help-42

[fiery crater]

you're right, the problem doesn't really make sense like this

[sudden sluice]

ill ask her tmrw

albeit we have a test ;c

.close

[calm coral]

Channel closed

Closed by @sudden sluice

Use .reopen if this was a mistake.

[calm coral]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[placid raptor]

I’m learning how to solve exact differential equations in my diff eq class. I solved this but got the wrong answer, and I have the right answer to the side of the page. Where did I go wrong with my math?

[leaden thunder]

What's the integral of 4yx dx

[calm coral]

@placid raptor Has your question been resolved?

[placid raptor]

Would it be

2yx^2 ?

Ahh oh my god I see my mistake

[placid raptor]

Thank you

.close

[calm coral]

Channel closed

Closed by @placid raptor

Use .reopen if this was a mistake.

[calm coral]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[karmic swift]

i see the right triangle is a 30-60-90 and i have the bottom equal to 4 and the side is 4root3. would i use the pythagorean theorem to find the bottom of the other triangle? follow up question if im trying to find angle A once i know all the side lengths would sine be the best option?

[ripe python]

You wanna find angle A right?

[karmic swift]

yes

[ripe python]

We'll keep it really simple

[karmic swift]

i’m trying to find the sides first and then i use sine cos tan

unless i’m making it to complicated

[ripe python]

Actually wait I thought of the question differently

Give me some time

[karmic swift]

ok ok thank you for helping

[jolly pilot]

your method looks almost correct, except, the bottom side is not 4. You can re check which side on 30-60-90 is half the hypotenuse

|| its the red ||

[ripe python]

We'll find the length of the red line

Are you seeing how can we do it?

[karmic swift]

is it by using the 30-60-90 triangle method?

like x 2x and x root 3

?

[ripe python]

Like we can do that certainly

I've been rusty on this method

[karmic swift]

so would i find x by dividing 8? since the 8 side is 2x

[ripe python]

So you tell me what'll be the length of the red line if we take the right triangle

[karmic swift]

i got 4 root3

or 6.9

[ripe python]

And the bottom one?

4?

[karmic swift]

yeah 4

[ripe python]

It'll be reversed

[karmic swift]

can you explain that?

[ripe python]

The red line is 4 and the bottom is 4√3

Do you know normal trigonometry?

I'd like to go that path to explain

[karmic swift]

ohh

i just looked at my drawing of it i see why

[ripe python]

Yeah

you got it

The red line's 4

[karmic swift]

ok yeah so the red line is 4

and to find the last missing side of use the pythagorean theorem correct?

[ripe python]

We don't need to

We need angle A

can we write sin A = 4/5

[karmic swift]

oh shit

sorry i’m just so used to finding every side

[ripe python]

Correct me if I'm wrong

[ripe python]

We don't always need to do that

It'll take our time for no apparent reason

[karmic swift]

true

and for the angle i think i use the tan -1

sorry sine -1

[ripe python]

Exactly

That's your answer

[karmic swift]

ok i see now but i have another question about a different homework if that’s ok to ask?

[ripe python]

Sure thing

I'll help if I'm able

[karmic swift]

i don’t know if i worded that question correctly

actually wait it’s like to hard to explain over text

i’ll just ask my teacher tbh sorry to take up your time on that part but thank you for the original help

[ripe python]

It's completely alright

Glad to help!

[karmic swift]

.close

[calm coral]

Channel closed

Closed by @karmic swift

Use .reopen if this was a mistake.

[calm coral]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[minor scroll]

For number 29, can I choose any two vectors with the same starting point, i.e., either RQ and RP, QR and QP, or PQ and PR?
Also, how would I tell the order in which I would calculate the cross-product? Meaning, how would I tell, for example, if I should do RP x RQ or if I should do RQ x RP?

[swift laurel]

the order doesn't matter. the only difference would be that RP x RQ = -(RQ x RP), but you are taking the magnitude so it doesn't affect the final result

and you can choose any two vectors, even without the same starting point, since if you take the negative of one you're guaranteed to end up with the same starting point (and that would only add a - to the cross product vector, which we take the magnitude of)

[minor scroll]

Thank you for your help

.close

[calm coral]

Channel closed

Closed by @minor scroll

Use .reopen if this was a mistake.

