#help-42

1 messages · Page 159 of 1

remote mural
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i guess so

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if only i understood it right from the start

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oh well

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ty

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tranquil bone
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spice venture
calm coralBOT
spice venture
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not able to find a method which involves less calculation

glass heart
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if you have g=f-(2x-1) then g(1)=...=g(5)=0

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that might help

restive sigil
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Or lagrange interpolation if you don't mind the time it takes

spice venture
glass heart
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no

spice venture
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mb sorry let me try again

restive sigil
spice venture
spice venture
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but ive not learnt that so i dont think im supposed to use it

restive sigil
restive sigil
glass heart
spice venture
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like what to do with that

glass heart
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well g seems nicer to work with

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it has easier values

restive sigil
glass heart
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just intuitively speaking

spice venture
glass heart
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given the values you can indeed just find out the formula of g easily

glass heart
restive sigil
swift ravine
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Is this group helpful for engineering students?

spice venture
spice venture
restive sigil
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Meaning write g as a product of monomials

spice venture
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oh ok so

swift ravine
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Guys?

restive sigil
spice venture
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(x-1)(x-2)(x-3)(x-4)(x-5)(x-alpha) + 2x + 1 = f(x)

spice venture
spice venture
glass heart
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g is also a polynomial of degree 6

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and has leading coefficient 2009

spice venture
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right so some unknown root alpha

glass heart
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not quite

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we havent used the condition f'(2)=2 yet

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what does it say about g

spice venture
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g(x) = f(x) -2x - 1
g'(x) = f'(x) -2
g'(2) = 0

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is this right

glass heart
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yes

spice venture
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oh but what does this mean

glass heart
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it means that 2 is a double root of g

spice venture
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oh

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so 2009(x-2)^2(x-1)(x-3)(x-4)(x-5) + 2x + 1 = f(x)

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now i put x=6?

glass heart
spice venture
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is it correct now?

glass heart
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yes

spice venture
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so now x=6? 😭

glass heart
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yes

spice venture
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okay thank u bro 😭 this question made me cry

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unreal rose
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why cant i do 9C3 = 84 ?

calm coralBOT
potent smelt
unreal rose
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damn

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alr ty

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ripe hornet
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Hiya I am having quite a simple issue. Its to do with integration but im strugging to see how google gets between two points. Pictures are below

ripe hornet
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step 2 is where im struggling to see the connection

rapid cliff
ripe hornet
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Yeahhh, i didnt see that

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thank you lol

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maiden gale
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Does anyone have any idea of how the hell im supposed to calculate this without a calculator??

velvet osprey
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$\sqrt{\frac{2\cdot 6.67 \cdot 10^{-11} \cdot 7.5 \cdot 10^{22}}{1.5\cdot 10^6}}$

potent lotusBOT
velvet osprey
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this?

maiden gale
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yes

velvet osprey
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well you can handle the powers of ten separately and the mantissas (ie everything else) separately

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pretending 6.67 ≈ 6.666... = 20/3 seems to also be a good idea

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so then that all becomes $\sqrt{\frac{2\cdot \frac{20}{3}\cdot \frac{15}{2}}{\frac32}\cdot 10^{-11+22-6}}$

potent lotusBOT
velvet osprey
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which is more amenable to manual solution

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why would they ban calculators for this q tho

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that or you recognize 2*7.5/1.5 = 10

maiden gale
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appreciate the help btw, ill give your method a go.

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manic jungle
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This is the graph of y=-sin(x/2)
But if the domain is from 0 to 180 then,
we'll only take this part, right?

manic jungle
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This part

leaden thunder
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π radians = 180 degrees

bold hatch
manic jungle
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Thanks!

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ancient grotto
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?!

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marble edge
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For the function F, it holds that
F′(x) = f(x)
and
F(−1) = 4.

Determine F(x) if the graph of y = f(x) is the line shown in the figure below.

marble edge
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its in swedish so i translated it

bold hatch
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Can you try figuring out an equation for f(x) @marble edge

marble edge
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no i cant im too dumb for it

tropic moth
bold hatch
tropic moth
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mx+b

marble edge
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nah we solve it with kx+m

marble edge
bold hatch
marble edge
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what

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they deleted my message for nothing

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i cant say low

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i

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q

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wow

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bro what is this censorship

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im leaving giving up in life

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cya guys

bold hatch
marble edge
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nah bro its fine

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im done bro

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have a good life

tropic moth
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😭

marble edge
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i pray for ur success

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im cooked

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worn hedge
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,rotate

calm coralBOT
potent lotusBOT
worn hedge
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Is this right

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Can u do that😭

unreal isle
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i might show more steps

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but yes

worn hedge
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Ok thanks

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visual gust
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when solving geometric problems with the roots of a complex number to form a polygon, how do you find all of the individual roots of unity?

visual gust
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I understand w = e^(2pi/n i), but on all of my sheets and stuff it just says "if you know one root of a complex number with n roots, then you can find the other roots by multiplying by an nth root of unity"

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I don't understand what it means by multiplying the root by an nth root of unity

velvet osprey
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multiplying by what you called w

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so if a number z has some nth root r then the others are rw, rw^2, rw^3, ..., rw^(n-1)

visual gust
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oh, right, okay. I think that makes sense.

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because if I just multiply the initial one n+1 times it seems to loop back around to the first root of unity

velvet osprey
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just n

visual gust
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oh sorry

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yeah

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okay sick, thank you.

