#help-42

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west horizon
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drifting seal
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this because we can do this

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hold on

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$x^2+y^2 = 400-2xy \geq 2xy \implies 400\geq 4xy$

potent lotusBOT
drifting seal
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so 100 >= xy

west horizon
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drifting seal
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hence how we get the x,y = 10

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because

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x + y = 20

west horizon
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drifting seal
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wdym

west horizon
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drifting seal
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i already did

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it’s easy asf

west horizon
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drifting seal
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alright

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wait

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lemme show you the other way

west horizon
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potent lotusBOT
drifting seal
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$f(x,y) = x^2+y^2 \quad g(x,y) = x+y$

potent lotusBOT
drifting seal
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$\nabla f = \langle 2x, 2y \rangle \quad \nabla g = \langle 1, 1\rangle$

potent lotusBOT
drifting seal
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$\langle 2x,2y \rangle = \lambda \langle 1, 1\rangle$

potent lotusBOT
drifting seal
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2x = lambda

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2y = lambda

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x = y

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x + y = 2x = 20 hence

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x = 10

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x = y = 10

west horizon
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drifting seal
west horizon
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drifting seal
west horizon
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potent lotusBOT
drifting seal
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partial derivatives

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i think i might’ve shown you those

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like when we did implicit

west horizon
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drifting seal
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remember my implicit differentiation trick

west horizon
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drifting seal
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$\frac{dy}{dx} = \frac{-\frac{\partial F}{\partial x}}{\frac{\partial F}{\partial y}}$

west horizon
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potent lotusBOT
drifting seal
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where $F(x,y) = c$

potent lotusBOT
drifting seal
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i definitely showed you

west horizon
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drifting seal
drifting seal
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implicit function theorem

west horizon
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drifting seal
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$\frac{\partial F}{\partial x} dx + \frac{\partial F}{\partial y} dy = 0$

potent lotusBOT
drifting seal
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bprp videos

west horizon
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drifting seal
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black pen red pen

west horizon
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drifting seal
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they’re good too

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but you’re missing out

drifting seal
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like the most effort they ever put into it

west horizon
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drifting seal
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the differential equations course on the other hand….

west horizon
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drifting seal
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not the differential equations in ap calc

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like

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further differential equations

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more advanced

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wasn’t so good

west horizon
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drifting seal
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needs a lot of work

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multivariable was good on khan academy actually

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because 3b1b did it

west horizon
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drifting seal
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3blue1brown

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goat math youtuber

west horizon
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drifting seal
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you might’ve seen his essence of calc series

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he’s probably the most popular math youtuber

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makes all those sick animations

west horizon
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drifting seal
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alright

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see ya

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.close

calm coralBOT
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mossy wigeon
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b right?

calm coralBOT
slender gate
unreal rose
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i think its a simply cuz its heavier

swift laurel
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they have the same mass

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we have to consider their moment of inertia

unreal rose
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oh same mass

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then yeah b

mossy wigeon
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ok ty

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.close

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obsidian swan
calm coralBOT
obsidian swan
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Help pls

torn gorge
jovial gyro
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which part are you exactly confused with?

calm coralBOT
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@obsidian swan Has your question been resolved?

obsidian swan
jovial gyro
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y intercept means that the function intersects y-axis at -8

obsidian swan
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How should I apply it in the equation

jovial gyro
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remember that if a function passes through that point it is a solution of that equation

obsidian swan
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Alright

jovial gyro
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so, if a function passes through (0, -3) then it has a solution x=0 and f(x)=-3

obsidian swan
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I see

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Ty

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.close

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barren sand
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I have no idea what to do here

calm coralBOT
umbral sinew
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what are you even trying to do

barren sand
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Completing squares with fractions trip me out

barren sand
umbral sinew
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this is the problem

barren sand
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How’d you get that?

umbral sinew
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from your working

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you are not supposed to expand it again

barren sand
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I know that’s correct, but how do we reach dat conclusion bc the fraction within the parameters is tripping me out

umbral sinew
barren sand
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Bro

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Ok

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Let's look at this

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This so far is correct right?

umbral sinew
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yes but no

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correct as in the number is correct

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but wrong as in the wrong step to take from the previous line

barren sand
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I should have left it as (3/2)^2?

umbral sinew
umbral sinew
barren sand
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Okay

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So I leave it at 3/2 squared, and then what do I do from that?