[calm coral]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[grizzled temple]

i just have a question for a)

how do i show that it is odd

like

can i just say that

since all the powers of x are odd

therefore the polynomial

is odd

[lost quest]

yea thats a way but proper would be P(-x)=-P(x)

[grizzled temple]

ohhh

okok thank u

.close

[calm coral]

Channel closed

Closed by @grizzled temple

Use .reopen if this was a mistake.

[calm coral]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[uncut topaz]

Hi I'm working through practice algebra problems. I don't understand how this algebraic expression was reached to get the answer. Why is it all equal to 9 and why did they pick 3.5, 1.8, and 3.5?

[uncut topaz]

Also, I think it supposed to read "calculate the thickness of the inner walls" not "rooms"

[calm coral]

@uncut topaz Has your question been resolved?

[calm coral]

@uncut topaz Has your question been resolved?

[calm coral]

@uncut topaz Has your question been resolved?

[calm coral]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[viscid yoke]

Help please

[viscid yoke]

I’m lost

[uneven shell]

Do you know the law of sines

[eternal shard]

Do you know that law of sine

[viscid yoke]

no 😦

[potent lotus]

bacc

[viscid yoke]

what does that mean

[eternal shard]

what

[viscid yoke]

how do i use that

[eternal shard]

Assume at A your have the angle alpha = 52°

Then the length a would be CB = a

At B you have beta = 25° and length AC = b

At C you have gamma = 103° and length AB = 55

[viscid yoke]

right but what am i trying to find for a,b

[eternal shard]

,, \frac{\sin 52^\circ}{a} = \frac{\sin 25^\circ}{b} = \frac{\sin 103^\circ}{55}

[potent lotus]

bacc

[eternal shard]

You basically have two equation to solve for

[viscid yoke]

how do i do that

[potent lotus]

bacc

[eternal shard]

Now take a calculator and solve for a and b

[viscid yoke]

i cant put an = sign in my calc. btw im stupid

[eternal shard]

bro

I meant with calculator the sine expressions

[viscid yoke]

?

[eternal shard]

what

what is sin(52°)

in your you calculator

[viscid yoke]

.788

[eternal shard]

ok

tell me the rest

[viscid yoke]

idfk

[eternal shard]

sin(103°)?

sin(25°)?

[viscid yoke]

.974

.423

[eternal shard]

see

[viscid yoke]

?

[potent lotus]

bacc

[viscid yoke]

oh

[eternal shard]

still lost?

[viscid yoke]

yes

lol

[eternal shard]

You can do now cross multiplication

[potent lotus]

bacc

[viscid yoke]

44.497

[eternal shard]

Now you can divide by 0.974

[viscid yoke]

23.886

[potent lotus]

bacc

[eternal shard]

If you use your calculator you should get it

[viscid yoke]

44.497 = a

23.886 = b

???

[eternal shard]

???

a or b bro

which is which

[viscid yoke]

do u see now?

[eternal shard]

yea

looks good

[viscid yoke]

YAY

ty pookie

[eternal shard]

💀

[viscid yoke]

xoxoxo

[eternal shard]

yw

[calm coral]

@viscid yoke Has your question been resolved?

Channel closed

Closed by @viscid yoke

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[viscid yoke]

Helpppp

[remote mural]

post question

[remote mural]

nvm

[viscid yoke]

I’m on my last attempt

[leaden thunder]

,tex .sine law

[potent lotus]

[viscid yoke]

Bro I tried

[leaden thunder]

show how you got your numbers

[viscid yoke]

I didn’t write it down

[leaden thunder]

¯_(ツ)_/¯

do it again and type it here

[viscid yoke]

Bro I tried so many times

I’m just lost

124.4
32.6
16.4

This is what I got

@eternal shard

[eternal shard]

bro you got riemann helping

[viscid yoke]

He not responding

[eternal shard]

just show your work

or do it again

[viscid yoke]

It’s on my calc

I did

[eternal shard]

lmao i wont walk you through again

[viscid yoke]

Can you just fact check my answer

124.4
32.6
16.4

@eternal shard

[calm coral]

@viscid yoke Has your question been resolved?