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wanton ember
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Hey so I have this question and basically I just confirmed that F = curl G. But my question is when I then calculate the flux do I use curl G instead of curl F?

wanton ember
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like should it be double integral curl G * ds?

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nvm I found some article for it

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thorny steeple
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<@&286206848099549185>

calm coralBOT
thorny steeple
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I need help!

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somebody pl

marsh valley
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What have you tried?

thorny steeple
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um

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well I know the int is 14

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but i dont know what x value is x

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anyone

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hello

limpid geyser
thorny steeple
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yes

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$int{u}dx$

potent lotusBOT
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Zentisuincarnate

limpid geyser
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its $\int_{lower}^{upper}$ btw

potent lotusBOT
limpid geyser
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if you know integration by parts just apply it to this problem set u=x and dv=f'(x)dx

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that should give u a good start

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you have all the info u need

thorny steeple
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$\int_{2}^{5}(x*f'(x))dx$

potent lotusBOT
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Zentisuincarnate

thorny steeple
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$$u=x, dv = f'(x), therfore , \int_{2}^{5}(udv) = uv - \int(v) du$$

potent lotusBOT
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Zentisuincarnate

thorny steeple
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right

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hello

limpid geyser
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yeah try to evaluate it now u set it up correctly

thorny steeple
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$$u=x, dv = f'(x), therfore , \int_{2}^{5}(xf'(x)) = xf(x) - \int(f) *1$$

potent lotusBOT
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Zentisuincarnate

limpid geyser
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actually since its a definite integral you need to include the bounds for the first term $\int_{2}^{5}xf'(x)dx = \bigl[x,f(x)\bigr]{2}^{5} - \int{2}^{5}f(x)dx$

potent lotusBOT
thorny steeple
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ok

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whats next?

limpid geyser
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literally just evaluate that i set it up for you

thorny steeple
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oh

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$\bigl[x,f(x)\bigr]{2}^{5} = [(5)f(5)-(2)f(2)] = [57-24]$

limpid geyser
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yeah right

potent lotusBOT
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Zentisuincarnate

thorny steeple
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35-8

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27

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but what about the $$\int_{2}^{5}(f(x))dx ? $$

limpid geyser
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that’s given to you in the problem

potent lotusBOT
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Zentisuincarnate

thorny steeple
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oh 14

limpid geyser
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yeah

thorny steeple
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so 27 -14

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so 13

calm coralBOT
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@thorny steeple Has your question been resolved?

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rocky mantle
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Im having trouble with AP stats. I dont know when to use a binomial probability. im guessing you DONT calculate a binomial probability when you're trying to guess what the next outcome would be? But you WOULD use it if you know the number of trials?

rocky mantle
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The main question I’m stuck on

swift laurel
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well you would use whatever probability distribution is underlying the event for figuring out the probability of a single trial

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then you can use the binomial distribution (along with the knowledge of the probability of a single trial) to find out the probability of something happening across multiple trials

rocky mantle
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ahh okay

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i think i get it

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thank you very much

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unborn stone
calm coralBOT
unborn stone
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why use the limit test if it already converges due to p series

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i dont need to use it right

velvet osprey
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(n+1)/(n^3+1) looks an awful lot like a p-series but formally is not one

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LCT is how you formalize the resemblance

unborn stone
velvet osprey
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sorry, i don't understand your question.

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are you asking "Why do we need to make a comparison at all?" or are you asking "So does sum a_n converge?"

unborn stone
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and n/n^3 is bn

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and it converges so shoudlnt (n+1)/(n^3+1) which is a_n also converge

velvet osprey
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... yes, sum a_n does converge.

unborn stone
velvet osprey
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uhh

unborn stone
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thats what i did

velvet osprey
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wait does the inequality (n+1)/(n^3+1) <= n/n^3 actually hold?

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as in do you have proof that it does?

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cause i actually think it doesn't, as-written

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(though you could tweak it to make it work still...)

velvet osprey
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"Sorry, I don't have proof that that inequality is true. Also, I decided not to give you a straight answer to your question."

unborn stone
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bruh ima just use limit then

pallid halo
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it fails rather badly for n=2

unborn stone
velvet osprey
unborn stone
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whenever the numerator is also adding or subtracting something?

velvet osprey
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and i think we just lost each other

calm coralBOT
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median cloak
#

Hello hello

calm coralBOT
median cloak
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I want a

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Application

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That can calculate anything I wrote

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Any sketches

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Immediately

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Is there anything like this

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Calculate what I wrote

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Microsoft

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Apple

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Applications

velvet osprey
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you are asking for something that is like Wolfram Alpha but also does handwriting recognition?

calm coralBOT
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@median cloak Has your question been resolved?

median cloak
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I cannot really type any mathematical operations.

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I can only draw

velvet osprey
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mmm

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yeah i dont think anything like that exists, unfortunately

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as far as typing math stuff goes, there is this markup language called LaTeX which all mathematicians use

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which is also what @potent lotus runs on

calm coralBOT
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@median cloak Has your question been resolved?

short salmon
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it might be easier to learn latex, a coding language, or how to use wolfram alpha, than find a tool like this right now

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though with AI improving, who knows honestly

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runic whale
#

how would i solve these

calm coralBOT
runic whale
#

or what can i search up to understand this

mellow harbor
runic whale
#

yes

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im just confused since its not on the unit circle

mellow harbor
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Do you know the identities $\sin(x \pm \frac{\pi}{2}), \cos(x \pm \frac{\pi}{2}), \sin(x + \pi), \cos(x + \pi)$

potent lotusBOT
#

@mellow harbor

manic jungle
# runic whale how would i solve these

This trigonometry video tutorial explains how to use reference angles to evaluate trigonometric functions such as sine, cosine, tangent, secant, cosecant, and cotangent with positive and negative angles in radians and degrees.. You need to have a good understanding of right triangle trigonometry, SOHCAHTOA, 30-60-90 triangle and the 45-45-90 tr...

