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the algebraic multiplicity of lambda = 2 is 1 and its geom multi is also 1 is it not because it has one parameter
but algebraic multi for lambda = 1 is 2
does each algebraic multiplicity for both eigenvalues have to match?
Brother
something from linear algebra at uni
yes i know
i just dont remember any algebra
if u give me something it might jog my memory
oh it's not the algebra you learn in school
algebraic is the integer k for (b - lambda)^k where b is an eigenvalue
why would it have to match
you can see that the algebraic multiplicity is different for both
no, the correct result is that algebraic multiplicity geq geometric multiplicity
but the algebraic multi and geo multi for eigenvalue 2 are both 1 arent they
that's not a problem
it's ≥
,w {{1,0,1},{0,2,0},{0,1,1}} char poly
oh wait for the eigenvalue 2? ah
no...
@topaz raft he is asking you politely to accept his freind request
tho you probably at least mean the correct thing
what do you mean?
that sentence is wrong
well im saying like the number of repeated roots ig if u call it that is the algebraic multiplicity
algebraic multiplicity is number of times the root is repeated in a characteristic poly
which is the number k here which we already found for E1 and E2
wait im confused whats ur question now
im asking why its not diagonalisable
for eigenvalue 2 its algebraic and geom multi are both 1
what says its not diagonalisable?
if the algebraic and geom multiplicity is the same it should be no?
right here
thats my question
why does it have to match?
what?
are you asking why gm == am for it to be diagonalisable
well look
that comes from the fact that the dimension of the eigenspace for v1 and v2 is 1
i believe the eigenvectors form the diagonal matrix
if we look at eigenvalue lambda = 1 it has AM = 2 right
are we using this fact here?
or are we talking about something different
different
this theorem
a matrix A of n x n size is diagonalisable if each eigenvalue has AM = GM
ah I see okay
so each eigenvalue in this case 1 and 2
yes I see now, so that's just another rephrasing
no, the geometric multiplicity is 1 for lambda = 1
how?
but the algebraic multiplicity is 2
ye algebraic multi is 2
,w {{1,0,1},{0,2,0},{0,1,1}} eigenvectors
how many eigenvectors did u find for each value
,w {{1,0,1},{0,2,0},{0,1,1}} eigenvalues and eigenvectors
so if for eigenvalue 1 if it had geo multi = 2 as well then it would be diagonlisable?
yes
that's not the case here however
yes
thats just by definition
,w eigensystem {{2, 0}, {0, 2}}
am must = gm
this is a case where AM = GM = 2
they didnt write the working out for lambda = 1 eigenvalue so they only showed the geo multi for eigenvalue of 2
but ig if u do the working out then
youll get one parameter as well?
ah okay so it's a problem with the working
for eigen 1
find the eigenvectors for lambda = 1
yes
i see
sorry i didnt realise what you were asking ahaha
if you sub in 1, try and find the eigenvectors
.solved
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yeah cause you get
(0 0 1)
(0 1 0)
(0 1 0)
and when multiplied by (x, y, z)^t, you get (z, y, y) so that forces y = 0 and z = anything, which is 1 dimensional
✅
\ = 2 has geometric of 1 and algebraic = 2
okay ur lecturer wrote it wrong lol
the underlined part is wrong
it should be "geometric multiplicity of lambda = 1 is 1"
ok yeah i was confused, cuz i checked the working it said GM = 1 but the AM should also be 1 for eigenvalue of 2
ur lecturer is silly
thats very unfortunate
also funny no one in ur class picked it up
is this unsw?
js maths
like what this class is?
unsw would be more rigorous lol
in their working out a tleast

ohhhh
nice, UQ is a nice uni but I think that combination is miserable
CS in particular has a shortage of good lecturers
no honestly uq is terrible
cause they could make 2x the pay working in industry
its actually embarrasing how bad some of the stuff is run here
maths is aight, unsw has a much better math dept but physics and chem is goated for usyd
lowkey makes me regret leaving adl
that's why I ask
cause you get compared to UNSW all the time
ye
hopefully the maths department is decent
doesn't need to be world-beating
like do you have decent course options, especially for 3rd year
yea theres plenty of stuff, unsw has a lot more but let me check
do lecturers and teachers give good explanations when questioned
yea the lecturers are pretty good at explaining things and the students pick up on it if theres a mistake so they can correct it
engi at unsw is worlds better tho^^
ah it's like my uni then, we're definitely very mediocre for pure maths course selection
same everyone's just so warm here
ofc ANU is the best
UNSW is probably on their level
and everyone else is below
BAHAHA JUST LIKE MINE
why do even 2nd year maths electives only get offered once a year
if you start midyear you're screwed
adl uni?
