#help-42

1 messages · Page 123 of 1

marsh blade
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"no acceleration'

crystal forge
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if there is no acceleration, what would happen to the velocity graph? remember what we said before that we can think of acceleration as the slope of the velocity graph (which we are looking at)

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so betwen B and C what would be the acceleration?

marsh blade
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since its constant velocty

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i said no acceleration

crystal forge
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the velocity at B is around 40 isnt it? and at C it's around 15...is that constant?

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between B and C the acceleration is negative (the velocity is decreasing)

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if there were no acceleration the graph of the velocity would appear flat (i.e. slope of 0)

marsh blade
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oh ok

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so how do i know when the parachute opens

marsh blade
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nvm its no acceleration

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velocity is +

crystal forge
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well think about what is happening, they jump at t = 0 and their velocity is increasing really fast right? until it sort of "peters off" because they are probably reaching terminal velocity (the velocity increasing from gravity's acceleration balances out with the velocity decreasing from air resistance). we can see how their veloicity increasing tapers off between A and B

crystal forge
# marsh blade is this correct to?

again, no velocity would be the velocity graph having a y of 0, over there the velocity is constant i.e. its around y = 8 or whatever for a short period that means there is ** no acceleration **

marsh blade
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what means terminal velocity

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because i have a quesiton on it

crystal forge
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then suddenly at point B their velocity decreases from a very high value to suddenly much lower, over a very short period of time...what do you think would cause your velocity to suddenly decrease quickly while you are falling?

marsh blade
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I guess its point B where parachute is opened due to difference in acceleration

crystal forge
marsh blade
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(the velocity increasing from gravity's acceleration balances out with the velocity decreasing from air resistance)

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that is what you said

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but i dont know how to apply it on this graph

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i say i guess 40?

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because it appears there is no acceleration at this point

crystal forge
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that's BEFORE the parachute is opened, but where does the balance point seem to lie afterwards? the air resistance is much higher now

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the parachute slows down the person a lot, but not all the way to 0, where does it balance out?

marsh blade
#

at 5s?

crystal forge
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5s?

marsh blade
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5 ms

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m/s

crystal forge
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right, at point D

marsh blade
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yes

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i get it now

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thanks alot

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i appreciate your time for helping me

crystal forge
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.close

calm coralBOT
#
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cobalt basalt
#

How do you do this?

calm coralBOT
bitter maple
#

The radius of the circle can be found using this formula

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For any inscribed triangle in a circle

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The radius of the circle is

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ABC/(4∆abc)

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A is the length of side a

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B is the length of side b

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C is the length of side c

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Divided by the area times 4

cobalt basalt
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A

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I meant question 38

calm coralBOT
#

@cobalt basalt Has your question been resolved?

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forest stag
#

The answer I got is (0.08, 0.34) but the correct answer given is (16.7, 27.0). Help

ancient grotto
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or, here, the sample given.

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so, its going to be (14-ak, 14+ak), where a and k are constants to be determined.

forest stag
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I don't understand, this is what i did:/

calm coralBOT
#

@forest stag Has your question been resolved?

forest stag
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<@&286206848099549185>

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pine hedge
#

i went through an example and i don’t understand how the program went from x^2 - 7x - 30 = 0 to (x + 3)(x - 10) = 0.
for the question i have to do, i need to factor x^2 - 3x - 40 = 0 and im not sure quite how to do that

finite oasis
pine hedge
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moreso the first part

finite oasis
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Okay, let's talk about that first then

pine hedge
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i largely don’t understand the factoring and need help with it. i provided both so either could be used in case one was easier haha

finite oasis
#

do you know the common mnemonic for factoring quadratics like that?

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"Find two numbers that multiply into -30, and add to -7"

pine hedge
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like common denominators?

pine hedge
finite oasis
finite oasis
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give it a think

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can you think of two numbers that satisfy that

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to thin it down, guess two numbers that multiply into -30 first

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any two numbers work

pine hedge
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six and five doesn’t, does it?

finite oasis
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Close! thats 30

pine hedge
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-5?

finite oasis
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sure

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so -5 and 6

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but do those two numbers add to -7?

pine hedge
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no it’s -1

finite oasis
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1 actually

pine hedge
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oh oops

finite oasis
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but yeah, incorrect either way

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so this guess was incorrect

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think of two other numbers that multiply into -30

pine hedge
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15 and -2? or -15 and 2?

finite oasis
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sure

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but again, they add to 13 and -13 respectively

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not what we want

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try again

pine hedge
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it can’t be -1 x 30 or 30 x -1

finite oasis
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nope

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you're getting close

pine hedge
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is it a decimal? i can’t think of any others that make 30

finite oasis
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it is not fractional/in decimal, no

pine hedge
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oh 3 and 10, i have it written, duh

finite oasis
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there is one obvious one you missed

finite oasis
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but is it -3 and 10 or -10 and 3

pine hedge
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-10

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to get -7

finite oasis
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yes exactly, so it should be (x-10)(x+3)

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ok now

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do the same thing but for x^2 + 4x - 21

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what is your first step?

pine hedge
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something that multiplies to -21?

finite oasis
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yes

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indeed

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any guesses?

pine hedge
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3 and 7

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-7?

