#help-42
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not able to find a method which involves less calculation
Or lagrange interpolation if you don't mind the time it takes
never heard that in my life
no
mb sorry let me try again
Given n coordinate pairs (x_i,y_i) you can find a unique polynomial such that P(x_i)=y_i
That's called lagrange interpolating polynomial
not getting it dude sorry 😔could you help?
oh
but ive not learnt that so i dont think im supposed to use it
After you find the expression of P you can evaluate it at 6
Oh okay you can do what Denascite said Ig it works as well
what about it do you not get
like what to do with that
You have all the roots of your polynomial
just intuitively speaking
the roots are 1,3,5,7,9?
given the values you can indeed just find out the formula of g easily
no
Yes but for g(x)=f(x)-2x+1 so you can factor out g
Is this group helpful for engineering students?
of g i mean
factor out meaning?
Meaning write g as a product of monomials
oh ok so
Guys?
Gotta go I've a physics exam
(x-1)(x-2)(x-3)(x-4)(x-5)(x-alpha) + 2x + 1 = f(x)
oh man
sorry i meant 1,2,3,4,5
thats false
g is also a polynomial of degree 6
and has leading coefficient 2009
right so some unknown root alpha
yes
oh but what does this mean
it means that 2 is a double root of g
.
is it correct now?
yes
so now x=6? 😭
yes
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why cant i do 9C3 = 84 ?
If you select all three points from a single line you do not get a triangle
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Hiya I am having quite a simple issue. Its to do with integration but im strugging to see how google gets between two points. Pictures are below
This calculus video tutorial provides a basic introduction into u-substitution. It explains how to integrate using u-substitution. You need to determine which part of the function to set equal to the u variable and you to find the derivative of u to get du and solve for dx. After replacing all x variables with u variables, find the antideriva...
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Does anyone have any idea of how the hell im supposed to calculate this without a calculator??
$\sqrt{\frac{2\cdot 6.67 \cdot 10^{-11} \cdot 7.5 \cdot 10^{22}}{1.5\cdot 10^6}}$
Ann
this?
yes
well you can handle the powers of ten separately and the mantissas (ie everything else) separately
pretending 6.67 ≈ 6.666... = 20/3 seems to also be a good idea
so then that all becomes $\sqrt{\frac{2\cdot \frac{20}{3}\cdot \frac{15}{2}}{\frac32}\cdot 10^{-11+22-6}}$
Ann
which is more amenable to manual solution
why would they ban calculators for this q tho
that or you recognize 2*7.5/1.5 = 10
I genuinely don’t know, they banned it for all of the exam as a whole
appreciate the help btw, ill give your method a go.
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This is the graph of y=-sin(x/2)
But if the domain is from 0 to 180 then,
we'll only take this part, right?
This part
π radians = 180 degrees
✅ assuming 0 and 180 are degrees
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For the function F, it holds that
F′(x) = f(x)
and
F(−1) = 4.
Determine F(x) if the graph of y = f(x) is the line shown in the figure below.
its in swedish so i translated it
Can you try figuring out an equation for f(x) @marble edge
no i cant im too dumb for it
do you not remember anything at all
ok start with the points (-2, 3) and (0, -1)
mx+b
nah we solve it with kx+m
i did check
and what did you get?
what
they deleted my message for nothing
i cant say low
i
q
wow
bro what is this censorship
im leaving giving up in life
cya guys
it might have been a mistake. can you try sending it again?
😭
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,rotate
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when solving geometric problems with the roots of a complex number to form a polygon, how do you find all of the individual roots of unity?
I understand w = e^(2pi/n i), but on all of my sheets and stuff it just says "if you know one root of a complex number with n roots, then you can find the other roots by multiplying by an nth root of unity"
I don't understand what it means by multiplying the root by an nth root of unity
multiplying by what you called w
so if a number z has some nth root r then the others are rw, rw^2, rw^3, ..., rw^(n-1)
oh, right, okay. I think that makes sense.
because if I just multiply the initial one n+1 times it seems to loop back around to the first root of unity
just n
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Hey so I have this question and basically I just confirmed that F = curl G. But my question is when I then calculate the flux do I use curl G instead of curl F?
like should it be double integral curl G * ds?
nvm I found some article for it
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<@&286206848099549185>
What have you tried?
