#help-42

1 messages · Page 170 of 1

remote mural
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so how

final parrot
#

Look at the second hint again

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What's the characteristic of this(quadratic) function?

remote mural
#

i dont think i get that

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wdym by characteristic exactly

final parrot
#

Is there anything useful for us to find max min value via some concept of a quadratic value?

final parrot
remote mural
final parrot
remote mural
#

i dont think i know

final parrot
#

that's about finding roots

final parrot
remote mural
final parrot
#

Yes

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and that's our protagonist

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That's the weapon to combat this heinous monster

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quick question

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$ax^2 + bx + c$ If a>0 does the function have maxmium value or minimum value?

potent lotusBOT
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This is sad 😢

final parrot
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yo, still alive?

remote mural
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yes

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im just thinking of the stuff inside the square root

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im just gonna think out loud

final parrot
#

yeah for sure

remote mural
#

so 38 + 13t^2 - 24t comes from arbitrary distances between arbitrary lines

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between the 2 lines of each ant

final parrot
#

sqrt(38 + 13t^2 - 24t)

remote mural
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yea

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and apparently

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each line between each two random points forms a parabola?

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when put together

final parrot
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well, I'd like to share more details but I get to sleep

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,ti skyandnight

potent lotusBOT
#

The current time for skyandnight is 02:50 AM (CST) on Fri, 26/09/2025, the same as huntiebounty!

final parrot
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I'm dying 💀

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Let's jump to the last step, if you'd like more details then wait for the next helper

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You wanna find the min of this function

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So when this function has min value, the stuff inside of the sqrt must be also at its min value

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For every $ax^2 + bx + c$ quadratic function\
When a > 0, the function have min value. Reversely has the max

potent lotusBOT
#

This is sad 😢

remote mural
#

oh

final parrot
#

This function, while a is greater than 0, it has min value

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Last but not least, how do we find the min or max value of a quadratic function?????

remote mural
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set it equal to 0\

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actualy no

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find its derivative

final parrot
#

the conventional way is to convert it into vertex form

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All roads lead to Rome anyways, let's try diff first

remote mural
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okay

final parrot
#

Just diff the stuff inside the root

remote mural
final parrot
#

yes

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in what condition does it become zero?

remote mural
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x intercept

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set it equal to 0

final parrot
#

yes, and that indicates when t = 12/13, the distance has its min value

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plug that in and you'll get what you want

remote mural
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true

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thanks alot for the help

final parrot
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So before you leave, I'll leave something that I haven't given you.

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You might just post these questions to the next helper in the future

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  1. How do I find the min value of this function by converting it into vertex form??
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  1. Why does derivative works on this question?
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And that's it, sorry I can't stay with you longer

remote mural
final parrot
#

Thanks for the understandings

remote mural
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yeah for sure

final parrot
#

anymore small questions before I leave?

remote mural
final parrot
#

Alright, have a good one catthumbsup

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@short salmon janitor come and clean up the pins, Imma go 寢

short salmon
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pinger ponger

short salmon
final parrot
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yes, that's why I need a janitor to clean up the pins

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bai

short salmon
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pins cleared

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now sleep u 坚韧不拔的纪录片

winter elbow
#

.solved

calm coralBOT
#
Channel closed

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remote mural
calm coralBOT
#
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spice venture
calm coralBOT
spice venture
#

i got the function as y=x^2+x

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and so f(2) = 6

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which is the correct answer

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but for some reason it was given as bonus

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can anyone explain to me why?

jade fractal
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why it was a bonus?

spice venture
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yes

jade fractal
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i don’t understand how that is a math problem

spice venture
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what do u mean

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it was given as bonus means that the question is wrong in some way

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and that is a math problem..

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nvm i got it the value of f(1)= 2 doesnt satisfy original equation

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.close

calm coralBOT
#
Channel closed

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spice venture
#

@jade fractal ^ (incase u want to know)

simple musk
#

nvm

spice venture
#

i used newton leibnitz

rustic osprey
potent lotusBOT
#

Civil Service Pigeon

rustic osprey
calm coralBOT
#
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simple musk
#

,, \lim_{(x,y) \to (1,0)} \frac{\sqrt{|y|}(x-1)(x+4)}{(x-1)^2 + y}

potent lotusBOT
#

Renato

simple musk
#

this is going to 0, right?

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,w lim (x,y) to (1,0) of (sqrt(|y|)(x-1)(x+4))/((x-1)^2 + y)

quick talon
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test with y = t^m and x = t^n+1 . You can play with m and n to find 2 different limits after simpliftying this thing

simple musk
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wdym?

quick talon
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Try to do the variable change. And once you do. If you change m and n it’s like changing the path approach

simple musk
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care to elaborate

quick talon
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Do the variable change and simplify first; you’ll see what I mean

simple musk
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wdym?

