help-42

[potent lotus]

depression

[bold bear]

And that will give you a value for a

That make sense?:

[hardy spindle]

i cant do that equation cuz we never learned it

[bold bear]

There's nothing special about -3 and 1 other than that f(those values)=0

But you can use it

okay

Put it like this

[hardy spindle]

but what do i replace x with

[bold bear]

You know that $y(x) = a(x+3)(x+1)$

[potent lotus]

depression

[sonic snow]

nothing

like x as x

dont change it

[hardy spindle]

then i cant find a

[sonic snow]

oh like that nvm mb

[bold bear]

So if you want to solve for $y(x_0)=y_0$ then that gives you $a(x_0+3)(x_0-1)=y_0$

[potent lotus]

depression

[bold bear]

Rearrange that and you get your value for a

Choose any $x_0$ you want

[potent lotus]

depression

[bold bear]

I recommend either 0, -3, or 1 because that will make the calculation easier

[hardy spindle]

wait

i pick?

[bold bear]

You should get the same answer regardless

[hardy spindle]

alr lemme try

i got a = 2

@bold bear

[bold bear]

Nearly

How did you get that?

[hardy spindle]

i did

6 = a(1+3)(1-1)

[bold bear]

Alright but y(1) = 0

Not 6

[hardy spindle]

how

[bold bear]

Also I have just realised that you can't use -3 or 1 because you don't really get any information

[hardy spindle]

oh

[bold bear]

0

[hardy spindle]

this is x

when y is0 x is what

theres 2 of that

1 and -3

[bold bear]

At x=1

The line is at y=0

So y(1)=0

That's what the plot is

[hardy spindle]

what does y(1) mean

[bold bear]

the y value at x=1

y is a function of x

[hardy spindle]

ohh

so whats the value of y when x is 1

its 0 tho

[bold bear]

That's what the graph says

[hardy spindle]

my idea here would be

to use canonic form

since we have h,k

so f(x) = a(x-h)^2 + k

h is -1 and k is 8

[bold bear]

You can do that too

It doesn't really change the question

Here's an easier version bc I don't think you really understand

Let's say I have a function

$f(x) = x+a$

[potent lotus]

depression

[bold bear]

Where a is some constant

And I know that f(20) = 25

What is a?

[hardy spindle]

-5

[bold bear]

Check again

[hardy spindle]

0.8

[bold bear]

$20 + a = 25$

[potent lotus]

depression

[hardy spindle]

5

[bold bear]

Yeah

5

Have you done that sort of thing before?

[hardy spindle]

no lol

[bold bear]

Interesting

Does it make sense?

[hardy spindle]

im tryna understand

but how does it correlate tho

20 is x

[bold bear]

Well we've got pretty much the same thing

[hardy spindle]

so then we have y

[bold bear]

$y(x) = a(x+3)(x-1)$

[potent lotus]

depression

[bold bear]

And $y(0)=6$

[potent lotus]

depression

[bold bear]

So you can use that to solve for a

[hardy spindle]

the thing is idk what thats supposed to be

cause i dont solve it like that

[bold bear]

How do you normally solve it?

[hardy spindle]

basically if we have a missing variable

u take the same equation

[hardy spindle]

from here

and u replace what u found

from the graph

so lets say u found x

u do it normally

and isolate a

[bold bear]

Yes

That's exactly the same

[hardy spindle]

same as y(0) = 6?

[bold bear]

You know from the graph that if x=0, then y = 6

Or if x = -1, y = 8

For any pair of values, you can substitute them for x and y, then solve for a

There isn't an individual x value

x doesn't have a value on its own

it's just a symbol

[hardy spindle]

so i dont find x

[bold bear]

x can be absolutely anything

from $-\infty$ to $\infty$

[potent lotus]

depression

[bold bear]

But for every value of x, there is a corresponding value of y

[hardy spindle]

yes

[bold bear]

So you can pick your favorite value for x, and the corresponding value of y

[hardy spindle]

alr and what form am i using

[bold bear]

Substitute them into this equation

And solve for a

[hardy spindle]

ok

[bold bear]

It doesn't matter

[bold bear]

(that was responding to this)

[hardy spindle]

can i pick x = 0 and y 6

[bold bear]

Yep

[hardy spindle]

itght

i got a = 4

[bold bear]

How did you get that?

[hardy spindle]

i did

6 = a(0+3)(0-1)

[bold bear]

You're missing a minus sign

[hardy spindle]

yeah i meant

0-1

mb

then

6 = a +3-1

right

6 = a + 2

-2 both sides

a = 4

[bold bear]

Where did the + come from?