[calm coral]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[viscid yoke]

Help please

[viscid yoke]

On both

ello?

@leaden thunder @eternal shard

[calm coral]

@viscid yoke Has your question been resolved?

[calm coral]

@viscid yoke Has your question been resolved?

[leaden thunder]

!noping

[calm coral]

Please do not ping individual helpers unprompted.

[calm coral]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[scarlet saddle]

help?

[wanton spear]

How far did you get on your own?

[scarlet saddle]

new to geo but all i got was B

sorry not e, D

[wanton spear]

Are there any you can eliminate as false?

[scarlet saddle]

C

[wanton spear]

So do you think D is true or false?

[scarlet saddle]

true

[wanton spear]

What does perpendicular mean to you?

[scarlet saddle]

equal

[wanton spear]

Ah

So you might want to review your notes for what perpendicular means

[scarlet saddle]

we didnt learn what it means

[wanton spear]

Oh well
Perpendicular means at a right angle

[scarlet saddle]

oh

so d is false

A is true

A

B

thats it?

[wanton spear]

What do you think about E?

[scarlet saddle]

not true

its equal

since cb and bc is cd

[wanton spear]

?

Just so I can have some context
Have you heard of the triangle inequality?

[scarlet saddle]

no

[wanton spear]

(also, in the context of E, CB,CD, and BD are referring to the lengths of lines)

[scarlet saddle]

yea im aware

[wanton spear]

Are you sure this question is meant for you?
Cause I'd expect this question to be presented to someone who has heard of perpendicular and of the triangle inequality

But also, take this

[wanton spear]

And think about how it applies to E

[scarlet saddle]

so C + B > D?

i get it

thx

wait what is C called?

in the triangle inequality thereom

[calm coral]

@scarlet saddle Has your question been resolved?

[calm coral]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[idle pollen]

can combine equations like 2x+3-1x(x) = 3x?

[grand trellis]

Yes

Distribute the -1x across x

So

-1x(x) = -x^2

Then

Substitute back into the equation

[idle pollen]

what if 2x+3x-1x(x)(y) = 3xy?

[grand trellis]

You would come out with something different

[grand trellis]

Is this the equation

Can you provide more context

[idle pollen]

idk if its correct or not, this channel is help

[grand trellis]

I have the answer

Its -x^2 - x + 3 = 0

There you do

[calm coral]

@idle pollen Has your question been resolved?

[idle pollen]

so 2x+3x-1x(x)(y) = 0

[grand trellis]

Can you give me a better question

Please

[idle pollen]

wdym getting a better question? im not good these maths so i just said the math problems if its correct or not

[grand trellis]

Goodbye

[calm coral]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[drowsy crag]

Im stuck on where to begin with this

[drowsy crag]

im wondering how it would be possible to answer this with being given any info other than time traveled

[rapid cliff]

let's begin by marking on the speeds for each leg of Nemo's journey

[drowsy crag]

ive done that

[rapid cliff]

ok, since he only walks in cardinal directions, we can simplify the problem into a two legs from A to B, the first north, the second West.

[drowsy crag]

what would that look like?

just a long leg north and then a short leg west

[rapid cliff]

yep

then the same back to A

[drowsy crag]

ok but how do i determine the distance of the path that we just made

[tall folio]

Hi can someone explain parabole

[rapid cliff]

now, let's suppose the length of the north/south path is N, and the length of the east/west path is E.

[rapid cliff]

!occupied

[calm coral]

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

[drowsy crag]

ok

[drowsy crag]

ive got the line written down with the km/h values

how do we determine distance travleed from that'

[rapid cliff]

I've also added points P and Q, because they might be useful

[drowsy crag]

going up would be west wouldnt it

[rapid cliff]

(it doesn't matter if he goes north/south before east/west)

[drowsy crag]

oh

[rapid cliff]

for simplicity, I've said he goes west to P, then north to B, then south to Q, then east back to A

[drowsy crag]

oh ok

[rapid cliff]

so, the length of the path from A to B is clearly (E + N), but we want to find this in numbers.

