#help-42
1 messages · Page 170 of 1
Look at the second hint again
What's the characteristic of this(quadratic) function?
Is there anything useful for us to find max min value via some concept of a quadratic value?
What would you come up with when it comes to quadratic function?
quadratic formular?
anything else?
i dont think i know
that's about finding roots
Alright, do you know a quadratic function has a vertex?
like the peak point?
Yes
and that's our protagonist
That's the weapon to combat this heinous monster
quick question
$ax^2 + bx + c$ If a>0 does the function have maxmium value or minimum value?
This is sad 😢
yo, still alive?
yes
im just thinking of the stuff inside the square root
im just gonna think out loud
yeah for sure
so 38 + 13t^2 - 24t comes from arbitrary distances between arbitrary lines
between the 2 lines of each ant
sqrt(38 + 13t^2 - 24t)
yea
and apparently
each line between each two random points forms a parabola?
when put together
no, don't think that way
well, I'd like to share more details but I get to sleep
,ti skyandnight
The current time for skyandnight is 02:50 AM (CST) on Fri, 26/09/2025, the same as huntiebounty!
I'm dying 💀
Let's jump to the last step, if you'd like more details then wait for the next helper
You wanna find the min of this function
So when this function has min value, the stuff inside of the sqrt must be also at its min value
For every $ax^2 + bx + c$ quadratic function\
When a > 0, the function have min value. Reversely has the max
This is sad 😢
oh
This function, while a is greater than 0, it has min value
Last but not least, how do we find the min or max value of a quadratic function?????
yes, that's a way
the conventional way is to convert it into vertex form
All roads lead to Rome anyways, let's try diff first
okay
yes, and that indicates when t = 12/13, the distance has its min value
plug that in and you'll get what you want
So before you leave, I'll leave something that I haven't given you.
You might just post these questions to the next helper in the future
- How do I find the min value of this function by converting it into vertex form??
- Why does derivative works on this question?
And that's it, sorry I can't stay with you longer
its all good its getting late for you anyway
Thanks for the understandings
yeah for sure
anymore small questions before I leave?
ahh not really thanks
Alright, have a good one 
@short salmon janitor come and clean up the pins, Imma go 寢
pinger ponger
IT'S 3 AM はよ寝ろ
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you as well
i remember u
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i got the function as y=x^2+x
and so f(2) = 6
which is the correct answer
but for some reason it was given as bonus
can anyone explain to me why?
yes
i don’t understand how that is a math problem
what do u mean
it was given as bonus means that the question is wrong in some way
and that is a math problem..
nvm i got it the value of f(1)= 2 doesnt satisfy original equation
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@jade fractal ^ (incase u want to know)
nvm
let $x=1$ and you get $0=3f(1)-1$
Civil Service Pigeon

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,, \lim_{(x,y) \to (1,0)} \frac{\sqrt{|y|}(x-1)(x+4)}{(x-1)^2 + y}
Renato
this is going to 0, right?
,w lim (x,y) to (1,0) of (sqrt(|y|)(x-1)(x+4))/((x-1)^2 + y)
test with y = t^m and x = t^n+1 . You can play with m and n to find 2 different limits after simpliftying this thing
wdym?
Try to do the variable change. And once you do. If you change m and n it’s like changing the path approach
care to elaborate
Do the variable change and simplify first; you’ll see what I mean
care to elaborate?
the point is that x,y change approach 1, 0 at different rates
changing the value of the limit
dude lets just do a change of variables
then what do you get?
yes
consider different paths to (0,0)
v=w is natural
you already know the limit doesn't exists
mine is better because gets rid of nasty sqrt dude
otherwise when lhopitaling
we get a nightmare-ish situation
do they approach different values or what
I forgot how to write this rigourously but here are the paths that lead to 3 different limits
like, we should be getting $\lim_{v \to 0} \frac{|v| + \frac{5|v|}{v}}{2}$
Renato
the issue is dude, this absolute value thing is making it hard
now you can consider the right limit
which is when v > 0
there its easy to find the value of this limit
but the left limit will have a different value if you look at it too
you are checking continuity?