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to also get -4

finite oasis
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but its +4

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not -4

pine hedge
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oh i read -

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so then -3?

finite oasis
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yeah

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so what is the factored form?

pine hedge
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(x - 3) (x + 7)

finite oasis
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yeah good job! u got the hang of it

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now for your second question

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do the same for x^2 - 3x - 40 = 0

pine hedge
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-8 and 5?

finite oasis
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super close

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oh wait

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no i was the one who messed up this time haha

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yeah it is that

pine hedge
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okayokay

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then (x - 8) (x + 5)?

finite oasis
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affirmative

pseudo wedge
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Note that -8 and 5 aren't the roots, 8 and -5 are

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Just something to keep in mind

pine hedge
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so then its (x + 8) (x - 5)?

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but what about the -3?

pseudo wedge
pine hedge
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wait what’s a root-

pseudo wedge
finite oasis
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No, don't conflate things. What he meant to say is that the roots are x_1 = 8 and x_2 = -5 but you write the quadratic as (x-8)(x+5) = 0

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its basically solving x-8 = 0 and x+5 = 0

pine hedge
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oh the answers then? like to make the () actually = 0?

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okayokay

finite oasis
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yes

pine hedge
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thank you!!!

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so very much appreciated a_bunny_love_heart_hug

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.close

calm coralBOT
#
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calm coralBOT
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noble crown
calm coralBOT
noble crown
#

how

swift dragon
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!status

calm coralBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
noble crown
#

what good is status?

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it doesn't do anything

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<@&286206848099549185>

clear delta
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we want to get a sense of where you are in terms of progress on this problem

noble crown
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Idk where to begin

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it was on my exam yesterday

noble crown
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and set your status

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it just gives u a bunch of questions

clear delta
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the idea is that you would choose one and tell us verbally

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well, in text

noble crown
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oh

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i guess

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do you have an idea on how to solve it?

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initially it seemed pretty easy

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im used to dealing with circles

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I was taught that the equation for the circle is

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$(x-a)^2$ + $(y-b)^2$ = $r^2$

potent lotusBOT
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kronium_

noble crown
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wait

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I THINK I GET HOW TO DO IT

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$x^2$ - $2ax$ + $y^2$ - $2by$ + $(a^2 + b^2 - r^2) $ = $0$

potent lotusBOT
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kronium_

noble crown
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so that means

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2ax = 6

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so $a$ = 3

potent lotusBOT
#

kronium_

noble crown
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$b$ = 2.5

potent lotusBOT
#

kronium_

noble crown
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$3^2 + 2.5^2 = 9 + 6.25 = 15.25$

potent lotusBOT
#

kronium_

noble crown
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so $r^2$ = 6.25,
Therefore 'r' must equal 2.5

potent lotusBOT
#

kronium_

noble crown
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$coordinates$ of the original of the circle must be [3, 2.5]
& since r = 2.5, which equals to the height, circle be tangent to the x axis cuz when its directly down it just touches the x axis

potent lotusBOT
#

kronium_
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

noble crown
#

$e^{ix}$ = $cosx$ + $i$$sinx$

potent lotusBOT
#

kronium_

noble crown
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nice

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thx for helping

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i got it

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.close

calm coralBOT
#
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eternal tiger
#

Can someone explain the second order conditions in lagrange multipliers method

leaden thunder
#

an example of what problem you're working on or screenshot/picture of what you're reading would be best

eternal tiger
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I'm thinking about the utility function maximisation problem

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In Economics

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Under the budget constraint

leaden thunder
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a specific, concrete problem

eternal tiger
#

Um, concretely speaking, I'm wondering why the bordered hessian being negative semi definite leads us to the maximas instead of the other stationary points, and also I'm wondering what the bordered hessian represents as opposed to say the hessian matrix of the lagrangian (L)

leaden thunder
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what does "leads to" mean

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do you have an actual question with a matrix

eternal tiger
#

No I'm just trying to figure out the reasoning here

eternal tiger
#

.close

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raven crest
#

Can someone please help me on this question

abstract wave
#

!status

calm coralBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
raven crest
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So far, I know that triangle ADM has side lengths 6, 8, 10, with the height being 8 and the other leg being 6

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and the hypotenuse is 10

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so side length AB and DC are both equal to 112/8=14

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idk what to do next

flat gorge
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wait what?

raven crest
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i tried creating more triangles but couldn't really go anywhere

flat gorge
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what value did you get for AM? Also how?

raven crest
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i got 8

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since AD is 10, i just used the pythagorean triple (3,4,5) to find the other side lengths

flat gorge
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it's not mentioned AM and DM have integer lengths

raven crest
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it never said it doesn't have integer lengths

flat gorge
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Exactly, so pythagorean triplets don't give you AM or DM just from knowing AD

raven crest
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then how am i supposed to calculate it?

abstract wave
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you can't assume something about anything unless specifically written in the question or proven by you

flat gorge
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Use that ABCD and EFGH are congruent => [EFGH] = 112 and FG = EH = AD = 10

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should know EN at a glance

raven crest
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11.2?

crude atlas
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en is 5

abstract wave
raven crest
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EN is not at the midpoint

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is EN the height of the entire paralleogram?

abstract wave
raven crest
#

bruh

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that's what i said last time and someone said it was wrong

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thanks for helping

#

.close

calm coralBOT
#
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lavish nova
#

I started from here, how would I factor this

ancient grotto
#

this isn't "nicely" factorable

viral patrol
#

One root is 7/2 it

ancient grotto
calm coralBOT
lavish nova
lavish nova
viral patrol
ancient grotto
#

sadly.