[hardy spindle]

cause its 3-1

which is 2

[bold bear]

No it's not

it's 3 * -1

Which is -3

When you put brackets together that means you multiply them

[hardy spindle]

wait so its 6 = a(3)(-1)?

is that what ur saying

[bold bear]

Otherwise it would be $y = a + (x+3) + (x-1) = a + 2x - 2$

Yes

[potent lotus]

depression

[bold bear]

Which is a completely different equation

[hardy spindle]

why we didnt remove it tho

[bold bear]

Wdym

[hardy spindle]

like after doing 0+3 and 0-1

usually we have to remove the paranthese no?

[bold bear]

You can multiply them out

You can't literally just remove them though

That changes the meaning of the equation

$y = a\cdot(x+3)(x-1)$

[potent lotus]

depression

[bold bear]

$6 = a\cdot(0+3)\cdot(0-1)$

[potent lotus]

depression

[bold bear]

$6 = a\cdot3\cdot(-1)$

[potent lotus]

depression

[hardy spindle]

why did u keep

that -1 parathense

[bold bear]

Does that make sense?

[hardy spindle]

and remove the other one

[bold bear]

It just clarifies that -1 isn't 1 being subtracted from something

It's pure notation

[hardy spindle]

no ik what it does

but why didnt u remove the paranthese

like

why keep it

[bold bear]

If I didn't have the dot then it would be the difference between $a-3$ and $a(-3)$

[potent lotus]

depression

[bold bear]

Those mean completely different things

You can't just put two operators next to each other otherwise it's not clear

There isn't a mathematical reason, it's just harder to read

[hardy spindle]

oh

alr

then i get

a = -2

[bold bear]

Yeah

So there's your answer

[hardy spindle]

alr but now its asking me

the rule

in factorised form

so in the same form

we were doing

the rule is 6 = -2 (0+3)(0-1)

rght

[bold bear]

No

That's a specific value for x and y

[hardy spindle]

replace the 0's with x

oh

f(x) = -2(x+3)(x-1)

[bold bear]

y is a function of x, y is not a number

Yes

Well done

[hardy spindle]

tysm bro

[hardy spindle]

alr

ok but

can u define

function

cause im not going to an english school

so when ppl say function and stuff like that its kinda hard to know

[bold bear]

une fonction

je pense

It takes a value of x, and it spits out a new value

[hardy spindle]

do u mean like

when y is something

x is something

so like pairs

[bold bear]

Yes

For example if $y=x^2$

[potent lotus]

depression

[hardy spindle]

so doesnt that mean x is a function of y

[bold bear]

Then y(1) = 1, y(2) = 4, etc

No

It can be

But in your example y is a function of x

x is not a function of y, because if y = 0 then x = -3 or 1

x doesn't have a unique value

[hardy spindle]

ohhhh

[bold bear]

You specify an x value and out comes a y value

[hardy spindle]

alr ty dude

[bold bear]

Np

[hardy spindle]

.close

[calm coral]

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[odd moon]

find the coordinates of D? that's hard to read

[knotty cosmos]

yes

oh shit thats long

its a link to the notes n stuff like idk

[swift dragon]

uhmmm

just take a screenshot

[pure kayak]

oh lord

[drifting seal]

nice

[knotty cosmos]

<@&286206848099549185>

[olive orchid]

Ok I am not like professor or what

But I am just thinking of find equation of both line

And for circle just use circle equation and plug in both equation

[knotty cosmos]

i think my tutor guy (who wrote the equation)

told me the other one was y=x

wait no

nvm

[knotty cosmos]

wait

what is this..

[olive orchid]

Oh dw it’s just the equation for the line

[olive orchid]

I am thinking of this

If we move all the lines equation in a equal distance of r (radius)
Eg:
let R be radius
line B we move it’s equation ‘s x by -r

Line C we move it’s equation’s y by +r

Line A we move it’s equation’s x by +r

And then plug into simultaneous equation because meet same point

[knotty cosmos]

iiiim so sorry but

im 100% lost

100% confused

[olive orchid]

Oh I am sorry

[knotty cosmos]

its not ur fault dwdw

[olive orchid]

Oh u found the values

[knotty cosmos]

im js

nope

thats a different thing

didnt mean to send tat

[olive orchid]

Oh

OPPs

Wait

Let me think if there are easier way to solve it

[knotty cosmos]

thanks

[olive orchid]

Oh ye have u found coordinate D?

[knotty cosmos]

i dont think so

[olive orchid]

The first one (lebellled 1) is the equation for the positive gradient pass 0,0

[olive orchid]

The second one is for the perpendicular

And we can find point D through simultaneous equation

Is that okay for u?