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y = t^m -> 0

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x = t^n + 1 -> 1

sour monolith
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the point is that x,y change approach 1, 0 at different rates

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changing the value of the limit

simple musk
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y = x^2

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look at this path

sour monolith
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it doesn't pass through 1,0

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look at x=y+1

simple musk
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dude lets just do a change of variables

sour monolith
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ok

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what change of variable

simple musk
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one second

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v = x - 1 -> 0

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w = y -> 0

sour monolith
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then what do you get?

simple musk
sour monolith
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yes

simple musk
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now what

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@sour monolith

sour monolith
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consider different paths to (0,0)

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v=w is natural

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you already know the limit doesn't exists

simple musk
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trust

sour monolith
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both are natural

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try both

simple musk
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mine is better because gets rid of nasty sqrt dude

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otherwise when lhopitaling

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we get a nightmare-ish situation

simple musk
sour monolith
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they probably will

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because you know the result

quick talon
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I forgot how to write this rigourously but here are the paths that lead to 3 different limits

simple musk
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I did something different without n or m

sour monolith
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last step is wrong

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you forgot to distribute |v| correctly

simple musk
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like, we should be getting $\lim_{v \to 0} \frac{|v| + \frac{5|v|}{v}}{2}$

potent lotusBOT
#

Renato

simple musk
sour monolith
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now you can consider the right limit

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which is when v > 0

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there its easy to find the value of this limit

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but the left limit will have a different value if you look at it too

simple musk
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you are checking continuity?

sour monolith
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checking if the limit exists

simple musk
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like whether if the limit exists

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both lateral limits need to coincide

sour monolith
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yeah but continuity and existence of the limit is not the same thing

sour monolith
simple musk
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,w lim x to 0 of (|x| + 5|x|/x)/(2)

simple musk
sour monolith
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on the left sided limit v stays v, but its negative

simple musk
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is this enough shit?

sour monolith
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if you found two paths that are not matchning then you are done

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you still have a small error in the left limit

simple musk
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in this case one path is undefined

sour monolith
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its (v + (-5v)/v) / 2

simple musk
#

excuse me?

simple musk
#

you tripping hard EsquieESQUIE

sour monolith
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oh yeah xD

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sorry

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I looked at the one above it instead of two about it

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anyway you are done with this question

simple musk
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the issue is

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do i need to find another path that is defined

sour monolith
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no

simple musk
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or one undefined path is enough

sour monolith
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two paths that don't match --> limit undefined

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you have two paths (the two directions of w=v^2)

simple musk
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care to elaborate?

sour monolith
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first path: w=v^2 where v approaches 0 from the right (v > 0)
second path: w=v^2 where v approaches 0 from the left (v < 0)

simple musk
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I mean

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its just one path I think, correct?

sour monolith
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its two paths

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a path is function f:[0,1] --> R^2 which is continuous

simple musk
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wdym?

sour monolith
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a path is a continuous function connecting two points

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thats what this definition says

sour monolith
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but along these paths the limit is different

simple musk
sour monolith
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v is not the input

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here if we translate these into functions,
then the first would be
t --> (t, t^2)
and the second would be
t --> (-t, t^2)

simple musk
#

care to elaborate?

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where did y came from?

sour monolith
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there is no y

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t --> (v, w)

simple musk
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t = (v,w)?

sour monolith
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the first coordinate is v, the second is w

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t is mapped to (v, w)

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I parameterize the path

simple musk
simple musk
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I mean

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the issue is that we are only trying out the path y = (x-1)^2

sour monolith
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we are trying both direction, which give two different paths

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paths with different direction are different

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heck even you go along the path at different speed its different

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as I said a path is a function

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any change to the function will give a different path

simple musk
#

I see

simple musk
simple musk
#

,w sin(2pi)

simple musk
#

,w cos(2pi)

simple musk
#

.close

calm coralBOT
#
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calm coralBOT
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wide cedar
#

I'm struggling with understanding how to complete the square
So I'm attempting to find the inverse of the attached equation, I've gotten as far as the second screenshot
After talking with ai i'm still not understanding how to continue

jade fractal
#

$r = {-b \pm \sqrt{b^2 - 4ac} \over 2a}$ where r is a root

potent lotusBOT
#

Médicis

jade fractal
#

you then get $ax^2 + bx + c = (x-r_1)(x-r_2)$

potent lotusBOT
#

Médicis

wide cedar
#

I've been instructed to solve it without the quadratic formula, could you explain how to do it without?

jade fractal
#

there’s no direct root so idk

wide cedar
#

like I just genuinly don't understand how this works

jade fractal
#

Oh

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you need in this form ok

wide cedar
#

sorry if I caused some confusion there

jade fractal
#

you’re searching for some solution in the form $2x^2 -6x -13 = (Ax + B)^2 +C$

potent lotusBOT
#

Médicis

wide cedar
#

yes!

jade fractal
#

develop the right part and try deducing what A, B and C are

wide cedar
#

well I know what they are I just don't understand how to get there

jade fractal
#

$(Ax + B)^2 + C = A^2 x^2 + 2ABx + B^2 + C$

therefore you have to search A, B and C such that:

$A^2 = 2 \2AB = -6 \ B^2 + C = -13$

potent lotusBOT
#

Médicis

wide cedar
#

.close

calm coralBOT
#
Channel closed

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calm coralBOT
#
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halcyon ore
calm coralBOT
halcyon ore
#

,rotate

potent lotusBOT
halcyon ore
#

what my prof did was define a function $f(m,n)$ such that $$f(m,n) = g(m,n,k)$$ then you can fix $f(m,n)$ to a contant and then you are basically done

potent lotusBOT
#

Bubbles

halcyon ore
#

what i dont get is how you can define that function like that??