viral patrol
lavish nova
viral patrol
#

Check for integers first

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That are divisors of constant

ancient grotto
viral patrol
#

N this case that is 1575

viral patrol
#

Then move to fractionals

lavish nova
#

That is so many bruh

#

.close

calm coralBOT
#
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onyx solar
#

Solve the equationsystem
8x+2y=4
4x+7y=6

calm coralBOT
onyx solar
#

Bear with me I'm new to this stuff

viral patrol
#

Are you taught method of elimination

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Or substitution

onyx solar
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I'm new to substitution

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I'm not familiar with how to solve when there are 2 constants

onyx solar
viral patrol
#

Ok I can guide you

onyx solar
#

That'd be very much appreciated

viral patrol
#

See from any equation isolate the variable x

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Like:
$8x+2y=4$

potent lotusBOT
viral patrol
#

You can write

onyx solar
#

-2y on both sides?

viral patrol
#

Yeah

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$8x = 4 - 2y$

potent lotusBOT
onyx solar
#

divide by 8?

viral patrol
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Yeah

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$x = (4-2y)/8$

onyx solar
#

lol

potent lotusBOT
viral patrol
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Now substitute this x is another equation

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Can you do this

onyx solar
#

yes Think so

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4x+7y=6

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4((4-2y)/8)+7y=6?

viral patrol
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Yeah try resolving it

onyx solar
#

uh ok

viral patrol
#

You can isolate y from here

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And get a equation only in y and constant

onyx solar
#

Wait do I divide by 8 first

viral patrol
#

You can take a factor of 4 common from 8

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Write 8 as 2×4

onyx solar
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Ok done

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What does that achieve

viral patrol
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You can get y

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Then you get

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$2-y+7y=6$

potent lotusBOT
viral patrol
#

Got it?

onyx solar
#

one sec

calm coralBOT
#

@onyx solar Has your question been resolved?

#
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mellow yew
#

a

calm coralBOT
mellow yew
#

@dreamy lance

dreamy lance
#

Oh I see you moved

mellow yew
dreamy lance
#

Okay, so lets say we restrict b and c to real numbers to be safe.

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Notice how going from the first line to the second the only real justification that is required is because bx=2(b/2)x

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Most of the justifications for each line are roughly along these lines.

dreamy lance
#

Simple statements that hold immediately by rules of algebra.

mellow yew
#

you want me to write my proof in mathematical or grammatical form?

dreamy lance
#

Try and limit yourself to at most a sentence per line.

dreamy lance
#

So for example "line 2 follows from line 1 because b=2(b/2)" would be a reasonable way to justify line 1 to line 2

mellow yew
#

oh so mathematical

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alr

dreamy lance
#

"Line 3 follows from line 2 because blah blah"

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There are multiple levels of formalism we could do here. But this level is most relevant imo

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How come I can go from line 2 to line 3?

mellow yew
# mellow yew https://cdn.discordapp.com/attachments/905286165316403271/1330345829243944960/20...

1we want to complete the square so given any value we can easily solve
2 because (10/2)^2 = 25's factors add to 10 and multiply to itself (proves any number divided by 2
squared grants number whos factors add & multiply to itself)
3 same as line 2
4 (x+b/2)^2 = line3 since both individual parts of square are equal solving for one solves for X
5 sqrt the right and left sides to maintain equality
6 you subtract everything affecting X to isolate X

drifting seal
#

doot if you dont mind can you check modmail

dreamy lance
#

I don't understand your numbering here but also my picture never mentions specific values for b and c so the numbers 10 and 25 don't really pop up.

mellow yew
#

i will clarify

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reread

dreamy lance
#

But I don't think your explanations of why each line follows from the last are sufficient.

mellow yew
#

the only part i completely do not understand is why you did this

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that is a self-terminating operation, why did you do it?

dreamy lance
#

The perfect square trinomial formula has a 2 on the x term. If I mult and divide by 2 like that it is in perfect square trinomial form.

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By perfect square trinomial formula I mean that x^2+2Bx+B^2 = (x+B)^2 (here B is unrelated to our earlier problem)

mellow yew
#

???? multiplying and dividing by 2 cancel each other

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wdym

dreamy lance
#

Okay, it's fine if they cancel each other out?

mellow yew
#

also wdym it is in perfect square if the perfect square was unassociated with the value itself

dreamy lance
#

The point is we want to write the quadratic in a particular form.

mellow yew
#

as you can see they simply added the perfect square to the right being (b/2)^2

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why do similar operations on the left if you already have the perfect square and why to the number youre trying to get it for?

dreamy lance
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The "perfect square" in that terminology is not referring to the squares in my derivation.

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We can drop that wording

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Lets say we don't use that term

dreamy lance
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I want the x^2+bx part of the given equation to resemble that formula

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But that formula has a 2Bx and our given does not have a factor of two on the bx coefficient.

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This is no problem, because b=2(b/2).

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So if I want I can just rewrite the x^2 + bx part as x^2 + 2(b/2)x

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The value doesn't change. The two expressions are equal.