I mean do u get what i mean

[knotty cosmos]

wh ats

simultaneus equation

[olive orchid]

Plug both equation into one

[knotty cosmos]

i thought the equation for that was root 3 x

[olive orchid]

Oh yes it is

My bad it is 2am for me

lol

Silly me

[knotty cosmos]

u should sleep gng..

oh wait

the equation for

[olive orchid]

Is ok I like maths

[knotty cosmos]

yeah

cuz its perpendicular

[olive orchid]

Yes

So we can solve it through plugging them together

And this question is so intresting that I am gonna stay awake

[knotty cosmos]

oh

wow

[olive orchid]

Have u found it yet

Coordinate for D

[knotty cosmos]

uhh

howw do i do that..

[knotty cosmos]

Ohh right

[olive orchid]

oh ye wait I missed sth

[olive orchid]

For the second equation
We need to find c for the y = mx + c

[knotty cosmos]

ohh for y2

[knotty cosmos]

-4??

[olive orchid]

?

[knotty cosmos]

ohh cuz u plugged in 4,0

[olive orchid]

Yessss

And then overalll

D = ( 1 , 1.732…)

[knotty cosmos]

i usually leave in in fraction form i think

thats what my reacher does

[olive orchid]

I think no fraction for that decimal

Prob it is wrong due to some Fi my calculation mistakes

[knotty cosmos]

oh wait mb

i wasw thinking smt helse

[olive orchid]

Okie

Now we need to find the circle

[ancient grotto]

We could just use a bit of similar triangles and/or Pythagorean, no?

[knotty cosmos]

i think that was what i was supposed to do

something about 1 1 and root 2 and

1 2 and root 3

idk i wasnt paying attention

[ancient grotto]

Yeah, quite a few ways to do part (2).

[ancient grotto]

Okay.

Tell me the angles inside triangle ADC. Then use the Pythagorean Theorem to find the radius.

[knotty cosmos]

uhh

90

60

30?

[ancient grotto]

Yep.

[knotty cosmos]

how do the angles

help

dont i need length for pythagorean theorem

[knotty cosmos]

how

[olive orchid]

Wait

[knotty cosmos]

iss that right

did u multiply by root 3

[olive orchid]

Yes

[knotty cosmos]

whered it go on the root 3 side

oh nvm
thats

wright

[olive orchid]

Cancel out

[ancient grotto]

You can just use the properties of 30-60-90 right triangles instead.

@olive orchid Why are you solving it for them?

[olive orchid]

Which

[olive orchid]

Is right triangle 100% 30-60-90?

[olive orchid]

Oh I am trying to like learn with them

[ancient grotto]

Both questions.

[ancient grotto]

Yes.

[knotty cosmos]

honestly, its fine

im still learning from it

[olive orchid]

Oh sorry

[ancient grotto]

!nosols exists for a reason.

[calm coral]

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

[olive orchid]

I am not like profession (helper) or what but I wanna get better with people

[olive orchid]

Ohhh

Wait fr?

[ancient grotto]

Yeah, but you should solve it on your own, then guide OP through the process.

[ancient grotto]

Yes. Notice the slope of the line.

[knotty cosmos]

whats.. that..

[olive orchid]

what slope

[knotty cosmos]

root 3 x

is the slope

i thinmk

[ancient grotto]

y_1=sqrt(3)*x.

[olive orchid]

Oh what about it

[knotty cosmos]

cuz

its perpendicular right

so like

theres a 90 degree angle

[ancient grotto]

Notice that the arctangent of a slope is the angle it makes with the x-axis.

[knotty cosmos]

and then the hypotenuse or whatvev

is straight up

so ,liiek

idk what im saying

[olive orchid]

Sorry I not quite get it

[ancient grotto]

This is the main thing.

[olive orchid]

What’s arctangent?

Let me search rq

[ancient grotto]

So y_1 makes a 60 degree angle with the x-axis.

[ancient grotto]

$\tan^{-1}(x)$.

[potent lotus]

;(

[olive orchid]

I am too stupid I still don’t get it

Cooked

[ancient grotto]

Hmm.

[knotty cosmos]

its okay twin

[ancient grotto]

You can open your own help thread once I am done here, and I (or someone else) can answer your questions about this.

For now, this is kimchi’s help thread.

[olive orchid]

Oki sorry and thanks

[knotty cosmos]

wait

does d=(x,sqrt3)?

[ancient grotto]

Show your work. And what is x?

[knotty cosmos]

i meant 1

sorru

[ancient grotto]

Then yeah.

[knotty cosmos]

okay

okay then back to finding r

how does pythagorean theorem help?

[ancient grotto]

Label the center of the circle R, and the rightmost tangent T. Draw the line CR, and notice the relationship between the sides of the triangle (formed by CR, CT, and TR.)