▶ Play video
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This should help

runic whale
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thank youuuuuuuuuuuu

manic jungle
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Ur welcome

runic whale
#

okay maybe i dont understand...

mellow harbor
#

?

manic jungle
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u'll get it

mellow harbor
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Since you know the unit circle you can also just try using it

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You'll see a relation soon enough

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if you look at the sin and cos values of standard angles on the unit circle

runic whale
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guys....

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is it bad to say

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i dont understand it

runic whale
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im sorry

mellow harbor
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NP lol

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Which part do you have issue with

runic whale
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in the video, i got really confused after he started drawing the triangles and labeling the sides

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😭

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but im looking at chatgpt

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and i dont understand the thought process of -5 pi/2 +2 pi = cos(-pi/2)

mellow harbor
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Well, do you know what $2\pi$ is?

potent lotusBOT
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@mellow harbor

runic whale
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nope

mellow harbor
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$2\pi = 360^{\circ}$

runic whale
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OHHHH

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ITS A FULL REVOLUTION

potent lotusBOT
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@mellow harbor

mellow harbor
runic whale
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AYYAYAYYA

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HURRAYYYYY

mellow harbor
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So it just gets back to the same point

runic whale
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SO SO THEN IT CANCELS OUT ITS LIKE BOOM -PI/2

mellow harbor
#

Yep

runic whale
#

that changes the negative sign?

mellow harbor
mellow harbor
runic whale
#

is tan or sin a even function

mellow harbor
#

No

#

$\sin(-x) = -\sin(x)$

potent lotusBOT
#

@mellow harbor

runic whale
mellow harbor
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Yes

runic whale
#

and turns the -pi/2 into just pi/2

mellow harbor
#

mhm

runic whale
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like does the negatives just cancel out

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like basic math

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vice versa for sin

mellow harbor
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IDK what you mean by cancel out here

runic whale
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OH OKAYYY

mellow harbor
#

$\cos(-\theta) = \cos(\theta)$, similar to $\sin(-\theta) = -\sin(\theta)$ and $\tan(-\theta) = -\tan(\theta)$ this is pretty easily visible on the unit circle

runic whale
#

i think i can just google that

potent lotusBOT
#

@mellow harbor

runic whale
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esp sin -23 pi/4

mellow harbor
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Sure

mellow harbor
potent lotusBOT
#

@mellow harbor

mellow harbor
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and then use the full revolutions

runic whale
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SO LIKE IDK IF IM DOING THIS RIGHT BUT

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would be like 5 full revolutions?

mellow harbor
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$2\pi$ is a full revolution

potent lotusBOT
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@mellow harbor

mellow harbor
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So, $5\pi$ is?

potent lotusBOT
#

@mellow harbor

runic whale
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2 1/4?

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WAIT NO 2 1/2

mellow harbor
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Yep

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2 full rotations

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and a half rotation

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Now what happens to sin on unit circle when you go half way accross the circle

runic whale
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i have no idea

mellow harbor
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Draw it on the unit circle

runic whale
mellow harbor
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Yep

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@runic whale

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?

runic whale
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OH SORRY

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I UNDERSTAND IT NOW

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AFTER YOU POINTED OUT THE REVOLUTIONS STUFF

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THANK YOUUUUU

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#
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polar bison
#

Let T be a right-angled triangle in the plane whose side lengths
are in a geometric progression. Let n(T) denote the number of
sides of T that have integer lengths. Then the maximum value
of n(T) over all such T is ?

polar bison
#

Is the answer 3

tropic breach
#

Hmm..got this eqn (r^4 - r^2 - 1 = 0) when I took the sides as (a, ar, ar^2) and applied the pythagoras theorem

polar bison
#

yes

#

you will get irrational no

tropic breach
#

if u solve the eqn, the values are irrational

polar bison
#

exactly

tropic breach
#

then the ans should be 1 as a can be considered as integer

polar bison
#

why can't ar be rational

calm coralBOT
#

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

polar bison
#

First read the full context

#

Then use bots

#

Anyways

#

cause a can be 1/r

#

so ar=1

tropic breach
polar bison
#

unless it's 1/that irrational right

tropic breach
#

not fully, contradiction arises in some cases

glass heart
#

rewording the question, does there exist a pythagorean triple in arithmetic progression

polar bison
#

gp

glass heart
#

fuck I cant read

polar bison
#

and I haven't seen anything

#

in a gp

tropic breach
polar bison
#

so I wrote answer as 3 cause

#

a can be integer then

#

ar and ar^2 are not

#

then ar can be integer if a=1/r so a and ar^2 cannot be

#

same for ar^2

tropic breach
#

yep..if u mention that case, then it's correct

polar bison
#

so you sure the answer is 3?