[drowsy crag]

right

[rapid cliff]

let's also give some names to the times for each leg.
Let's say TN is the time for the north/south legs, TE is the time for the eastern leg, and TW is the time for the western leg.

(we don't need different north vs south times, because theyr'e the same, because he travels at the same speed for the same distance on these legs).

[drowsy crag]

ok

ive wrote those down

[rapid cliff]

now we can calculate the time taken for him to complete each leg.
For example, the time for the north/south legs is N/4

[drowsy crag]

so 1 hour?

[rapid cliff]

we don't know the distances, so we can't quite yet give them values.

[drowsy crag]

oh ok

[rapid cliff]

Let's just look at his first leg, A to P.
The distance is E km, and his speed is 6 km/h, so it would take him TW = E/6 h (hours).
We need to do the same for TN and TE.

[drowsy crag]

divide all directions by 6 hours?

or the km/h values of each one

[rapid cliff]

the speeds (km/h values) for each leg.

[drowsy crag]

ok did it

[rapid cliff]

you have this?

• AP: distance = E km, speed = 6 km/h, so time = E/6 h
• PB: distance = N km, speed = 4 km/h, so time = N/4 h
• BQ: distance = E km, speed = 3 km/h, so time = E/3 h
• QA: distance = N km, speed = 4 km/h, so time = N/4 h

[drowsy crag]

yes

[rapid cliff]

Cool. And we know the total time is 6 hours, which means E/6 + N/4 + E/3 + N/4 = 6.

[drowsy crag]

is the first e/4 supposed to be e/6

[rapid cliff]

yes, good catch

[drowsy crag]

ok i got that down

[rapid cliff]

can you simplify that?

[drowsy crag]

i think so'

[rapid cliff]

it simplifies to something very nice

[drowsy crag]

i cant figure what it simplifies to

[rapid cliff]

start by grouping the E terms separate from the N terms

E × (???) + N × (???) = 6

[drowsy crag]

do i multiply both terms

[rapid cliff]

what have you got so far?

[drowsy crag]

E/6 + N/4 + E/3 + N/4 = 6

i have this but im stuck at that

[rapid cliff]

ok, first rearange the order in which things are added so we have Es first, and Ns second.

[drowsy crag]

E/6 + E/3 + N/4 + N/4 = 6

thats what i have now

[rapid cliff]

yep, and now factor out the E from the first two terms, and the N from the second two terms

[drowsy crag]

can u show

an example

if possible

[rapid cliff]

$$\frac{x}{2} + \frac{x}{3} + \frac{y}{4} + \frac{y}{4} = x \left(\frac{1}{2} + \frac{1}{3}\right) + y \left( \frac{1}{4} + \frac{1}{4}\right)$$

[potent lotus]

Shuba

[drowsy crag]

ah i get it

ok i got that down

[rapid cliff]

and now you can evaluate what's in the brackets.

for example;

[drowsy crag]

i got 1/2 in both brackets after simplifying

[rapid cliff]

$$x \left(\frac{1}{2} + \frac{1}{3}\right) + y \left( \frac{1}{4} + \frac{1}{4}\right) = x \left( \frac{5}{6} \right) + y \left( \frac{1}{2} \right)$$

[potent lotus]

Shuba

[rapid cliff]

yep, perfect

So, you now have $E \frac{1}{2} + N \frac{1}{2} = 6$. Can you simplify it any further?

[potent lotus]

Shuba

[drowsy crag]

not sure

[rapid cliff]

(ignore that last message XD)

[drowsy crag]

i dont know how to simplify further

would i be able to move N1/2 to the other side

[rapid cliff]

you could get rid of the 1/2 on the left side.

[drowsy crag]

divide?

[rapid cliff]

by what?