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I just hug it with brackets n make it (x +3/2)^2 n we good?

barren sand
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Ok so

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I understand

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Now

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Is this something I apply with all completing the square procedures that involve fractions?

That is, getting the (b/2)^2 n hugging dat + squaring it n eliminating da real b variable?

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Ik how to complete squares yfm, it's just when they fractions it tweaks me out a bit

umbral sinew
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treat a fraction like a regular number

barren sand
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Ok ty

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.solved

calm coralBOT
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calm coralBOT
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calm coralBOT
calm coralBOT
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@sinful oak Has your question been resolved?

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simple musk
calm coralBOT
simple musk
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4.- Let $B = {(0,1,1), (2,0,1), v}$ and $B' = {(-3,1,0), v, (0,0,1)}$ be bases of $\mathbb{R}^3$. Find, if possible, $v$ and $w$ in $\mathbb{R}^3$ such that the coordinates of $w$ in the basis $B$ are $(w)B = (3,-4,1)$ and the coordinates of $3w$ in the basis $B'$ are $(3w){B'} = (7,2,-4)$.

potent lotusBOT
simple musk
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w = 3(0,1,1) -4(2,0,1) + v

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3w = 7(-3,1,0)+2v-4(0,0,1)

calm coralBOT
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simple musk
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.reopen

calm coralBOT
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simple musk
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I miss clicked

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9(0,1,1)-12(2,0,1) +3v = 7(-3,1,0)+2v-4(0,0,1)

onyx berry
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good

simple musk
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,av @onyx berry

potent lotusBOT
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simple musk
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9(0,1,1)-12(2,0,1) +3v = 7(-3,1,0)+2v-4(0,0,1)
3v - 2v = 7(-3,1,0) -4(0,0,1) + 12(2,0,1) - 9(0,1,1)

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,w 7(-3,1,0) -4(0,0,1) + 12(2,0,1) - 9(0,1,1)

potent lotusBOT
simple musk
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v = (3,-2,-1)

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w = 3(0,1,1) -4(2,0,1) + v

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w = 3(0,1,1) -4(2,0,1) + (3,-2,-1)

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,w 3(0,1,1) -4(2,0,1) + (3,-2,-1)

potent lotusBOT
simple musk
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w = (-5,1,-2)

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too easy

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@onyx berry

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💖❤️

onyx berry
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good that I could help

simple musk
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,av @onyx berry

potent lotusBOT
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simple musk
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.solved

calm coralBOT
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calm coralBOT
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wheat owl
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I need to solve for x

calm coralBOT
glad parrot
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try to write left side as (x-1)^smth

wheat owl
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Wdym

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Btw if y^y^2 = 2
Then we can start from there

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@glad parrot

glad parrot
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well you can also write 8/4(x-1) as 2/(x-1)

wheat owl
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Yeah

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That's the first step

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What now

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@glad parrot

manic sandal
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(2/(x -1))^(1/x) looks promising

wheat owl
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Did that

manic sandal
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assuming it’s xth root and not multiplied by x

wheat owl
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We can raise both sides to the power of x

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And do some other stuff

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And substitute

manic sandal
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okay so where are you getting stuck?

wheat owl
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And finally get y^y^2 = 2

manic sandal
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can i see all your work

wheat owl
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Y = x-1

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Lemme write again

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Hold on

manic sandal
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holding

wheat owl
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I was solving it with someone here but I didnt really like the solve

manic sandal
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all fine

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just hard to know where you are without all the work

wheat owl
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Here

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@manic sandal

manic sandal
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sorry i got class rn someone else gon help

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i would usually just plug into desmos or smth to find it quickly

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but an exact answer can’t give right now

wheat owl
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Its pre differentiation

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And I can't use a calculator

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Also idk what desmos is

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Anyways

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It's alright

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Good luck

manic sandal
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graphing calculator

manic sandal
wheat owl
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Npnp

calm coralBOT
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@wheat owl Has your question been resolved?

frail yacht
wheat owl
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Hey @frail yacht

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Sorry didn't see that

wheat owl
wheat owl
frail yacht
wheat owl
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Or are you thinking of a different approach

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Hold on

frail yacht
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Do u see?

wheat owl
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Wait...