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the function just gives the relation between the points

sleek vessel
#

What's the infinite ramsay theorem

halcyon ore
#

ramsay therom but for inf number of points

sleek vessel
#

That tells me very little lmao

halcyon ore
#

1 sec still typign

#

it says their exists an infinite complete subgraph that is monochromatic given a finite amount of colors

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lemme find the defintino from the book

sleek vessel
#

Yes please

#

I have an idea of what the proof is, but I'd like to be sure

halcyon ore
sleek vessel
#

Oh hm okay then I have no idea how this would go

halcyon ore
#

lmao

sleek vessel
#

Hopefully someone else can help you lol

halcyon ore
#

lets hope

#

<@&286206848099549185>

calm coralBOT
#

@halcyon ore Has your question been resolved?

halcyon ore
#

<@&286206848099549185>

calm coralBOT
#

@halcyon ore Has your question been resolved?

craggy heron
#

Hello

halcyon ore
#

hello

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are you here to save me

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@craggy heron any idea on how to solve 😭

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or is it just wraps

halcyon ore
#

It’s wraps

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.clode

manic oracle
halcyon ore
#

Yes

manic oracle
#

so f(m, n) kinda should use information about g(m, n, k)... well, we can aggregate it for all the distinct k and just pick a color that appears infinitely often

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and use that to color f(m, n)

halcyon ore
#

OKAY

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THATS WHAT I WAS THINKING

manic oracle
#

but that doesn't work yet

halcyon ore
#

oh

manic oracle
#

another idea

define graph with vertices {a, b} of unordered pairs of naturals

#

{a, b} {a, c} has color g(a, b, c) obviously
{a, b} {c, d} ?

halcyon ore
#

uhh

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why unordered

halcyon ore
manic oracle
#

hmm... maybe color it with {g(a, b, c), g(a, c, d), g(a, b, d), g(b, c, d)}?

halcyon ore
#

there are an inf number of points btw

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we can assume 2 colors for simplicity too

manic oracle
#

oh yeah we can

manic oracle
#

just take any vertex that is included? nothing about that forces the triples to share that colour

halcyon ore
#

sorry its blurry

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this was the sol

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he wrote on the board

manic oracle
#

or are we fixing a particular k

halcyon ore
#

thats waht i dont get he just "erased" the k

manic oracle
#

we fix a k, and then we colour g(m, n) by the triple color f(m, n, k)

halcyon ore
#

yeah. then we can create a sequence k1, k2, etc

manic oracle
#

okay that's probably it

halcyon ore
#

and by ramseys we can create a inf sub sequence that is all the same color

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not ramseys

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pigeon hole

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he might have messed up the proof idk

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ill ask him abt it

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would u mind if i sent another q?

manic oracle
#

usually recommend to start another channel, or #1021175428326633542 if you want it to last quite a while

halcyon ore
#

kk

#

.close

calm coralBOT
#
Channel closed

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halcyon ore
#

thank you for the help

manic oracle
#

oh yeah for each k we can see if it forms color 0 triples or color 1 triples

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something following the classic ramsey proof where we try to construct both cliques at the same time

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if it's color 0 triple, add it to the 0 sequence
if it's color 1 triple, add it to the 1 sequence
we never run out of vertices

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so at least one sequence goes infinite

halcyon ore
#

yeah

calm coralBOT
#
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foggy heron
calm coralBOT
final parrot
#

What have you tried in advance?

foggy heron
#

nothing

#

these are the notes, im trying to understand them

final parrot
#

Are you notes still loading?

#

@foggy heron

foggy heron
#

what do you mean

final parrot
#

these are the notes, im trying to understand them
I thought you were going to share your notes

foggy heron
#

no as in thats one of the excercises in the notes and i dont know how to do it and i want to know how to do the excercise so i can understand the ntoes

old plume
#

Let's try it.

How many total ways of selecting 5 balls from collection of 15 balls?

leaden lion
#

can it be solved with combinations?

safe lynx
safe lynx
#

First find the no of ways to select 5 balls from total no of balls i.e 15

foggy heron
#

then 15!/(15-5)!?

leaden lion
#

then do 15C5 for the denominator fraction

safe lynx
final parrot
#

Can we not have so many helpers lol

leaden lion
safe lynx
leaden lion
foggy heron
#

i thought it mattered for this

#

well not this problem?

old plume
#

Now, there are 5 red balls and 10 blue balls, you're selecting 5 such that 2 are red and 3 are blue. In how many ways you can do that?

foggy heron
#

the example they gave

#

idk

old plume
#

(5C2)*(10C3)

foggy heron
#

ah

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so 5c2*10c3/15c5?

