taking 1 journey

And calculating the KE gain and PE loss

Now

The PE loss is mg(a-acostheta)

[frigid furnace]

P to L???

[mossy island]

You r getting confused in this part

[mossy island]

Yes

[mossy island]

Correct?

[frigid furnace]

yh

but wtf is P to L lol

[mossy island]

From point P to point L

L is the lowest point

[frigid furnace]

and point P is?

[mossy island]

And P is the starting point

[frigid furnace]

u mean O?

[mossy island]

No no

O is the centre of the circle

The body with is moving

Is starting from P

[frigid furnace]

and where is this P

[mossy island]

Its smth like this

[frigid furnace]

oh

OHH

like the

little see thru dots

like these

[mossy island]

Yes that is the "ball" or body that is moving actually

[frigid furnace]

ahh

okok

[mossy island]

So back to the pe loss

Yk GPE is mgh

Correct?

[frigid furnace]

yeah

[mossy island]

So try to calculate PE at P and at L

[frigid furnace]

at P it would be 4/9 a

4/9 mga

[mossy island]

Why?

[frigid furnace]

because a-5/9a is 4/9 a

[mossy island]

Where did you get that from

Oh no no no

[mossy island]

R u taking the distance from O to A

[frigid furnace]

yweah

yeah

OHHH

[mossy island]

Your method would have been correct if P and A were at same level

But they aren't necessarily!

[frigid furnace]

but you cant prove that

they are

[mossy island]

It's not mentioned in the question I believe

[frigid furnace]

so then its a?

[mossy island]

Nope

[frigid furnace]

a-acostheta

[mossy island]

Ok let's try a different approach

[mossy island]

Yes

But do u get how that is coming

?

[frigid furnace]

not reallt but kinda

the whole diamater is a

[mossy island]

Should I explain???

[frigid furnace]

yes

[mossy island]

Let the point L have 0 PE i.e it is at ground

Then let P be h distance above ground

Now look at this triangle

[frigid furnace]

ahhhh

and the acostheta is like

[mossy island]

Here OL is a

[frigid furnace]

right next to my '5/9 a'

but its not exactly that

and then a is the whole diamater?

[mossy island]

More like radius but ye

[frigid furnace]

why is it radius?

Oh

cuz

O is the

centre

LOL

oops

mb

[mossy island]

Yess

Now

OL is a

In triangle OCP

Apply cos theta

You will get OC= a×cos(theta)

Now CL is h (the height we assumed P to be above the ground

Now from the figure you can see OL -OC= CL

[frigid furnace]

i get itt

thank youu

[mossy island]

Noice

[frigid furnace]

so at L

pe is 0

[mossy island]

Yes

You can consider any one level at 0 in doing such problems

If it involves change in GPE

It makes the calculations easy

[frigid furnace]

okok

thanks

.close

[compact pewter]

Channel closed

Closed by @frigid furnace

Use .reopen if this was a mistake.

[compact pewter]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[rugged widget]

I have to solve this question:

Jack and Jill heard a noise in the woods and both ran off in different directions. Jack’s GPS informs him that he ran 29 m at a bearing of 40 degrees South of East and Jill’s compass watch indicates that she ran 42 m at an angle of 11 degrees South of West. What is the displacement from Jill to Jack at this point?

I got the meters of the displacement correct (64.3m) but when I try to solve for the angle I get 80.5 degrees N of E instead of 9.5 degrees S of E. What did I do wrong to get this answer?

[rigid perch]

can you show your work?

[rugged widget]

Sorry I was just looking over my work while I waited for a response and saw that I drew the final triangle backwards. I got the right answer.

I had the direction of my x opposite then it should have been for the final triangle.

.close

[compact pewter]

Channel closed

Closed by @rugged widget

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[jade pumice]

this is hellish

[vivid breach]

thats neat, I was doing something like this a moment ago

have you tried cubing both sides yet?

[jade pumice]

this is the first time we're doing cubic roots and the teacher gave us this, look what I did

[forest token]

is that 1-x,x and 1-2x?

[vivid breach]

yes

that is a way to write down x as $x$

[boreal girder]

mtt

[vivid breach]

I personally dont like it since it looks like a fancy H

[forest token]

well straight away we can see x=1/2 works right?

x=0 also works

and x=1?