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X

frail yacht
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You only get one real solution x =0

wheat owl
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Is part of the root

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Not like x multiplied by the root

frail yacht
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U can substitute I to Original equation to see

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If its valid

wheat owl
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It's the xth root of the mentioned thing

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Not X . The square root

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So what you did is wrong

frail yacht
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Ifk then

wheat owl
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Okay

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Appreciate your help tho !

calm coralBOT
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@wheat owl Has your question been resolved?

wheat owl
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Ima head to bed now

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I'd appreciate if someone solves this by the time I wake up

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Good night!

calm coralBOT
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@wheat owl Has your question been resolved?

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rapid lion
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Evaluate the function ƒ(x) = −x^2 − 1 and simplify at the indicated value: ƒ(−a) = ?

rapid lion
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I got f(-a) = a^2 - 1 but it says its wrong

pallid halo
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be careful about order of operations

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-x^2 means first compute x^2, then multiply the result by -1

rapid lion
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so lets say x = 1 -(1)^2 you do 1 * 1 = 1 then mulitply it by a negative to get -1?

pallid halo
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yes that's right

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1 - (1)^2 would be 1 - 1 = 0

rapid lion
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ok that makes sense ty

calm coralBOT
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@rapid lion Has your question been resolved?

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viral abyss
calm coralBOT
viral abyss
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got 4.5 but it was wrong :p

wet urchin
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so

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the midpoint of maple street

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is 0.45 miles

viral abyss
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yes

wet urchin
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and the midpoint of walnut street is 0.9 miles

viral abyss
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yes

wet urchin
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so

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0.9

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plus

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did u solve for oak street

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if so what did u get

viral abyss
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isnt it 0.9

wet urchin
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idk

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you have to use the pythrageon theroum

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to solve for it

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i didnt do it

viral abyss
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its the midsegment so its half of spruce street what

wet urchin
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what

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walk me through your thought process of why you think that

viral abyss
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triangle midsegment theorem "the segment connecting the midpoints of two sides of a triangle is paralle to the third side and is half as long as that side"

light acorn
wet urchin
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sorry

viral abyss
wet urchin
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well

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if ur right

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and its 0.9

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0.9 + 0.9 + 0.45 + 1.8

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miles

viral abyss
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yep we got it TP_Cat_dance

viral abyss
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.close

calm coralBOT
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fleet cairn
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hi i need help on a stats question

calm coralBOT
fleet cairn
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im just confused on what the

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7% is used for

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actually idek what formula to use

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i think its the

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n = z^2 ( p(p-1)) / e^2

calm coralBOT
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@fleet cairn Has your question been resolved?

fleet cairn
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<@&286206848099549185>

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ok so

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i found the solution for it

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but

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im still confused

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they said e = .07

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so WHYYY in the bottom right is it .03?

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.close

calm coralBOT
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west horizon
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west horizon
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manic sandal
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lets use area formula

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volume*

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what’s the volume of a cone

west horizon
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manic sandal
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formula

west horizon
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manic sandal
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cool cool

west horizon
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potent lotusBOT
manic sandal
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it’s alright

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i understand what it means

west horizon
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manic sandal
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uhm

west horizon
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manic sandal
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what i think you needa do

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is use differentiation

west horizon
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manic sandal
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dV/dt = -50

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which will be useful

west horizon
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potent lotusBOT
manic sandal
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you see the problem is we don’t know r’

west horizon
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manic sandal
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uhhh

manic sandal
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water level

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which is height no?

west horizon
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manic sandal
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so i’m thinking more like

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uhh

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i wanna say plug in r before differentiating but it isn’t constant

west horizon
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manic sandal
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yea

west horizon
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manic sandal
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we know h tho

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we don’t know h’

west horizon
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manic sandal
west horizon
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potent lotusBOT
manic sandal
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oh

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wait

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you need to find r in terms of h using similar triangles

west horizon
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manic sandal
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or else you have 2 variables to work with which doesn’t work

manic sandal
west horizon
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manic sandal
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i don’t have a pencil

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one second

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yoy agree that the radius and the height wit change in proportion to one another

west horizon
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manic sandal
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nope

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very white

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irish/jewish

west horizon
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manic sandal
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we could make something like this

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then h/6 = r/45

west horizon
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manic sandal
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so r = 45h/6

west horizon
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manic sandal
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plug thag back in

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THEN differentiate with respect to h