glass heart
#

you just excluded 3

tropic breach
#

In general, I would say the ans is 1 as there are no cases mentioned

polar bison
#

hmm

polar bison
glass heart
#

you showed that it can never be all 3 sides

polar bison
#

yes

#

it can never

glass heart
#

so n(T) is never 3

#

so why should the maximum suddenly be 3

tropic breach
polar bison
#

choosing 1 is safer

tropic breach
#

yep

polar bison
#

ok

#

thanks

#

.close

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#
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crystal zephyr
#

Guys how do I solve

calm coralBOT
crystal zephyr
#

Ended up getting these 2 linear equations but didn’t work out

#

Can someone help me

calm coralBOT
#

@crystal zephyr Has your question been resolved?

polar bison
#

Don't open 2 help channels

calm coralBOT
#

@crystal zephyr Has your question been resolved?

crystal zephyr
#

Mb

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@crystal zephyr Has your question been resolved?

unkempt blade
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polar bison
#

Let n > 1 be the smallest composite integer that is coprime to
10000!/9900! . Then n leq 100 , 100<n leq 9900 , n <9900 leq 10000 , n>10000?

vagrant oak
polar bison
#

ok

vagrant oak
#

so you will probably be looking for primes which dont divide 10000!/9900!

polar bison
#

n cannot be between 9900 and 10000

vagrant oak
polar bison
#

I need to eliminate other options also

vagrant oak
#

Do you know how to rewrite 10000!/9900! as a product

polar bison
#

9901*9902..10000

vagrant oak
#

yeah

#

can n <= 100?

polar bison
#

I think no

vagrant oak
#

why not?

polar bison
#

If we take the even composites 2 will be common

vagrant oak
#

what about primes like 93?

#

wait im stupid

#

93 isnt prime

polar bison
#

It has to be composite

vagrant oak
#

91 then

polar bison
#

91

#

13*7

#

and

vagrant oak
#

oh im stupid twice

polar bison
#

There surely exists some number in that product

rocky flower
vagrant oak
vagrant oak
#

what about 97? Can you prove that 97 is not coprime with the product?

#

It's gonna be cruicial anyway in the next part

polar bison
#

97 is prime

vagrant oak
#

yes, ik, we'll need it later

polar bison
#

we need to find composite number right

vagrant oak
#

okay, let's just return to that later

vagrant oak
#

you are trying to minimize n

#

that means that your n should be product of exactly 2 primes

#

and the primes should be least

#

(and also equal therefore)

#

so you are looking for the least prime p which is coprime with the product

#

and then n is just gonna be p^2

#

do you get that?

polar bison
#

yes

vagrant oak
#

alright, now try eliminating more intervals

#

use the fact that n = p^2

#

for the least prime p which doesnt divide the product

#

if you cant do that currently, can you at least reduce the question about in which interval n is to question about in which interval p is?

polar bison
#

I just square the intervals?

vagrant oak
#

if n < 100, what's p?

polar bison
#

<10000

vagrant oak
#

nope

#

n = p^2

polar bison
#

oh

vagrant oak
#

substitute p^2 in the inequality

#

yeah

polar bison
#

p<10

vagrant oak
#

so to prove that n < 100, we only need to prove that each p < 10 divides the product

polar bison
#

ah

vagrant oak
#

what about n < 10000?

polar bison
#

p<100

vagrant oak
#

yeah

#

and n > 10000 would just be p > 100

#

so now you see why determining whether all primes < 100 divide the product is crucial

polar bison
#

yes

#

And it does

#

all primes <100 divides

vagrant oak
#

why?

polar bison
#

cause 9901 to 10000 is like 100

vagrant oak
#

Exactly

polar bison
#

ok so p>100

vagrant oak
#

and so there must be at least 1 multiple of each p < 100 in that interval

polar bison
#

yes

vagrant oak
#

and hence n > 10000

polar bison
#

wow

#

thanks

#

.close

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#
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keen tinsel
calm coralBOT
keen tinsel
#

Does anyone know how you get d theta by dx

#

The cos squared one that I have in a box

#

Wait I figured it out

#

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cedar rune
#

hey. idk if that question fits in here but i guess so. its not really a math problem question. i am currently looking for good material to practice and exercise in general. this autumn i will start studying physics and therfore i try to improve my math skills at least a bit. so what i am looking for is i a book or any other common material to improve my integral calculus skills. so does anyone know like a source like a book or pdf which contains lots of integral questions? that would be nice. if possible with structured solutions as well. :3

glad parrot
#

Hf with integrals !

cedar rune
#

my bad. i have not seen it. that probably solves it yet. thanks 😅 should have looked better

#

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glad parrot
#

Its ok, there are also a lot of great online content for integrals

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plucky karma
plucky karma
#

so I can understand this while looking a graph but I don't know what the variable behaves or how to graph it

#

Therefore I don't understand how it behaves, thus I am unable to answer the question

valid linden
#

do u hv an idea of how does the graph of x^(2n) changes as we increase the value on n

plucky karma
#

no

valid linden
#

when we increase the value of n the graph kinda remains like the graph of y=x²

#

But...

#

It gets steeper

#

maybe u should plot a graph of y=x^(2n)

#

And u should try seeing what's going on when u increase n

#

{n is a natural number}

plucky karma
#

Okay I think I understand

valid linden
#

:)

plucky karma
#

its kinda like a parabola but its the w thing

#

postive goes up and negative goes down

valid linden
#

no

#

when y= x^(smtg even) then the values never goes negative

plucky karma
#

I mean lie -2x^2 would open down

valid linden
#

yea then it will be a downward parabola

#

because its leading coefficient is negative

calm coralBOT
#

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fluid swallow
#

Help

calm coralBOT
fluid swallow
#

Did I do this correctly and is the parentheses handle correctly should I do left closed right open?