[vivid breach]

theres a systematic way you can solve this

[forest token]

but its so fun guessing 💀

[vivid breach]

make this substitution

then cube both sides

cancel out 2v on both sides

factor everything

and therefore get v = -1, 0, 1 as the only solutions

[remote current]

what's the motivation for that

[vivid breach]

this?

[remote current]

yeah

[vivid breach]

thats a good question

I also guessed the solutions

[remote current]

-_-

[forest token]

SEEEEEE

[vivid breach]

doing this substitution moves the three solutions to be symmetric around 0

and then confirms that those solutions are the only ones

theres also that 1 - x and x

that already suggests to create a variable thats centered around 1/2

though 1/2 + v did not work as cleanly

[compact pewter]

@jade pumice Has your question been resolved?

[jade pumice]

thx for the help guys

[compact pewter]

Channel closed

Closed by @jade pumice

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[celest jungle]

Idk how to solve these and here r the angles we have to find

11:
TUW
WUV
SUV
SUT

12:
DBF
DBC
CBE
ABE
ABF

[vale star]

For 11 notice that <WUV + < TUW =<TUV

And we know <TUV=?

[compact pewter]

@celest jungle Has your question been resolved?

Channel closed

Closed by @celest jungle

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[pale ocean]

Kind of a random q

[pale ocean]

But yk how some textbooks provide the answers to the odd-numbered q’s or wtvr? Is there a way I can find the solutions to the even-numbered problems?

[silk steeple]

the full solution manual, probably

[compact pewter]

@pale ocean Has your question been resolved?

[pale ocean]

But it’s usually not in the actual textbook, right?

Bc I can’t find it

[silk steeple]

no, those are not given in the textbook

[rigid perch]

usually these sorts of textbooks give the solutions to half the questions so that students can check their work, and won't give solutions to the other half so instructors can give them as homework problems

[compact pewter]

@pale ocean Has your question been resolved?

[pale ocean]

But the thing is my teacher wants me to fully correct my work before submitting it

U think he might be referring to only the odd problems?

[rigid perch]

if some questions have listed answers and some don't then you may only have to check the ones with listed answers

although in many cases the solution may be possible to check by calculator

[pale ocean]

How?

It’s a physics textbook

[brazen quiver]

you'll of course need to understand the problem well enough to turn it into math as a prerequisite to using your calculator

[compact pewter]

@pale ocean Has your question been resolved?

Channel closed

Closed by @pale ocean

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fair thunder]

2.3.16
completely stuck on how to proceed
i mean the first thought came to me waa to use mod but, well that cant be used

[fair thunder]

i assume it should be done with contradiction maybe

assuming it to be ordered

but i have no idea how to proceed

[kind bronze]

well lets dig into it

for a set to be ordered, you must have, for two random elements, only one of the following statements to be true: a>b, a=b, a<b

lets try this with a random number z and 0, since its pretty convenient

actually lets just pick z to be just i, since the real problem comes up in the imaginary part

if i>0, then i*i = -1 < 0 which conflicts with a property of a well ordered field, the compatibility with multiplication

compatibility with multiplication just states that if a>0 and b>0, then a*b>0

[fair thunder]

right

okay yeah

that was really nice

[kind bronze]

well we have i>0 and i>0 by assumption, but i*i=-1<0

and if you try the same with i<0, then you just work with -i and end up in the same contradiction

[fair thunder]

makes sense

right

but then

is this enough to show that it wont be ordered

[kind bronze]

yes

for a set to be ordered you must have the following 3 properties:
the trichotomy i mentioned, aka only one of the following is true: a<b , a=b, a>b
compatibility with addition: aka if a<c and b<d, then a+b<c+d
and compatibility with multiplication: aka if a>0,b>0 then ab>0

notice how the second 2 properties basically just ensure that the first property has some sound logic to it

because at the end of the day, to have a well ordered set you have to make sure that you can compare two numbers

[fair thunder]

right

okay

so we basically proved it for 1 case technically?
and that automatically makes it unordered?

[kind bronze]

yup

[fair thunder]

aahhh makes sense

thank you so much tho

.close

[compact pewter]

Channel closed

Closed by @fair thunder

Use .reopen if this was a mistake.

