help-43

[near swan]

I've never made a boundary condition before, it was always just given to me so I'm a little confused

and I can't imagine what a 3D wave equation is graphically

[compact pewter]

@near swan Has your question been resolved?

[near swan]

<@&286206848099549185> any thoughts are much appreciated

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[quartz yoke]

For problem 8, at the bottom of the LHS it says “substituting b = 1 in equation(3) gives” i am not sure why they substitue 1 for b, and what the purpose of that is

[placid bridge]

,rccw

[kind viper]

well prior to this step you found b as 1

so yknow like. it's just replacing b with its now-known value

[lavish gull]

you found b and now you wanna find a, but the other equation has a and b

so you put the known value of b back in there

otherwise you can't solve for a

btw, is this Bird's Comprehensive Engineering Mathematics?

[quartz yoke]

oh im tapped 😭 i read it all EXCEPT the part they found b as one

[quartz yoke]

yeaa it is its the normal engineering one

[lavish gull]

aye

[quartz yoke]

engineering mathematics

[lavish gull]

not bad. i went with James and Dyke myself

but gl with the rest of the book

[quartz yoke]

haha tysm

[lavish gull]

any other questions?

[quartz yoke]

not for now but ill deffo open another channel if i get another

tysm

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[quartz yoke]

So im thinking of V as R²
And The subspaces would be lines in R² which contain 0
The intersection would always be 0 if V1 /= V2
And if V1 = V2 their intersection would also be V1
in both cases subspaces of R²

[kind crane]

that's a correct example of what's happening yes. the proof shouldn't assume so though

[quartz yoke]

hmmmmmm

Imma think about i again and open channel again

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[unkempt sail]

https://www.youtube.com/watch?v=iWpLWM1DhMU&list=PLOzRYVm0a65fh_rqHrLelra4VgaLhE43a&index=2
start from timestamp 22:22
I can't quite write this problem, since I myself havent been able to grasp what the conditions are given. Can anybody provide some insight on how to solve this question? the prof says converting this problem from 2D to 3D helps immensely, but im not sure how.

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[open phoenix]

how is the speed at both points the same. the question asks about DEceleration why does the guy in the video say that the speed is the same at both points. at point O its 0 and at L its 54m/s and at M its 30m/s. i can link the video if needed

[subtle helm]

the speed is not the same at both points

but acceleration is

[open phoenix]

so the guy in the video is mistaken. as u can see in the image he wrote that v(ol) = v and u(lm) = v

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[subtle helm]

.reopen

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✅

[subtle helm]

@open phoenix v is usually for final velocity whereas u is usually for initial velocity

so the guy in the video is not mistaken

[open phoenix]

so he's basically saying that at the END of ol, the velocity is equal to the STARTING velocity of LM. correct?

[subtle helm]

yup

[open phoenix]

thank you

.close

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[open phoenix]

.reopen

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✅

[open phoenix]

can i ask you to explain something to me. like the concept itself. SUVAT. when do i know which formula to use. i understand each 1 has a factor thats missing like v=u+at doesnt have s but how do i know which 1 to use when i have all the factors

[subtle helm]

wdym u have all the factors?

[open phoenix]

i have all the values for s,u,v,a and t

[subtle helm]

what are u even solving at that point 😭

[open phoenix]

listen bro i know im washed at this but i need someone to explain and help me solve. is there a group or server or anything really where i can find someone to help me understand in a vc

[subtle helm]

the physics server, prolly?

[open phoenix]

this is maths tho

[subtle helm]

kinda

[subtle helm]

but if u have s,u,v,a,t what are u even solving for

[open phoenix]

so i can find someone who'll join a vc and help me there?

[open phoenix]

good question...

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[silk phoenix]

i got no idea

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[sonic oxide]

hi

[sterile crag]

hi

[stone jackal]

Hi, do you have a math question?

[lost jackal]

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@sonic oxide Has your question been resolved?

[kind crane]

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[sonic oxide]

whatz 5000 + 6899

[stark marsh]

,calc 5000+6899

[boreal girder]

Result:

11899

[open plaza]

mf has discord but not google's calculator

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[lament token]

can someone please explain how we got the S(deviation angle as two theta

[lament token]

(its a parallelogram

the 3 other angles are 2 theta 90 and 90

we have to find the angle on the right's supplementary angle

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@lament token Has your question been resolved?