[knotty cosmos]

what is a tangent?

OH WAIT IVE DONET HIS

hold on

cuz like

those make 3 triangles

and if u split the triangles again

then its a bunch of right triangles

right?

[ancient grotto]

Yeah.

[knotty cosmos]

okay so

how

do i find the lengths?

wait nvm i think i go ti

t

what do i do after that though?

[ancient grotto]

Find r. Show me what you have.

[knotty cosmos]

okay, give me a few minutes

my mom is being annoying

[ancient grotto]

Lol

[knotty cosmos]

do i find the length of dc

by plugging it 4,0 into

wait no nvm

do i use

distance formula

or whatveer

[ancient grotto]

Sure.

[knotty cosmos]

okay

sorry, annoying mom again

dc=sqrt12??

or sqrt6?

i feel dumb for asking but im confusing myself

[calm coral]

@knotty cosmos Has your question been resolved?

[calm coral]

@knotty cosmos Has your question been resolved?

[knotty cosmos]

<@&286206848099549185>

[ancient grotto]

Yes.

[knotty cosmos]

okay

[ancient grotto]

Sorry, I’m about to go to sleep.

Getting late over here.

[knotty cosmos]

all good

i kinda gotta hurry anyway

so im js gunna willy nilly it

cuz its due in like 10 minutes

[ancient grotto]

Ok.

[knotty cosmos]

thanks for ur help!

.close

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[calm coral]

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[hushed flare]

this is what I have so far

the question states that at t=0 the blade should be at a minimum

so that means I need a y value of 8 to be at x=0 right?

everytime I do this i get a totally different answer and I'm not sure whats going wrong, I've reached a shift of 4.5, 2.5, 1.25 and pi

what I did was graph the function WITHOUT including a c parameter, then I found the nearest minimum point (4.5, 0) and used that to shift all the way over, that way I'd get t(0) = 8

but everytime I seek any AI assistance theyre telling me its pi or 2.5

at one point I got 2.5 aswell but I can't replicate it to make it make sense graphically

<@&286206848099549185>

[calm coral]

@hushed flare Has your question been resolved?

[calm coral]

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[oblique echo]

i need help with this problem, how should i start solving this?

[fiery basalt]

have you learnt implicit differentiation

[oblique echo]

our lesson is currently on that topic, this is a practice sheet my prof gave us, do i need to do implicit differentiation before solving for the tangent line?

[fiery basalt]

we use implicit differentiation to find dy/dx, which is the slope

then we plug in the point to find dy/dx

[oblique echo]

i'll try solving and come back later for answer confirmation, thanks!

.close

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[tiny sand]

guys I'm stuck

[soft scarab]

@undone nova

[undone nova]

a

[primal bear]

!status

[calm coral]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[vagrant oak]

3

[tiny sand]

2

[vagrant oak]

Just plug in 2 and see what you get

[undone nova]

use L hospitals rule

[tiny sand]

what?

[velvet osprey]

bad

[undone nova]

it's in 0/0 form

[velvet osprey]

is it

[vagrant oak]

what do you get when you plug in 2 to that expression you got?

[primal bear]

[undone nova]

it is

[soft scarab]

most people hate it

[velvet osprey]

the original might be

[tiny sand]

√2/0

[velvet osprey]

but also lhop is brain poison

[primal bear]

he's basically there

[vagrant oak]

Yeah, which is not indeterminate

[tiny sand]

yeah lol

[primal bear]

oookay but we're not done though

@tiny sand can you find the LHL?

[soft scarab]

cheating

[tiny sand]

what is LHL

[vagrant oak]

left hand limit i think

[tiny sand]

lol

[soft scarab]

left hand limit

[vagrant oak]

now that you got this, the last step to do is basically just deciding whether it's +inf, -inf or neither (so the limit DNE)

and to do that, you need to compute both the one-sided limits

[tiny sand]

damn that gets too hard

[tiny sand]

I think I ruined it lol😭

So it is not derivable.

-∞ is undefined

[undone nova]

limit probably doesn't exist then

[tiny sand]

in 2-

but in 2+

.close

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[valid trout]

[
\boxed{
\text{المعادلة } (E_n) \text{ لها حلول في } \mathbb{Z}^2 \text{ إذا وفقط إذا } n \not\equiv 4 \mod 5 \text{ أو } 2^n \equiv n \mod 5
}
]

[potent lotus]

BQBQ
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[calm coral]

@valid trout Has your question been resolved?

[calm coral]

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[calm coral]

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[dapper sable]

@lilac eagle Oh, sorry, I made a small mistake in the other channel. The multiples of x^2 are x^2, x^3, x^4. You can multiply it by x several times.