checking if the limit exists
yeah but continuity and existence of the limit is not the same thing
yes, but here they sadly don't
,w lim x to 0 of (|x| + 5|x|/x)/(2)
on the left sided limit v stays v, but its negative
do I need to check other paths ?
is this enough shit?
if you found two paths that are not matchning then you are done
you still have a small error in the left limit
in this case one path is undefined
its (v + (-5v)/v) / 2
excuse me?
oh yeah xD
sorry
I looked at the one above it instead of two about it
anyway you are done with this question
no
or one undefined path is enough
two paths that don't match --> limit undefined
you have two paths (the two directions of w=v^2)
care to elaborate?
first path: w=v^2 where v approaches 0 from the right (v > 0)
second path: w=v^2 where v approaches 0 from the left (v < 0)
wdym?
a path is a continuous function connecting two points
thats what this definition says
now, these are two different function, so two different paths
but along these paths the limit is different
what if v < 0
v is not the input
here if we translate these into functions,
then the first would be
t --> (t, t^2)
and the second would be
t --> (-t, t^2)
the first coordinate is v, the second is w
t is mapped to (v, w)
I parameterize the path
how?
.
like this
we are trying both direction, which give two different paths
paths with different direction are different
heck even you go along the path at different speed its different
as I said a path is a function
any change to the function will give a different path
I see
I didnt know
,w cos(2pi)
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I'm struggling with understanding how to complete the square
So I'm attempting to find the inverse of the attached equation, I've gotten as far as the second screenshot
After talking with ai i'm still not understanding how to continue
$r = {-b \pm \sqrt{b^2 - 4ac} \over 2a}$ where r is a root
Médicis
you then get $ax^2 + bx + c = (x-r_1)(x-r_2)$
Médicis
I've been instructed to solve it without the quadratic formula, could you explain how to do it without?
there’s no direct root so idk
like I just genuinly don't understand how this works
sorry if I caused some confusion there
you’re searching for some solution in the form $2x^2 -6x -13 = (Ax + B)^2 +C$
Médicis
yes!
develop the right part and try deducing what A, B and C are
well I know what they are I just don't understand how to get there
$(Ax + B)^2 + C = A^2 x^2 + 2ABx + B^2 + C$
therefore you have to search A, B and C such that:
$A^2 = 2 \2AB = -6 \ B^2 + C = -13$
Médicis
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,rotate
what my prof did was define a function $f(m,n)$ such that $$f(m,n) = g(m,n,k)$$ then you can fix $f(m,n)$ to a contant and then you are basically done
Bubbles
what i dont get is how you can define that function like that??
the function just gives the relation between the points
What's the infinite ramsay theorem
ramsay therom but for inf number of points
That tells me very little lmao
1 sec still typign
it says their exists an infinite complete subgraph that is monochromatic given a finite amount of colors
lemme find the defintino from the book
Oh hm okay then I have no idea how this would go
lmao
Hopefully someone else can help you lol
@halcyon ore Has your question been resolved?
<@&286206848099549185>
@halcyon ore Has your question been resolved?
Hello
hello
are you here to save me
@craggy heron any idea on how to solve 😭
or is it just wraps
yeah so you want to find another coloring
Yes
so f(m, n) kinda should use information about g(m, n, k)... well, we can aggregate it for all the distinct k and just pick a color that appears infinitely often
and use that to color f(m, n)
but that doesn't work yet
oh
another idea
define graph with vertices {a, b} of unordered pairs of naturals
{a, b} {a, c} has color g(a, b, c) obviously
{a, b} {c, d} ?
alos why does this not work
say you grab the ascending sequence from pairs, can you reconstruct the triples in the original graph?
hmm... maybe color it with {g(a, b, c), g(a, c, d), g(a, b, d), g(b, c, d)}?
oh yeah we can
yes
why not
just take any vertex that is included? nothing about that forces the triples to share that colour
or are we fixing a particular k
thats waht i dont get he just "erased" the k
we fix a k, and then we colour g(m, n) by the triple color f(m, n, k)
yeah. then we can create a sequence k1, k2, etc
okay that's probably it
and by ramseys we can create a inf sub sequence that is all the same color
not ramseys
pigeon hole
he might have messed up the proof idk
ill ask him abt it
would u mind if i sent another q?