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then would this be 15c2*2c18/4c33?

old plume
#

18c2 instead
(You can't select 18 out of 2)

foggy heron
#

4ith5

#

right

#

cool thanks yall

#

.close

calm coralBOT
#
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blazing coyote
#

Just have time to talk about the iden tity for now

blazing coyote
#

$a \ in S \implies \exists s ' \in S : as'=a (S=aS)$ and $a \in S \implies \exists s'' \in S " s''a =a$ ( as S=Sa).

#

this isnt enough to say the set has an identity is it

#

I have to show that the left and right identity are the same, right

potent lotusBOT
blazing coyote
#

though tbh this doesn't guarentee that every element will have the same identity does it

#

I'll have to show that too

sour monolith
#

$aS=S=Sa$ tell you that maps $x \mapsto ax$ and $x \mapsto xa$ from S to S are surjective.

potent lotusBOT
#

ExpertEsquieESQUIE

sour monolith
#

you good ?

calm coralBOT
#

@blazing coyote Has your question been resolved?

blazing coyote
calm coralBOT
#
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low lodge
#

hey, i proved T(x) is differentiable and cont so it has MIN and MAX in the interval [-3,-1] but idk how to attack it since T'(x) is unworkable to find critical points

low lodge
#

any hint (no full answer) will be nice

sour monolith
#

find critical points

#

it shouldn't be hard

#

it will just be a polynomial equation

low lodge
sour monolith
#

אחלה

low lodge
jade fractal
low lodge
jade fractal
low lodge
#

right

low lodge
jade fractal
low lodge
#

+1/(1+x^2)

#

so i get 2x+2x^3+1=0

#

finding critcal points with that equation not so simple

sour monolith
#

but what sign is this derivative?

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in [-3, -1]

#

||its negative||

low lodge
#

since 2x is larger

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i suppose i need to prove that on [-3, -1] T'(x)<0

sour monolith
#

this should be easy by continuity

low lodge
#

since T''(x) actually easier to work with lol

sour monolith
#

you can do it

low lodge
sour monolith
#

this is probably the easiest way

low lodge
#

T''(x)>0 on the interval we mentioned so T'(x) is an increasing function on that interval so i can do T'(-3) and see if its >0. if it is then T is increasing on that interval

low lodge
#

maybe T'(-3)<0

sour monolith
#

you would want T'(-1)

#

because if its increasing before it, and its negative at -1, it must be negative before -1

low lodge
low lodge
#

i think

sour monolith
#

Read closly

low lodge
#

tryin

sour monolith
#

You say T'(-3) > 0 which it isn't

low lodge
low lodge
#

i mean i get what you say

low lodge
sour monolith
#

Yes

low lodge
#

תודה יא קינג

#

.close

calm coralBOT
#
Channel closed

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calm coralBOT
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tardy kayak
calm coralBOT
rigid jewel
#

e^(i*theta)

#

wait nvm

sharp narwhal
rigid jewel
#

ah recurring function

#

stupid jee

#

just solve upto 2 or 3 recursions and see how the pattern goes
it will probabily converge into something

tardy kayak
#

I've tried leibniz

#

But I got stuck midway

sharp narwhal
#

u differentiated both sides wrt theta?

#

i think that's a decent approach

#

u can also integrate both sides wrt theta from 0 to pi/2

tardy kayak
#

Ohh

#

Wait lemme try

#

But Idk double integration

#

How can I integrate both sides?

sharp narwhal
#

just think about what terms are constant wrt the integral

#

i don't think u need to know extra theory

#

eg. if ur interating wrt t, you can pull out sin(theta)

tardy kayak
#

Ohh

#

Okay lemme try

rigid jewel
#

integeral of sine term should be 0 since it is odd function

tardy kayak
sharp narwhal
#

wdym

sly brook
# tardy kayak

apply kings rule here by replacing the angle theta by negative theta (as pi/2+(-pi/2)-theta=theta)

#

try by it

#

and then add the integral obtained after this transformation to the original one

tardy kayak
sly brook
#

,rttr

#

,rotate

potent lotusBOT
velvet osprey
sly brook
#

i dont know much about it

rigid jewel
tardy kayak
#

Yes

rigid jewel
tardy kayak
#

How

rigid jewel
#

ahem

#

u need to check wether terms in the exapansion are odd or even

#

if its odd the term vanishes if its even then the integral becomes half of 0 to 2pi

calm coralBOT
#

@tardy kayak Has your question been resolved?

tribal copper
rigid jewel
rigid jewel
sly brook
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rigid jewel
calm coralBOT
rigid jewel
#

what i did was integral -a to a of odd function = 0
integral -a to a of even function = 1/2 of integral 0 to a

sly brook
#

ok ok

#

yes that works too

#

rest ill figure out

#

@rigid jewel close this channel mistakenly opeaned by you by typing .close

rigid jewel
#

.close

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frail light
#

is there a need to get the present year ratio first?
also tell me what it means of last two lines

fickle steeple
#

can you tell me the source of this question? like for what exam are you preparing with this?

frail light
#

SSC

fickle steeple
#

ok 👍

safe lynx
calm coralBOT
#

@frail light Has your question been resolved?

old plume
#

Since, P and S are twins.
P=S
Also, P+S = M
And 3 years ago, the ratio was (P-3)/(M-3) = 2/7

You got three equations, three unknowns.

calm coralBOT
#

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civic roost
calm coralBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
civic roost
#

1

violet vector
civic roost
#

how is that

#

in anyway

#

related to the problem i need help in?