Then, you have the multiples of x are x, x^2, x^3, x^4. So, the first that appears in both lists is x^2.

[dapper sable]

.close

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[prime topaz]

Hi I don't get this part of the solutions

[calm coral]

@prime topaz Has your question been resolved?

[remote mural]

yo

we have the equations (1) and (2)

its right there marked in the question

we found lmda(1)

think what we must do to find lmda(2)

[prime topaz]

Wait i circled the wrong thing, I dont get the bit below that like how does that show the ratio

[remote mural]

Oooh

lemme solve the question

[prime topaz]

oki

[remote mural]

Hii

So

we know the AC vector right?

[prime topaz]

mhm

[remote mural]

AC vector = (lmda1)AP vector

Right?

[remote mural]

right?

[prime topaz]

right

[remote mural]

soo, there's a property

CP vector can also be written as?

[prime topaz]

λAP?

[remote mural]

nuh uh

ab = ob - oa

where ob and oa are position vectors

that form

[prime topaz]

op-oc

[remote mural]

well

since we need it in terms of a

we do ap-ac

got that?

[remote mural]

NEBULAA

[remote mural]

no

[remote mural]

see

lmda 1 =?

[calm coral]

@prime topaz Has your question been resolved?

[calm coral]

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[calm coral]

Channel closed

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[velvet osprey]

whoops you messed up the channel

[swift pier]

can somebody help me solve this problem

[swift pier]

what did i do

[primal bear]

.reopen

[swift pier]

.reopen

[primal bear]

f

[swift pier]

why isnt working

[warped solar]

[swift pier]

i have no idea on how this thing works

[velvet osprey]

!msgdel

[calm coral]

The original post of this help channel has been deleted, and it will abruptly close and possibly lock. (This is irreversible.) Please claim a new channel, and don't delete the first message of any future channel you claim.

[primal bear]

just use a different one atp

[velvet osprey]

you have to open a new channel

[swift pier]

letme get into a new one ig

[calm coral]

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[calm coral]

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[bleak thistle]

Hello , this is implicit differentiation and I just wanted to see if my answer’s correct the original relation is boxed in red

[bleak thistle]

I used partial differentiation to get to the answer

@ me when someone answers thanks !

[alpine current]

yeah using implicit differentiation you're right

[bleak thistle]

Is the result correct?

[alpine current]

yeah your y' is correct

[bleak thistle]

Okay thank you 😊

.close

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[wet herald]

can i have help marking my exam paper

i cant find this mark scheme anywhere its only about 10 questions

[pure kayak]

sure, send one at a time

[wet herald]

alr ty

[pure kayak]

3 marks for the first

but you havent shown any working on the second and i dont think the answer is correct

[wet herald]

how do i do it? or should i mark all the questions first w you then understand the mistakes? i dont mind either or

[pure kayak]

we can do either sure,

1200 is the upper quartile, so everything below is 75% of the days

[wet herald]

so is it 80*0.75

[pure kayak]

yeah

[wet herald]

oh alr, ty

[pure kayak]

(a) 2
(b)(i) 1
(b)(ii) 1

[wet herald]

huh?

[pure kayak]

im just saying the marks

you got them all

[wet herald]

ohhh

nice, ty

i was hella confused there

this next one tho i got no answer for it, i had no cluer

[pure kayak]

its a bit of a dodgy circle, if i recall arent you allowed a compass

i cant say if theyd give you one or two for that

actually, you will need a good circle to do ii

[wet herald]

i dont have a compass at home i think so the circl ekinda sucked but in the actual test i wouldve used one

[pure kayak]

the way you would do ii
is you draw the line y=3/2 x on the graph and look where it intersects the circle

[wet herald]

so the second mark is to bisect the cirle and the first mark is to draw it?

[pure kayak]

the first two marks are to draw the circle, id probably give you 1 for having the right radius

the next 3 are probably:
draw the line (1)
and then one mark for each point

[wet herald]

ohhhh alr

then what ius the equation there for

[pure kayak]

which equation?

[wet herald]

simultaneous equations

[pure kayak]

because youre solving them, thats what the three marks for (b) are

the way to graphically solve simul. equations is to graph them and see where they intersect

[wet herald]

so you get the line from the equation? how do you get the line

[pure kayak]

2y=3x rearranged to y=3/2 x

[wet herald]

and the y interscept is when you replace either y or x with 13 or 0 and then solve?

[pure kayak]

the y intercept is just 0

y=3/2 x + 0

[wet herald]

ohhhhhh right

so to draw the line do you just plot the points and draw a line of bestr fit?