usually recommend to start another channel, or #1021175428326633542 if you want it to last quite a while
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thank you for the help
oh yeah for each k we can see if it forms color 0 triples or color 1 triples
something following the classic ramsey proof where we try to construct both cliques at the same time
if it's color 0 triple, add it to the 0 sequence
if it's color 1 triple, add it to the 1 sequence
we never run out of vertices
so at least one sequence goes infinite
yeah
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What have you tried in advance?
what do you mean
these are the notes, im trying to understand them
I thought you were going to share your notes
no as in thats one of the excercises in the notes and i dont know how to do it and i want to know how to do the excercise so i can understand the ntoes
Let's try it.
How many total ways of selecting 5 balls from collection of 15 balls?
can it be solved with combinations?
binomial coefficient 15,5
Yes
oh well order matters right
First find the no of ways to select 5 balls from total no of balls i.e 15
then 15!/(15-5)!?
then do 15C5 for the denominator fraction
n!/k!*(n-k)!
Can we not have so many helpers lol
15!/(15-5)!5!
Aight
sorry
but thats when order doesnt matter
i thought it mattered for this
well not this problem?
Now, there are 5 red balls and 10 blue balls, you're selecting 5 such that 2 are red and 3 are blue. In how many ways you can do that?
i dont know
(5C2)*(10C3)
18c2 instead
(You can't select 18 out of 2)
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Just have time to talk about the iden tity for now
$a \ in S \implies \exists s ' \in S : as'=a (S=aS)$ and $a \in S \implies \exists s'' \in S " s''a =a$ ( as S=Sa).
this isnt enough to say the set has an identity is it
I have to show that the left and right identity are the same, right
wai
though tbh this doesn't guarentee that every element will have the same identity does it
I'll have to show that too
$aS=S=Sa$ tell you that maps $x \mapsto ax$ and $x \mapsto xa$ from S to S are surjective.
ExpertEsquieESQUIE
you good ?
@blazing coyote Has your question been resolved?
Sorry, in a class
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hey, i proved T(x) is differentiable and cont so it has MIN and MAX in the interval [-3,-1] but idk how to attack it since T'(x) is unworkable to find critical points
any hint (no full answer) will be nice
מה המצב 🙂
אחלה
אנסה עוד פעם פשוט קיבלתי משוואה של 2x + 1/(1+x^2)
do you know arctan differentiation?
1/(1+x^2)
yes, so arctan is always growing on R
right
ig R is real nums
Yes
but i have this 2x
+1/(1+x^2)
so i get 2x+2x^3+1=0
finding critcal points with that equation not so simple
intuitively <0
since 2x is larger
i suppose i need to prove that on [-3, -1] T'(x)<0
this should be easy by continuity
it has to do smth with T''(x)?
since T''(x) actually easier to work with lol
you can do it
is there a better way?
this is probably the easiest way
T''(x)>0 on the interval we mentioned so T'(x) is an increasing function on that interval so i can do T'(-3) and see if its >0. if it is then T is increasing on that interval
is that a good direction ^
maybe T'(-3)<0
you would want T'(-1)
because if its increasing before it, and its negative at -1, it must be negative before -1
why? T''(x)<0 for every x<0 then T' increasing for every x<0 . if T'(-3)>0 then ofc T'(-1)>0 since its increasing..
.
whys that matter its the same thing..
i think
Read closly
tryin
You say T'(-3) > 0 which it isn't
iam not sure thats y i have to check
youre right
i mean i get what you say
but theoretically if T'(3) was positive T'(-1) was also positive i think
Yes
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ah recurring function
stupid jee
just solve upto 2 or 3 recursions and see how the pattern goes
it will probabily converge into something
u differentiated both sides wrt theta?
i think that's a decent approach
u can also integrate both sides wrt theta from 0 to pi/2
just think about what terms are constant wrt the integral
i don't think u need to know extra theory
eg. if ur interating wrt t, you can pull out sin(theta)
integeral of sine term should be 0 since it is odd function
What about the f(t) and t now?
wdym
apply kings rule here by replacing the angle theta by negative theta (as pi/2+(-pi/2)-theta=theta)
try by it
and then add the integral obtained after this transformation to the original one
you might be thinking of ,rccw (rotate counterclockwise)
oh
i dont know much about it
is answer 1/2 ?