i dont think anu is the best
these rankings
i realise now
are complete poo poo
the only thing they tell u about is research output
yes
not actually about how good the uni is
exactly
even for research yk you've got to find a fricking supervisor
i didnt go to anu for cs because their cs program is outdated as hell
Adelaide only offers geometry-related topics for pure maths research
if you want to do number theory they'd make you do geometry with some application to that
yea ive seen
really? wow
adl maths department is a bit lacking i think
yea imo, i did a tiny bit of research
students have gone to Cambridge and shit
but yeah that's not cause of the uni I feel
yea i think its not the uni, its just people are cracked
I switched out of majoring in maths
tons of ppl in adl got into the quant firms tho
they may have something good going on in cs
ah yea same at uq
my friend told me they don't teach well
yea possibly
i think they have a summer program
which is very very good
for something
but yeah I think the societies are quite supportive regarding work opportunities
my friend just got an atlassian internship
have no direct experience but that's my general impression
at least smth is going good
maths society's fairly dead at ours
oop
if you look at the UNSW maths society, not to compare, they're really really active with what like 5000 members
mhm
are you a first year?
3rd year lol
oh what
yeah
that's very true
i have unsw math notes for first year and the pdf they use and its so much more rigorous and detailed compared to usyd even comparing with advanced and regular stream
i thought u were asking eigen questions as a third year ahhaha
I've forgotten a lot of 1B so I might need to actually lol
if there's some algebra application idk
❤️🔥
Yo Sydney uni discussion and no one pinged me
u know before i think 2 years ago linear algebra and calculus were separate credit point courses
but they combined them
that's not necessarily a good thing
so linear alg and calc is one whole course
oh no
yeah it's an Aus-wide trend
so that means that IB students can't get any maths credit
we have lin alg and calc separately
since they obviously don't learn LA, no one does in high school
oh that's nice
actually Adl doesn't do discrete maths
we do sequences, series and lin alg etc sem 1
the prof left one year and the course just died
then odes and multi var sem 2
lmao lustri the goat
They learn matrices
yes this is one of the big sillies at adl imo
different
Goat fr
not same
I think they cram some of it into 2nd year algebra
shut up you go to Macquarie
Fuck me dead why am I here
Why am I here…just to suffer
after i saw that law video
Ur just wrong tho
hell no
You are objectively wrong in this subjective competition
I’m sorry to tell you that
I know it’s hard to face reality
unsw notes are pretty good
From what I can tell you can actually learn from them
Not so much the usyd notes
ya they cover a lot of things in lot more detail
Those always seem to be a mess
tell me why tho
they have trimesters so they suck
no one uses our notes lol
simply cause no one has ever heard of them
theyre getting rid of it!
I believe ours are good
and @gritty copper is a big fan of the trimesters hes a unsw boy
oh, 2028
he says he likes it cuz hecan overload on credit or some bs
wait did you go to a private or public school?
just curious
public
selective?
na
interesting
our school is pretty good at specific hsc subjects tho
we'll all be drowing in hecs debt at the end
does it matter which uni we go to

at least we all get 20% off
thanks Labor!
wait so are you actually doing a maths degree?
for 2nd year physics and beyond ya
@unkempt drift oh yeah they banned calculators this year for maths
🤣
someone asked on our forums this
...
lmaooo
hey man
wsg
hows it going bro
ours start next week
die
i dont like you
take me to poker night some time
june 20 my last exam i think or its 21st ill have to check
Guten Abend <@&1345378535463718943>
Just here to let everyone know that we have a poker tournament week 3 Friday with collaboration with Elsoc, Quantsoc, Ramsoc
Details:
DATE: 20th June (Week 3 Friday)
LOCATION: Tyree G16
ENTRY: $5 for UNSW students, $10 for non-UNSW
TIME: 3:30pm Start, 5pm Rego closes. 5:30 - 6pm food break. Finishes late
PRIZES: $500 in prizes to be given out!