[quartz yoke]

sum of internal angles of quadrilateral equals 360

as it is parallelogram opposite angles are equal

[lament token]

yea but we got the supplimentary angle of the opposite angle to be found

and that came to be 2theta

[quartz yoke]

i cannot understrand your drawing

wait

is this?

and then u need to find delta

[lament token]

yes

but they found delta to be 2 theta

and the other to be prolly 180-2theta

[quartz yoke]

delta is gonna be 180 - 2theta

[lament token]

yeaa

thats what i figured too

[quartz yoke]

because it's the supplementary of 2 theta

[lament token]

prolly the thing done here is wrong

yeaa

right

thanks

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[solar abyss]

hi am I allowed to ask for this much help :' Where I live theres a typhoon and we just started school, classes were cancelled for a whole week so our teachers r js sending us work to do but theres no explanation or anything and ion get the math-

[solar abyss]

if anyones willing to help me with this much work, pls and thankyouu :'

[flint wing]

which questions

[solar abyss]

I have to answer 1-6

Im starting with 1a, b, and c

[flint wing]

ok well 1 seems simple enough so what have you tried for 1a,b,c

[solar abyss]

thats the thing, we werent given any instructions or formulas to solve it

so I honestly have no idea what to do

[wanton ferry]

how do you find the value of f at a point?

[solar abyss]

I mean I tried f(-1)=x^3+1 but idk if thats the right start

for 1a

[wanton ferry]

what is the definition of a function?

[flint wing]

what does f(-1) tell you to do what does it mean

[solar abyss]

a function is like a rule and f(x), x is the rule. In this case -1 is asking me to multiply something

??

[flint wing]

no f(-1) means wherever you see an "x" you replace it with -1

[solar abyss]

you replace "x" with the given number rightt, thats what I tried

[spark folio]

thats close enough, but not entirely right. You can indeed think of f(x) as a rule at your stage. The rule is, for any value of x, you have to change it according to the "rule" mentioned by the definition of the function, which in this case is x^3 + 1 (cube it and add 1 to it)

[flint wing]

and what did you get?

[spark folio]

So, when you are asked to find the value at x = -1, you can put this value for x in the expression at all places where there is x

[solar abyss]

so I have to cube and subtract 1 from (-1) which is x

[spark folio]

oops, sorry mb I didnt read it properly

the function is f(x) = x^3 + 1

so you have to add it and not subtract

[solar abyss]

alrr

[spark folio]

I changed what I wrote accordingly

[solar abyss]

f(-1) = x^3 + 1
f(-1) = x + 1

op

[spark folio]

no, you have to replace x^3 by (-1)^3

[solar abyss]

OHH

okay okay

[spark folio]

coz you are given x has a value of -1

[solar abyss]

holon quick question, so if there are multiple x's, u replace the x with the given number and in this case it's -1?

[spark folio]

yea, for every occurance of x, you replace it with its given value

[solar abyss]

mkayy

f(-1) = (-1)^3 + 1
f(-1) = -1+1
f(-1) = 0

thats that?

[spark folio]

uhh, no

yea

[solar abyss]

mb

[spark folio]

now its correct

[solar abyss]

oohh easier than I thoughtt

okeyy

[spark folio]

how about 1b now?

[solar abyss]

f(2) = (2)^3 + 1

f(2) = 8 + 1
f(2) = 9

ayee tyty :))

thenn for 1c is it set up as
f(-1) - f(2) =

[spark folio]

well, generally the stuff is flipped

if you are asked between difference in two quantities a and b, then it is usually calculated as b - a

So, in this case it would be f(2) - f(-1)

[solar abyss]

ohh mk

f(2) - f(-1) = f(3)

[spark folio]

you cant do it like that. You know the actual values for f(2) and f(-1) from the parts 1a and 1b

use those

[spark folio]

there are very few cases when this would be correct, but in general, this is not true at all

[solar abyss]

OH HAHAHA okay mybadd 🥹

the answer would js be 9 then right or would it be f(9)

[spark folio]

just 9

[solar abyss]

gotchuu

f(2) - (-1) = 9

[solar abyss]

for 2 the input is the rule and the output is the value

[spark folio]

thats good enough for personal understanding, but in mathematical literature, these have specific names

So, no

[solar abyss]

mmm okayy

[spark folio]

Maybe, you can try to find it in your textbook

it would surely be mentioned there

[solar abyss]

I'll look through

oh alrso the input is the domain and the output is the range

[dusky pecan]

Filipino?

[solar abyss]

yeahh

[dusky pecan]

Kabayan

Nasagot naba?

[solar abyss]

ayee :0

[solar abyss]

yeah im tryna figure out 3 tho

[dusky pecan]

Functions ah

[solar abyss]

yepp

[dusky pecan]

Number 3?