[drowsy crag]

1/2

[rapid cliff]

yep 🙂

[drowsy crag]

does it get rid of both

[rapid cliff]

try it

[drowsy crag]

idk

its not working for me

can u show

example

[rapid cliff]

$$x \left( \frac{5}{6} \right) + y \left( \frac{1}{2} \right) = 3 \quad(\times 6)\qquad\implies\qquad 5x + 3y = 18$$

[potent lotus]

Shuba

[drowsy crag]

so do i multiply both sides by 2

[rapid cliff]

multiplying by 2 and dividing by 1/2 is actually the same thing

[drowsy crag]

oh ok

so i just have E +N =12

[rapid cliff]

yep 🙂

[drowsy crag]

thats the total distance right

[rapid cliff]

yep, the total distance must be 12 km, even though we don't know how much of that is in which direction.

[drowsy crag]

thats from A to B right

not there and back

[rapid cliff]

that's A to B and back to A

[drowsy crag]

oh ok

[rapid cliff]

so, the distance from A to B (question 1) is?

[drowsy crag]

6

[rapid cliff]

yep 🙂

nice one.

[drowsy crag]

i appreciate u so much

would u wanna help with 2

[rapid cliff]

sure

[drowsy crag]

thank you

[rapid cliff]

Now, instead of looking at distances, I'm going to switch to looking at displacements (which are distances in a direction).

or, let me work this through and see if there's an easier way

[drowsy crag]

sounds good

[rapid cliff]

yep, got it

[drowsy crag]

ok perfect

[rapid cliff]

so, we know E + N = 12.

Or, respectively W + N = 12 (because B might be west-ish of A)

[drowsy crag]

yup

[rapid cliff]

so, let's look at the first one. we can have any combination of north and east, so long as the total distance is 12 km. let's look at if the E = 0, or N = 0.

if E = 0, then N = 12. and if N = 0, then E = 0.

i.e. he walks in a straight line.

what direction could A to B be, which would mean his speed would be fastest?

by which i mean, is directly east fastest, or maybe directly north, or maybe a little bit of both?

[drowsy crag]

11km north

1km east

[rapid cliff]

what if A to B is directly north, so no east leg?

[drowsy crag]

that would be the fastest

[rapid cliff]

cool. So, if it is directly north, and he travels 6 km (as we determined in question 1), how long would it take him to get there?

[drowsy crag]

1 hour

[rapid cliff]

nope. what's his northerly speed?

[drowsy crag]

4km/h my bad

its would take 1hr 30min

[rapid cliff]

yep

and it would be the same if B was directly south of A (because his southerly speed is the same as his northerly speed)

So, what's the slowest direction A to B could be in?

[drowsy crag]

12km east

[rapid cliff]

yep, which would take how long?

[drowsy crag]

2 hours for 6km

[rapid cliff]

yep

now, let's look at if B is instead westerly of A.

again, the northerly / southerly time would be 1 hour 30 minutes. What about if A to B is directly west?

[drowsy crag]

1 hour

[fair charm]

in help guys i cant think of anything

[rapid cliff]

!occupied

[calm coral]

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

[rapid cliff]

yep, cool. So the fastest time he could do it is 1 hour, and the slowest is 2 hours.

which doesn't make sense now I think about it. one second

[drowsy crag]

were we supposed to use west

[rapid cliff]

if A is north of B: distance = 6, speed = 4, time = 1.5
return: distance = 6, speed = 4, time = 1.5
total time = 3 hours

i've screwed up somewhere XD

[drowsy crag]

in the first question?

[rapid cliff]

oh, it's 12 km from A to B.

that's why

[drowsy crag]

so is it 24k total then

[rapid cliff]

yep

[drowsy crag]

okok

[rapid cliff]

I mixed up total time with distance from A to B.

nvm

so, the fastest direction A to B could be is directly west, which would mean it would take how long?

[drowsy crag]

2 hours

4 hours

[rapid cliff]

yep, and the slowest direction is directly east, which could take how long?

ye, 4 hours XD

[drowsy crag]

haha

[rapid cliff]

and that's the answer to question 2 🙂

it would take between 2 and 4 hours to get from A to B.