CAPPED at 100 players!!!
Signup at https://shorturl.at/Ax2Ph
More details regarding weekly poker nights will be announced soon. We are all excited for term 2!
(There is no week 1 event.)
shiii i gotta photoshop my ID card to pretend like im unsw
"$10 for non-UNSW"
im a broke uni student i need those 5 dollars
u ever win a game yet
bruh
is it nice
its the math department
the other wing is school of built environment
thats us
smaller afaik?
u gotta give me a tour one day bro
if our schedules align
waterrbeam
tbnd boy
come hold me accountable in vc 🐑
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You mean the red centre
Goated building btw
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yeah but that doesnt help him navigate a map
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please help fast i need to complete my dpp
@dull token Has your question been resolved?
did you try plugging in alpha = x + iy and 1/alpha_bar into both circles
?
!show
Show your work, and if possible, explain where you are stuck.
i am on pc btw
and?
?
type your work here like everyone else does
ok
2 min
alpha lies on (x - x_{0}) ^ 2 + (y - y_{0}) ^ 2 = r ^ 2 ) eq 1
(1/aplha) = (aplha/mode(alpha^2) lies on (x - x_{0}) ^ 2 + (y - y_{0}) ^ 2 = 4r ^ 2 eq 2
these two are first two eq ?
do u want 3 and 4rth also ?
Uh i recommend u use `
like this
don't see where you did this yet

There's gotta be a better way than to just solve 4 equations
!noans
The purpose of this server is to help you learn, not to hand out answers. Do not ask someone to give you the answer directly.
great you think of it then
ok
the question is hard that the reason i am here
coz i usually have no problem solving locus questions...
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How do i answer this question?
Question 6.) If p,q are primitive statements, use duality theorem to prove that
(p →q)∧(q∧p∨True) ≡ (p∧q)
I started but idk where to go from here:
I think (p →q)∧(q∧p∨True) ≡ (p∧q) is not correct?
take p=False, q=True
Oh that’s what’s given to us
But that’s also what I thought
left side evaluates to true but right side evaluates to false
So you’d just write that it’s not valid?
yeah the question is not correct...
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Please help I'm very close to solving this problem
I think the denominator of the probability is 64 choose 2
and I also that there are 4 cubes that have exactly two painted faces
but i dont know how to write it in a way so that the numerator shows that only 1 of the 2 unit cubes chosen have 2 painted faces exactly
oh wait 36 choose 1 * 4?
so is the answer 1/14
can someone please confirm before i submit it
<@&286206848099549185>
How many cubes have exactly 2 painted faces?
yeah i did my explaining above
Correct
How many cubes have no painted faces?
36?
what how is it 4.36?
4 choices for the one with 2 painted faces
36 choices for the one with no faces
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if I know a number is 1 mod 5^n and 0 mod 2^n, how can I find the value mod 10^n ?
use the chinese remainder theorem
can I use p-adic numbers?
yes using Hensel’s lemma
But I think crt should be easier? Depends on what you rather use
ok
is this correct btw
no
oof
how did you factorize that
2^k*5^k = 10^k ?
so did i make a silly mistake
Seems cool although would try this as an alternative as soon as I got it right the “conventional” way because teachers can be strict on solutions not made the way they were in class
ok
2^(4*5^k) ≠ 1 mod 5^k+1
so the normal way is crt?
i thought the totient of 5^(k+1) is 4*5^k
For me, it is, idk what you were taught?
i am self taught
idk how to use crt lowkey
this is what I have, ig I need to find m or n?
or figure out which m/n make this equal
but you can’t raise to the power of 2^k-1 while preserving 1 mod 5^k+1
I recommend either https://www.math.cmu.edu/~mradclif/teaching/127S19/Notes/ChineseRemainderTheorem.pdf
or YouTube
1 thought 1 mod anything powered is still 1
because 1^x = 1
if u write $2^{10^k} = (2^{4 \cdot 5^k})^{2^{k-2}} \equiv 1^{2^{k-2}} \equiv 1 \pmod{5^{k+1}}$ it mean that $10^k \mid 4 \cdot 5^k$
tm
or maybe im saying full shit 😭
Think so yup
Gtg, if you can’t resolve it tonight dm me, I’ll be answering in 8-10 hrs
@frosty leaf Has your question been resolved?