#

<@&286206848099549185> heyy anybody free?

violet vector
#

@calm coral 1

violet vector
rustic osprey
# civic roost

This is just knowing your basic facts. Reflections are rigid motions, so triangle A’B’C’ is congruent to triangle ABC.

A dilation with scale factor k multiplies all of the side lengths by k. So, the side lengths of A’’B’’C’’ are twice the corresponding side lengths in A’B’C’.

civic roost
#

:/

#

.close

calm coralBOT
#
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narrow folio
#

can proofs have "subproofs"

calm coralBOT
narrow folio
#

i.e. if im proving smth can i posit something then prove the thing i posited inside the proof trolled

swift laurel
#

yeah that's called a lemma

narrow folio
#

thanks

pallid halo
#

you could factor it out as a lemma yea

narrow folio
#

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red breach
#

So I am having trouble conceptually understanding what the problem wants me to do

red breach
#

(currently am on a)

#

the column space would just be composed of columns, right? [3, 6, -9] and [-1, -2, 3]

#

I'm just not sure how constraint equations come into play and I'm not sure why there is a linear combination of rows of A summing to 0

#

So this is listed in the answers- same as what I got myself

#

but I just don't get how it leads back to the column vector, I'm getting confused

leaden thunder
#

did you try to row reduce A

#

b is in the column space of A does not mean what you think it is

red breach
#

wdym

red breach
red breach
leaden thunder
#

yea that looks right

red breach
leaden thunder
red breach
#

So just [-1, -2, 3]

#

yeah guys I got it

#

thanks

#

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median cloak
#

Diffusion models, CLIP, and the math of turning text into images
Welch Labs Book: https://www.welchlabs.com/resources/imaginary-numbers-book

Sections
0:00 - Intro
3:37 - CLIP
6:25 - Shared Embedding Space
8:16 - Diffusion Models & DDPM
11:44 - Learning Vector Fields
22:00 - DDIM
25:25 - Dall E 2
26:37 - Conditioning
30:02 - Guidance
33:39 - Neg...

▶ Play video
median cloak
#

can someone explain what the presenter trying to convey.

hexed grove
#

ive seen this video lol

#

we use physical diffusion processes in reverse to generate images from text

#

and hence diffusion models

median cloak
#

specifically, why the diagonal is matching and others is not? also matching to what

hexed grove
#

you need to be specific

#

im not sure what youre asking

median cloak
#

he says the diagonal is "matching" and other entries are not

#

"the diagonal" correspond to matching image and caption

#

this is what he said, while others are not

hexed grove
#

i think this is called the co-occurance matrix, idrk

#

the diagonal is where the text represents the image

median cloak
hexed grove
#

so we need each diagonal entry to dominate the non-diagonal entries

median cloak
hexed grove
hexed grove
#

so, the entries in the matrix are probabilities that the text matches the pictures

#

rather, they encode the probabilities with vectors

median cloak
#

I totally agree. But why others do not match but only the diagonal

hexed grove
#

training

#

before training its totally random

#

but after (assuming we trained it properly) it should match

median cloak
#

I mean if you look at the entry_21, it has a caption of cat as well as a picture of cat

#

it is matching, no?

hexed grove
#

i honestly have no idea

violet vector
hexed grove
#

but the point is to make this matrix totally randomly, and then through training, the model will "learn" to match text to images

median cloak
#

How

hexed grove
#

thats a much more technical question lol

#

the general idea is to evaluate the error, and backpropagate it through gradient descent

#

we need to start with a training batch of correctly assigned images to do this

hexed grove
median cloak
#

no

hexed grove
#

i suppose these channels can be used to help you learn actual math as well (i might be wrong), but you shouldnt leave it open if youre done

median cloak
#

I'm not done. someone has not answered my question yet.

hexed grove
#

everything starts out randomly, and then through the training process, the model learns to make the diagonal match and nothing else match

calm coralBOT
#

@median cloak Has your question been resolved?

calm coralBOT
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calm coralBOT
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scenic briar
#

lets say we wanna use an identity on (-4x-1)^2

scenic briar
#

now would b = -1

#

or b = 1

amber bay
#

For this to be less complicated

velvet osprey
#

name which identity you wish to use

#

(you can use either one)

amber bay
#

u can write (-4x-1)^2 = (-1(4x+1))^2 = -1^2 * (4x+1)^2 = 1*(4x+1)^2

scenic briar
#

this

velvet osprey
#

ok and you want to use that AS IS?

scenic briar
#

yup

velvet osprey
#

then a=-4x and b=+1.