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and you win

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gg ez

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(i am also doing related rates in calc rn 😜)

west horizon
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manic sandal
west horizon
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manic sandal
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n

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no

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i’m 16 in high school

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i just mess w math

west horizon
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manic sandal
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😭😭

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it’s all good

west horizon
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manic sandal
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anyways u got the rest of the problem or any more questions

potent lotusBOT
manic sandal
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nonono

west horizon
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manic sandal
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too early

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plug r back into ur volume equation

west horizon
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manic sandal
#

wait i’m tripping

#

how do you spell

#

silly

#

solly

#

like

#

huh

#

😭

west horizon
#

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manic sandal
#

no like

#

idk

west horizon
#

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manic sandal
#

it doesn’t t matter

#

anyways

#

V = whatever in term of h

west horizon
#

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manic sandal
#

h not h’

west horizon
#

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manic sandal
#

not yet

#

fix that latex

#

😔

potent lotusBOT
manic sandal
#

combine terms???

west horizon
#

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#

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manic sandal
#

#

u wanna product rule

#

instead of combine terms

west horizon
#

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manic sandal
#

225h^2/4 * h/3
75h^3 * pi =V

west horizon
#

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manic sandal
#

now

west horizon
#

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manic sandal
#

(15h/2)^2

#

15*15 =225

#

🤯

west horizon
#

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manic sandal
#

2^2

#

is what

west horizon
#

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manic sandal
#

WOAH

west horizon
#

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manic sandal
#

im on my phone watching arcane eating famous amos cookies

west horizon
#

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#

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manic sandal
#

oki

west horizon
#

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manic sandal
#

2

west horizon
#

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manic sandal
#

just started

#

watched 1 a while go

#

ago

#

anyway

west horizon
#

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manic sandal
#

V = 75h^3*pi

#

then differentiate

#

wait

#

oop

#

i forgot

#

V = 75/4 * h^3 * pi

#

not differentiate

#

now

west horizon
#

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#

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manic sandal
#

west horizon
#

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#

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manic sandal
#

okay

#

i will write it out

west horizon
#

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manic sandal
#

3 minutes

#

😭

#

back to my show

west horizon
#

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#

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manic sandal
#

i combined???

west horizon
#

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#

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manic sandal
#

okay

west horizon
#

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manic sandal
#

do we understand

west horizon
#

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manic sandal
#

now

#

DIFFERENTIATE

west horizon
#

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potent lotusBOT
manic sandal
#

???

west horizon
#

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manic sandal
#

dV/dt = 75pi/4 * 3h^2 * dh/dt

#

yes yes???

west horizon
#

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manic sandal
#

yes

#

but it’s like

#

product rule

#

or chain rule

#

idk

west horizon
#

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manic sandal
#

Okay

#

if you product rule

#

and you differentiate anything but h^3

#

you’ll have 0

#

so like

#

yes

#

do i needa restate

#

what’s the derivative of a•x^n

west horizon
#

One message removed from a suspended account.

manic sandal
#

n•a•x^(n - 1)

#

in this case a = all the constants

#

n is 3

#

and x is h

#

yay’

west horizon
#

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manic sandal
#

yea

west horizon
#

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manic sandal
#

😭

#

a just like

#

stays there

#

🙏🙏🙏

west horizon
#

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manic sandal
#

okay

#

now

manic sandal
#

do i needa latex or u got it

west horizon
#

One message removed from a suspended account.

manic sandal
#

okay

#

so

#

dV/dt = -50
h = 5

#

then isolate dh/dt and you win

west horizon
#

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manic sandal
#

😭😭

#

do i needa pull out the paper

west horizon
#

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#

One message removed from a suspended account.

manic sandal
#

okay

#

yayes

west horizon
#

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#

One message removed from a suspended account.

calm coralBOT
#
Channel closed

Closed by @west horizon

Use .reopen if this was a mistake.

manic sandal
#

gotchu

#

same process for next step btw

calm coralBOT
#
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west horizon
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potent lotusBOT
potent igloo
#

Looks good so far

west horizon
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potent lotusBOT
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potent lotusBOT
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potent igloo
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potent igloo
west horizon
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potent igloo
#