[pure kayak]

its a straight line, so you could just plot one point and then draw the line that passes through it and the origin

[wet herald]

alr

thank you

lemme do that real quick

I can’t do it for some reason I’ll try a different question after

These 2 were on the same page so I just got this

[west shard]

GCSE woooo

[pure kayak]

what youve done in 4 is essentially say that a kilogram of anything costs the same

so sadly 0

you should have divided 480 by 5+9=16

[west shard]

@wet herald do you not have access to mark scheme?

[wet herald]

nope

[wet herald]

ty

[west shard]

if you dm me it I'm happy to mark it then

i wonder if mark scheme is online tho

[wet herald]

ty but @pure kayak is already helping me go through it, ill add you anyway tho

[west shard]

np

[wet herald]

ohh i accidently did 12 insteaad of 16

i did this tet 2 days ago so i dont remember everything well

[west shard]

are you on easter break?

[wet herald]

yup

[west shard]

that's why you're not at school lol

[wet herald]

ye

[west shard]

i recognise these questions - they're NOT from 2023 lol

or restricted to

[wet herald]

2023

[west shard]

i know i just read it

[west shard]

I very clearly remember this question

[pure kayak]

actually nvm scrap that
let 5x be the costs of 1kg of carrots, 9x be the cost of 1kg of tomatoes

then you can solve for x

[wet herald]

this test is so wierd, its ment to be non calc but i just did 480 / 14 to get x and its 34.28571429

[pure kayak]

yeah i realised i cant add at my big age

[pure kayak]

this will probably be easier

[wet herald]

lemme try

wait is it meant to be = to 480?

[pure kayak]

yeah

after you multiply

7(5x)+5(9x)=480

[wet herald]

.

i see how that works but i dont understand?

[pure kayak]

thats quite a gap

[wet herald]

the gap in my knowledge rn

[pure kayak]

since the prices are in the ratio 5:9 for 1kg
then then its 5x:9x is the same, we aim to find x

its 7kg of carrots so 7(5x)
and 5kg of tomatoes so 5(9x)

then we want their sum to be 480 so we just find x

[wet herald]

i feel like i need to do more questions of this topic so i can get it, do you know the name of it, or is it a mix of topics

[pure kayak]

it would just be ratios

[wet herald]

x = 6

so what is the p amount for carrots and tomatoes

[pure kayak]

the price of 1kg of carrots is 5x, and tomatoes is 9x

[wet herald]

oh so carrots of 30p

okay so how abt question 5

[pure kayak]

if error carry forward gets you marks, then maybe you could have 3

otherwise, maybe 1 or none

[wet herald]

btw after we do question 5 is it okay if i dm you the rest tommorow bc damn my head is burning from these quesdtuions not gonna lie

[pure kayak]

i dont really do dms but you can ping me

[wet herald]

alr bet

[pure kayak]

we're in the same time zone anyway

[wet herald]

really? wow

uk right?

[pure kayak]

yeah

[wet herald]

nice

alr i added you

well have a good day 👍🏾

[pure kayak]

for (5):
your working has some issues, like its * (4+root3)/(4+root3) not just 4+root3 but you do the process

then the denominator would be 16-3=13, not 12
i guess everything after doesnt work due to that

fix that and you should be fine

[wet herald]

alr

👋🏾

.close

[calm coral]

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[calm coral]

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[median cloak]

I would like to be engaged in some role-playing.

[median cloak]

with all of you being the participants.

I'm the professor of Harvard Math department.

I'm going to send you guys some question

you guys need to solve it in order to impress me.

[sharp wren]

@median cloak bro literally got preuni math role

I wonder what professor has pre uni math role

[median cloak]

I'm trying to make the question official.

[velvet osprey]

#chill

[sharp wren]

I'm a*

[velvet osprey]

nope

[sharp wren]

^

[median cloak]

As the diagram illustrates, P is inside the square ABCD. Given that PA=2, PB=3, and PC=4, what is the length of PD and the area of the square.

[minor gust]

https://tenor.com/view/cat-balloon-shaking-gifdopedrao-gif-18309166828393550457

[median cloak]

As the diagram illustrates, P is inside the square ABCD. Given that PA=2, PB=3, and PC=4, what is the length of PD and the area of the square.

[sharp wren]

Bro has no diagram

[median cloak]

Patient, youngster.

[minor gust]

Professor tough knuckles over here huh

[median cloak]

I got my pace, which, after couple classes of mine, you should find yourself being acquainted with.

[clear delta]

yeah no

we're not doing that here

[pale blade]

kinky

[clear delta]

if you need help with a math problem then ask that

otherwise

.close

[calm coral]

Channel closed

Closed by @clear delta

Use .reopen if this was a mistake.

[median cloak]

why

I did

I did asked my question

[clear delta]

• Show your work, and if possible, explain where you are stuck.