#

I actually don’t have to say the convergence implies measurability it is already proven I guess

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#

@fluid swallow Has your question been resolved?

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@fluid swallow Has your question been resolved?

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olive lion
calm coralBOT
olive lion
#

My professor did an example with apples (0,2 euro) and pears (0,3) euro and they spend 5,50 and bought 20 in total so help me with this please cuz this is way harder ;/

glass heart
#

take it sentence by sentence and think about how you can model each of them

olive lion
#

but the per soon confused me

#

for like the sweetener for example

#

do I want to convert that to the ratio of the calories?

glass heart
#

not sure what you mean

#

you specify how many spoons of each ingredient are in the milkshake

olive lion
#

so I want to use spoons instead of calories?

#

for the modeling ?

#

I now have the following:

x1 = total calories, 380=<x1=<420
x2 = vitamins >= 50
x3 = fat calories =< 0.2 * x1
x4 = sweetener => x5/1.2
x5 = artificial sweetener

glass heart
#

ok

#

how can you express x1 in terms of the number of spoons of each ingredient

olive lion
#

x1 = 50 . N + 100 . R + 120 . K + 80 . V?

#

with N R K V being the amount of spoons for that certain ingredient?

glass heart
#

yes

olive lion
#

Thickener = 3N + 8R + VS + 2K + 25V = 15

#

2N >= K ?

glass heart
#

not quite

olive lion
#

oh true

glass heart
#

that would allow for example N=1 and K=2

olive lion
#

ye shit

#

fat calories = N + 75R + 30V <= 0.2 Total calories

#

Vitamins = 20N + 50VS + 2V >= 50

#

N >= 2K

#

min (cost) = 10N + 8R + 25VS + 15K + 6V
Such that:
N + 75R + 30V =< 10N + 20R + 24K + 16V
20N + 50VS+2V >= 50
3N + 8R + VS + 2K + 25V = 15
N >= 2R
N,R,VS,K,V >= 0

glass heart
#

check for typos

olive lion
glass heart
olive lion
olive lion
glass heart
#

you need the 380<=x1<=420

olive lion
#

Aaah true

#

i forgot about that one!

olive lion
#

and that is a typo yes

glass heart
#

I think the rest checks out

olive lion
#

perfect thank you very much :)

#

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wide scaffold
#

is this correct

calm coralBOT
bold hatch
wide scaffold
#

.close

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pearl crag
#

in the sd formula, is it n or or n-1

calm coralBOT
pearl crag
#

its apparently n but ive been taught its n-1

limpid lagoon
#

depends on context of the problem

#

i believe if you have data for the entire area then it's n and if it's a sample then n-1

pearl crag
#

can u explain what

#

u mean

near crag
#

ohhhh this is one of my favorite things lol

#

it's been a while since I had it fresh in memory though

pearl crag
#

yh got an exam tmrw

#

and i swr ive never been taught to use n

#

but it says to use n or n-1

#

and im confused on what requires what

near crag
#

If you have one discrete random variable of a certain kind, then there's a formula for the standard deviation of that variable, and it includes n where n is how many different values the variable can take

#

but in practice, you don't care about a single random variable, instead you consider a collection of independently and identically distributed random variables

#

So if I have ten variables that are i.i.d., then that models me going out in the wild and getting 10 samples of something

#

and it turns out that if you want to estimate the standard deviation of that underlying distribution, then the formula will have n-1

#

So basically the way the mathematical analysis goes is that you assume the underlying distribution has some expected value mu, then you form a new random variable according to the sample variance formula where

R = 1/(N-1) * ( (X_1 - mu)^2 + ... + (X_N - mu)^2 )

#

and if you compute the expected value of this random variable (i.e. R) then you'll notice that it perfectly lines up with the standard deviation of X_1

#

So presumably, hopefully, if you plug in your samples in place of X_1, ..., X_N, you'll get a good estimate for the standard deviation

#

If you know mu, you're golden

#

If you don't know mu, then you need to guess

#

And a good estimator for that is the sample mean

#

Because if you define the random variable

Q = (1/N) * (X_1 + X_2 + ... + X_N)

then its expected value will be the expected value of X_1

#

which is quite wonderful

#

So, a magical random variable R has the property that its expected value is the standard deviation of X_1, therefore we call it an unbiased estimator

#

A magical random variable Q has the property that its expected value is the expected value of X_1, therefore we call it an unbiased estimator again

#

And when you use an estimator, you essentially get a sample of the magical random variable

#

Now, because the process is random, it's entirely possible that the sample mean gives a completely wrong estimate for the mean, or the sample variance gives a completely wrong estimate for the variance

#

But, nonetheless, the expected value of the magical random variable matches what its trying to estimate

lean hull
#

I wish i can hear this explanation in real life

#

Text is so confusing imo

near crag
#

There are many layers of abstraction here and I think the reason that this stuff is often confusing is because statisticians try to make it seem less abstract than it really is

calm coralBOT
#

@pearl crag Has your question been resolved?

near crag
#

So first, you have a random variable X that models the height of a single person

Then, you have 100 random variables X_1, X_2, ..., X_100 that model an experiment where I go and measure the heights of a 100 people (these are identically and independently distributed)

Now, let's say I don't know the mean or the variance of X_1

I can define a new variable

Q = 1/N * (X_1 + X_2 + ... + X_100)

That has the property that its expected value is the same as the expected value of X_1.