Yes

How
ahem
u need to check wether terms in the exapansion are odd or even
if its odd the term vanishes if its even then the integral becomes half of 0 to 2pi
@tardy kayak Has your question been resolved?
i keep getting 1 can you elaborate further
all the odd terms keeps on vanishing in the reccuring function and only tsin(t)dt term remained
ig you did it by king's rule?
idk what is king's rule
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what i did was integral -a to a of odd function = 0
integral -a to a of even function = 1/2 of integral 0 to a
ok ok
yes that works too
rest ill figure out
@rigid jewel close this channel mistakenly opeaned by you by typing .close
.close
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is there a need to get the present year ratio first?
also tell me what it means of last two lines
can you tell me the source of this question? like for what exam are you preparing with this?
SSC
ok 👍
Great man
@frail light Has your question been resolved?
Since, P and S are twins.
P=S
Also, P+S = M
And 3 years ago, the ratio was (P-3)/(M-3) = 2/7
You got three equations, three unknowns.
@frail light Has your question been resolved?
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What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
1
1
IS THAT A tokamak reactor on the bots pfp?
let me ask you something
how is that
in anyway
related to the problem i need help in?
<@&286206848099549185> heyy anybody free?
@calm coral 1
the bot is broken man
This is just knowing your basic facts. Reflections are rigid motions, so triangle A’B’C’ is congruent to triangle ABC.
A dilation with scale factor k multiplies all of the side lengths by k. So, the side lengths of A’’B’’C’’ are twice the corresponding side lengths in A’B’C’.
I figured it out
It's A
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can proofs have "subproofs"
i.e. if im proving smth can i posit something then prove the thing i posited inside the proof 
yeah that's called a lemma
thanks
you could factor it out as a lemma yea
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So I am having trouble conceptually understanding what the problem wants me to do
(currently am on a)
the column space would just be composed of columns, right? [3, 6, -9] and [-1, -2, 3]
I'm just not sure how constraint equations come into play and I'm not sure why there is a linear combination of rows of A summing to 0
So this is listed in the answers- same as what I got myself
but I just don't get how it leads back to the column vector, I'm getting confused
did you try to row reduce A
b is in the column space of A does not mean what you think it is
wdym
I could divide the top row by 3 which would be the last step but I don't see how it would help
my work so far comes from trying to reverse engineer the solution provided
yea that looks right
column space does not just equal the columns
I mean, you know, after you remove the reduncancies
So just [-1, -2, 3]
yeah guys I got it
thanks
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https://www.youtube.com/watch?v=iv-5mZ_9CPY 5:00 to 5:20
Diffusion models, CLIP, and the math of turning text into images
Welch Labs Book: https://www.welchlabs.com/resources/imaginary-numbers-book
Sections
0:00 - Intro
3:37 - CLIP
6:25 - Shared Embedding Space
8:16 - Diffusion Models & DDPM
11:44 - Learning Vector Fields
22:00 - DDIM
25:25 - Dall E 2
26:37 - Conditioning
30:02 - Guidance
33:39 - Neg...
can someone explain what the presenter trying to convey.
ive seen this video lol
we use physical diffusion processes in reverse to generate images from text
and hence diffusion models
specifically, why the diagonal is matching and others is not? also matching to what
he says the diagonal is "matching" and other entries are not
"the diagonal" correspond to matching image and caption
this is what he said, while others are not
i think this is called the co-occurance matrix, idrk
the diagonal is where the text represents the image
what do you mean.
so we need each diagonal entry to dominate the non-diagonal entries
text represent the image what do you mean
the text "photo of a cat" should be assigned to the actual photo of a cat, and nothing else
yes
so, the entries in the matrix are probabilities that the text matches the pictures
rather, they encode the probabilities with vectors
I totally agree. But why others do not match but only the diagonal
training
before training its totally random
but after (assuming we trained it properly) it should match
I mean if you look at the entry_21, it has a caption of cat as well as a picture of cat
it is matching, no?