[solar abyss]

yeah im trying to figure out how to find the domain

[spark folio]

you dont have to find the domain tbh

just check for x=5

[solar abyss]

oh :'

so the only function with 5 in the domain is the one in the middle?

I assumed that one of the others would also have 5 in the domain if u had to calculate it and the answer had a 5 or smthnn

I just wasnt sure so I looked thru the book and still dont get it-

[dusky pecan]

Wait

[spark folio]

well, no

[dusky pecan]

Anong part kana ba?

A or B?

Sa number 3

[solar abyss]

A

[solar abyss]

ohh alrr-

[dusky pecan]

Okay, now how do you define domain for you?

[spark folio]

All you have to check if the number is in domain is if you can evaluate the expression of the function with that specific value

If you get a result, then yes, it is in the domain

otherwise its not

[dusky pecan]

Mhm

Right

[solar abyss]

ohh mkayy

[dusky pecan]

Sa part A

Ano sagot mo

[solar abyss]

g(x) = x-5/x

[dusky pecan]

Okay good

Now paano mo isosolve yan for part B

Ano ung stock knowledge mo para dyan

[solar abyss]

when it asks find the value of the function at 5, am I supposed to find x

and maybe it has smthn to do with transposing or cancelling out(??)

[spark folio]

no, all you gotta do is put x = 5, similar to how you did it in q1

[dusky pecan]

Noo

[solar abyss]

OH alr

[dusky pecan]

Substitute 5 on it

You'll get the domain

[solar abyss]

mkayy

[dusky pecan]

I'm wondering what could be the answer in the item 4

It's "one" elements right

[solar abyss]

so the answer which is the "range" is 5?
g(5) = x-5/x
g(5) = 5-5/5
g(5) = 0

[dusky pecan]

No

5-5 =??

0 right?

[solar abyss]

yep

oh

ops

[dusky pecan]

Try again

[spark folio]

well, range and domain are sets. So technically, the answer is not called range, but rather an image. But thats more maths jargon that you need not be aware of at this stage

[solar abyss]

oh alr alrr-

[spark folio]

but its important to know that its not range, coz that may confuse you later on

[solar abyss]

g(5) = x-5/x
g(5) = 5-5/5
g(5) = 0
is that correct na :'

[spark folio]

yea

[dusky pecan]

You got it

[spark folio]

now do the same for f(x) and h(x) as well

[dusky pecan]

@spark folio whats your answer in item 4?

The blank one

[spark folio]

||one||

[solar abyss]

and if the answer is 5, that means it has 5 in their domain?

oh wait

understood that wrong nvm

[spark folio]

answer can be anything, doesnt have to be 5

[solar abyss]

mm alr

for f(x) = x^2 - 3x
its f(5) = -5

[dusky pecan]

No

Substitute 5 to the function

[solar abyss]

f(x) = x^2 - 3x
f(5) = (5)^2 - 3(5)

f(5) = 10 - 15
f(5) = -5

[spark folio]

(5)^2 = 10???

[solar abyss]

OH

MB

f(x) = x^2 - 3x
f(5) = (5)^2 - 3(5)
f(5) = 25 - 15
f(5) = 10

[spark folio]

yea, this is correct

so, whats the conclusion?

[solar abyss]

I also did the "h(x) = ..." one and

[solar abyss]

do they have to = 0?

[spark folio]

no

the question is whether 5 is in the domain, so your conclusion should be about that

[solar abyss]

I have three answers
g(5)= 0
f(5)= 10
h(5)= √5

[spark folio]

are you sure about h(5) value?

[solar abyss]

it doesnt go any lower tho unless it includes decimals

[spark folio]

why is your x - 10 equal to 5 tho?

5 - 10 shouldnt be 5

[solar abyss]

oh its -5

[spark folio]

you really really really need to double and triple check your basic arithmetic calculations ngl

you must be losing marks left and right with these silly mistakes

[solar abyss]

ikk this is why I need help w math, I need to get my understanding w these things right :'

im working on it

so my conclusion is that the only function with 5 in their domain is g(x) = x-5/x and the value of the function at 5 is 0(?)

[spark folio]

what? what happened to f(5) and h(5)?

you have $f(5) = 10$, $g(5) = 0$ and $h(5) = \sqrt{-5}$

[boreal girder]

Bacter10Fr4g

[spark folio]

why do you say only g(x) has 5 in the domain?