But +12 (don't forget your units) is still the correct answer to (a), btw

west horizon
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potent lotusBOT
west horizon
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potent igloo
west horizon
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potent igloo
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potent lotusBOT
west horizon
west horizon
potent igloo
#

oh yea

#

you are correct

west horizon
#

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potent igloo
#

I was doing dy/dx derp

potent lotusBOT
west horizon
#

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potent igloo
#

yeah 12 ft/s is the rate at which the ladder falls

west horizon
#

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potent igloo
#

naw area is $A=\frac12xy$

potent lotusBOT
west horizon
#

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potent igloo
#

and $\dot{A}=\frac12(x\dot{y}+y\dot{x})$

potent lotusBOT
west horizon
#

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potent igloo
#

,calc (12*(-12)+5*5)/2

potent lotusBOT
#

Result:

-59.5
west horizon
#

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potent igloo
#

discord hid the asterisks

west horizon
#

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potent igloo
potent lotusBOT
#

Result:

-59.5
west horizon
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calm coralBOT
#
Channel closed

Closed by @west horizon

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potent igloo
calm coralBOT
#
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tired locust
calm coralBOT
#

Please don't occupy multiple help channels.

tired locust
#

.close

calm coralBOT
#
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calm coralBOT
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odd heart
#

how does it go from line 1 to line 2, more specifically the derivatives?

calm coralBOT
#

@odd heart Has your question been resolved?

odd heart
#

<@&286206848099549185>

unkempt drift
potent lotusBOT
unkempt drift
#

so yeah you can interchange the derivative and the summation like that

#

also for the second summation just swap p and q everywhere that they appear
so instead of d/dp, you do d/dq and so on

odd heart
#

what keeps it equal?

#

oh nvm

unkempt drift
#

oh ok

odd heart
#

yeah it's just weird

#

so it's because of this right $k^2p^{k-1}=k\frac{\mathrm{d}}{\mathrm{d}p}p^k$?

potent lotusBOT
unkempt drift
odd heart
#

ok makes sense thanks

#

you just have to do the process again to fully get rid of the k right

unkempt drift
odd heart
#

yup makes perfect sense now

#

man it seems so simple now but thanks again

#

.close

calm coralBOT
#
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potent lotusBOT
calm coralBOT
#
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strange crown
#

if I were to look at the left branch of this graph, so when x < 4, what's an intuitive way to see if the slope is negative & increasing or negative & decreasing at, when glancing at it.

My first assumption was negative & increasing but turns out it's negative & decreasing

latent pelican
cursive tartan
#

^

strange crown
#

and oo I see

cursive tartan
strange crown
latent pelican
cursive tartan
latent pelican
#

if you were to say x > 4 if you were to analyze that then it would be increasing, positive as the slope never goes below 0 and just flattens out

potent smelt
#

Its slope is negative because it's going down. And it's decreasing because it's going more and more down (becoming larger negative values)

simple cave
#

always direction is left to right.

strange crown
strange crown
potent smelt
#

A negative number decreasing means that the magnitude is increasing

#

So -3 decreases to -4 and so on

#

On the other hand a negative number increasing means its magnitude is decreasing, -3 increases to -2

calm coralBOT
#

@strange crown Has your question been resolved?

calm coralBOT
#
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#
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topaz raft
#

I’m confused, shouldn’t it be n-3 as the power not n-2?

pallid halo
topaz raft
#

secxtanx

pallid halo
#

yep...

topaz raft
#

ohhhhh

#

ok that makes sense

#

thanks bungo

pallid halo
#

sure, yw

topaz raft
#

.close

calm coralBOT
#
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calm coralBOT
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potent totem
#

Okay, so solving part a) is pretty much just plugging in number into the formula. 2pi * integral (g(y)+2) * \sqrt(1+(5y^4)^2)dy. Probably typed something in wrong (not sure how to do latex on discord).

But for part b, rotating around the x-axis, I'm not sure what I need to do.

The formula is basically the same, but do I need to change my limits of integration? Do I still use g(y) in my equation?

To be clear, this is an old exam. I'm going back over it in preparation for finals and this is one that I wasn't sure how to do.

cursive tartan
#

So just [y^6/6]

potent totem
#

Sorry, I think I'm being dense and missing what you're saying. I can see how integrating x would give us y^6/6, but I'm not seeing why that's the solution to rotating around the x-axis.

'I'm not doubting you, just trying to understand.

cursive tartan
#

1 way : they gave limits for y (which for lower cases means you gotta integrate in terms of y)

#

If you gonna ask can't you get x from y , you can't here

cursive tartan
potent totem
#

Okay, this is helpful. I feel like I need to draw the diagrams myself and work on some more problems. This was useful. Thank you.