i honestly have no idea
Damn
but the point is to make this matrix totally randomly, and then through training, the model will "learn" to match text to images
How
thats a much more technical question lol
the general idea is to evaluate the error, and backpropagate it through gradient descent
we need to start with a training batch of correctly assigned images to do this
do you have an actual math question tho?
no
i suppose these channels can be used to help you learn actual math as well (i might be wrong), but you shouldnt leave it open if youre done
I'm not done. someone has not answered my question yet.
everything starts out randomly, and then through the training process, the model learns to make the diagonal match and nothing else match
using this idea https://en.wikipedia.org/wiki/Backpropagation
@median cloak Has your question been resolved?
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lets say we wanna use an identity on (-4x-1)^2
For this to be less complicated
what identity
name which identity you wish to use
(you can use either one)
u can write (-4x-1)^2 = (-1(4x+1))^2 = -1^2 * (4x+1)^2 = 1*(4x+1)^2
ok and you want to use that AS IS?
yup
then a=-4x and b=+1.
but @amber bay's suggestion is good otherwise bc it cuts down on minus signs
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Calculate the three quartiles for a random variable
𝑋 with the probability density function
dont know how i should go about this problem
I'm not sure which function should be used when calculating each quartile
this didnt help either
67
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i dont understand what that 'D' is for in the differential eqn
i differentiated y=mx + c wrt x to get dy/dx = m
and thats it
Df sometimes refers to the first derivative of f
oh
D(Df) might be written as D^2f, the second derivative
Dy = differential of y w.r.t any variable if im not wrong
so lets take it with respect to x
oh wrt any variable?
okay
ur eqn would be y'' - 3y' - 4y = -4x
ye
By plugging in
i got
3m+4mx+4c=4x
i think now u have to differentiate y=mx + c and put values of y' and y'' in the differential eqn
I don't think that's helpful
You can right away follow something out of this
On both sides, you have a parametrization of a line
4y=4x-3m
y=mx+c
now we can compare?
And well, when are two such things equal?
You compare the left side to the right
You will get two equations out of this
no we can just match the coefficients right
yup
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hey i would like a hint with 2.
thats what ive tried so far:
the problem is with the red. if it was <0 then ofc it was an increasing function on the interval [1,+inf) so then f(1) was the min in that interval
Differentiate the function
i did
purple brackets
ah, didnt see
mb
when x is very big, sinx->x, cosx->1
meaning that f'(x)~=pi/x^2>0
f(x) is increasing
so if absolute minimum exists, it would be closer to 0
thing is i cant use ~.. anyways the answer in the book says that since for every x>1 f itself is >0 and f(1)=0 so ofc x=1 is the min in the interval [1,inf]
anyways thx for trying < 3
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o, didnt see it start from 1. Obviously when x>=1, 0<=pi/x<=pi, meaning that sin(pi/x)>0. In addition, (x-1)>=0 when x>=1. As explained earlier, that it is increasing, so the f(x)'s absolute minimum exists. For a absolute minimum to not exist, the f(x) has to decreasing to -infinity at some values. Furthermore, abs minimum exists at x=1
.reopen
✅
thx !
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how do I solve this??
I have tried integrating the whole function
wrt theta
but then I got stuck
is there any other way of solving this?
I didn't understand it
yea i did
what did you get
after integrating wrt theta i got $\int_0 ^{\frac{\pi}{2}}f(\theta)d(\theta) = 1 + \int f(t)dt + \int tf(t)dt$
oops
Put d outside of \dtheta
Prathmesh
yup this is what i got
limits of f(t) from -pi/2 to +pi/2
$\int f(\theta) d\theta = \int f(t) dt$
Miyagi
i got 1 but i didnt integrate wrt theta
i did simultaneous equations instead
do you have the correct answer
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Can someone explain what a regular language is? And what a context-free language is?