[solar abyss]

ohh- then why is it asking for the functions that "do" have 5 in their domain as if some of the others dont

I have a feeling theres a misunderstanding on my part

[spark folio]

coz some of these dont

[solar abyss]

none of them have 5 tho aside from the x itself being replaced by 5

mb I feel rlly dumb rn :'

[spark folio]

A number is in the domain of a function when it can be used as an input to the function without causing any undefined results. So, you need to check which of these three are defined numbers and which yield an undefined value

[solar abyss]

h(5) = √-5 seems to be undefined

[spark folio]

yep

So, you have an answer for g(x) and h(x). What about f(x)

[solar abyss]

10 and 0 are the only defined numbers so the only functions with 5 in their domain is the first 2

[spark folio]

[solar abyss]

aaaaaa I get itt okay

and then b is just asking for the answer we got from using 5 as its domain

[spark folio]

yep, you already did that

[solar abyss]

iciccc

okay

I think I got confused cuz earlier I thought one of u said g(x) = x-5/x is the only one that has 5 in its domain lmao

thankuuu tho I get it now

[spark folio]

npnp

[solar abyss]

for num 4 I have to figure out if y can be a function of x

would that be like f(x) = y

[spark folio]

yea, its supposed to be like that

[solar abyss]

alrr

[spark folio]

you should try and find the rule about how to define a function in your book

[solar abyss]

mhmm

f(x) = x^2 + 4 is the formula

does it apply to all of the numbers in our case

[spark folio]

Noo, you dont have to define the function yourself

you just need to find what conditions should a valid function satisfy

[spark folio]

that seems like you did too much

[solar abyss]

it said that in the book :' A function f is defined by the formula f(x) = x^2 + 4

[spark folio]

(also, you will learn later on there is no unique formula to define function based on few values of x and y like this)

[solar abyss]

oh alrightt

[spark folio]

thats more like an example rather than a condition

[tame quarry]

it could be formula. example

[spark folio]

well, my point was, its irrelevant to the problem you have at hand

[solar abyss]

does f(b) - f(a) have anything to do with num 4

[spark folio]

not really

What is the exact definition of a function you have in your textbook? Something like A function is a mathematical relation that blah blah

you know, something that you answer when someone asks you to describe what are functions in maths

[solar abyss]

"A function is a rule. To talk about a function, we need to give it a name. We will use letters such as f, g, h, . . . to represent functions. For example, we can use the letter f to represent a rule as follows:
"f" is the rule "square the number"

[spark folio]

oof, that doesnt seem like a rigourous mathematical definition

sad

idk now how to tell you, except directly say the answer

[solar abyss]

uhh

hm

[spark folio]

but fair enough, since its a definition, its not like its any different from a book telling you or me telling you it

Have you heard of terms such as one-to-one, many-to-one?

[solar abyss]

yeahh

[spark folio]

good

so functions can be one to one or many to one relations

so like, for a given value of x, f(x) is gonna be unique

[solar abyss]

mhmm

[spark folio]

that is to say, it wont be one-to-many kind of a relation

[solar abyss]

so in our problem, (i) is a rule that assigns to (ii).
or does it mean in (i), x is A and y is B

[spark folio]

second

[solar abyss]

ah okok

[spark folio]

all the x's are A, and the y's are f(x) which form B

A is the domain, and B is the range

[solar abyss]

so if I were to write this down, it would be
f(x) = y
or f(1) = 5

for the first one

[spark folio]

yes

something like that. Its just that you have to determine whether the relation is a valid function

[solar abyss]

how do I do/calculate that-?

[spark folio]

well, you have the definition. You gotta see if the pairs (x,y) are according to the definition

is the corresponding y unique for each x

[solar abyss]

oh so I can say (ii) isnt a function because it has two ones under x

[spark folio]

well, your answer is correct, explanation is not

[solar abyss]

and (i) is a function because they're all unique numbers

[solar abyss]

alrr

[spark folio]

its not a function coz even if x = 1 is mentioned twice, the reason its not a function is coz the two times it maps to a different value of y. The y's being different is the reason its not a function

[solar abyss]

oh so if both of them had 5 as y, it could still be a function

with x being 1 still

[spark folio]

yep

[solar abyss]

alrrr

I think I can answer 5 thenn

[spark folio]

simple way to remember is if given some x, f(x) is ambiguous, then the relation is not a function

[solar abyss]

ah alrr

notedd

say if
x y
1 5
2 5
3 6
4 8
it doesnt matter that y has two of the same numbers, it depends on the x solely?