[median cloak]

can we reopen this channel please, I will do no more role-playing.

[clear delta]

ugh

.reopen

[tribal jetty]

You do have the power to do that yourself

[calm coral]

✅

[median cloak]

I cannot find the area of the square.

[minor gust]

god forbid a man catch a vibe with some role playing at 8 am

[velvet osprey]

not the place for it!

[median cloak]

Should I open a new channel. This one seems drifted from the question.

Of course, sir. You should have done it.

.reopen

.close

[calm coral]

Channel closed

Closed by @median cloak

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[calm coral]

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[bronze adder]

I just wanna outline my strategy for (a) here

I think I'm gonna have to use a sequence

that's doubly indexed?

[potent lotus]

shawarma

[bronze adder]

and prove that lim x_n = x is a limit point of A and thus must be in L

[upbeat venture]

that's the basic idea

I wouldn't doubly index tho just bc that's a bit confusing

[ancient thistle]

depending on how things have been defined for you it might be easier to prove the complement is open

[calm coral]

@bronze adder Has your question been resolved?

[bronze adder]

Uh I'll be back to this

[calm coral]

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[high basin]

May someone please help me with number 1 and 2

[high basin]

<@&286206848099549185>

[calm coral]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[tough prism]

wat u tried

[high basin]

@tough prism

[gentle salmon]

Hello. For 1), you can cancel all 2^k terms in numerator as it's a common factor

It's clearer if you first factor 2^k out in the numerator first

[high basin]

please show me

[gentle salmon]

Notice that in the numerator 2^k is a common term

so you can factor it

and then cancel it with the other 2^k in denominator

[high basin]

idk what you are talking about

[high basin]

how did that cancel?

because I do not see another 2k to cancel

[gentle salmon]

2^k below divides each term above. It divides both 2^k and 2^k 2^3

[high basin]

so if I do what you just showed me its fine?

[gentle salmon]

I think you should first factor 2^k in the numerator

and then cancel it with 2^k below

[high basin]

please show me how to do that please

[high basin]

oh🤦

what about number 2 is it correct?

[gentle salmon]

no

[high basin]

could you show me how to do it and where did i go wrong?

[gentle salmon]

you changed addition by multiplication

[high basin]

so it is supposed to be 1 over 2 plus 2 to the power of 5?

for the answer?

[gentle salmon]

No

The way you cancelled terms is also wrong

you should have 1 + 2 in the numerator

When you cancel something "it becomes" 1 not 0

[high basin]

ohhh

so its 3 over 2 plus two to the power of 5?

[gentle salmon]

no

do it again

considering the mistakes I mentioned

[high basin]

2 over 2 plus two to the power of 5

[gentle salmon]

That's a plus sign, not a multiplication

It's all correct until that part

Now continue carefully

[high basin]

oh my gosh man

2 over 1 times two to the power of 2 plus two to the power of 5

[gentle salmon]

numerator is wrong

[high basin]

one plust two?

[gentle salmon]

Yes but show your work if possible

[high basin]

alright let me try these again

@gentle salmon

[calm coral]

@high basin Has your question been resolved?

[gentle salmon]

https://tenor.com/view/theboys-perfect-gif-23821319

[high basin]

https://tenor.com/view/omg-hell-gif-454585956181663238

[high basin]

thanks man for the help!

[gentle salmon]

Ok no problem 👍🏽

[high basin]

.close

[calm coral]

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[calm coral]

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[patent cypress]

what is the inverse limit topology?

[patent cypress]

as in this example

[velvet osprey]

i'd imagine that speaking abstractly it's the coarsest topology under which all of the projections down to O/t^n O are continuous

[calm coral]

@patent cypress Has your question been resolved?

[calm coral]

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[patent cypress]

hmmm it's not clear why does it say that the rings are equiped with the discrete topology

[velvet osprey]

.reopen

[calm coral]

✅

[velvet osprey]

well you gotta have SOME topology on the rings being projected down to, don't ya

[patent cypress]

the one induced by the norm I think

[calm coral]

@patent cypress Has your question been resolved?

[calm coral]

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[calm coral]

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[fathom rock]

am i understanding this question wrong

[fathom rock]

$$\int_{1}^{2}\left(2x^{3}+1\right)dx$$

[potent lotus]

Thyroxine

[fathom rock]

this is the solution in the textbook

im confused

[leaden thunder]

that solution looks like a completely different problem

[fathom rock]

thanks for confirming, i will bring this up to the prof, thought i was going crazy

[calm coral]

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[fresh imp]

not quite sure what to do here

[calm coral]

@fresh imp Has your question been resolved?