#

but @amber bay's suggestion is good otherwise bc it cuts down on minus signs

amber bay
#

I mean why if u wanna use that

#

then b would equal 1

#

but why not make life easier

calm coralBOT
#

@scenic briar Has your question been resolved?

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somber swift
#

Calculate the three quartiles for a random variable
𝑋 with the probability density function

somber swift
#

dont know how i should go about this problem

#

I'm not sure which function should be used when calculating each quartile

#

this didnt help either

kind light
#

67

calm coralBOT
#

@somber swift Has your question been resolved?

somber swift
#

.close

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spice venture
calm coralBOT
spice venture
#

i dont understand what that 'D' is for in the differential eqn

#

i differentiated y=mx + c wrt x to get dy/dx = m

#

and thats it

void frost
#

Df sometimes refers to the first derivative of f

spice venture
#

oh

void frost
#

D(Df) might be written as D^2f, the second derivative

spice venture
#

oh ok

#

so how do i solve this?

harsh night
#

Dy = differential of y w.r.t any variable if im not wrong

#

so lets take it with respect to x

spice venture
#

oh wrt any variable?

spice venture
harsh night
#

ur eqn would be y'' - 3y' - 4y = -4x

spice venture
#

ye

void frost
spice venture
harsh night
#

i think now u have to differentiate y=mx + c and put values of y' and y'' in the differential eqn

void frost
#

Do you see how to continue?

spice venture
#

oh we can take 4 common

#

3m+4y = 4x

void frost
#

I don't think that's helpful

#

You can right away follow something out of this

#

On both sides, you have a parametrization of a line

spice venture
#

4y=4x-3m
y=mx+c
now we can compare?

void frost
#

And well, when are two such things equal?

void frost
#

You will get two equations out of this

spice venture
harsh night
spice venture
#

y=mx+c
y=x-3m/4

#

m=1

#

c=-3/4

harsh night
#

yeah

#

there u go

spice venture
#

got it thanks

#

.close

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#
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low lodge
#

hey i would like a hint with 2.

calm coralBOT
low lodge
#

thats what ive tried so far:

#

the problem is with the red. if it was <0 then ofc it was an increasing function on the interval [1,+inf) so then f(1) was the min in that interval

ornate thunder
#

Differentiate the function

low lodge
low lodge
tranquil sundial
#

where is your differentiated function?

#

@low lodge

low lodge
tranquil sundial
#

ah, didnt see

#

mb

#

when x is very big, sinx->x, cosx->1

#

meaning that f'(x)~=pi/x^2>0

#

f(x) is increasing

#

so if absolute minimum exists, it would be closer to 0

low lodge
#

anyways thx for trying < 3

#

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tranquil sundial
low lodge
#

.reopen

calm coralBOT
#

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#
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tardy kayak
calm coralBOT
tardy kayak
#

how do I solve this??

odd fulcrum
tardy kayak
#

I have tried integrating the whole function

#

wrt theta

#

but then I got stuck

#

is there any other way of solving this?

upbeat coral
#

Notice that the function f is inside its definition

#

So it might help to isolate it

tardy kayak
tribal copper
#

did you try expanding everything

tardy kayak
#

yea i did

tribal copper
#

what did you get

tardy kayak
#

after integrating wrt theta i got $\int_0 ^{\frac{\pi}{2}}f(\theta)d(\theta) = 1 + \int f(t)dt + \int tf(t)dt$

#

oops

upbeat coral
#

Put d outside of \dtheta

potent lotusBOT
#

Prathmesh

tardy kayak
#

yup this is what i got

tardy kayak
upbeat coral
#

$\int f(\theta) d\theta = \int f(t) dt$

potent lotusBOT
#

Miyagi

tribal copper
#

i got 1 but i didnt integrate wrt theta

#

i did simultaneous equations instead

#

do you have the correct answer

calm coralBOT
#

@tardy kayak Has your question been resolved?

calm coralBOT
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sleek vessel
#

Can someone explain what a regular language is? And what a context-free language is?