[spark folio]

yep

[solar abyss]

alrrr

gotchu

[spark folio]

there are constant function, so an infinite number of x-values would have same y

[solar abyss]

alrrr

I see

js double checkingg

and then 6 is my last questionn

for 5a, yes. 5b, no

num 6. multiply by 3, then subtract by 5 would be
f(x) = (3) - 5

I have a feeling thats wrong :'

[spark folio]

yea

wheres the x?

[solar abyss]

hm?

f(x) = x(3) - 5

[spark folio]

yea, this looks alright

tho i'd write it as f(x) = 3x - 5

[solar abyss]

oh yeah that makes more sense

alrrr thankyouuu!! I appreciate the help so muchhh

[spark folio]

np

good luck

[solar abyss]

I wish I could thank u somehow but yeaa, cant do much online. But u really helped me understand, thankyou is all I can say sadlyy :'

[spark folio]

oh yea, I forgot to say, take care in the typhoon

[solar abyss]

thankyouu

will do

I really really appreciate it tho. U take care as well wherever u are

[spark folio]

no clue how the stuff is rn for you, but if it needs schools to close, i think the situation requires taking care of oneself

[solar abyss]

we got asynchronous classes :'

[spark folio]

damn those are not good for learning from my covid-time experience

[solar abyss]

yeahh really isnt in my opinion

im gonna close this now so other ppl can use it :)) see u wheneverr

.close

[compact pewter]

Channel closed

Closed by @solar abyss

Use .reopen if this was a mistake.

[compact pewter]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[kind wind]

@pine thicket

[compact pewter]

Please don't occupy multiple help channels.

[kind wind]

so

[pine thicket]

hi

[kind wind]

wait

the formual

Q=cv

lets discuss it a bit

it is found

Q is proportional to V
that the more charges add up greater will be the potential

in the plate being charged

or is it

the potential difference

what does v here represent

[pine thicket]

V represents pd

[soft bobcat]

Potential difference across the capacitor

[kind wind]

hmm

the more charges add up

greater the potential diff

how can it be

[pine thicket]

do you agree that elec field is directly proportional to charge?

[kind wind]

well it kinda make

sense

but i wanna know ur opinion

[solemn matrix]

this is a help channel

[kind wind]

that electric field is stronger where more charges

[solemn matrix]

not #math-discussion 😭

[kind wind]

huh

[pine thicket]

thank you for your input

[kind wind]

wait is this where

we talk such things

[solemn matrix]

this is your help channel

😭

not a discussion place

[kind wind]

but im asking for help

nah

[pine thicket]

do you know the derivation of Q = CV?

[solemn matrix]

are you discussing or are you asking for help 😭

this does not make any sense at all

[kind wind]

no im actually asking for help

its theory based

but

yeah

[solemn matrix]

alr

[kind wind]

well

its not rigorous

for sure

Q being proportional to pd and c being added as proportionality constant

id like to know more rigorous def if u know

[pine thicket]

there is a proper proof

do you know the field of an inf thin plane sheet?

[kind wind]

yuh

[pine thicket]

what is it?

[kind wind]

E=sigma /2 epsilon nought

but i just looked in book

i had done this weeks before

but yeah

[pine thicket]

sigma = Q/A

[kind wind]

wait

what

ohhh

thats

surface

charge

density

[pine thicket]

yes

the more the charge, the more sigma, the more E, the more pd

[kind wind]

man

ok

i had to get them sistaz the mobile

[kind wind]

lemme digest

the more the charge

more the sigma

means more charge concentrated in

an area

greater the magnitude of charge more the E because

E= Q/4pie epsilon nught r^2

E due to point charge

am i correct

???

[pine thicket]

2

and capacitor plates are usually rect so leave it with A

[kind wind]

huh

[pine thicket]

rectangle

[kind wind]

wdym

by A

for parallel plates rect capacitors

teh electric field is given by

[pine thicket]

A is plate area

[kind wind]

E=sigma/epsilon

[pine thicket]

instead of pi r^2 use A

[kind wind]

ohhhh

ohh yeah

right

lol

wait

but

r is the distance na

but that E is for point charge Q

for the capacitors

[pine thicket]

India?

[kind wind]

E= sigma/epsilon nought

[kind wind]

nepal

u

??

[pine thicket]

India

[kind wind]

W

[pine thicket]

lol

[kind wind]

i know few hindi

bhenchod

pakad

and some cid memes

[pine thicket]

lmao

i also know some nepali

momos

im sorry

[kind wind]

nah

we live by it

we love it lol

just had yesterday

[pine thicket]

oh lol

[kind wind]

buff momos and chowmein with roasted potatoes

yummy

ok but lets stop

it here

lol

[pine thicket]

loll

[kind wind]

!!!!

so

[pine thicket]

btw crunchy spring rolls are 🐐

[kind wind]

pd across plates that is increases as charge accumulates in a plate

butt

hoooow

i wanna know ur opinion

[kind wind]

that

[pine thicket]

.