#

.close

calm coralBOT
#
Channel closed

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calm coralBOT
#
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subtle palm
#

how to do these types of questions? i never understand how they just know

finite oasis
subtle palm
#

yeah to some extent

#

i can do normal binomial expansion but doing that wastes too much time in an exam

#

so they do the binomial expansion with combinatorics and algebra

finite oasis
#

Yes you shouldnt actually expand it

subtle palm
#

andi dont get the shortcutted combinatorics version

lapis oracle
#

need help with this

lapis oracle
finite oasis
# subtle palm andi dont get the shortcutted combinatorics version

Basically, for a binomial of the form $(a+b)^n$ the $k$-th general term of its expansion is given by [
T_k = \binom nk \cdot a^{n-k} b^{k}
]
Thus, for your binomial, the $k$-th general term can be represented as[
T_k = \binom 6k \cdot \left(\frac{3}{x^2}\right)^{6-k} \cdot \left(-\frac{x}{2}\right)^k
]
Your objective is to simplify the above expression, and find under what conditions is the exponent of $x$ equal to 0

gray smelt
potent lotusBOT
subtle palm
#

oh, i see so from here it kind of is like guess and check to see what makes x's power = 0

finite oasis
#

You needn't guess

#

it is algebra

#

Try to simplify first

#

distribute the powers, group like terms, etc.

subtle palm
#

yep okay
thank you!

#

.close

calm coralBOT
#
Channel closed

Closed by @subtle palm

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calm coralBOT
#
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pallid coral
#

In high school, does yall teacher make quizzes?

gray smelt
#

why do you ask

pallid coral
#

.close

calm coralBOT
#
Channel closed

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#
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remote mural
calm coralBOT
remote mural
#

In need of dire help, the answer sheet (very unreliable) tells that it is option (B).

amber bolt
#

doesn't make sense

#

even the unit doesn't make sense

#

wtf

remote mural
#

It should be 1500Pa right?

amber bolt
#

it should be 0 because there's only atmospheric pressure in those points

#

like yeah, it will flow to the right, so there's a pressure difference, i'm just really confused

gray smelt
remote mural
#

Thank you

#

I have another question

#

How can we even approach finding it?

amber bolt
#

so 1500 Pa

calm coralBOT
#

@remote mural Has your question been resolved?

remote mural
#

<@&286206848099549185>

dire gulch
#

ok

#

firstly, wlog, let us assume A>B

#

yes?

#

ping me when you are there

remote mural
#

yes

dire gulch
#

ok are u here now?

#

pls ping me when u r

#

anyway

#

you agree we can just cut of the length b from both of the parralel sides, withouth changing the distance we want to find?

remote mural
#

yes

#

@dire gulch

dire gulch
#

yes

#

so now we have a traingle

#

with the top angle 90*

#

and the bottom length a-b

#

and we want to find the median length

remote mural
#

can you show the diagram?

dire gulch
#

sry, i am doing this mentally, you can imagine what i am saying tho?

#

oh

remote mural
dire gulch
#

yes

#

now you contract CD around the center by length AB

#

can you do that?

#

just make the midline first

#

do you get this?

#

@remote mural

remote mural
#

oh

dire gulch
#

yeh

#

E i midpoint of AB

#

H is midpoint of CD

remote mural
#

Oh so AE = DF?

dire gulch
#

yes

#

and we know that FEG = 90*

#

right?

remote mural
#

yes

dire gulch
#

and you know that the median length of a rightangle triangle is half the hypotenuse

#

since

#

if one side is a, and the other sidelngth is b

remote mural
#

I know this

dire gulch
#

yeh

#

so you are done?

remote mural
#

oh yes

#

thanks

#

.close

calm coralBOT
#
Channel closed

Closed by @honest stream

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dire gulch
#

welcome

calm coralBOT
#
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prisma wyvern
#

If $F(x)=\int^x_1 e^x+e^t dt$, then $F'(x)=2e^x$ is this correct?

potent lotusBOT
noble lynx
#

yes.