@frosty leaf Has your question been resolved?
@frosty leaf Has your question been resolved?
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Any ideas what to do niw
,rccw
Why
How did u know
It 's possible
let $f(x, y) = x^3 (x^2 + y^2)^{-3/2} - x (x^2 + y^2)^{-1/2}$ and check lim f(x,0), lim f(0,x) and lim f(x,x) when x->0
tm
there is a problem with lim f(x,x)
Am i just trolling right now
Also how did u know to look at those curves
So fast
<@&268886789983436800>
i have -1/2^(3/2)
if we want to calculate the limit just make sure it has no problem about existence lol
Yes i get that but how did u know it has a problem specifically at f(x,x) so fast
Where exactly
because this is frequently where the problem of the limit arises
when we take y=x
for f(x,x)
Oki
u need details ?
Let me try again ok

Yes
Idk i got something wrong again i think
,rccw
(x^2)^(-3/2)=x^-3
Omg
and (x^2)^-1/2=x^-1 and then everything simplify there is no more x
True
its ok its 3 am for me idk what’s ur time zone 😭
you’re forgiven🙏🏼
Ok i get it now
Thx so limit doesn't exist
yep
.solved
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Wassup bakas
I need a chronically online tutor
@heavy sundial we're not a tutoring service. we're volunteers who can help with specific problems or topics
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!status
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
ok
i calculated the total angle of c to be 90
because semi circle
but
then i calculated 180-98 getting 82
but now what do i do
That doesnt work
Oh wait
You mean to find f + the third angle in the left triangle?
Yeah so use algebra to find the angles
No the 180-98 is 82
have you learnt angle at center = 2 times angle at circumference?
that might be applicable here
No thats just the semicircle bit
I dont think you can use it from there
for angle f: OA = OC. An isosceles triangle can be formed.
Angle AOC is the angle at center.
Angle ABC = e is the angle at circumference
If you take 2 points on the circle and connect them each to the center and some other point on the circumference, the angle at the center is twice the angle at the other point
yeah
the angle at he center is 180
i got that
but why is it an isocles
if there is not 2 radiuses
the angle at the center is not 180
but the angle at the circumfrience is 90?
look at it from point b
since its a semi circle
okay yeah for that one the angle at center is 180
yeaah
but for ABC the angle at center is different
angle ABC is the one we're interested in
yup
are you sure you calculated this right?
yeah'
where are you getting 82
no
180 - 131 is not 59
sorry 49
and then you also mess up your f
what angle?
=96
specifically?
AOB
yup
wrong
there are two easy methods i can think of
one doesnt need the angle at center = 2 times angle at circumference property at all
96 + 42 = 138
138
ok
anyways
otherwise fine
there are two easier methods
no
yh?
listen there is a way easier method
First method, using angle at center = 2 * angle at circumference, angle AOB = 84. OA = OB so angle OAB = angle OBA. Hence x = (180 - 84)/2
Second, use your right angle in semicircle property. CBA = 90. x = 180 - 90 - 42..
y'know about the properties of angles in cyclic quadrilaterals?
yeah
name them
no...
yeah
idk abt c
what angle is opposite to d?
96
so 96 + d = 180...?
is C 101
c*
??
why?
because c is opposite to 180-101
wtv u get for that answer
u subtrnce anyways
so u get 101
no
juist some friendly advice man don't rush it
@sour yoke if at any point you feel these questions are too easy i got some harder ones if you need more practice
@sour yoke Has your question been resolved?
could angle ADC be 90 degrees since u can divide into semi circles?