I'm doing a course on program analysis, and I was promised I wouldn't need any automata theory stuff but they just threw this at me in an assignment.

sleek vessel
#

The assignment problem, if that helps

#

I don't want help with answering this. I just wanna know what exactly a regular language and a context-free language is. Preferably a description that doesn't use automata

#

(please tag me if anyone answers)

thorny stump
sleek vessel
#

I'm gonna need to learn automata theory huh

thorny stump
#

Well, you probably don't need to if that's the only problem you want to answer; one is a strict subset of the other

sleek vessel
#

I mean I imagine regular is a subset of context-free

#

Cuz an FSM with a stack should be able to capture anything an FSM without a stack captures

thorny stump
#

It's not clear to me what IVP means? Interprocedurally Valid Paths? Did they really write IVPaths paths?

sleek vessel
#

Yes

#

Smh my head

thorny stump
#

Ok well I'm not familiar with these terms (initial IVP, program points, call-strings, call points)

sleek vessel
#

Ah that's fine, I really just wanted to know what regular language means

thorny stump
#

I imagine, since (2) says "of call-strings along initial IVPs" while (1) just says "of initial IVPs", that (1) is the context free

sleek vessel
#

I can describe the terms to you but that isn't really relevant to my question

#

Fair enough

#

I just don't know if that's enough justification

#

And it just feels unsatisfying to use the containment

thorny stump
sleek vessel
#

Fair maybe I will closer to the deadline

#

Gonna keep this open in case anyone else wants to comment

thorny stump
#

To give a little more context, combinatorial logic circuits are contained by finite-state machines which are contained by pushdown automata which are contained by Turing machines

sleek vessel
#

Interesting. Somehow the only thing on that list that I've done are turing machines lol

#

And even that was very limited

thorny stump
#

You start with "instant output given current inputs", then add a graph of states and transitions, then add a stack (which you can only read and write to at the top), then you switch from stack to tape (which you can access anywhere without losing data)

#

(that's my understanding anyway, I'm no automata theory expert)

sleek vessel
#

Well you certainly understand it better than me lol

#

.close

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#
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coarse karma
#

hello,
So I have an exam in a few hours and I was running through practice problems online. My brain might be fogging right now because I couldn't figure out what went wrong and how I got the boxed answer a^2-a-3 instead of -19/8

The topic is about rational equations and I'd appreciate it if someone would point out the thing(s) I did wrong

coarse karma
#

this was the problem for referenc

#

what I did was eliminate the lcds by multiplying the whole expression with the denominmators

upbeat coral
#

You turned the a into a 9

#

Bruh moment

coarse karma
#

wher

upbeat coral
#

I might be hallucinating

#

Anyways

coarse karma
#

sory bad handwriting

upbeat coral
#

Your approach is correct

coarse karma
#

I was rushing through

coarse karma
#

do you think it was a problem with the answer key

upbeat coral
#

You should end up with a quadratic equation

#

That equals zero

coarse karma
#

ooh I see

coarse karma
upbeat coral
#

Not much to say

novel raven
upbeat coral
#

I think the a^2 terms cancel out

#

Which makes things easy

coarse karma
coarse karma
coarse karma
#

.close

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#
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fringe reef
#

$\int_0^1 \frac{\ln(x)}{x^2 - x+1} dx$

calm coralBOT
potent lotusBOT
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artemetra

fringe reef
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is this anything nice?

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saw it on an instagram post

fringe reef
#

,w \int_0^1 \frac{\ln(x)}{x^2 - x+1} dx

fringe reef
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bruh

pseudo wedge
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You can multiply the numerator and denominator by 1+x and then series expand the denominator

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That’ll lead to some series which are hopefully simplifiable

rustic osprey
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,w integrate (ln x)/(x^2-x-1) dx from 0 to 1

potent lotusBOT
rustic osprey
#

,w \frac{pi^2}{5sqrt5}

potent lotusBOT
rustic osprey
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Typo?

fringe reef
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possibly..

pseudo wedge
fringe reef
pseudo wedge
potent lotusBOT
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kheer257

pseudo wedge
fringe reef
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i see

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but tl;dr the former one isn't worth trying?

pseudo wedge
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Why not?

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Every integral is worth trying

fringe reef
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True..

pseudo wedge
fringe reef
# pseudo wedge The latter

you mean the former lol
(x^2-x+1)(1+x) = (x^2-x+1+x^3-x^2+x) = x^3+1
(x^2-x-1)(1+x) = (x^2-x-1+x^3-x^2-x) = x^3-2x-1

rustic osprey
pseudo wedge
#

My method was for the former

fringe reef
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ah alr

pseudo wedge
#

The latter is solved in a different way

pseudo wedge
#

It’ll still be nonelementary I think

fringe reef
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at least the integral inside the sum does

rustic osprey
fringe reef
#

$\int_0^1 x^k \log(x) dx = -\frac{1}{(k+1)^2}$

potent lotusBOT
#

artemetra

fringe reef
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if I'm not mistaken

pseudo wedge
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Yes

calm coralBOT
#

@fringe reef Has your question been resolved?

rustic osprey
#

@fringe reef You good?

calm coralBOT
#

@fringe reef Has your question been resolved?

calm coralBOT
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torpid anvil
calm coralBOT
torpid anvil
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ive just played around w them icl

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nvm

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.close

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remote mural
#

i found the equation for the parabola at the y = 5 plane , i just dont know how to continue from there

nimble harbor
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send

nimble harbor
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like what u normally do for when y is the dependent one instead of z

calm coralBOT
#

@remote mural Has your question been resolved?

tawny mesa
#

is xy+2y=1 a function

calm coralBOT
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shut harness
#