[drowsy crag]

perfect thank you alot

[rapid cliff]

[drowsy crag]

do you get paid

[rapid cliff]

you're the second person to offer XD
I don't but maybe I should start properly tutoring.

you're good XD

[drowsy crag]

you really should

cus i could not find an answer to this anywhere

[rapid cliff]

thanks ❤️

[calm coral]

@drowsy crag Has your question been resolved?

[calm coral]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[heady jungle]

can someone explain the best method and explanation for b)?

my method was finding the extrema of f(x) and then testing the x-coordinates of those extrema, leading me to an answer of (3-sqrt(3))/3.

I'm not completely sure how I can write my explanation quickly and concisely in words.

[boreal rose]

you can just show that the function is monotone between the 2 turning points

since turning points are symmetrical for this function

[pallid halo]

the two turning points are not of the form -k and k though

they're both positive

[boreal rose]

oh yikes

my bad

i just assumed it was idk why

in that case u just find maximum turning point

[calm coral]

@heady jungle Has your question been resolved?

[heady jungle]

wdym

[calm coral]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[heady jungle]

.reopen

[calm coral]

✅

[heady jungle]

<@&286206848099549185>

[calm coral]

@heady jungle Has your question been resolved?

[calm coral]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[halcyon ore]

IS 12.65 m CORRECT PLZ I HAVE MY LAST CHANCE

[halcyon ore]

D:

[rapid cliff]

What's A, B, and C?
Hint: A = (-10, 4)

Then, calculate A - B - C
Hint: (Ax, Ay) - (Bx, By) = (Ax-Bx, Ay-By)

Then calculate the magnitude.
Hint: |(x, y)| = sqrt( x^2 + y^2 )

[halcyon ore]

so b is

8,8

?

[halcyon ore]

uh'

i got 29.73

with those points

[rapid cliff]

what have you got for A-B-C?

[calm coral]

@halcyon ore Has your question been resolved?

[calm coral]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[calm coral]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[halcyon ore]

i m so srry

but can someone explain this for me

like i got down si prefixes but

why are we cubing these and 1milliter = 100cm?

i thought 1 mililiter was 10^-3

and centi would be 10^-2 like wot

Or are these just different

[pure kayak]

theyre not denying what you said at all
1mm=10^(-3)m
1cm=10^(-2)m

ie 1m=1000cm
1m=100cm

[swift laurel]

100 cm = 1m
(100 cm)^3 = (1m)^3
100^3 cm^3 = 1 m^3

so one cubic meter is actually 100^3 cm^3 = 1000000 cm^3

[halcyon ore]

Ohhhhhh

It just says it different way ok

Got it thanks

[calm coral]

@halcyon ore Has your question been resolved?

[halcyon ore]

wati

so 1cm is not 10^-2 cm

1 cm is just 1 cm

can i convert b/w anything in si prefixes?

it kind of messing with my mind lol

like 0.01 is just the multiplier

.close im idiot lol

[calm coral]

Channel closed

Closed by @halcyon ore

Use .reopen if this was a mistake.

[calm coral]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[ionic lake]

i’m confused is this right?

[ionic lake]

,,ccw

[potent lotus]

☠ cjtx Σ

[ionic lake]

oops

,cw

erm

,rccw

[ionic lake]

there

[vernal portal]

yes its right

[ionic lake]

how do i find the horizontal asymptote?

[vernal portal]

what value can't f(x) be

[ionic lake]

0

[vernal portal]

yes

so the horizontal asymptote is just

y = 0

[ionic lake]

so

inversely could i say this?

[vernal portal]

yes

[ionic lake]

so the end behavior is dependent on the horizontal asymptote?

or it will approach the horizontal asymptote?

[strange tinsel]

when the limit of a function as x approaches a value is infinity, you conclude about existence of a vertical asymptote

when the limit of a function as x approaches infinity is a finite value, you conclude about existence of a horizontal asymptote

[ionic lake]

omfg thank you

lowkey just saved me

my teacher never really went over it she kinda just does it and expects us to see the pattern, despite the fact that she has only done like 3

[strange tinsel]

lol

[ionic lake]

ty!