@open atlas
<@&286206848099549185>
it is
thales theorem
ok
w=45
AOC=180
Is T also not equal to 32
due to same segment theorem
<@&286206848099549185>
b=a?
ADB angle is 90 due to semi circle?
yea
you need answer or help
wow thread still alive
xD
np
did he get a and b
prob
no
whats your answer
thats from before
they're not the same right?
theyre not the same
ok
here i got the angles of bot triangle as 40 70 70
now what do i do
<@&286206848099549185> 😭
dude you have someone helping you, you dont need to ping helpers
yea
its 70
i think its not calculateble under current circumstances
wdym?
there are too less information
triangleABC equilateral
unless there is more and you didnt show
ok this is just harder
slow down dude
did they give that CB or AB are tangents?
alternate segment theorem
yea thats a good question
For q1
there is no text in the question
alternate segment theorem
only the question
then it is impossible.
told you
oh
Don’t move onto the next problem without finishing the previous
xD
alt. seg. theorem only works if they have tangents
yea
(not given)
I thought AB was a tangent
yeah
Okay these questions are weird
what ab q3
Again, it looks like we have tangents
I think we should say they are tangents if the problem is unclear
tangent is not clearly shown though
i think i'll skip these and practice the other questions
That way at least we have an idea of what the answer is if it turns out to have one
bec in my exam im getting pp which define if theres a tangent
AB doesnt look like a tangent imo
It looks like we can solve it if they are tangents*
look at the bottom
I know
i think it's CB
But if there is no other way, we must assume the question is faulty, and in that case we should just make the smallest changes possible imo
im going to practice tangent from smwhere else dw
maybe tell us that youre leaving that question beforehand
if AC is a tangent though, then 4a + a + 90 = 180 (angle sum of triangle)
guh
why 90
because is 2 straight lines?
tangent perpendicular to radius
OB is the radius, AC is the tangent, angle OBC = 90
yhh
anyways what do you get after solving this?
is this still that one or another one
@sour yoke you still here?
@sour yoke Has your question been resolved?
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should i check D?
no, the minimum could be very local 
what a trap
If it were a global minimum, it'd be true
But "local" just means there's some "circle" around this point I could draw where that point itself is the minimum
The circle could be tiny af
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The numbers 1, 2, ....., 9
are randomly placed into the
9 squares of a 3 x 3
grid. Each square gets one number, and each of the numbers is used once. What is the probability that the sum of the numbers in each row and each column is odd?
What have you tried in advance?
lol
Alright
9! on the bottom?
Can you draw me a 3x3 grid first?
okay, in what condition will you get an odd number after adding up three numbers?
odd odd odd
nope, there's one more :))
correct
Alright, now we can work on it
Take out the paper with your grid on it, and try to fill it out with any of the solution
uh
wait the middle has to be odd
and the corners are even
yooo
wait
is that right
yoooo
bro
Can you take a pic of it?
uh nah im on pc
wait
so 9 choopse 4
times
9 choose 5
wait
nah
its just
9 choose 4
time
5!
/9!
wait
i understnad it now
uh
ys
lemme draw
cuz 1 through 9
is 5 odds
and 4 evens
so it has to be like this
good start, but you over looks smth
oh shoot
you've already calcualted it
no wait, let's not calcualte anything for now
ok
Do you find any pattern here?
yes, that's the whole point
We want either OOO or 1 O in a row or column, right?
yes
And we don't want two O in a column or a row, right?
yes
There are five O on the board, right?
yes
Right, so we want all the Os to stay together, or else there must be two isolated O staying together
yes
wtj
look, if we banish that guy to the marginal of the grid, there would be three rows/column that does not fit our requirement
2*
oh
That's why we want all Os to stay together, while maintaining a T / cross / L shape simultaneously
yes
Alright, how many cross and T are there?
wdym T
oh shoot
I saw this problem yesterday but with 4x4, they did it by showing the 3x3 area decides the letters for the rest of the grid, and counting how many ways that can be filled in (2^9)
yes
no, wtf
what
nvm, you're correct, I've verified it with a senior helpful
Anything else you wanna ask?
Oh wait it’s numbers 1…9 nvm sorry (about my method)
what does 9/ 9 mean?
9 / (9 5)