[compact pewter]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tulip rain]

Its scale factor 2 but I dont understand what the sentences r even asking me

[tulip rain]

@helper

<@&286206848099549185>

[upbeat gorge]

!15m pls

[compact pewter]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[tulip rain]

Mb

.close

[compact pewter]

Channel closed

Closed by @tulip rain

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[quartz yoke]

help

[quartz yoke]

im so lost

how to factor ts

i think its difference of cube

but how on earth do i make these cubed

[near jay]

There is no term without x so you can factor out x, and you can keep doing this till you have a term without x

[compact pewter]

@quartz yoke Has your question been resolved?

Channel closed

Closed by @worn sun

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[quartz yoke]

hey

[quartz yoke]

for this question when can i use the cube idenitiy?

should i foil the quadratics first then use the cubic idenity or can i use the cubic idenity with the nearest quadratic first?

[near jay]

Try to split up x^9+y^9 maybe

I’m not sure

[quartz yoke]

you know the cube identity right?

chatgpt answerd the questions, you have to pick the one cube identity falls which is the first one

but yeah

thank you nel if you were going to say somehting smart

.cancel

[verbal kiln]

I think you mean .close

[compact pewter]

@quartz yoke Has your question been resolved?

Channel closed

Closed by @worn sun

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cyan fox]

how to do secant lines

[upbeat gorge]

do you know/remember how to get the equation of a line from 2 points?

[cyan fox]

yah kinda i find slope and intercept

[upbeat gorge]

ye exactly

[cyan fox]

ok dat secant

[upbeat gorge]

as a refresher: if we have points $(x_1, y_1)$ and $(x_2, y_2)$, then the slope is $$\frac{y_2 - y_1}{x_2 - x_1}$$

[boreal girder]

χασιβ ♥

[cyan fox]

yas

[cyan fox]

how i do points why the cordinates so weird

[upbeat gorge]

right, so the coordinates need a bit more work from us

[cyan fox]

oh

[upbeat gorge]

we need to find f(1) and f(0.9), i.e. we evaluate the function at those values

[cyan fox]

oh oka so plug in

[upbeat gorge]

then you get 2 "normal" points and you can get the equation that way

[cyan fox]

yas i got it 💅

.close

[mild garnet]

Gyus

[compact pewter]

Channel closed

Closed by @cyan fox

Use .reopen if this was a mistake.

[mild garnet]

Is this correct?

[upbeat gorge]

ok W

[cyan fox]

yah show me

[upbeat gorge]

this channel isn't available yet, it's gonna lock soon

[mild garnet]

Jesus Christ lightning response

[cyan fox]

no it's wrong

[mild garnet]

So should be y^4?

[upbeat gorge]

try an available one like #help-36 :)

[mild garnet]

Ah thank you

[cyan fox]

no it should be [2e^x)^12)]

=

x/xy

and then you get 1/24e * e^4

[mild garnet]

May I ask where do you get the 12?

[cyan fox]

yah so in essence you have (1/2e^y)4

but then

you raise it by 3

so there 4*3

which gets u the 12

[upbeat gorge]

this simplification is correct

[mild garnet]

Okay thank you

[mild garnet]

Where does the 3 come from?

[upbeat gorge]

this is what i want to know too

[cyan fox]

from e

[compact pewter]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[frigid furnace]

hey guys

[frigid furnace]

How do i integrate sin^2 (2x)

[cursive harbor]

As a hint, what's cos(2x)

[frigid furnace]

um

it can be a lot of things

1 - 2 sin^2 x

@cursive harbor

[cursive harbor]

Good

Can you write sin^2(2x) in terms of cos now

[frigid furnace]

cos^2(90-2x)

[cursive harbor]

...no

Using what you just said

[frigid furnace]

oh lol mb

sin^2(2x)=(1-cos(2x))/2

[cursive harbor]

Close

[frigid furnace]

what

[cursive harbor]

The expression for cos 2x has sin²x

You want this expression to have sin²2x

So what cos do you use

[frigid furnace]

cos(4x)

ohhh

[cursive harbor]

Yes

[frigid furnace]

thanks

.close

[compact pewter]

Channel closed

Closed by @frigid furnace

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[heady spruce]

Let $ABCDE$ be an equilateral pentagon. If the pentagon is concave, and $\angle A = \angle B = 108^{\circ},$ then what is the degree measure of $\angle E$?