um
well I know the int is 14
but i dont know what x value is x
anyone
hello
do you know integration by parts
Zentisuincarnate
its $\int_{lower}^{upper}$ btw
nilo
if you know integration by parts just apply it to this problem set u=x and dv=f'(x)dx
that should give u a good start
you have all the info u need
$\int_{2}^{5}(x*f'(x))dx$
Zentisuincarnate
$$u=x, dv = f'(x), therfore , \int_{2}^{5}(udv) = uv - \int(v) du$$
Zentisuincarnate
yeah try to evaluate it now u set it up correctly
$$u=x, dv = f'(x), therfore , \int_{2}^{5}(xf'(x)) = xf(x) - \int(f) *1$$
Zentisuincarnate
actually since its a definite integral you need to include the bounds for the first term $\int_{2}^{5}xf'(x)dx = \bigl[x,f(x)\bigr]{2}^{5} - \int{2}^{5}f(x)dx$
nilo
literally just evaluate that i set it up for you
yeah right
Zentisuincarnate
that’s given to you in the problem
Zentisuincarnate
oh 14
yeah
@thorny steeple Has your question been resolved?
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Im having trouble with AP stats. I dont know when to use a binomial probability. im guessing you DONT calculate a binomial probability when you're trying to guess what the next outcome would be? But you WOULD use it if you know the number of trials?
The main question I’m stuck on
well you would use whatever probability distribution is underlying the event for figuring out the probability of a single trial
then you can use the binomial distribution (along with the knowledge of the probability of a single trial) to find out the probability of something happening across multiple trials
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why use the limit test if it already converges due to p series
i dont need to use it right
(n+1)/(n^3+1) looks an awful lot like a p-series but formally is not one
LCT is how you formalize the resemblance
why i compare it to n/n^3 which is bn and is 1/n^2 which converge. and since bn converge an must also?
sorry, i don't understand your question.
are you asking "Why do we need to make a comparison at all?" or are you asking "So does sum a_n converge?"
ok i made comparison of the (n+1)/(n^3+1) to n/n^3
and n/n^3 is bn
and it converges so shoudlnt (n+1)/(n^3+1) which is a_n also converge
... yes, sum a_n does converge.
ok so i coulda used direct comparison instead of limit?
uhh
thats what i did
wait does the inequality (n+1)/(n^3+1) <= n/n^3 actually hold?
as in do you have proof that it does?
cause i actually think it doesn't, as-written
(though you could tweak it to make it work still...)
ok how
"Sorry, I don't have proof that that inequality is true. Also, I decided not to give you a straight answer to your question."
bruh ima just use limit then
it fails rather badly for n=2
ok so limits only way
yeah but my point is OP is bad at communicating with me in this moment
whenever the numerator is also adding or subtracting something?
@unborn stone Has your question been resolved?
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Hello hello
I want a
Application
That can calculate anything I wrote
Any sketches
Immediately
Is there anything like this
Calculate what I wrote
Microsoft
Apple
Applications
you are asking for something that is like Wolfram Alpha but also does handwriting recognition?
@median cloak Has your question been resolved?
Yes
I cannot really type any mathematical operations.
I can only draw
mmm
yeah i dont think anything like that exists, unfortunately
as far as typing math stuff goes, there is this markup language called LaTeX which all mathematicians use
which is also what @potent lotus runs on
@median cloak Has your question been resolved?
it might be easier to learn latex, a coding language, or how to use wolfram alpha, than find a tool like this right now
though with AI improving, who knows honestly
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how would i solve these
or what can i search up to understand this
Do you know the sin and cos of standard values?
Do you know the identities $\sin(x \pm \frac{\pi}{2}), \cos(x \pm \frac{\pi}{2}), \sin(x + \pi), \cos(x + \pi)$
@mellow harbor
This trigonometry video tutorial explains how to use reference angles to evaluate trigonometric functions such as sine, cosine, tangent, secant, cosecant, and cotangent with positive and negative angles in radians and degrees.. You need to have a good understanding of right triangle trigonometry, SOHCAHTOA, 30-60-90 triangle and the 45-45-90 tr...
This should help
YAYYAYYA
thank youuuuuuuuuuuu
Ur welcome
?
Yeah, try going through the vid
u'll get it
Since you know the unit circle you can also just try using it
You'll see a relation soon enough
if you look at the sin and cos values of standard angles on the unit circle
can u come back and explain please 😞
im sorry
in the video, i got really confused after he started drawing the triangles and labeling the sides
😭
but im looking at chatgpt
and i dont understand the thought process of -5 pi/2 +2 pi = cos(-pi/2)
Well, do you know what $2\pi$ is?