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[ebon nexus]

how do i solve this without a calculator? i did laws of sins, so like BC/sin50 = 10/sin30. but i can’t solve sin 50 without a calc, so what do i do?

[leaden thunder]

why can't you leave it exactly as sin(50 deg)

[ebon nexus]

idk if i can cuz my teacher doesn’t allow calculators

[leaden thunder]

that's a question for your teacher

[ebon nexus]

wait so like it’s not possible to do it any other way than to leave the answer as 20sin50?

[leaden thunder]

define "possible"

calculators are fine

[glossy pulsar]

Do u have to write as a integer or can it just be like sine50?

[calm coral]

@ebon nexus Has your question been resolved?

[calm coral]

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[gleaming hare]

Why the point (1,2,3) on this second order taylor polynomial for a multivariable function is a local maximum, not a saddle?

[gleaming hare]

I calculated the determinant of the hessian matrix on the rightmost term, and got -3, which suggested to me that every critical value of that function is a saddle point

[calm coral]

@gleaming hare Has your question been resolved?

[elder pawn]

@gleaming hare only computing the det isnt enough. we must compute all principal minors (Delta_k below)

https://i.gyazo.com/539242f4b7abdb8ffa0f9ce9caaca396.png

https://i.gyazo.com/3b8a98b4ea6797df795bdb82b621f3b9.png

u should see ur hessian is negative definite hence ur critical point is a local max

[calm coral]

@gleaming hare Has your question been resolved?

[calm coral]

Channel closed

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[calm coral]

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[tepid finch]

selling 30 products for 5 dollars each and our production cost is 2.66 how many would i need to sell to break even?

[shy swallow]

just sell N and then have sold amount equal production amount 🤔

then find N

but you should note that if its fractional, you have to round it off to the highest integer

[tepid finch]

could i please have a simple answer sorry if this sounds rude

wait do i do 80/2.34

[pure kayak]

!xy

[calm coral]

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

[tepid finch]

BROOO

[calm coral]

@tepid finch Has your question been resolved?

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[paper forge]

Hi for total area I need to add up using green and blue individually but why can't I just use definite integral from 0-3 and find total area doesn't work for me

[paper forge]

Do ping me ty 👍😀

[indigo grove]

some of the area would be negative (from 0 to ln(4)) that's why you don't take the whole integral from 0 to 3 when finding total area

[paper forge]

Hmm yea but I used modulus when subbing in 0 tho or is that conceptually still wrong ?

[indigo grove]

was afk for a while but by adding modulus you meant after adding both integrals or for each separately ?

[paper forge]

Like subbing in 3 and then modulus for subbing in 0 since ik area there is -

[indigo grove]

that's not really how it works
what'll you do is calculate the integral from 0 to ln4 then take the modulus of the resulting value (because it'll be negative) and same from ln(4) to 3 (or don't because we know it's positive)

[paper forge]

Oh wait there's no proof area from ln(4) to 3 is + it cld be - too?

[indigo grove]

you could see it from the graph
or just know that it's an increasing function
or another ways you might use etc.

[paper forge]

Ohhh

I see thanks a lot!!

.close

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[remote mural]

.reopen

guys need help here

[tall moon]

where exactly?

[remote mural]

nvm

found it

sorry

.close

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[storm spire]

Hello Why are they subtracting from the triangle surely the polar integration is enought between pire/4 and 0

[storm spire]

nevermind i understand

.close

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[reef kindle]

someone please help fast

[elder pawn]

why fast?

[primal bear]

fast?

[pearl jolt]

academic misconduct?

[reef kindle]

i have to submit an assignment with this question in 30 minutes

😭

[primal bear]

[elder pawn]

that sucks but it was a bad idea to leave it to 30min

[reef kindle]

nvm i got the ans

.close

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[stiff axle]

Please help how can i solve this question?

I got this far

But idk where to start now

Or begin

[stuck sail]

Uhm

Angle BCD is also x

So x+x+49+108=360

[vale flower]

the shape is a kite

[stiff axle]

Does it require trig?

This question

[stuck sail]

Nopes

[vale flower]

no

the line of symmetry bisects both angles

[stuck sail]

101.5

Is your answer

It's symmetrical

So BCD AND BAD angles are equal

Sum of angles in a quadrilateral is 360

[calm coral]

@stiff axle Has your question been resolved?

[stiff axle]

<@&286206848099549185>

[calm coral]

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[hearty tusk]

how do I find y? I wanna try it

[vale flower]

move all x terms to one side and y terms to the other

then integrate both sides

[polar bison]

is this like differential equations

variable separable

[hearty tusk]

separation of variables?

[gray smelt]

ye

[hearty tusk]

and integrate?

ok let me try