[boreal girder]

✪~nano-rōnin~✪

[heady spruce]

i got 216 someone pls verify

[cursive harbor]

!show please

[compact pewter]

Show your work, and if possible, explain where you are stuck.

[heady spruce]

i drew a weird diagram

[cursive harbor]

Well show it

[heady spruce]

made an asumption\

i ma redo it

ye i need help

[cursive harbor]

Well you still haven't shown what you have done

Even if it's wrong

[heady spruce]

so i drew a diagram

and i kinda assumed D and C were 54

but you can do that

cant

[cursive harbor]

My brother in christ

Send a picture please

[safe olive]

xDDD

[cursive harbor]

It is hard to help with geometry without diagrams

[cursive harbor]

Descriptions only go so far

Thank you

Let's call m_1 A and so on

We have angle A = angle B

[heady spruce]

ok

[cursive harbor]

Also god this pentagon is numbered weirdly

Who the fuck numbers a pentagon this way

[safe olive]

and the diagram isnt exact

[cursive harbor]

This isn't the diagram he drew, he just sent an image off the internet lol

[safe olive]

lol

its easy

should i say it

[cursive harbor]

Ehh I've given up, if he won't show his work there isn't much I can do

That being said however

!nosols

[compact pewter]

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

[safe olive]

huh

[heady spruce]

..

[safe olive]

so i can explain

[heady spruce]

sur

[cursive harbor]

Leaving this to you

Doing geometry with words doesn't sound very fun to me right about now

[safe olive]

because its sides are equilateral, there is two pentagone we can draw

[heady spruce]

yea

[safe olive]

one conclave, one convex

[heady spruce]

it asks for concave

[safe olive]

wait ill draw some pictures

[heady spruce]

ok

[safe olive]

so

[heady spruce]

yea

[safe olive]

because 4 points are fixed in first pentagon, and is convex, it means all angles are 108°

[heady spruce]

ofc

[safe olive]

and on the 3rd pentagon, E3 D3 C3 D3' is a deltoid, specifically a rhombus

thus D3 angle is equal to D3' angle which is equal to 108°

[heady spruce]

okay

[safe olive]

which means the D2 angle is 360°-108°=252°

[heady spruce]

oh

[safe olive]

understood?

[heady spruce]

wait

its not 252

[safe olive]

its not?

[heady spruce]

ye

[safe olive]

hmm

oh yea

because we're searching for E2

[heady spruce]

ye

[safe olive]

and because E2 = C2

[heady spruce]

E=C

[safe olive]

so 108+108+252+E+C=540

[heady spruce]

so 36

[safe olive]

yea

[heady spruce]

tsym

[safe olive]

np

[heady spruce]

i have another

Alex thinks $163$ degree angles are neat. What is the maximum number of interior angles of a convex polygon that can have measure $163$ degrees?

for this

[boreal girder]

✪~nano-rōnin~✪

[heady spruce]

do i find a polygon that has 163 deg for all angles

[safe olive]

no

[heady spruce]

then?

like experiment?

[safe olive]

this can be converted into algebra

let n be the angle count

[heady spruce]

okay

[safe olive]

then the angle sum is 180*(n-2)

[heady spruce]

mhmm

yea

so make 180 or smth

[safe olive]

no wait

[heady spruce]

k

okay..

yea

[safe olive]

so the angles are max 163

and we know that each angle is angle sum / angle count

[heady spruce]

yea

[safe olive]

which is 180*(n-2)/n

so 180*(n-2)/n < 163

now solve this

[heady spruce]

kk

0 to 360/17

i think

[safe olive]

yea but because its angle count, its a whole number

[heady spruce]

mhmm

[safe olive]

so we round down and its 21

[heady spruce]

21

yea

[safe olive]

ok now i have to eat bye

[heady spruce]

ok

tsym

[compact pewter]

@heady spruce Has your question been resolved?

[heady spruce]

do i use 30 60 90 trick

<@&286206848099549185>

[weak cobalt]

What's the 30 60 90 trick?

[heady spruce]

like one side is x another is xroot(3) and last is 2x

[tulip spear]

[heady spruce]

?

[weak cobalt]

Of the right triangle? That's not true

[heady spruce]

yea

[weak cobalt]

Do you know cos(45º)?

[heady spruce]

isn't it root(2)/2 or smth

[weak cobalt]

Yes

[heady spruce]

how do i use it?