@mellow harbor
nope
$2\pi = 360^{\circ}$
@mellow harbor
YES
So it just gets back to the same point
SO SO THEN IT CANCELS OUT ITS LIKE BOOM -PI/2
Yep
is cos the only even function
that changes the negative sign?
cos is an even function
?
is tan or sin a even function
@mellow harbor
sorry i keep referencing back to this pic, but yk how it says step 2 even function
Yes
and turns the -pi/2 into just pi/2
mhm
IDK what you mean by cancel out here
OH OKAYYY
$\cos(-\theta) = \cos(\theta)$, similar to $\sin(-\theta) = -\sin(\theta)$ and $\tan(-\theta) = -\tan(\theta)$ this is pretty easily visible on the unit circle
i think i can just google that
@mellow harbor
is it okay if you walk me thru the rest of these problems 😞
esp sin -23 pi/4
Sure
Use the identity $\sin(-\theta) = -\sin(\theta)$ as stated before on $\sin(\frac{-23\pi}{4})$
@mellow harbor
and then use the full revolutions
$2\pi$ is a full revolution
@mellow harbor
So, $5\pi$ is?
@mellow harbor
Yep
2 full rotations
and a half rotation
Now what happens to sin on unit circle when you go half way accross the circle
thats a good quesiton
i have no idea
Draw it on the unit circle
does it flip it to negttive
OH SORRY
I UNDERSTAND IT NOW
AFTER YOU POINTED OUT THE REVOLUTIONS STUFF
THANK YOUUUUU
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Let T be a right-angled triangle in the plane whose side lengths
are in a geometric progression. Let n(T) denote the number of
sides of T that have integer lengths. Then the maximum value
of n(T) over all such T is ?
Is the answer 3
Hmm..got this eqn (r^4 - r^2 - 1 = 0) when I took the sides as (a, ar, ar^2) and applied the pythagoras theorem
if u solve the eqn, the values are irrational
exactly
yep
then the ans should be 1 as a can be considered as integer
why can't ar be rational
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
I mean if r is irrational, anything multipled with irrational is irrational again soo
unless it's 1/that irrational right
not fully, contradiction arises in some cases
rewording the question, does there exist a pythagorean triple in arithmetic progression
gp
fuck I cant read
same
so I wrote answer as 3 cause
a can be integer then
ar and ar^2 are not
then ar can be integer if a=1/r so a and ar^2 cannot be
same for ar^2
yep..if u mention that case, then it's correct
so you sure the answer is 3?
you just excluded 3
In general, I would say the ans is 1 as there are no cases mentioned
hmm
?
you showed that it can never be all 3 sides
But if it's a proof kinda question, u can mention this case (if a = 1/r)
choosing 1 is safer
yep
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Guys how do I solve
Ended up getting these 2 linear equations but didn’t work out
Can someone help me
@crystal zephyr Has your question been resolved?
Don't open 2 help channels
@crystal zephyr Has your question been resolved?
Mb
@crystal zephyr Has your question been resolved?
Oklid maybe????
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Let n > 1 be the smallest composite integer that is coprime to
10000!/9900! . Then n leq 100 , 100<n leq 9900 , n <9900 leq 10000 , n>10000?
n must be composite, that means that it's a product of at least 2 primes
ok
so you will probably be looking for primes which dont divide 10000!/9900!
n cannot be between 9900 and 10000
Yep, thats correct
I need to eliminate other options also
just with this, you should be able to eliminate one more
Do you know how to rewrite 10000!/9900! as a product
9901*9902..10000
I think no
why not?
If we take the even composites 2 will be common
It has to be composite
91 then
oh im stupid twice
There surely exists some number in that product
You mean 97
Yeah, why
yep, that'd work
what about 97? Can you prove that 97 is not coprime with the product?
It's gonna be cruicial anyway in the next part
97 is prime
yes, ik, we'll need it later
we need to find composite number right
okay, let's just return to that later
back to this
you are trying to minimize n
that means that your n should be product of exactly 2 primes
and the primes should be least
(and also equal therefore)
so you are looking for the least prime p which is coprime with the product
and then n is just gonna be p^2
do you get that?
yes
alright, now try eliminating more intervals
use the fact that n = p^2
for the least prime p which doesnt divide the product
if you cant do that currently, can you at least reduce the question about in which interval n is to question about in which interval p is?