[kind wind]

as E increases pd also increases

[pine thicket]

yes

[kind wind]

why is that

[pine thicket]

do you know that C = epsilon_0 * A / L

[kind wind]

nooo

[pine thicket]

oh

np

[kind wind]

u were talking abt some

rigorous proof

[pine thicket]

ill write k instead of E_0

[kind wind]

huh

[pine thicket]

epsilon 0

[kind wind]

oh

[pine thicket]

not k

o

E = Q/2Ao

now dV = - E dx

[kind wind]

say dx

[pine thicket]

if you integrate from 0 to L

where L is the distance between capacitor plates

you get

[kind wind]

ok

V=-Ed

[pine thicket]

V = QL/(2AO)

[kind wind]

what da

ohh

yeahhhh

yeah

[pine thicket]

for a give capacitor A and L are const

O and 2 are already const

[kind wind]

buuuuut

[pine thicket]

so V increases with Q

[kind wind]

electric field in a capacitor should be given by E=sigma/o no??

[pine thicket]

if you take all the to the other side

[pine thicket]

yes mb

V = QL/(AO)

[kind wind]

yuh

now we talkin

[pine thicket]

Q = V AO/L

and Q = CV

[kind wind]

ahhhhh

[pine thicket]

so noww you derived this

[kind wind]

wait

[pine thicket]

.

[kind wind]

lemme digest it

[pine thicket]

im sure you will be doing this soon in your class

[kind wind]

no

we will not do it

[pine thicket]

12th?

[kind wind]

because it was in grade 11

im in 12th

[pine thicket]

oh

we do this in 12th

[kind wind]

idk if it is there

tbh

but regardless

lemme digest

[kind wind]

A again A???

from where

[pine thicket]

i wrote sigma as Q/A

[kind wind]

ahhh

ure right

give me a sec

ohhh

yuhhh

right

c=A epsilon/d

where A epsilon and d are constants

[pine thicket]

thus C is a capacitors property

[kind wind]

so for a given capacitor with the following constants
the capacitor will have constant capacitance for a given area, d and permitivity

[pine thicket]

yess

so Q = CV

hence Q up, V up

[kind wind]

right

and it comes st from the electric field and potential difference relation of E=V/d

so V is essentially pd

no doubt

[pine thicket]

yeah

[kind wind]

so as charge increases V increases

yuhhh

dang

bro

are u down with one more

question

[pine thicket]

💀

[kind wind]

or could u accept the req

we'll discuss like this afterwards

learned so much talking to u

[pine thicket]

lets just get it over with

i dont think ill be online again in a while

[kind wind]

okkaaaaay

i dont plan to sleep today

if we go down like this

[pine thicket]

its only 6:40 pm rn

[kind wind]

6 52 here

12 minutes diff

in parallel combination of capacitors the potential difference is same across the whole system

why is that

[pine thicket]

15 it was 6:37

i rounded

[kind wind]

oh

[pine thicket]

?

[kind wind]

in system of capacitors

i meant

all the capacitors having

same

pd

bruv you there

shall we move to private

[pine thicket]

something like this?

its because of the battery

[kind wind]

yeah

similarly what gives series combination different pd

across each capacitor

[pine thicket]

in series combination

each capacitor has same charge

so pd depends on their C

[kind wind]

ahhhhhhh

yeah yeah

makes sense

V=Q/C

[pine thicket]

yess

[kind wind]

c makes the difference

yeah

but in parallel

??

the charge given by the current distributes over three diffrent wires

its uncertain that

[pine thicket]

yeah

[kind wind]

each wire gets

same magnitude of charge

[pine thicket]

but pd is same becuase of bettery

[kind wind]

why is that

[pine thicket]

V is EMF

[kind wind]

the emf thing is just after

the capacitors

so

im not that strong in that

[pine thicket]

emf just means the batteries pd

[kind wind]

yuhh

sooo

how does the battery determine

pd of the capacitors

and also

that it remains the same for all the capacitors

[pine thicket]

how battery works is a checmistry thing

and we havent done it yet

[kind wind]

no abt the pd

why is the same pd shared

[pine thicket]

becuase the wires are connected like that

a wire has the same pd on it throughout

[kind wind]

huh

[pine thicket]

i meant pot not pd

mb

[kind wind]

hmmm

sooooo......