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You see what I mean right?

dreamy lance
mellow yew
#

why do you want that formula

dreamy lance
#

Completing the square like you said lol

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A more intuitive way to see it

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Is we want to gather all the x terms into a single squared thing

mellow yew
#

why do you want anything, cant you just divide by 2 and exponentiate in any scenario so long as it has real solutions

dreamy lance
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Now all the x terms are gathered up inside that square

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There are no other x's in the equation

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So once we get to that point, solving for x is easy

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Subtract out the c, square root both sides, subtract out the b/2

dreamy lance
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You can't just divide thru by x

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Nor with x's

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Nor can you solve for x^2and square root both sides

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None of the these isolate the x

mellow yew
#

im curious if ill ever be able to not perceive the explanations people give as just terrible due to reverse tunnel vision sigh

dreamy lance
#

Wow what a shitty thing to say

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Have you considered that you aren't doing your end of the work by saying shitty things like that

mellow yew
# mellow yew

are you just saying that you cant get it into (x + 6/2) without converting B to 2(b/2) because it wouldnt multiply to itself without that?

dreamy lance
#

You have an obligation to try and understand people if people are willing to try and offer you help for free when you seek out help

mellow yew
dreamy lance
#

I disagree

mellow yew
#

this is part of what im saying

dreamy lance
#

I've seen you say things like this multiple times.

mellow yew
#

you think that thats rude but you actually agree with me whole heartedly

dreamy lance
#

I don't need to help you

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No I don't agree with you

mellow yew
#

that isnt your choice to make shrug

dreamy lance
#

I'm choosing to help you

mellow yew
#

its just the wind

dreamy lance
#

Meet me half way by choosing to make an effort to understand

mellow yew
#

you only were offended because you took your interpretation of what I said

#

and were offended by your own interpretation

dreamy lance
#

Multiple people have complained about you

#

For this exact reason

mellow yew
#

sorry i guess if the resonating memetic form of what I said offended you from your perspective

dreamy lance
mellow yew
#

bandwagon fallacy

#
  • this isnt that type of problem
dreamy lance
#

My point here is you have to make an effort to understand people

mellow yew
#

I do understand you

#

perfectly actually

dreamy lance
#

If you understood you would be able to give me succinct single sentence justifications for each line in the above pic

mellow yew
#

but you still dont choose the things you think you do nor do you represent yourself in the way you think you do

#

if you look into phenomenology youd know what I mean

dreamy lance
#

You should not try and act smart while misunderstanding elementary algebra

mellow yew
#

? youre the one acting smart

dreamy lance
#

Nobody cares about how smart you want to feel

mellow yew
#

when youre really smart you know how much you dont know

#

you are smart so you think you know what you dont and you interpret things through a somewhat faulty lense

dreamy lance
#

I have a degree in math and cs. I am in a math PhD program. I am literally teaching a precalc class right now.

#

I feel like I understand thus enough to tell you that you don't

mellow yew
#

you arent choosing to do what you are you doing right now you are just resonating from a faulty lense your brain told you was true which your emotions then manipulated you into thinking was an attack

dreamy lance
#

And the way you respond to people is unnecessarily prolonging you learning this.

mellow yew
#

I am completely outside of myself and the world is completely within me

dreamy lance
#

That's dumb

#

Go take intro phil in your own time

#

We're doing intro math

mellow yew
#

do you think that maybe you actually proved my point?

#

you didnt just prove it, you embodied it, though you yourself did not

dreamy lance
#

Get off your self congratulating high horse lmao

#

We're doing math.

unique jackal
#

if nobody can interpret what you mean, I feel that that's a communication problem on your end, rather than an understanding problem on everyone else's

dreamy lance
#

Focus on the math

mellow yew
#

I hope later you will come to clarity.

dreamy lance
mellow yew
#

? Because I cant? but you can?

#

Duh

dreamy lance
#

Every single line is justified by simple algebra you should know by now.

#

Things like b=2(b/2)

mellow yew
#

if you dont get it, I dont fault myself because I cannot explain what I fundamentally dont know

ebon pagoda
#

genuine question lol

dreamy lance
#

Substitution

#

Stuff like that

#

None of it is rocket science

mellow yew
#

but you can, shrug

dreamy lance
#

At some point the problem fails to be EVERYBODY ELSE giving you shitty solutions

mellow yew
# dreamy lance None of it is rocket science

you do realise by insulting my intelligence you are proving my point even more that your intelligence puts you on a semi-high horse meaning you fundamentally cannot perceive how others perceive your explanations and thus your explanations would be false to others perspective due to lack of experiental understanding

#

ight, bye

dreamy lance
#

I'm telling you you're overthinking the justifications to each line

unique jackal
ebon pagoda
dreamy lance
#

You realize smart people can overcomplicate things?

#

You're not above overcomplicating simple things homie

mellow yew
#

they did actually

#

they had no idea what i was talking about and tried talking about an abstract concept they had no idea what I meant by

#

shrug

dreamy lance
#

Yeah clearly you could never misunderstand anything.