I just square the intervals?
<10000
oh
p<10
so to prove that n < 100, we only need to prove that each p < 10 divides the product
ah
what about n < 10000?
p<100
yeah
and n > 10000 would just be p > 100
so now you see why determining whether all primes < 100 divide the product is crucial
why?
cause 9901 to 10000 is like 100
Exactly
ok so p>100
and so there must be at least 1 multiple of each p < 100 in that interval
yes
and hence n > 10000
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Does anyone know how you get d theta by dx
The cos squared one that I have in a box
Wait I figured it out
.close
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hey. idk if that question fits in here but i guess so. its not really a math problem question. i am currently looking for good material to practice and exercise in general. this autumn i will start studying physics and therfore i try to improve my math skills at least a bit. so what i am looking for is i a book or any other common material to improve my integral calculus skills. so does anyone know like a source like a book or pdf which contains lots of integral questions? that would be nice. if possible with structured solutions as well. :3
my bad. i have not seen it. that probably solves it yet. thanks 😅 should have looked better
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Its ok, there are also a lot of great online content for integrals
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This example provides two examples of how to describe the end behavior and long run behavior of a function.
Site: http://mathispower4u.com
Blog: http://mathispower4u.wordpress.com
so I can understand this while looking a graph but I don't know what the variable behaves or how to graph it
Therefore I don't understand how it behaves, thus I am unable to answer the question
do u hv an idea of how does the graph of x^(2n) changes as we increase the value on n
no
when we increase the value of n the graph kinda remains like the graph of y=x²
But...
It gets steeper
maybe u should plot a graph of y=x^(2n)
And u should try seeing what's going on when u increase n
{n is a natural number}
Okay I think I understand
:)
its kinda like a parabola but its the w thing
postive goes up and negative goes down
I mean lie -2x^2 would open down
yea then it will be a downward parabola
because its leading coefficient is negative
@plucky karma Has your question been resolved?
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Did I do this correctly and is the parentheses handle correctly should I do left closed right open?
I actually don’t have to say the convergence implies measurability it is already proven I guess
@fluid swallow Has your question been resolved?
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My professor did an example with apples (0,2 euro) and pears (0,3) euro and they spend 5,50 and bought 20 in total so help me with this please cuz this is way harder ;/
take it sentence by sentence and think about how you can model each of them
but the per soon confused me
for like the sweetener for example
do I want to convert that to the ratio of the calories?
not sure what you mean
you specify how many spoons of each ingredient are in the milkshake
so I want to use spoons instead of calories?
for the modeling ?
I now have the following:
x1 = total calories, 380=<x1=<420
x2 = vitamins >= 50
x3 = fat calories =< 0.2 * x1
x4 = sweetener => x5/1.2
x5 = artificial sweetener
x1 = 50 . N + 100 . R + 120 . K + 80 . V?
with N R K V being the amount of spoons for that certain ingredient?
yes
not quite
oh true
that would allow for example N=1 and K=2
ye shit
fat calories = N + 75R + 30V <= 0.2 Total calories
Vitamins = 20N + 50VS + 2V >= 50
N >= 2K
min (cost) = 10N + 8R + 25VS + 15K + 6V
Such that:
N + 75R + 30V =< 10N + 20R + 24K + 16V
20N + 50VS+2V >= 50
3N + 8R + VS + 2K + 25V = 15
N >= 2R
N,R,VS,K,V >= 0
check for typos
Hmm
also this is missing
i added that to the first inequality
I substituted it here
you need the 380<=x1<=420
N>=2K
and that is a typo yes
I think the rest checks out
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is this correct
✅
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in the sd formula, is it n or or n-1
its apparently n but ive been taught its n-1
depends on context of the problem
i believe if you have data for the entire area then it's n and if it's a sample then n-1
ohhhh this is one of my favorite things lol
it's been a while since I had it fresh in memory though
yh got an exam tmrw
and i swr ive never been taught to use n
but it says to use n or n-1
and im confused on what requires what
If you have one discrete random variable of a certain kind, then there's a formula for the standard deviation of that variable, and it includes n where n is how many different values the variable can take
but in practice, you don't care about a single random variable, instead you consider a collection of independently and identically distributed random variables