what of it

[pine thicket]

if we assume that the -ve plate of battery is at 0

then the capacitors plates connected to the same wire will be at 0 too

and same for V

[kind wind]

is this a fact

??

but dont u think

as charge disperses on the wire

potential decreases

in the positive terminal as teh positive charges readjust themselves so as to get the minimum electrostatic force of repulsion

but yeah

for a given section of wire

if we were to calculate its potential

it would have to be same

and same goes for all the sections that make up the wire

[pine thicket]

we assume that wores are super conductors

so no resistance

[kind wind]

okayyyyy

[pine thicket]

if there is a resistance then it will drawn with curvy lines

[kind wind]

yuh

[pine thicket]

even in reality the R for metal wires is very low so it can be ignored in most cases

[kind wind]

okayyyy

[pine thicket]

nicee

so anything else?

!close

damn bot is down

[kind wind]

sooooo

basically

with no resistance

charges effortlessly disperse

[pine thicket]

yeah

[kind wind]

creating same potential

[pine thicket]

yess

[kind wind]

and because

other wires connected via the capacitor share the same wire

will have the same potential

??

[pine thicket]

?

pls draw circuit and send

[kind wind]

wait

took my time lol

[pine thicket]

lol

[pine thicket]

they both are basically the same thing

[kind wind]

yeah i know

like the wire that connects to that positive face of the capacitor

will also get those charges

but if charges were to disperse effortlessly and particularly in superconductor

so as to get the minimum electrostatic force of repulsion wouldnt they wanna

disperse uniformly over those three wires

??

[pine thicket]

i honestly dk

maybe they might

[kind wind]

orrrr

is it teh edge effect

charges concentrate on the edge where the wires connect

[pine thicket]

umm

[kind wind]

what would that do

[pine thicket]

rn we are talking about eqll

so these things have already happened

[kind wind]

eqll

mean

[pine thicket]

equilibrium

[kind wind]

equilibrium of what

[pine thicket]

the capacitors have been charged

and no currect flows

[kind wind]

yeah

yeah

charges are already given

[pine thicket]

so charge in not moving

in the wires

[kind wind]

but it is not certain that they are equal infact they are not

for each capacitor

and also the capacitance differs for each capacitor

which should yeild different pds across the system of capacitors

in parallel combination

but it is not the case

i wonder why

[pine thicket]

in parallel charge on each capacitor may be diff

pd is same

[kind wind]

yuh

[kind wind]

yeh

[pine thicket]

hmm

i have to go now

gl

bye

[kind wind]

no problem bro

thanks for everything

have a great and splendid tommorow

be the guy

thanks man

love u

we'll discuss some things later bye

[pine thicket]

[kind wind]

.close

[compact pewter]

Channel closed

Closed by @kind wind

Use .reopen if this was a mistake.

[pine thicket]

[compact pewter]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[quartz yoke]

ef and bf are root 2

no

[nocturne pasture]

ac is root8, right?

[gaunt wedge]

I don’t see how that would be useful

[nocturne pasture]

what about putting it on a graph?

[gaunt wedge]

Wdym a graph?

Appart from Pythagoras sand Thales what tools can u use

[quartz yoke]

uh

where t o go now

[open plaza]

I am back

[quartz yoke]

ok

what do i do

[open plaza]

let me cook first

[quartz yoke]

ok

[quartz yoke]

wdym by cook?

[nocturne pasture]

cook means doing something well

[quartz yoke]

ik

been a while

[open plaza]

One thing I noticed is E, F and D lie on the same line

[quartz yoke]

yea

[quartz yoke]

then?

[open plaza]

hmm

[nocturne pasture]

I dont see how the right triangle helps.

[open plaza]

I found a solution related to a previous problem that I solved but it'd be way too long

[nocturne pasture]

is the point where CF and AB intersect the midpoint?

[open plaza]

no

hmmm ∆FBD is 30-60-90

[quartz yoke]

ye

[open plaza]

Oh solved it

[quartz yoke]

ok

[open plaza]

similar triangles

hahaa

[quartz yoke]

ok

[arctic portal]

it wouldn't be pretty but you could use law of cosines here

[open plaza]

obv

[nocturne pasture]

they can't

.

[open plaza]

@quartz yoke still here?

[arctic portal]

ohh mb

[open plaza]

ping me if you're back

[nocturne pasture]

where did you make that?

[open plaza]

make what?