#

You could never talk out your ass either.

mellow yew
#

doot that wasnt even the topic

dreamy lance
#

Everybody else is the problem!

mellow yew
#

you dont understand the topic fundamentally thats why ive been ignoring you

#

because you arent in control rn

dreamy lance
#

I don't understand the topic?

mellow yew
#

no you dont?

dreamy lance
#

Dog I passed intro precalc lmao

mellow yew
#

i didnt even tell you what the topic was

#

this isnt even about math

#

its a phenomenological concept you tried intruding on about how people perceive explanations

#

and you immediately called it shitty

#

:/

ebon pagoda
# mellow yew i didnt?

ok I misquoted you, meant to say you called their explanations "just terrible" in that message. same thing really

dreamy lance
#

Then why are you here? Go join the philosophy server. We're here to do math. Not listen to you crank ramble about philosophy you've misunderstood.

keen flower
#

This is going off the rails

mellow yew
mellow yew
#

i tried pulliing out multiple times but shrug

#

ima just make sure this time

keen flower
#

Did you learn to expand?

mellow yew
#

cuz they are being manipulated rn by their emotions

#

wait

#

wait

#

axe

#

axe can we like

#

go somewhere private

#

to discuss this

mellow yew
#

well almost

#

like a few details are off here and there but we ball

keen flower
#

Cool

mellow yew
#

can we like idk go to dms or like a private thread idk somewhere

#

cuz they are gonna ruin it

dreamy lance
#

I'd definitely fail somebody explaining completing the square like you tried above.

ebon pagoda
#

my impression is that the average helper here understands the subject well enough, but don't care enough to get lost in useless sophistry about how people perceive things or such lol

dreamy lance
#

Your explanation was not a correct one.

keen flower
mellow yew
#

alrr

#

.close

calm coralBOT
#
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crystal forge
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#
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gusty lance
calm coralBOT
gusty lance
#

Once i find 4nCr2 what can i do

#

if i dont want to find all the ways it can be written

#

like
1,2 2,3, 2,4
1,3 1,4
3,4

#

and then find which cases 2 is the greates which is obv 1/6

#

and so on

#

how do I find it like using the fact that a + b + 1/2 =1

calm coralBOT
#

@gusty lance Has your question been resolved?

gusty lance
#

.close

calm coralBOT
#
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calm coralBOT
#
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muted ibex
#

what does this convention in maths mean? v index m raised to j?

bold bear
#

What's the context?

#

It could mean a lot of different things

muted ibex
#

in calculus

#

what does it represnet

#

@bold bear

bold bear
#

I'm afraid that barely narrows it down

#

v_m^j is probably a vector?

muted ibex
#

nope

bold bear
#

And s_i is probably a permutation of the vectors

#

It's not a standard notation used all across math

muted ibex
#

in algorithms?

bold bear
#

Yeah no sorry

stoic oyster
#

like read your paper more carefully idk

bold bear
#

If it's in an algorithm then it probably said further up in the code what it meant

#

But I can't really help you

stoic oyster
#

we can't always divine the meaning of every symbol thought by every author in existence

#

especially when it's something super generic looking like this

#

they gotta have defined it before as depression said

calm coralBOT
eternal shard
#

καλά σου λένε

muted ibex
#

nvm thank's

#

.close

calm coralBOT
#
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potent igloo
calm coralBOT
#
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hidden pine
#

is a manifold in $R^n$ always $\sigma$-compact?

potent lotusBOT
#

Sheymes

hidden pine
#

.close

calm coralBOT
#
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static dirge
#

or no?

swift laurel
#

what limit?

static dirge
#

or is it not doable bc of the graphhhh?

swift laurel
#

i don't understand what you mean

static dirge
#

lim = x(3) + 4
x -> 4

#

like thiss

static dirge
calm coralBOT
#

@static dirge Has your question been resolved?

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devout meteor
#

i'm stuck with how to integrate absolute value of 7-x. i think i need to do u sub but im also not sure

ancient grotto
#

do you know how absolute values are defined?

devout meteor
#

do u mean that its only positive?

ancient grotto
devout meteor
#

um im sure i did at one point but can u remind me

ancient grotto
potent lotusBOT
ancient grotto
#

so, what do you think we should define |7-x| as?

#

Also note that |7-x|=|-(x-7)|=|x-7|

devout meteor
#

well wouldn't it depend on x?

#

because if x is larger than 7 then it is less than 0

ancient grotto
#

well, have you ever graphed an absolute value function?

devout meteor
#

ya

#

its a v

drifting seal
#

$|7-x|=\begin{cases} 7-x& (7-x)\ge 0 \ -(7-x)&(7-x)<0\end{cases}$

potent lotusBOT
ancient grotto
drifting seal
#

"x" was just taken to be the input

#

if it was hotdog then you would do hotdog instead

ancient grotto
# devout meteor its a v

yes, but what about |x-a|, where a is a constant? where would the “turning point” be, specifically?

devout meteor
drifting seal
devout meteor
#

wouldnt it be 7 because that would make 0

drifting seal
devout meteor
#

okay so does that have significance with the bounds of the integral? or why is this important in order to integrate?

drifting seal
devout meteor
#

okay sick that makes sense

#

so like this

drifting seal
#

brilliant yes

#

but remember to write dx btw

#

and the 1/6 factor is on both

#

integrals

devout meteor
drifting seal
#

indeed

devout meteor
drifting seal
#

you can

#

but you have to do that if you don’t want it on both

#

or else you might make the mistake of only having it on the first after calculation

devout meteor
#

better?

drifting seal
#

yes but why the second integral being subtracted now?

devout meteor
#

oh when i eraed the plus sign to write in dx i must have rewritten a - instead of +

#

i fixed it in my notes now

#

okay now do i just integrate what is in the absolute value signs?

drifting seal
#

use the definition

drifting seal
#

in the interval 4 to 7 is 7-x > 0 or is 7-x < 0

devout meteor
#

less than 0

drifting seal
#

why is that?

devout meteor
#

because it is the left half of the function

drifting seal
#

what does that mean?