So if I have ten variables that are i.i.d., then that models me going out in the wild and getting 10 samples of something
and it turns out that if you want to estimate the standard deviation of that underlying distribution, then the formula will have n-1
So basically the way the mathematical analysis goes is that you assume the underlying distribution has some expected value mu, then you form a new random variable according to the sample variance formula where
R = 1/(N-1) * ( (X_1 - mu)^2 + ... + (X_N - mu)^2 )
and if you compute the expected value of this random variable (i.e. R) then you'll notice that it perfectly lines up with the standard deviation of X_1
So presumably, hopefully, if you plug in your samples in place of X_1, ..., X_N, you'll get a good estimate for the standard deviation
If you know mu, you're golden
If you don't know mu, then you need to guess
And a good estimator for that is the sample mean
Because if you define the random variable
Q = (1/N) * (X_1 + X_2 + ... + X_N)
then its expected value will be the expected value of X_1
which is quite wonderful
So, a magical random variable R has the property that its expected value is the standard deviation of X_1, therefore we call it an unbiased estimator
A magical random variable Q has the property that its expected value is the expected value of X_1, therefore we call it an unbiased estimator again
And when you use an estimator, you essentially get a sample of the magical random variable
Now, because the process is random, it's entirely possible that the sample mean gives a completely wrong estimate for the mean, or the sample variance gives a completely wrong estimate for the variance
But, nonetheless, the expected value of the magical random variable matches what its trying to estimate
There are many layers of abstraction here and I think the reason that this stuff is often confusing is because statisticians try to make it seem less abstract than it really is
@pearl crag Has your question been resolved?
So first, you have a random variable X that models the height of a single person
Then, you have 100 random variables X_1, X_2, ..., X_100 that model an experiment where I go and measure the heights of a 100 people (these are identically and independently distributed)
Now, let's say I don't know the mean or the variance of X_1
I can define a new variable
Q = 1/N * (X_1 + X_2 + ... + X_100)
That has the property that its expected value is the same as the expected value of X_1.
I can define another random variable
R = 1/(N - 1) * ( (X_1 - E[X_1])^2 + ... + (X_100 - E[X_1])^2 )
whose expected value is the same as the variance of X_1.
Therefore, to have a reasonable guess for the mean and variance of the human height (assuming it follows a probability distribution where those quantities are well-defined), I should evaluate Q to get the mean and R to get the variance. I can't evaluate R without knowing E[X_1], but I can fix that issue by just using the estimate I got from evaluating Q
Of course this is just the big picture idea. Showing that E[Q] = E[X_1] is perhaps quite easy, but showing that E[R] = Var[X_1] might require some work
If you look up the Wikipedia page for an estimator, nowhere does it state that an estimator is essentially just another random variable that you evaluate based on your data. I think that's the crucial understanding that statisticians want to sweep under the rug for some reason
Like that description is technically not wrong but it reads to me the same as saying "An integral is a rule for computing the area under a curve"
Like yeah okay that's true but you're really obfuscating the mathematical details
The very first sentence on the Wikipedia page for an integral says "an integral is the continuous analog of a sum"
which is already giving mathematical intuition
You can describe literally any mathematical construct as "a rule for computing X" but that's just stupid lol
That is just over complicating it
that might literally be the problem
I don't even understand what a continuous analog means
somethings are oversimplified at the expense of important details
continuous analog means its like the continuous version of sum
instead of discrete
no not always
Rieman sum is continuous sum, ive questioned it once but a summation doesn't need to be discrete no?
Im only alevel fm student so im not well rehearsed on thsi stuff
Just more about computing it in my syllablus so correct me if im wrong
riemann sums can be quite inaccurate for some integrals
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why would my teacher have done this when yo ucan just mannipulate it into sec=sec
and if you did it that way you would not need to cehck for npvs? or no
also whats the point of calclating the npv for this quesiton in the first place
, i also dont even know what is hapining on the left side as a whole
what is that for?