[strange tinsel]

$\lim_{x \to \infty} f(x) = a \quad \implies $ y=a is a horizontal asymptote of $(C_f)$ at $\infty$

$\lim_{x \to a} f(x) = \infty \quad \implies $ x=a is a vertical asymptote of $(C_f)$

[potent lotus]

Emily

Emily

[graceful dust]

also worth noting if the limit is infinity or -infinity on just one side of a (not necessarily both), usually you still say there is an asymptote there

like with log

or something piecewise defined by 1/x on the left and whatever on the right

[strange tinsel]

true, lemme edit it rq

[graceful dust]

oh you don't have to, what you said is still right

i was just pointing out the converse isn't true

[strange tinsel]

$\lim_{x \to \infty} f(x) = a \quad \implies $ y=a is a horizontal asymptote of $(C_f)$ at $\infty
\ $\lim_{x \to -\infty} f(x) = a \quad \implies $ y=a is a horizontal asymptote of $(C_f)$ at $(-\infty) \ \
$\lim_{x \to a^{\pm}} f(x) = \pm \infty \quad \implies $ x=a is a vertical asymptote of $(C_f)$

[potent lotus]

Emily
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[strange tinsel]

😛

[graceful dust]

also fair haha

[calm coral]

@ionic lake Has your question been resolved?

[ionic lake]

oh oops

[calm coral]

Channel closed

Closed by @ionic lake

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[remote mural]

why does adding these turn the denominator from -25+10h into 25-10h?

[flat tendon]

person multiplied numerator with -1 as well

notice the minus before the fraction

[remote mural]

ohh i see thank you

do you know why that is?

or do you need more context

[flat tendon]

its not trivial why they did so

could be purely for esthetic reasons

[remote mural]

ah got it

thanks!

.close

[calm coral]

Channel closed

Closed by @ivory thunder

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tulip lantern]

I’m having trouble seeing where I went wrong for this vector problem

It’s asking for the resulting vector R and I took the components of X and H for each, added them and then put them into the Pythagorean theorem

Is that not what I’m suppose to do in this situation?

[teal drift]

Yep, that's it

Maybe check calculations again

And look carefully at vector C, for the x-component you'll have to use sin(thetaC) and not cos

Same goes for its y-component

[tulip lantern]

How do you know which to use for what

[teal drift]

The definition of cos and sin for angles in a right triangle

[calm coral]

@tulip lantern Has your question been resolved?

[tulip lantern]

I figured it out but I’m missing something now

I have all the numbers for the components and the results but I can’t figure out what I’m doing wrong when I’m finding theta

Is it not just arctan (y/x)?

[calm coral]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[steady girder]

Could someone help me

[steady girder]

This related rates question

I tried evaluating cos(theta) = base/hypotenuse

Then take derivative

[hasty fiber]

so far so good

i probably wouldn't use cos (you don't know the horizontal distance) but it works

[idle pollen]

is there equations like 2d+ 2d = 4d?

[steady girder]

Would I use tan?

[hasty fiber]

you can use any of them

but tan would be my first pick

[steady girder]

Got this equation

To let x go to 700 and let theta be 45

Am I on the right track

[hasty fiber]

i'm not sure i see where that equation comes from

[steady girder]

Tan(theta) = y/x

X is same thing as base

I just wrote it was that

Then we can rewrite it to be in terms of x = y/tan(theta)

X= 4/tan(theta)

[hasty fiber]

i don't know if that step is necessary

[steady girder]

I’m gonna skip the question and just take the B on the assignment

.close

[calm coral]

Channel closed

Closed by @steady girder

Use .reopen if this was a mistake.

[calm coral]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[limber zenith]

can someone help me with a couple of these

starting with 40 please help!!!

i have a general grasp i just need some help

[naive escarp]

for 40 you should put a x value that is a little bit bigger than 1 right?

some value like 1.0000001

[limber zenith]

right, as its coming from the right

lets just use

2

so

4/-1

and thats negative

so negative infity?