#

oh i see your confusion

devout meteor
#

like this (it it were centered at the origin)

drifting seal
#

you’re thinking of it like |x| and how the "left" branch is for x < 0

drifting seal
#

i’m asking where is the input, -x > 0 and where is it < 0

#

that’s a different question isn’t it

devout meteor
#

oh

drifting seal
#

here you can think of 7-x being the negation of x-7

#

which is why you shouldn’t just go based on what |x| is like

#

7-x is certainly < 0 for x < 7

#

and the interval 4 to 7 satisfies that doesn’t it

#

take any x value in that interval, say 5

#

7-5 = 2 > 0

#

since it’s greater than zero we look back to our definition

#

7-x >= 0 hence for that interval |7-x| = 7-x

devout meteor
#

okay ya this makes sense!

#

so do i need to put a negative sign before the absolute value on the interval 7 to 10?

drifting seal
#

yes exactly

#

as per our definition

#

in the interval 7 to 10 we have 7-x <= 0 which means we must negate it

#

|7-x| = x-7 for x > 7

#

notice why we do this

#

since the inside (7-x) is less than zero we negate it to make it positive which should make sense with the way you originally defined absolute value (just making it positive)

#

so if we have a negative input in the absolute value we have to negate it to make it positive

#

but when it’s already positive we just leave it as is

devout meteor
#

got it!

#

so am i ready to integrate?

drifting seal
#

yes

#

did you set them up?

#

by getting rid of the absolute value and changing to the appropriate functions for each interval?

devout meteor
#

like this?

drifting seal
#

mhm exactly

#

and you should be able to integrate those

devout meteor
#

?

drifting seal
#

yes

devout meteor
#

okay i should be able to finish the algebra thank u!

drifting seal
#

you’re welcome

calm coralBOT
#

@devout meteor Has your question been resolved?

#
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shy mantle
#

.close

calm coralBOT
#
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tender cradle
#

I'm kinda stuck i dont know if what im doing is right

tender cradle
#

sorry for the handwriting im writing on a really old tablet

leaden thunder
#

You're almost there

#

Put the 1/(x+h)-1/x over a common denominator

tender cradle
#

ok so lcd for that would be x + h?

#

or (x)(x+h)

#

and for the left side

#

do i factor out an h?

#

and cancel it out

#

because thats what i was going to do

#

@leaden thunder ?

flat gorge
tender cradle
#

i see

flat gorge
#

Proceed further and you should be getting -h/[x(x + h)] for the difference

#

Along with the rest of the terms, you would be able to cancel out the h from the denominator of the whole expression

tender cradle
#

ok ok

#

i am now stuck again i have no clue

leaden thunder
#

Use (a+b)/c = a/c + b/c on the first term

#

And the last term you can just plug in h=0

tender cradle
#

the question said h must not equal 0

leaden thunder
#

Yea but sometimes when you're evaluating limits, you can just plug in h=0

#

,tex .calculate limit

tender cradle
#

i see

potent lotusBOT
#

riemann

tender cradle
#

is this the final equation?

leaden thunder
#

No

#

Your answer shouldn't have h

tender cradle
#

so is it this one?

leaden thunder
#

Closer but no

tender cradle
#

hmm

leaden thunder
#

What's the limit of h as h goes to zero

tender cradle
#

0

flat gorge
#

They didn't ask for limit though. It's fine to conclude with the difference quotient

tender cradle
#

so is my first answer the right one?

flat gorge
#

$\Delta f = 2x + h - \frac{1}{x(x+h)}$

potent lotusBOT
flat gorge
#

Is what you should get

flat gorge
leaden thunder
calm coralBOT
#

@tender cradle Has your question been resolved?

#
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civic delta
#

hi is this correct? Assuming that a blank (0 g/mL) ethanol concentration produces no color change and that a 0.0001 g/mL ethanol concentration produces an absorbance of 0.2, how can we model this relationship using a mathematical function? If this function exists, would we expect it to be continuous within the relevant range of ethanol concentrations in breath?

calm coralBOT
#

@civic delta Has your question been resolved?

civic delta
#

💔

calm coralBOT
#

@civic delta Has your question been resolved?

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flint mist
#

Im stuck.

I need to prove that hat(beta_0) and hat(beta_1) in 7.12 (first image) in Example 7.3.1b are the same as in (6.5) and(6.6)

flat gorge
flint mist
#

alright brb

flint mist
#

is this (i * x_i^2)?

flat gorge
#

no

flint mist
#

or is it \sum_i

flat gorge
#

that's sum of x_i^2 over all i

flint mist
#

why did they add the _i here but didnt for the other sums

#

isnt it over all i for the others too

flat gorge
flint mist
#

where did you get - 2x(bar) sum x_i from

flat gorge
#

sum x_i = nx(bar)

#
  • 2x(bar) sum x_i = -2nx(bar)^2
#

if you're confused at any step, write it down.

flint mist
#

isnt it

n sum x_i^2 - (nx(bar))^2 = n sum x_i^2 - n^2 x(bar)^2 = n (sum x_i^2 - n x(bar)^2) = n(sum (x_i - x(bar))^2) ?

flint mist
#

what did I do wrong

flat gorge
#

that doesn't give you what you want ._.