Why your teacher considered the 30 degree case, I don't know
but you should investigate when tan(theta) / sin(theta) is a valid expression
and when 1/cos(theta) is a valid expression
and presumably you'll get different results
does it count as an identity, well equality holds wherever both sides are defined
but that doesn't necessarily mean they're the same function
so you should probably ask your teacher how they feel about that
in any case I think this is a completely trash horrible exercise that makes students not really focus on the right things
but you should not tell your teacher that
The problem is that the way functions are handled in high school is so sloppy that it's very easy to generate questions regarding singularities that are difficult to answer
Like does the function "x/x" have a limit at 0. I think most teachers would say yes even though the function isn't defined there
And that's not necessarily an issue since we also speak of the limit of the difference quotient as h->0
but if we choose this path then you can have a function that is not defined on a large strip. And do limits exist somewhere on that strip? For logical consistency you would have to say yes, but what is the limit? Well logically speaking the limit could be any real number. And now we're making some very unorthodox claims about limits. Kinda my point is that in high school we just don't have the nuance to talk about these things properly, so any teacher attempting to get philosophical with these is probably just shooting themselves in the foot
Because at the end of the day these things depend exclusively on the way mathematicians like to define things, and definitions can vary...
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How come when i put it in my casio calc
I get 6.49x10^21
I used to just do a fraction bar on my ti84 and it fixed the problem but ti84s are banned from my class now
You forgot to use parentheses for the denominator.
Oh
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Could you show me a solution using combinatorics
actually this is more sophisticated
this is a diphantine equation, you need to write it using whole numbers , like this
write it in cents
price of bananas is 60, number of bananas b
price of strawberries is 75, number of strawberries s
price of water is 80, number of water units (bottles or whatever) w
you want to solve
60b+75s+80w=1480
an equation when youre dealing with whole numbers is called a Diophantine equation
this is much easier to do when:
a) you have only two variables
b) you limit yourself to all integers, positive and negative, and then at the end discard solutions with negative numbers
follow so far?
Im following
Sorry i replied late
Diophantine equation 😭
okay let's firs tmake sure there is a solution so we dont waste time looking for somrthing that doesnt exist
,w solve 60b + 75s + 80w = 1480 in integers subject to b>=0, s>=0,w>=0
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boo okayu we'll do it by hjand
as I said it's much easier with two variables so I will introduce a fake variable
X=60b+75s
the equation becomes
X+80W = 1480
Yeah
theorem: this has a solution (allowing for negative integers) precisely when gcf(1,80) | 1480
similkarly the original has a solution precisely with gcf(60,75,80)|1480
the lines mean "divides" , like "is divisible by" but the other direction
,w gcf(60,75,80)}
good , original has a solution
actually you know what
now that we know that it' divisible by 5 throughout
let's divide it by 5 throughout!
we get:
12b+15s+16w=296
let X = 12b+15s
X+16W=296
now this is annoying
but we can do this
have you seen modular arithmetic before? things like: a≡4 (mod 6)
if not, it's less intimidating then it looks
Whats that
Is modular arithmetic when you get remainders?
is it the same as modulous
yeah
so we write 8 ≡ 2 (mod 2)
okay so, using a computer to make things faster
12b+15s+16w=296
let X = 12b+15s
X+16W=296
,w prime factorization of 296
great, so, watch this
My eyes are open
X+16W=296 , let's divide bhoth sides by 8 and take remainders
X ≡ X (mod 8), doesn't really help
16W ≡ 0 mod 8 though!
because 16W is a multiple of 8
so we have:
X+8 ≡ 0 (mod 8)
X = -8 mod 8
37
by the way in theory
you dont have to use all factors, you could use just 37, or just 2
but im assuming solving all of them will be helpful
looking up what to do, I forgot
okay it doesnt simplify without knowing what w is
however we had before
12b+15s+16w=296
$\begin{cases} 16w \equiv -12b - 15s \pmod {37} \ X \equiv -8 \pmod 8\end{cases}$
gfauxpas
Yeah
and might as well go back to how we defined x actually
X= 296-16W
$\begin{cases} 16w \equiv -12b - 15s \pmod {37} \-16w \equiv -8 \pmod 8 \end{cases}$
gfauxpas
ah, great
😭😭
no, it's good, we split the equation itno 2 simpler ones
Okk
except
the second one isnt useful lol because it's just saying 0=0
so we have:
$15w \equiv -12b - 15s \pmod {37}$
gfauxpas
alright, let's see
I have a better approach
12b+15s+16w=296
I thougth of this now, didnt see it earlier
we have 2,2^2,2^3, 37 | 296
so let's just take all 4 of those and mod the equation
mod 2 gives
s=0 (mod 2) because the other coefficients are even
mod 4 gives
3s = 0 (mod 4)
mod 8 gives
12b+15s+0=0 (mod 8)
and mod 37 gives
12b+15s+16w=0 (mod 37)
working on it
sorry im not particularly good at this, i need to look things up
gcf(3,4) = 1, so
3s = 0 (mod 4)
simplifies to
s = 0 (mod 4)
because a number cant magically become divisible by 4 by multiplying it by 3!