[weak cobalt]

For a unit circle, it would be the distance from the center to the point with that right angle

So if the radius of this octagon is r, you get sqrt(2)/2 * r + 1 = r

[heady spruce]

mhmm

[weak cobalt]

Then x = 2r-1

[heady spruce]

yea

how do we find radius

[weak cobalt]

By solving this

[heady spruce]

ye

isn't it jst root(2)+2

[weak cobalt]

Yes

[heady spruce]

2root(2)+3?

[weak cobalt]

Yes

[heady spruce]

tsym

.close

[compact pewter]

Channel closed

Closed by @heady spruce

Use .reopen if this was a mistake.

[compact pewter]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sage glen]

ok i got a test trmrw

[sage glen]

and im completely lsot

its 1am

i cant think

can someone nudge me in the right dreicton

direction

ik t=s/d

do i uhh

wait

[hexed crow]

the subquestion itself hints at the form of the expression the time for cycling should take.

[kind viper]

why are you doing math at 1 in the morning?

[sage glen]

i gotsa test tmrwinnit

i didnt see we had this wokrsheet

[kind viper]

then SLEEP!!

for the love of god sleep.

[sage glen]

LET ME FINISH this one q and then i sleep y

[kind viper]

if you try to cram now, you will be sleepy and tired on exam day.

[hexed crow]

gods, you can't even type straight right now.

[sage glen]

just one question

i swrear

i thjoght i finish

d

FINSIHED

FINISHED

reviewing

[near jay]

Go to sleep bruh

[sage glen]

lads this is just 5 minutes

max

[vale star]

What have u tried?

[sage glen]

nothing is coming into my head

[hexed crow]

^

[sage glen]

let me see

[kind viper]

his running speed is x km/h and the cycling speed is 10 km/h more than that

[sage glen]

ait no

[hexed crow]

is the cycling distance 12km?

[sage glen]

im close

26

[hexed crow]

you're one step closer, but not quite there, after changing that.

[kind viper]

the brackets around 12/x are unnecessary btw.

[sage glen]

iim not feelin this

[sage glen]

ye ik

[kind viper]

ok so this is an expression for the total time

now how much is this equal to?

[sage glen]

2.8

[kind viper]

yes

[sage glen]

uis thast it

holy hell

some serious changes are needed

to my studying

yep

thank u guys

bro

i need to sleep

i

slacked on this subject

bc the stuff we did in clas WERE SO ESY

.close

[compact pewter]

Channel closed

Closed by @sage glen

Use .reopen if this was a mistake.

[sage glen]

thank you all som uch

goats

[compact pewter]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[arctic cliff]

[
M \mid (A - B) ;;\Rightarrow;; A - B = K_{1}M.
]

[
M \mid (C - D) ;;\Rightarrow;; C - D = K_{2}M.
]

Now, adding them:

[
(A - B) + (C - D) = K_{1}M + K_{2}M.
]

[
A + C - (B + D) = (K_{1} + K_{2})M.
]

[
\Rightarrow ; A + C = (K_{1} + K_{2})M + (B + D).
]

[boreal girder]

x

[arctic cliff]

is this ok or no

how to proceed

to prove it

[thorny kestrel]

it's good

[arctic cliff]

.

[mild sky]

a \equiv b mod m so a-b is a multiple of m

or a = mk + b

for some k

likewise for c,d

[arctic cliff]

.

[mild sky]

yeah saw that now

[arctic cliff]

so what now

[mild sky]

you are done

[arctic cliff]

?

[mild sky]

you showed (a+c)-(b+d) is a multiple of m

so they are equal mod m

[arctic cliff]

ok

what about second part

we just multiply?

[mild sky]

yep

[arctic cliff]

wait wont we also have ad and bc

what about tjem

can you show me how to do it

pls

@mild sky

[compact pewter]

@arctic cliff Has your question been resolved?

[mild sky]

sorry for taking my time

a = mk + b

c = mp + d

ac = (mk+b)(mp+d)=m(mkp+kd+pb)+bd

[arctic cliff]

oh

(mkp+kd+pb) is an int

so proved

correct?

[mild sky]

yep

[arctic cliff]

okok

thanks bro

appreciate it

.close

[compact pewter]

Channel closed

Closed by @arctic cliff

Use .reopen if this was a mistake.