I can define another random variable

R = 1/(N - 1) * ( (X_1 - E[X_1])^2 + ... + (X_100 - E[X_1])^2 )

whose expected value is the same as the variance of X_1.

Therefore, to have a reasonable guess for the mean and variance of the human height (assuming it follows a probability distribution where those quantities are well-defined), I should evaluate Q to get the mean and R to get the variance. I can't evaluate R without knowing E[X_1], but I can fix that issue by just using the estimate I got from evaluating Q

#

Of course this is just the big picture idea. Showing that E[Q] = E[X_1] is perhaps quite easy, but showing that E[R] = Var[X_1] might require some work

lean hull
#

Im struggling to comprehend tbh

#

My stats is terrible and i need to improve

near crag
#

If you look up the Wikipedia page for an estimator, nowhere does it state that an estimator is essentially just another random variable that you evaluate based on your data. I think that's the crucial understanding that statisticians want to sweep under the rug for some reason

#

Like that description is technically not wrong but it reads to me the same as saying "An integral is a rule for computing the area under a curve"

#

Like yeah okay that's true but you're really obfuscating the mathematical details

lean hull
#

I mean a intergal is exactly that?

#

Its a rieman sum

near crag
#

The very first sentence on the Wikipedia page for an integral says "an integral is the continuous analog of a sum"

#

which is already giving mathematical intuition

#

You can describe literally any mathematical construct as "a rule for computing X" but that's just stupid lol

lean hull
#

That is just over complicating it

boreal rose
#

that might literally be the problem

lean hull
#

I don't even understand what a continuous analog means

boreal rose
#

somethings are oversimplified at the expense of important details

boreal rose
#

instead of discrete

lean hull
#

Yh a rieman sum

#

Is enough no?

boreal rose
#

no not always

lean hull
#

Rieman sum is continuous sum, ive questioned it once but a summation doesn't need to be discrete no?

#

Im only alevel fm student so im not well rehearsed on thsi stuff

#

Just more about computing it in my syllablus so correct me if im wrong

boreal rose
#

riemann sums can be quite inaccurate for some integrals

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#
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stable hollow
calm coralBOT
stable hollow
#

why would my teacher have done this when yo ucan just mannipulate it into sec=sec

#

and if you did it that way you would not need to cehck for npvs? or no

#

also whats the point of calclating the npv for this quesiton in the first place

stable hollow
# stable hollow

, i also dont even know what is hapining on the left side as a whole

#

what is that for?

lean hull
#

Npvs?

#

Npv??

near crag
#

but you should investigate when tan(theta) / sin(theta) is a valid expression

#

and when 1/cos(theta) is a valid expression

#

and presumably you'll get different results

#

does it count as an identity, well equality holds wherever both sides are defined

#

but that doesn't necessarily mean they're the same function

#

so you should probably ask your teacher how they feel about that

#

in any case I think this is a completely trash horrible exercise that makes students not really focus on the right things

#

but you should not tell your teacher that

#

The problem is that the way functions are handled in high school is so sloppy that it's very easy to generate questions regarding singularities that are difficult to answer

#

Like does the function "x/x" have a limit at 0. I think most teachers would say yes even though the function isn't defined there

#

And that's not necessarily an issue since we also speak of the limit of the difference quotient as h->0

#

but if we choose this path then you can have a function that is not defined on a large strip. And do limits exist somewhere on that strip? For logical consistency you would have to say yes, but what is the limit? Well logically speaking the limit could be any real number. And now we're making some very unorthodox claims about limits. Kinda my point is that in high school we just don't have the nuance to talk about these things properly, so any teacher attempting to get philosophical with these is probably just shooting themselves in the foot

#

Because at the end of the day these things depend exclusively on the way mathematicians like to define things, and definitions can vary...

calm coralBOT
#

@stable hollow Has your question been resolved?

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halcyon ore
calm coralBOT
halcyon ore
#

How come when i put it in my casio calc

#

I get 6.49x10^21

#

I used to just do a fraction bar on my ti84 and it fixed the problem but ti84s are banned from my class now

bold hatch
halcyon ore
#

Oh

calm coralBOT
#

@halcyon ore Has your question been resolved?

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pastel igloo
calm coralBOT
pastel igloo
#

What type of math is this?

#

I dont know what to use

#

What do you mean

serene talon
#

like the word "combination"

pastel igloo
serene talon
#

actually this is more sophisticated

#

this is a diphantine equation, you need to write it using whole numbers , like this

#

write it in cents
price of bananas is 60, number of bananas b
price of strawberries is 75, number of strawberries s
price of water is 80, number of water units (bottles or whatever) w

#

you want to solve
60b+75s+80w=1480

#

an equation when youre dealing with whole numbers is called a Diophantine equation

#

this is much easier to do when:
a) you have only two variables
b) you limit yourself to all integers, positive and negative, and then at the end discard solutions with negative numbers
follow so far?

pastel igloo
#

Im following

pastel igloo
#

Diophantine equation 😭

serene talon
#

okay let's firs tmake sure there is a solution so we dont waste time looking for somrthing that doesnt exist

#

,w solve 60b + 75s + 80w = 1480 in integers subject to b>=0, s>=0,w>=0

potent lotusBOT
serene talon
#

boo okayu we'll do it by hjand

#

as I said it's much easier with two variables so I will introduce a fake variable
X=60b+75s

#

the equation becomes
X+80W = 1480

pastel igloo
#

Yeah

serene talon
#

theorem: this has a solution (allowing for negative integers) precisely when gcf(1,80) | 1480

#

similkarly the original has a solution precisely with gcf(60,75,80)|1480

#

the lines mean "divides" , like "is divisible by" but the other direction

#

,w gcf(60,75,80)}

serene talon
#

good , original has a solution

#

actually you know what

#

now that we know that it' divisible by 5 throughout

#

let's divide it by 5 throughout!