#

you want to change the 7.12 into desired form

flint mist
#

but i got to the same conclusion as you...

flat gorge
#

no

flint mist
#

fixed the typo mb

#

i was just confused how u did it

#

i fixed it

#

i was tripping

#

so now we have 1/(n(sum(x_i - xbar)^2) outside

#

what should the next step be should i start replacing the term inside the big brackets

flat gorge
#

n (sum x_i^2 - n x(bar)^2) = n(sum (x_i - x(bar))^2)
How?

flint mist
#

what r u copying

#

n(sum (x_i - x(bar))^2)

#

i got this

flint mist
#

and u got

n[sum (x_i - x(bar))²]

flat gorge
#

how'd you go from second last step to last step

flint mist
#

what am i missing sorry im so lost rn

#

i used this identity

#

from my class

flat gorge
#

alr then, if I knew you knew that, this conversation would've been easy for both of us

flint mist
#

my bad

flat gorge
#

and yes, you're right. that is indeed the case

#

so you know how to change the denom

#

work on the num, and tell me how far you get

flint mist
flat gorge
#

yes

flint mist
#

so should i start replacing terms here aswell

flat gorge
#

yes

flint mist
#

alr brb

flint mist
#

is this a combination? im kinda confused

#

or is this one long equation fit in 2 lines

flat gorge
#

one long expression that wasn't fitting in 1 line

flint mist
#

sum x_i y_i - n(x(bar) y(bar)) = sum (x_i - x(bar))(y_i - y(bar)) (do i sub this?)

#

idk what to do with

"y(bar) sum x_i^2 - x(bar) sum x_i y_i"

flat gorge
# flint mist

put (x_i + y_i) in place of x_i in this eqn. and see what you get. (x_i + y_i){bar} would replace (x_i){bar}

#

idts it should be this messy tbh, the result would be easier to prove in an opposite fashion

#

show that (6.5) , (6.6) is 7.12

#

and reverse the steps

flint mist
#

kinda confused where would I use this

flint mist
flint mist
flat gorge
#

also, why so many pings T-T

flint mist
#

my bad

#

alright let me restart

#

with the reverse way

#

wait

#

im even more confused now wow

#

what exactly am i suppose to compare this to?

#

what exactly is Beta_1(hat) here?

#

😵‍💫

calm coralBOT
#

@flint mist Has your question been resolved?

flint mist
#

<@&286206848099549185>

calm coralBOT
#

@flint mist Has your question been resolved?

flint mist
#

😢

calm coralBOT
#

@flint mist Has your question been resolved?

calm coralBOT
#
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eternal shard
#

In an exercise I was asked to verify:

If a,b are elements in a commutative ring that are null divisors then the product ab is always a null divisor.
I thought this was true, because for some x,y in R ax = 0 = by so you can choose xy and do (ab)(xy) = axby = 0, but it said it was wrong because in case of 0 you also get 0 but 0 is not a null divisor, I don't understand where I am wrong tho?

jade quartz
#

you need to show that $xy\neq 0$

potent lotusBOT
#

Arnavutköy

jade quartz
#

the point in a non-zero divisor is that you are multiplying by a non-zero number to get 0

eternal shard
#

but a,b,x,y must not be 0

#

that is in the assumption

#

if a,b are null divisors then there exist x,y and they are not 0

jade quartz
#

yes, but $x\neq 0, y\neq 0\not\implies xy\neq 0$

potent lotusBOT
#

Arnavutköy

jade quartz
#

it is possible that x and y are both not zero but xy=0

eternal shard
#

so we must additionally assume x,y are not null null divisors for the statement to be true then?

glass heart
#

but they are. ax=0

jade quartz
#

for example, if we are working in the integers mod 4,

eternal shard
#

but i dont understand, intuitively it does

eternal shard
#

2 is a null divisor

jade quartz
#

wait sorry that doesn't work

eternal shard
#

the only one

jade quartz
#

wait the statement may be correct actually

#

your proof is wrong still though

#

you need to show that $xy\neq 0$ still

potent lotusBOT
#

Arnavutköy

jade quartz
#

and that is non-trivial

eternal shard
#

i feel also impossible without restricting x,y in some sense

#

anyway i think i get it

#

need to be more meticulous

jade quartz
#

this is interesting, im going to try it

eternal shard
#

well one obv is x,y in R s.t. xy != 0 KEK

jade quartz
eternal shard
#

hmm yea

jade quartz
#

oh wait

#

this is easy

#

$ax=0\implies abx=0$

potent lotusBOT
#

Arnavutköy

jade quartz
#

were stupid

#

in fact only one of a and b need to be null divisors

#

not even both

eternal shard
#

oh yea but then you are kinda changing the statement

#

i mean of course the product of a null divisor with a not null divisor is 0

jade quartz
#

well i mean this statement implies the original statement?

jade quartz
eternal shard
#

yes sorry

#

i meant null divisor

#

wait i get it

#

#

If a and b are null divisors and to show ab is one too, just pick either x or either y so that (ab)x = ax * b = 0

#

i am so lost

#

I will ask my professor

ancient thistle
#

whats going on here

exotic cosmos
eternal shard
#

If a,b are null divisors then is (ab) a null divisor too?