[nocturne pasture]

the diagram

[quartz yoke]

yea

[open plaza]

GeoGebra

[quartz yoke]

mb

[open plaza]

alright

first part

we're going to prove E, F and D lie on the same line

[quartz yoke]

ok

[open plaza]

so first what is angle DAE?

[quartz yoke]

150

90+60

[open plaza]

and what's special about ∆DAE?

[nocturne pasture]

thanks

[quartz yoke]

its

[open plaza]

we have a lot of equal sides in the figure

[quartz yoke]

yea'

[open plaza]

so do you think that all 6 blue sides are equal

[quartz yoke]

yea ofc

[open plaza]

so ∆DAE has AD = AE

what kind of triangle is it

[quartz yoke]

iscocelese

[open plaza]

ok so what are angle ADE and AED

[quartz yoke]

uh 15

[open plaza]

alr

now can you calculate angle AEF

remember that we haven't proved E,F and D lie on the same line yet

[quartz yoke]

uh

[open plaza]

so you have to calculate angle AEF

[open plaza]

maybe you can look at the original figure

[quartz yoke]

ok

[open plaza]

tell me how you can calculate AEF

[quartz yoke]

uh

[nocturne pasture]

-# may i help

[open plaza]

yea sure go ahead and chime in

[quartz yoke]

idk rlly

[nocturne pasture]

you know EAF right?

[quartz yoke]

yea

wait

[open plaza]

no need for EAF

[nocturne pasture]

oop

[open plaza]

what is angle FEB?

[quartz yoke]

45

[open plaza]

and AEB?

@quartz yoke what is special about ∆AEB?

[quartz yoke]

uh

equilaterial

[open plaza]

so what is angle AEB?

feels like you're a bit slow today

[nocturne pasture]

-# have you two spoken before?

[open plaza]

yes

a lot

[nocturne pasture]

-# ohhk

[quartz yoke]

tired

[open plaza]

@quartz yoke you can take a break if you're overwhelmed

[quartz yoke]

no need

[open plaza]

because this problem is not easy

[quartz yoke]

its k

[open plaza]

now what is angle AEB?

[quartz yoke]

60

[open plaza]

so what is AEF?

[quartz yoke]

uh

15

[open plaza]

ok

so what we've shown is angle AEF = AED = 15°

which means E, F and D must lie on the same line

[quartz yoke]

yea

[open plaza]

now next step

fuck it deleted my figure

fuck you GeoGebra

son of a b

[nocturne pasture]

woah chill

[open plaza]

@quartz yoke so we've already proven E, F and D lie on the same line

[quartz yoke]

yea

[open plaza]

now calculate angle EDB

[quartz yoke]

uh

E is 45

[open plaza]

alr lemme help you again

what is angle ADE

[quartz yoke]

15

[open plaza]

and BDC

[quartz yoke]

45

[open plaza]

now this

[quartz yoke]

30

[open plaza]

good

now what kind of triangle is ∆FBD

[quartz yoke]

iso

[open plaza]

no

look again

what is angle BFD?

we already have BFE = 90

[quartz yoke]

90

[open plaza]

so what kind of triangle is ∆FBD

[quartz yoke]

90

[open plaza]

more specifically

[quartz yoke]

60 30?

no

ye

idk

[open plaza]

ye it is a 30 60 90

[quartz yoke]

ok

ye

[open plaza]

now calculate DE

[quartz yoke]

root(6)+root(2)?

[open plaza]

ok

now here comes the hardest parts

[quartz yoke]

noo

go ahead

[open plaza]

calculate angle EBD

[quartz yoke]

90?

[open plaza]

oh god

EBD = EBA + ABD

[quartz yoke]

oh

105

[open plaza]

now calculate angle FBC

[quartz yoke]

uh 90+

no wia

t

15

+90

what

105?

[open plaza]

nice job

[quartz yoke]

why it in red

god i have one more

ok what now

[open plaza]

?

[quartz yoke]

nth

where do we go now

like what we do

[open plaza]

next

what is ratio EB/FB

what

[quartz yoke]

ohh oh

mb

2/root(2)

[quartz yoke]

am i right?

[open plaza]

just say √2

[quartz yoke]

ok

ig

[open plaza]

what is BD/BC

[quartz yoke]

uh

root(8)/2

[open plaza]

BD is just a diagonal in a square right?

[quartz yoke]

yea

[open plaza]

you're joking me

[quartz yoke]

WHAR

[open plaza]

it's still √2

[quartz yoke]

oh

frgot to simplify

[open plaza]

now here comes the hardest part