#

we get:
12b+15s+16w=296

#

let X = 12b+15s

#

X+16W=296

#

now this is annoying

#

but we can do this

#

have you seen modular arithmetic before? things like: a≡4 (mod 6)

#

if not, it's less intimidating then it looks

pastel igloo
#

Is modular arithmetic when you get remainders?

#

is it the same as modulous

serene talon
#

it's related

#

8/3 = 2 r 2 right

pastel igloo
#

yeah

serene talon
#

so we write 8 ≡ 2 (mod 2)

pastel igloo
#

Ohh

#

i see

serene talon
#

11/7 = 1 r 4

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so 11 ≡ 7 (mod 4)

pastel igloo
#

yeah

#

Okk

serene talon
#

okay so, using a computer to make things faster

#

12b+15s+16w=296
let X = 12b+15s
X+16W=296

#

,w prime factorization of 296

serene talon
#

great, so, watch this

pastel igloo
#

My eyes are open

serene talon
#

X+16W=296 , let's divide bhoth sides by 8 and take remainders

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X ≡ X (mod 8), doesn't really help

#

16W ≡ 0 mod 8 though!

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because 16W is a multiple of 8

pastel igloo
#

YEAH

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and so is 296

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so 16 goes away

#

?

serene talon
#

so we have:
X+8 ≡ 0 (mod 8)

pastel igloo
#

X = -8 mod 8

serene talon
#

X ≡ -8 (mod 8) let's put that to the side

#

yeah

#

what was the other factor

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37

pastel igloo
#

37

serene talon
#

by the way in theory

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you dont have to use all factors, you could use just 37, or just 2

#

but im assuming solving all of them will be helpful

pastel igloo
#

Yeah

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Theres 4 solutions apparently

serene talon
#

296 ≡ 0 (mod 37)
X≡X (mod 37)
16w≡ ... uhh, hmm

#

any recommendations?

pastel igloo
#

not sure 😭

#

Watermelon

serene talon
#

looking up what to do, I forgot

#

okay it doesnt simplify without knowing what w is

#

however we had before

#

12b+15s+16w=296

#

$\begin{cases} 16w \equiv -12b - 15s \pmod {37} \ X \equiv -8 \pmod 8\end{cases}$

potent lotusBOT
#

gfauxpas

pastel igloo
#

Yeah

serene talon
#

and might as well go back to how we defined x actually

#

X= 296-16W

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$\begin{cases} 16w \equiv -12b - 15s \pmod {37} \-16w \equiv -8 \pmod 8 \end{cases}$

potent lotusBOT
#

gfauxpas

serene talon
#

ah, great

pastel igloo
#

😭😭

serene talon
#

no, it's good, we split the equation itno 2 simpler ones

pastel igloo
#

Okk

serene talon
#

except

#

the second one isnt useful lol because it's just saying 0=0

#

so we have:
$15w \equiv -12b - 15s \pmod {37}$

pastel igloo
#

Im watching a yt video about it rn too

#

😭😭

#

This is so cooked

potent lotusBOT
#

gfauxpas

serene talon
#

alright, let's see

#

I have a better approach

#

12b+15s+16w=296

#

I thougth of this now, didnt see it earlier

#

we have 2,2^2,2^3, 37 | 296

#

so let's just take all 4 of those and mod the equation

#

mod 2 gives
s=0 (mod 2) because the other coefficients are even

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mod 4 gives

#

3s = 0 (mod 4)

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mod 8 gives
12b+15s+0=0 (mod 8)

#

and mod 37 gives

#

12b+15s+16w=0 (mod 37)

#

working on it

#

sorry im not particularly good at this, i need to look things up

#

gcf(3,4) = 1, so
3s = 0 (mod 4)
simplifies to
s = 0 (mod 4)
because a number cant magically become divisible by 4 by multiplying it by 3!

serene talon
#

and s=0(mod 4) is a stronger statement than s=0(mod 2), so we can get rid of the latter. if it's divisible by 4, it's divisible by 2, but not vice versa necessarily

pastel igloo
#

I saw a video on triple unknowns

#

With diophantine

serene talon
#

so,
s=0 (mod 4)

#

ahah

#

great

pastel igloo
#

Let me send it here

#

Acc

serene talon
#

for 12b+15s = 0 (mod 8)

pastel igloo
serene talon
#

we can replace "s" with "4t", because, s is divisible by 4! t is any whole number

#

so remember s = 4t
12b+15s=12b+60t=0 (mod 8)

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60 mod 8 is 4

#

so 60t mod 8 is 4t also

#

replace 60t with 4t

#

12 / 8 = 1 r 4

#

so 12b = 4b (mod 8)

#

so 12b+60t=4b+4t=4(b+t) mod 8

#

okay 4(b+t) considered mod 8 is tricky

#

because dividing by 4 can ruin the divisibility by 8

#

but it cant ruin divisibility by 2 , because (b+t) has to be even for 4(b+t) to be a multiple of 8

#

so we have
b=-t (mod 2)
s=0 (mod 4)

#

but t = s/4

#

b=(-s/4) (mod 2)

#

now you normally cant multiply both sides of a congruence by -1 because that's not the same thing as multiplying by 1 most of the time

#

but -1 = 1 (mod 2) so with mod 2 you can!