#

And I say YES

ancient thistle
#

whats your definition of null divisor?

eternal shard
#

ax = 0 where a,x != 0

ancient thistle
#

okay so you require specifically that both elements are non-zero?

eternal shard
#

yes

ancient thistle
#

okay sure

#

well uh

#

take a and x in the definition of null divisor

#

ax = 0, so ax is not a null divisor because its 0 itself

#

which feels kinda strange but aight

eternal shard
#

yes

#

I did this now
Suppose a,b in R are null divisors. Then there are x,y in R s.t. ax=0=by.
Then wlog choose x then (ab)x = (ax)b = 0b = 0

ancient thistle
#

no no like

ancient thistle
#

ax = 0

#

a and x are null divisors

#

ax is not

eternal shard
#

lol

#

is this a counter example

ancient thistle
#

well yes

eternal shard
ancient thistle
#

which is like kinda dumb because it feels forced by the weird choice of definition but aight

eternal shard
#

but then where is the proof going wrong

ancient thistle
#

well

#

choose a = a and b = x in your proof

#

and see where it goes wrong

#

ab = 0

eternal shard
#

this is so horrendous

#

this is like

#

you wanna trap your students

#

or i am not careful catshrug

ancient thistle
#

idk this all feels very silly

eternal shard
#

i agree

#

anyway

#

thank you snow

ancient thistle
#

👍

eternal shard
#

and @jade quartz too!

#

.solved

calm coralBOT
#
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calm coralBOT
#
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terse shore
#

is the answer for i) 84%? the answers right 68%

terse shore
#

84% as its including everyhthing move than 11 minutes

#

and 68% is just middle

calm coralBOT
#

@terse shore Has your question been resolved?

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trail escarp
#

Hello, everyone! I'm working on graph theory (using Ore's book with practical examples), and I'm stuck on a term.

We're discussing the concept of a 'chain' in a graph. Ore defines a chain as a path that can include duplicate vertices, but the edges must be unique (this is my understanding).

However, when I search for 'chain in graph' on Google, I find definitions stating that a chain is a path where all vertices must be unique.

amber bolt
#

wikipedia doens;t know it at all

#

so it's not like one is obviously wrong, choose whichever you like

trail escarp
#

Interesting. Ok, thank you

#

.close

calm coralBOT
#
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exotic cosmos
#

@flat gorge what do you mean with this?

exotic cosmos
#

yeah a_1 is the first term

#

but the issue is what is meant by the "sum of the first n terms", no?

#

i guess you mean a_359 is the last term you can add up to

#

and thus n has to be 359

flat gorge
exotic cosmos
#

😭

#

i just moved on from the question

#

but yeah okay valid

flat gorge
#

sad overthought the q?

#

why'd you start with a_0 ?

exotic cosmos
#

idk these questions don't specify much

#

so some of the questions are ambiguous

#

so maybe why

#

😭

exotic cosmos
#

intuitively feels right

#

anyway what's done is done 😭

#

thanks tho

#

.close

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#
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simple musk
calm coralBOT
potent lotusBOT
#

938c2cc0dcc05f2b68c4287040cfcf71

calm coralBOT
#

@simple musk Has your question been resolved?

calm coralBOT
#

@simple musk Has your question been resolved?

simple musk
#

I am getting stronger, I can feel it

#

.solved

calm coralBOT
#
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simple musk
calm coralBOT
clear delta
#

q quiere decir Nu?

simple musk
#

ker

potent lotusBOT
#

938c2cc0dcc05f2b68c4287040cfcf71

simple musk
#

x1 = -x4

#

(-x4,x2,x3,x4) = x4(-1,0,0,1)+x2(0,1,0,0)+x3(0,0,1,0)

#

S =<(-1,0,0,1),(0,1,0,0),(0,0,1,0)>

#

Is it me or they want me to define a projection

#

no

#

because in a projection the image and the kernel are in direct sum

#

f(v1) = w1
f(v2) = w2
f(v3) = w3
f(v4) = w4

#

f(v1) = (-1,0,0,1)
f(v2) = (0,1,0,0)
f(v3) = (0,0,1,0)
f(v4) = 0

#

f(-1,0,0,1) = w1
f(0,1,0,0) = w2
f(0,0,1,0) = 0
f(v4) = w4

#

f(1,0,1,-1) = (-1,0,0,1)
f(0,1,0,0) = (0,1,0,0)
f(0,0,1,0) = 0
f(0,0,0,1) = (0,0,1,0)

#

I did it

#

let's check

#

,w det {{1,0,1,-1},{0,1,0,0},{0,0,1,0},{0,0,0,1}}

potent lotusBOT
simple musk
#

determinant non zero

#

we have a basis of R4

#

{(1,0,1,-1),(0,1,0,0),(0,0,1,0),(0,0,0,1)}

#

is a basis dim 4

#

Ker(f) = <(0,0,1,0)>

#

Im(f) = <(-1,0,0,1),(0,1,0,0),(0,0,1,0)>

#

S =<(-1,0,0,1),(0,1,0,0),(0,0,1,0)>

#

(1,0,1,-1) not in Im(f)

#

the problem is that Im(f) can't be equal to S

#

because then (1,0,1,-1) is in Im, because is in S

#

what we can do is

#

just repeat one vector in S

#

and then the image is two dimensional

#

f(1,0,1,-1) = (-1,0,0,1)
f(0,1,0,0) = (0,1,0,0)
f(0,0,1,0) = 0
f(0,0,0,1) = (0,1,0,0)

#

Im(f) = <(-1,0,0,1),(0,1,0,0)>