I'm doing a course on program analysis, and I was promised I wouldn't need any automata theory stuff but they just threw this at me in an assignment.
The assignment problem, if that helps
I don't want help with answering this. I just wanna know what exactly a regular language and a context-free language is. Preferably a description that doesn't use automata
(please tag me if anyone answers)
I might not be the best to answer this but:
- a regular language is a set of strings that can be produced by a regular expression (a finite state machine)
- a context-free language is a set of strings that can be produced by a pushdown automaton (it's like a FSM but with a stack)
I'm gonna need to learn automata theory huh
Well, you probably don't need to if that's the only problem you want to answer; one is a strict subset of the other
I mean I imagine regular is a subset of context-free
Cuz an FSM with a stack should be able to capture anything an FSM without a stack captures
It's not clear to me what IVP means? Interprocedurally Valid Paths? Did they really write IVPaths paths?
Ok well I'm not familiar with these terms (initial IVP, program points, call-strings, call points)
Ah that's fine, I really just wanted to know what regular language means
I imagine, since (2) says "of call-strings along initial IVPs" while (1) just says "of initial IVPs", that (1) is the context free
I can describe the terms to you but that isn't really relevant to my question
Fair enough
I just don't know if that's enough justification
And it just feels unsatisfying to use the containment
Me neither, maybe ask in https://discord.com/channels/268882317391429632/1313711459385081876 though
Fair maybe I will closer to the deadline
Gonna keep this open in case anyone else wants to comment
To give a little more context, combinatorial logic circuits are contained by finite-state machines which are contained by pushdown automata which are contained by Turing machines
Interesting. Somehow the only thing on that list that I've done are turing machines lol
And even that was very limited
You start with "instant output given current inputs", then add a graph of states and transitions, then add a stack (which you can only read and write to at the top), then you switch from stack to tape (which you can access anywhere without losing data)
(that's my understanding anyway, I'm no automata theory expert)
Well you certainly understand it better than me lol
But yea thanks. Ig I'll ask my prof tomorrow and then ask #theoretical-cs
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hello,
So I have an exam in a few hours and I was running through practice problems online. My brain might be fogging right now because I couldn't figure out what went wrong and how I got the boxed answer a^2-a-3 instead of -19/8
The topic is about rational equations and I'd appreciate it if someone would point out the thing(s) I did wrong
this was the problem for referenc
what I did was eliminate the lcds by multiplying the whole expression with the denominmators
wher
sory bad handwriting
Your approach is correct
I was rushing through
That's good to hear
do you think it was a problem with the answer key
ooh I see
Do you have any tips regarding rational equations? or is there not much to say about the topic
Not much to say
on the second line shouldnt it be (a-2)(a+2)?
wait lemme double check
o I merged them
okok, thank you for the clarification
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$\int_0^1 \frac{\ln(x)}{x^2 - x+1} dx$
artemetra
no idea how to go about this
,w \int_0^1 \frac{\ln(x)}{x^2 - x+1} dx
bruh
You can multiply the numerator and denominator by 1+x and then series expand the denominator
That’ll lead to some series which are hopefully simplifiable
,w integrate (ln x)/(x^2-x-1) dx from 0 to 1
,w \frac{pi^2}{5sqrt5}
Typo?
possibly..
This is a pretty famous integral
do you mean with the x^2-x+1 or the x^2-x-1 version?
[ \sum_{n\ge 0} (-1)^n \int_0^1 (1+x)x^{3n}\log x\dd{x} ]
kheer257
The latter
True..
You can likely get a “closed form” for this using trigamma functions
you mean the former lol
(x^2-x+1)(1+x) = (x^2-x+1+x^3-x^2+x) = x^3+1
(x^2-x-1)(1+x) = (x^2-x-1+x^3-x^2-x) = x^3-2x-1
I take it back - this does reduce quite nicely
No, the latter is famous
My method was for the former
ah alr
The latter is solved in a different way
Does it
It’ll still be nonelementary I think
at least the integral inside the sum does
Yeah but it’s concise
$\int_0^1 x^k \log(x) dx = -\frac{1}{(k+1)^2}$
artemetra
if I'm not mistaken
Yes
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@fringe reef You good?