prisma wyvern
#

ok thx

#

.close

calm coralBOT
#
Channel closed

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mortal orbit
#

the way you wrote it

#

$F(x) = (x-1)e^x + e^x - 1$

potent lotusBOT
#

rafilou is not not born in 2003

mortal orbit
#

so $F'(x) = (x+1)e^x$

potent lotusBOT
#

rafilou is not not born in 2003

prisma wyvern
#

oh i should add the parenthesis

#

(e^x+e^t)

mortal orbit
#

you can only use FTC if you have $F(x) = \int_a^x f(t)dt$

potent lotusBOT
#

rafilou is not not born in 2003

mortal orbit
#

is that f also depends on x

#

so no FTC

prisma wyvern
#

okay

#

.reopen

calm coralBOT
#

prisma wyvern
#

wait no

#

hmm

#

ok

#

.close

calm coralBOT
#
Channel closed

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#
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fleet cairn
calm coralBOT
fleet cairn
#

so i split this into 2 integrals

#

and when im solving the left integral

#

im using x = 2tan(theta)

#

but when im using photomath to double check its saying the answer is ln something

#

how to do

calm coralBOT
#

@fleet cairn Has your question been resolved?

vagrant oak
vagrant oak
vagrant oak
#

of what "degree" is the first fraction? Of what degree is the second one?

calm coralBOT
#
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weary cape
#

Let V be a finite set with at least two elements. Does the structure of a Q-vector space exist on V?

weary cape
#

how would I go about showing or disproving this?

calm coralBOT
#

@weary cape Has your question been resolved?

weary cape
#

<@&286206848099549185>

calm coralBOT
#

@weary cape Has your question been resolved?

weary cape
#

<@&286206848099549185>

mortal orbit
#

call v1 the element that would correspond to the 0 vector

#

and v2 a different element

#

Can you explain why there must exist different p,q in Q such that p * v2 = q * v2?

#

then conclude as to the existence of such a structure

weary cape
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$\mathbb{Q}$ is infinite right?

potent lotusBOT
weary cape
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now I am honestly already confused at what it means for a Q-Vectorspace to exist on a set.

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because if I take any element/vector in V and use scalar multiplication to multiply it with a rational number then it might not exist in V anymore

mortal orbit
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if you have a Q-vectorspace structure

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it means that you have

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an addition operation

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meaning for v,w in V

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v+w in V

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so (V,+) is a commutative group

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and a scalar multiplication operation

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meaning that for q in Q, v in V

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q * v is in V

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and it satisfies (pq) * v = p * (q * v), 1 * v = v and distributivity

mortal orbit
weary cape
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cuz if p*v2 ≠ v2 it can only be v1

mortal orbit
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in a vector space, if p * v = the zero vector, then p = 0 or v = the zero vector

weary cape
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yes but there are no other vectors besides v1 (zero vector) and v2 so scalar multiplication wouldn't work with any elements of Q besides 0

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and therefore it cannot exist?

mortal orbit
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?

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you haven't told me why yet

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i could very much have p*v2 = v2 when p is not 0

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why doesn't it work?

weary cape
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the neutral element wouldn't be unique?

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i remember a proof we had where if there are two elements having the property of e * v = v = e' * v then e = e'

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but then for all q in Q q*v2 = v2

mortal orbit
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well try to apply that

weary cape
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okay

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thank you

calm coralBOT
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@weary cape Has your question been resolved?

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gentle rampart
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hi

calm coralBOT
gentle rampart
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how can i solve this?\

onyx berry
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given an angle and radius, what is the formula for the arc length, and the formula for the area of the sector?

odd moon
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$\frac{\theta}{2 \pi} \cdot \pi r^2 = 6\pi$

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oops

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the area of the sector can be described like this

onyx berry
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now you are mixing degree and radians

odd moon
potent lotusBOT
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tenshi

odd moon
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$\frac{\theta}{2 \pi} \cdot 2 \pi r = 2\pi$

potent lotusBOT
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tenshi

odd moon
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this is the length of the arc

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solve the system for theta and r

gentle rampart
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ah

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i was using the equation and using theta/360

odd moon
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hm i got r = 6?

glad adder
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I got the same radius

calm coralBOT
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@gentle rampart Has your question been resolved?

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torpid summit
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wait how do you do this again 💀

calm coralBOT
torpid summit
kind meteor
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just supstitue t to be 60?

torpid summit
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damn

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wait what

kind meteor
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i think?

torpid summit
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not that simple lmao

kind meteor
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yea

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nvm