[compact pewter]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[drifting drum]

the gradient at y = pi/4 is 8

so the gradient of the normal should be -1/8?

why is the answer this?

i got y = -x/8 + (sqrt(3) + pi) / 4

[kind viper]

note that your equation is x=g(y) and not y=f(x) as it normally is

so the roles of x and y are switched

[drifting drum]

hmmmm

[drifting drum]

so why does the mark scheme use the y = mx + c formula

[kind viper]

they find dx/dy

the gradient of the tangent is dy/dx

and its negative reciprocal is therefore -dx/dy

so they put -8 as the gradient

[drifting drum]

.close

[compact pewter]

Channel closed

Closed by @drifting drum

Use .reopen if this was a mistake.

[compact pewter]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[drifting drum]

can anyone spot where i made a mistake

i can't see it

also yes i ran out of paper lol

[potent berry]

different question?

[potent berry]

ok

what is any of this

like

any of it

what

[drifting drum]

nope

[potent berry]

what is this

why is it u

[drifting drum]

we have dy/dx, i'm tryna find the second derivative

[drifting drum]

that's how i write my v's

[potent berry]

why is this the derivative

[drifting drum]

dv/dx

[potent berry]

okay what the fuck is v

[potent berry]

why is the next line a y

[potent berry]

oh fucking shit

ok

that makes more sens

[potent berry]

are we sure this is right

i dont see any steps

[wary mulch]

wheres the question

[drifting drum]

i think so - chain rule: 1 * 6x * 1/2 * (x - 1)^-1/2

[potent berry]

and are we just ignoring the 6x

[drifting drum]

how

1/2 * 6x = 3x

[potent berry]

okaaaaaaaay

[potent berry]

• what?

you do product rule first

[drifting drum]

yeah ur right

.close

[compact pewter]

Channel closed

Closed by @drifting drum

Use .reopen if this was a mistake.

[potent berry]

????

insane

okay

[drifting drum]

how is that insane

[potent berry]

werent you doing integration the other day

[drifting drum]

yes

[potent berry]

proceeds to not know product rule?

what is blud doing

[drifting drum]

i know it i just didnt do it

because thats what happens when you make a mistake

[potent berry]

eh sure

[compact pewter]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[chrome quail]

,rotate

[chrome quail]

plotting straight line

using a table

is this correct

[hexed crow]

x = -2 is wrong.

[chrome quail]

how

[bold sigil]

2-3(-2)

What does that give you?

[hexed crow]

you have $y = 2 - 3x$, so when x = -2, you should have what impulse said, not merely $2 - 6$.

[boreal girder]

Lute

[chrome quail]

4

[bold sigil]

How come?

[chrome quail]

-3(-2) is 6

2-6

[bold sigil]

Uhh

Exaclty

Its 6

Not -6

Why are you taking negative 6

Negative × negative=positive

[chrome quail]

no i mean 2-6 is 4

wait

-4

thats how come

[bold sigil]

I want you to reflect on this

-3 × -2 is 6

NOT -6

[chrome quail]

ok

[bold sigil]

That gives you 2+6

[chrome quail]

so its 8

[bold sigil]

Yep

[chrome quail]

so below -2 is supposed to be 8

[hexed crow]

x = -2 gives y = 8, yes.

[chrome quail]

so other than that the answer is good?

[bold sigil]

Pretty much

[chrome quail]

in the x value i saw someone swap 0 for 1

[hexed crow]

as long as you have at least two points, you can plot a straight line.

doesn't really matter which two points.

[chrome quail]

wym by 2 points

[hexed crow]

each x-y pair here is a point that you will use to plot your graph. agreed?

[chrome quail]

yes

[hexed crow]

so any 2 points is sufficient to plot your graph. be it x = 1, x = 0, x = 100, etc.

so there's nothing wrong with using x = 1 instead of x = 0.

but there's also nothing wrong with using x = 0, if that is your concern.

[chrome quail]

ok ty

[hexed crow]

!done

[compact pewter]

If you are done with this channel, please mark your problem as solved by typing .close

[chrome quail]

wait

[hexed crow]

sure. do you have anything else?

[chrome quail]

im plotting it on the graph rn

[hexed crow]

alright. I'll be on standby for any questions.