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i found the equation for the parabola at the y = 5 plane , i just dont know how to continue from there
send
js imagine z as the dependent variable and x as the independent variable
like what u normally do for when y is the dependent one instead of z
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is xy+2y=1 a function
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Need help


Ok ignore what question 9 asks. But for 11. ive encountered many questions like it on tests and always get it wrong.. im pre calc grade 12 level i understand the first answer which is 3 but not the 2 second one and i understand the 3rd one and 4th
anyone pls
@desert relic @odd fulcrum 😄
Okay
im sorry bro I cannot help 


Also @shut harness please don't ping individual helpers, like me and Infinium are chill but some of the helpers are very particular about this :)
What does ping mean?
Like '@'ing someone
like you just did @{somebody}
Okey sorry
nah its good, some people are adiment about it though.
Nah you're fine dude, we don't mind it much, but some of the others are just kinda serious about it
Well I looked it up, it says to get the original function and transformed function equal to each other and then find their value
Like f(x) = y^2
So for the first one, f(x) = 3/sqrt(f(x))
y^2 = 3/y
y^3 = 3
So it has only one solution, hence only one point
Now I should say that I'm shooting shots in the dark here, I've got no clue if this is the correct approach
The only actually reliable stuff which I've looked up is this, the rest is me rambling
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backing this up ^
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Is the space of non-parametric functions strictly larger than parametric functions? Ie are there functions that can be described non-parametrically, that cannot be described by parametrically? (This is for my own edification, and a simple counter example would suffice)
Ik that it is generally assumed to be true, but my intuition says that anything can be modeled parametrically
Good follow up, i am not sure. Citing this response to googling my question, an infinite dimensional or infinite number of parameters. Which implies that parametric (finite dimensional theta) is nested by non-parametric models, so the answer is yes. But not for reason I initially thought
Now, i need to review gaussian process regression where i saw this last
Anyway
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yo i have a question, just want to confirm my work is right
please send it here
heres my answer, im sending question 1s
Georgia has 15 apps on her phone. Of these apps, 10 are connected to social media, seven are games, and five are prayer/meditation apps.
wait what are questions a)/b)?
you seem to not have considered prayer/meditation apps in a)
your conclusion is correct though
so everything is right, just need to add the prayer/mediation apps to a?
for completeness, I would say so.
alright, thanks
your Venn diagram is also missing the prayer/meditation app circle
(if it was drawn as part of the question)
how would i draw it instead
three circles
not two
and you probably no longer need the rectangle outside, but no harm keeping it I think
3rd rectangle?
put however much you found out
I haven't fully worked it out yet, so can't confirm
you may send it, if I'm not available other helpers will come in
but either way, sure
you've got to show the original context, mate
oh it's basically a toy caterpillar that has a 50/50 chance of either going to red or blue
lowk forgot to send that lol
then what does it mean hitting red twice? I think the original question would still help here
Connect the caterpillar scenario above to a question you would ask related to probability.
basically the probability of the caterpillar not hitting red in 2 attempts
and instead going to blue both times
this was the initial question, i made that one up
so in 2 attempts, the caterpillar turns blue
yeah, both times
in that case, it's more straightforward to just calculate the probability it hits blue both times, right?
if you want to do inclusion-exclusion, you'd have to account for any event where at least one of them is red
i'm allowed to do either
wouldn't that be 1/4
the red text is the feedback I recieved, i'm not exactly sure what i'd change
and it'd be 1/4. try listing out the possible events (R = red, B = blue)
red red
red blue
blue red
blue blue
so the probability of it not being red twice is 3/4
so the answer is right? but something with P(A') is wrong?
^
when I asked, you said that both times must be blue
so is it "at least one time not red", or "neither attempt is red"?
(also, this is why i asked for the og question)
this is the og question
"what is the probability of the caterpillar never hitting red"
thats the choice i made
neither attempt is red
then your P(A') should be 3/4, because A is the event where neither attempt is red, so A' is the event where at least one attempt was red.
ohh, so where i wrote P(A') should be P(A)