Its okay
and s=0(mod 4) is a stronger statement than s=0(mod 2), so we can get rid of the latter. if it's divisible by 4, it's divisible by 2, but not vice versa necessarily
for 12b+15s = 0 (mod 8)
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we can replace "s" with "4t", because, s is divisible by 4! t is any whole number
so remember s = 4t
12b+15s=12b+60t=0 (mod 8)
60 mod 8 is 4
so 60t mod 8 is 4t also
replace 60t with 4t
12 / 8 = 1 r 4
so 12b = 4b (mod 8)
so 12b+60t=4b+4t=4(b+t) mod 8
okay 4(b+t) considered mod 8 is tricky
because dividing by 4 can ruin the divisibility by 8
but it cant ruin divisibility by 2 , because (b+t) has to be even for 4(b+t) to be a multiple of 8
so we have
b=-t (mod 2)
s=0 (mod 4)
but t = s/4
b=(-s/4) (mod 2)
now you normally cant multiply both sides of a congruence by -1 because that's not the same thing as multiplying by 1 most of the time
but -1 = 1 (mod 2) so with mod 2 you can!
replace -s/4 with s/4
b=s/4 (mod 2)
we have:
s=0 (mod 4)
b=(s/4) (mod 2)
and I'm getting tired so im gonna leave it at that
you still need to work on:
16w=-12b-15s (mod 37)
but im getting sleepy sorry
Its okay
Good night
I might sleep too
This is pretty cool icl
$\begin{cases} s = 0 \pmod 4 \ b \equiv \frac s 4 \pmod 2 \ 16w=-12b-15s \pmod {37}\end{cases}$
gfauxpas
the third one is not simplified
asking a computer, it turns into
w=27b + 6s (mod 37)
with the same kind of sorcery we've been using so far but im too tired to do it by hand
Thank you
$\begin{cases} s = 0 \pmod 4 \ b \equiv \frac s 4 \pmod 2 \ w=27b+6s \pmod {37}\end{cases}$
gfauxpas
so this is enough to find a solution
pick any s divible by 4. once you choose s, choose b = s/4 (mod 2)
meaning (b-s/4) must be even
and then once youve chosen b and s, you find w, and if w is larger than 37, take remainders!
or, well
pick the multiple of 37 that makes sense
@pastel igloo I asked a computer to find all non-negative solutions using our congruences, here it is
(b,s,w) triples with non-negative values:
(2, 0, 17)
(6, 0, 14)
(10, 0, 11)
(14, 0, 8)
(18, 0, 5)
(22, 0, 2)
(1, 4, 14)
(5, 4, 11)
(9, 4, 8)
(13, 4, 5)
(17, 4, 2)
(0, 8, 11)
(4, 8, 8)
(8, 8, 5)
(12, 8, 2)
(3, 12, 5)
(7, 12, 2)
(2, 16, 2)
gn
Omg thank you! 😭
I was gonna ask my calc teacher
Tomorrow
If he knows how to solve diophantine equations
maybe you ddint realize how difficult this problem is lol
I was helping my brother and this was on his assignment
diophantine equations can get really tricky really quickly
Looks tricky
Okk gn
Im bouta pass out
Thank you
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Where am I wrong
hint: int 1/(a - x) dx = - int 1/(x - a) dx
Taking - as common
But why I have to
+C
Nahh
not sure what you mean here
you should use the sub u = a - x
but yes also you are missing + C
What
if you differentiate log|a-x| wrt x what do you get
-1/log|a-x|
is what what you were integrating?
Huh?
this is not correct
How
what is the derivative of log(x)
1/x
ok so what is the derivative of log(a-x)
-1/log(a-x)
Yes
what is it
I did it with the chain rule
write out the chain rule
well which do you think
well it can only be one
1st one
...
f(x)g′(x) + f′(x)g(x)
What u asking
Log (a-x) is f ad (a-x) is g
That's what I wrote
what could f(x) be
no
So what
ok seperate scenario
if i say f(x) = x^2 and g(x) = x - 3 then what is g(f(x)), what is f(g(x))
(x-3)^2
for which
What