Need help

calm coralBOT
desert relic
shut harness
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sec

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my pc lagging

odd fulcrum
shut harness
#

Ok ignore what question 9 asks. But for 11. ive encountered many questions like it on tests and always get it wrong.. im pre calc grade 12 level i understand the first answer which is 3 but not the 2 second one and i understand the 3rd one and 4th

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anyone pls

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@desert relic @odd fulcrum 😄

desert relic
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Yeah I've never heard the term before

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Was looking it up

shut harness
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Oh

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It means a point in the new graph that doesnt change from the old one

desert relic
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Okay

odd fulcrum
desert relic
#

Also @shut harness please don't ping individual helpers, like me and Infinium are chill but some of the helpers are very particular about this :)

desert relic
odd fulcrum
#

like you just did @{somebody}

shut harness
#

Okey sorry

odd fulcrum
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nah its good, some people are adiment about it though.

desert relic
shut harness
#

CAN someone pls help

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😩

desert relic
#

Well I looked it up, it says to get the original function and transformed function equal to each other and then find their value

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Like f(x) = y^2

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So for the first one, f(x) = 3/sqrt(f(x))

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y^2 = 3/y

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y^3 = 3

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So it has only one solution, hence only one point

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Now I should say that I'm shooting shots in the dark here, I've got no clue if this is the correct approach

desert relic
calm coralBOT
#

@shut harness Has your question been resolved?

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nimble badge
#

Is the space of non-parametric functions strictly larger than parametric functions? Ie are there functions that can be described non-parametrically, that cannot be described by parametrically? (This is for my own edification, and a simple counter example would suffice)

nimble badge
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Ik that it is generally assumed to be true, but my intuition says that anything can be modeled parametrically

jade fractal
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define non-parametrically

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nevermind I minsunderstood it

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don’t mind me

nimble badge
#

Now, i need to review gaussian process regression where i saw this last

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Anyway

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.close

calm coralBOT
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calm coralBOT
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weak vapor
#

yo i have a question, just want to confirm my work is right

weak vapor
acoustic wraith
#

please send it here

winter elbow
weak vapor
#

heres my answer, im sending question 1s

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Georgia has 15 apps on her phone. Of these apps, 10 are connected to social media, seven are games, and five are prayer/meditation apps.

jovial bridge
#

wait what are questions a)/b)?

weak vapor
#

oh sorry

jovial bridge
acoustic wraith
#

you seem to not have considered prayer/meditation apps in a)

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your conclusion is correct though

weak vapor
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so everything is right, just need to add the prayer/mediation apps to a?

acoustic wraith
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for completeness, I would say so.

weak vapor
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alright, thanks

acoustic wraith
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your Venn diagram is also missing the prayer/meditation app circle

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(if it was drawn as part of the question)

weak vapor
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how would i draw it instead

acoustic wraith
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three circles

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not two

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and you probably no longer need the rectangle outside, but no harm keeping it I think

weak vapor
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okay

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and in the 3rd rectangle id put 2?

acoustic wraith
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3rd rectangle?

weak vapor
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i mean

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circle

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oh sorry, 3

acoustic wraith
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put however much you found out

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I haven't fully worked it out yet, so can't confirm

weak vapor
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alright

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ty for the help

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oh I have one more question, if you're available

acoustic wraith
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you may send it, if I'm not available other helpers will come in

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but either way, sure

weak vapor
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what would I change to get this right, i lost a mark from this

acoustic wraith
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you've got to show the original context, mate

weak vapor
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oh it's basically a toy caterpillar that has a 50/50 chance of either going to red or blue

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lowk forgot to send that lol

acoustic wraith
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then what does it mean hitting red twice? I think the original question would still help here

weak vapor
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Connect the caterpillar scenario above to a question you would ask related to probability.

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basically the probability of the caterpillar not hitting red in 2 attempts

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and instead going to blue both times

weak vapor
acoustic wraith
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so in 2 attempts, the caterpillar turns blue

weak vapor
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yeah, both times

acoustic wraith
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in that case, it's more straightforward to just calculate the probability it hits blue both times, right?

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if you want to do inclusion-exclusion, you'd have to account for any event where at least one of them is red

weak vapor
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i'm allowed to do either

weak vapor
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the red text is the feedback I recieved, i'm not exactly sure what i'd change

acoustic wraith
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and it'd be 1/4. try listing out the possible events (R = red, B = blue)

weak vapor
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red red
red blue
blue red
blue blue

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so the probability of it not being red twice is 3/4

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so the answer is right? but something with P(A') is wrong?

acoustic wraith
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when I asked, you said that both times must be blue

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so is it "at least one time not red", or "neither attempt is red"?

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(also, this is why i asked for the og question)

weak vapor
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"what is the probability of the caterpillar never hitting red"

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thats the choice i made

weak vapor
acoustic wraith
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then your P(A') should be 3/4, because A is the event where neither attempt is red, so A' is the event where at least one attempt was red.

weak vapor
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ohh, so where i wrote P(A') should be P(A)