#

replace -s/4 with s/4

#

b=s/4 (mod 2)

#

we have:
s=0 (mod 4)
b=(s/4) (mod 2)

#

and I'm getting tired so im gonna leave it at that
you still need to work on:
16w=-12b-15s (mod 37)
but im getting sleepy sorry

pastel igloo
#

Hii

#

Thank you for your help

pastel igloo
#

Good night

#

I might sleep too

#

This is pretty cool icl

serene talon
#

$\begin{cases} s = 0 \pmod 4 \ b \equiv \frac s 4 \pmod 2 \ 16w=-12b-15s \pmod {37}\end{cases}$

potent lotusBOT
#

gfauxpas

serene talon
#

the third one is not simplified

#

asking a computer, it turns into

#

w=27b + 6s (mod 37)

#

with the same kind of sorcery we've been using so far but im too tired to do it by hand

pastel igloo
#

😭

#

Im learning it rn

serene talon
#

$\begin{cases} s = 0 \pmod 4 \ b \equiv \frac s 4 \pmod 2 \ w=27b+6s \pmod {37}\end{cases}$

potent lotusBOT
#

gfauxpas

serene talon
#

so this is enough to find a solution

#

pick any s divible by 4. once you choose s, choose b = s/4 (mod 2)

#

meaning (b-s/4) must be even

#

and then once youve chosen b and s, you find w, and if w is larger than 37, take remainders!

#

or, well

#

pick the multiple of 37 that makes sense

#

@pastel igloo I asked a computer to find all non-negative solutions using our congruences, here it is
(b,s,w) triples with non-negative values:

(2, 0, 17)
(6, 0, 14)
(10, 0, 11)
(14, 0, 8)
(18, 0, 5)
(22, 0, 2)
(1, 4, 14)
(5, 4, 11)
(9, 4, 8)
(13, 4, 5)
(17, 4, 2)
(0, 8, 11)
(4, 8, 8)
(8, 8, 5)
(12, 8, 2)
(3, 12, 5)
(7, 12, 2)
(2, 16, 2)

#

gn

pastel igloo
#

I was gonna ask my calc teacher

#

Tomorrow

#

If he knows how to solve diophantine equations

serene talon
#

maybe you ddint realize how difficult this problem is lol

pastel igloo
#

I was helping my brother and this was on his assignment

serene talon
#

diophantine equations can get really tricky really quickly

pastel igloo
#

And i was so confused cuz it doesnt seem that easy

#

😭😭

pastel igloo
#

Okk gn

#

Im bouta pass out

#

Thank you

#

.close

calm coralBOT
#
Channel closed

Closed by @pastel igloo

Use .reopen if this was a mistake.

#
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steady dome
calm coralBOT
steady dome
#

Where am I wrong

untold summit
steady dome
#

But why I have to

serene talon
steady dome
untold summit
#

you should use the sub u = a - x

#

but yes also you are missing + C

steady dome
#

What

serene talon
steady dome
serene talon
#

is what what you were integrating?

steady dome
#

Huh?

untold summit
steady dome
untold summit
#

what is the derivative of log(x)

steady dome
#

1/x

untold summit
#

ok so what is the derivative of log(a-x)

steady dome
#

-1/log(a-x)

untold summit
#

no

#

do you know the chain rule

steady dome
#

Yes

untold summit
#

what is it

steady dome
#

I did it with the chain rule

untold summit
#

write out the chain rule

steady dome
#

Ohh

#

Yes my fault

#

-1/(a-x) or 1/(a+x)

untold summit
#

well which do you think

steady dome
#

@untold summit

#

Both

untold summit
#

well it can only be one

steady dome
#

1st one

untold summit
#

yes

#

you should write out the chain rule explicitly to prove it to yourself

steady dome
untold summit
#

yes we'll get back to that

#

first this

#

what does d/dx f(g(x)) = ?

steady dome
#

f(x)g′(x) + f′(x)g(x)

untold summit
#

no thats product rule

#

thats d/dx f(x) * g(x)

steady dome
#

What u asking

untold summit
#

chain rule

#

d/dx f( g(x) ) = ?

steady dome
#

I will write it down and sendu

untold summit
#

yes perfect

#

so when we want to find d/dx ln(a - x)

#

what is f(x), what is g(x)

steady dome
#

Log (a-x) is f ad (a-x) is g

untold summit
#

no

#

g is correct

#

f is not

#

log(a-x) is f(g(x))

#

you know that g(x) = a -x

steady dome
#

That's what I wrote

untold summit
#

no you said f is log(a- x)

#

that is not correct

steady dome
#

Mhm

#

Ok

untold summit
#

what could f(x) be

steady dome
#

Log(a-x )

#

Idk

untold summit
#

no

steady dome
#

So what

untold summit
#

ok seperate scenario

#

if i say f(x) = x^2 and g(x) = x - 3 then what is g(f(x)), what is f(g(x))

steady dome
#

(x-3)^2

untold summit
#

for which

steady dome
#

What

untold summit
#

i asked you what g(f(x)) was and also what f(g(x)) was

#

you gave one answer

#

so which question are you answering