[chrome quail]

,rotate

[chrome quail]

are these numbers supposed to be closer to each other

i seperated them by 2cm

[hexed crow]

your scale between the two axes are not equal and thus weird, but since they are even between themselves, I think there isn't too much of an issue.

[potent berry]

thats one cursed leq

[hexed crow]

best to make them uniform though.

[chrome quail]

you mean together

[near jay]

L

[hexed crow]

no I mean, like you're doing one big box = 1 on the x axis, but on the y-axis you're doing half a big box = 1.

either you make it so that half a big box = 1 on both, or one big box = 1 on both.

[chrome quail]

aight

this what i got after being plotted

[hexed crow]

the line looks off on the top point, and the two axes are still uneven, but otherwise I'd give this a pass.

[chrome quail]

lets say all of these are blank

how do i find out the x values

ik how to find out the y but not the x

[hexed crow]

you're allowed to take any x-value you wish.

x is an independent variable here.

[near jay]

You can fill in one given the other

[hexed crow]

of course, since you have limited graph space, it would be prudent to not pick an x-value so far out, it'd take you ten years to get enough paper to draw the graph.

(in short, keep it simple.)

[chrome quail]

ok

but i was told to follow this when finding out the x

it can only follow between -2 to 4 i thin

[hexed crow]

then take any x-value between those two.

[chrome quail]

so can i do x = -2, -1 , 0

[hexed crow]

absolutely, if you wish.

[near jay]

In the future, you should try to make the horizontal line on your $\le$ shorter

[chrome quail]

ok

[near jay]

Should be same length as the <

[chrome quail]

aight

[near jay]

And make sure they point < not L

[chrome quail]

so what ur tryna say is that it doesnt matter what x values i use as long as it becomes a straight line on the graph

[hexed crow]

by the nature of the function you will get a straight line no matter what points you choose.

[chrome quail]

ok

[near jay]

That’s why it’s called linear (kind of)

If you chose every possible point, you would get a line

Lines are actually just a collection of every point the formula gives basically

(Depends how you define a line)

[hexed crow]

the proper definition would be the set of all points in the space that satisfy the equation, but I don't want to overwhelm OP right now.

does OP have anything else?

[chrome quail]

alright

one more thing

[hexed crow]

sure. what is it?

[chrome quail]

theres another question i need to see if its correct

[hexed crow]

normally it is suggested to separate channels for different questions, but you may send it here.

[chrome quail]

,rotate

[hexed crow]

,rccw

[hexed crow]

well...

[chrome quail]

shi mb

[hexed crow]

this too.

[chrome quail]

i didnt double check

[hexed crow]

only x = 3 is correct.

[chrome quail]

is this one supposed to be -2

[hexed crow]

yes.

[chrome quail]

this shits hard asf

[hexed crow]

please take it slowly.

[chrome quail]

actually i got it

thanks

.close

[compact pewter]

Channel closed

Closed by @chrome quail

Use .reopen if this was a mistake.

[compact pewter]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fossil sage]

My method was to split the triangles into two:

1/2(50)(65)Sin(130) for the upper triangle

for the lower triangle I found AC through the cosine rule, then rearranged pythagoras to find AD. I then did 67 (which was AD) multiplied by 80 all over 2. I’m getting 3900 and something but the markscheme says 3360. Any help would be appreciated.

[kind viper]

then rearranged pythagoras to find AD.
did you assume that angle D was 90°?

[fossil sage]

yes

but even then I did it without assuming it as 90

using the area formula for non right angled triangles

and still got an answer that wasnt on the markscheme

[kind viper]

67*80/2 supposes angle C is right instead, which it still isnt

err

no wait hold up i confused myself.

can you quote the area formula you are using

[fossil sage]

for the upper triangle

1/2abSin(C)

for the lower triangle

1/2ab

[kind viper]

ok but... where do you see a right angle in ACD tho

1/2ab
for this to represent the area, either a and b have to be a base and a height, or they have to be two sides that meet at a right angle

[fossil sage]

i assumed ADC was right angled

perhaps thats wrong

but even when i didnt assume it

[glass cipher]

https://cdn.discordapp.com/attachments/632070496594165790/1383930282012442755/togif.gif

[fossil sage]

i did 1/2(AC)(CA)Sin(52/2) and still didnt get the answer

[kind viper]

??

[kind viper]

and since when do we know AC bisects angle C

thats another unjustified assumption you're making