[naive escarp]

yes

[limber zenith]

ok so whenever its a negative value its just negative infinity for these ones?

[naive escarp]

when it is negative and when denominator is approaching to 0 (and numerator is not approaching to 0)

[limber zenith]

ok

would 42 just be 1/2

[naive escarp]

yes

[limber zenith]

for 44, can I plug in zero?

as it is larger than -1/2

and that would be 1/3

if i plug in zero

[naive escarp]

if you plug 0 than denominator is negative but if you plug 1/2 denominator is 0

[limber zenith]

i thought it just had to be a value greater?

[naive escarp]

think if you gut a value like -0.499999, you would get a negative denominator but still very near to 0

[naive escarp]

^ this applies

[limber zenith]

but its just a value greater thatn -1/2?

[naive escarp]

oh 1min I think I did not see the minus

[limber zenith]

so that is right

or nah

[naive escarp]

nah

[limber zenith]

but if you plug in 0

its just -1/-3

[naive escarp]

but you can still get more near to -0.5 than 0

frist plug -0.5 what do you get

[limber zenith]

ohh ok

something over 0

do i need to find numerator

0/0

so direct sub fails

now i plug insomething close but greater than -1/2?

[naive escarp]

if it is 0/0 then you can use L'Hospital or try to simplify it (get rid of the coefficients that makes it 0/0)

[limber zenith]

we havent learned that yet sadly

im in calc ab

[naive escarp]

but you can factor it right?

[limber zenith]

oh ye

[naive escarp]

factor and simplify

[limber zenith]

got to

3x-1

over 2x-3

[naive escarp]

now plug -0.5

[naive escarp]

and you get the result

[limber zenith]

-2.5/-4

2.5/4

and thats the answer?

oh

[naive escarp]

yes

[limber zenith]

so

pos inf?

[naive escarp]

nope, denominator is not 0 after simplifying

[limber zenith]

but for 40

40 the denominator was -1

and we said it was neg inf

[naive escarp]

for 40 we first plug 1 and we get 0 at denominator than we put a value bigger than 1 (2) to find signs of numerator and denominator

[limber zenith]

oh i see

[limber zenith]

but wait

we did the same thing on 44

[naive escarp]

44 is 0/0 so we had to simplify first

[limber zenith]

so when the denom is 0 but numerator isnt after simplifying and what not you do either pos or neg inf?

[naive escarp]

yes either pos or neg inf on that case, you put another value to find signs

[limber zenith]

ok

thats so confusing lol

46 is lightwork

just 1/2

1/9***

[naive escarp]

1. Plug the given value to see if it is 0/0 or not
2. If it is 0/0 then simplify and plug the given value, you found the answer
3. If it is x/0 (x is not 0) then plug another compatible value to find signs and answer is either pos or neg inf
4. If it is x/y (neither x nor y is 0) answer is x/y

[limber zenith]

thank you

[naive escarp]

you're welcome

[limber zenith]

.close

[calm coral]

Channel closed

Closed by @limber zenith

Use .reopen if this was a mistake.

[calm coral]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[manic monolith]

did my teacher make a mistake? how is q'(0) = 1/2??

shouldnt it be 0

[sharp junco]

yeah q'(0) should be 0

[manic monolith]

does everything else look good aside from that?

[sharp junco]

everything else looks right

seems they accidentally used p'(0) instead of q'(0)

[manic monolith]

yep

thanks

.close

[calm coral]

Channel closed

Closed by @manic monolith

Use .reopen if this was a mistake.

[calm coral]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wraith shuttle]

b) set up the integral that will find the volume of the solid generated by revolving the region about the x-axis
c) use disk/washer method to write the integral(s) that will compute the volume of the solid generated when the region is rotated about the y-axis
d) use shell method to write the integral(s) that will compute the volume of the solid formed when this region is rotated about the y-axis
e) set up the integral that will compute the volume of the solid generated by revolving the region about the line y=6
f) set up the integral that will compute the volume of the solid generated by revolving the region about the line x=3

I only need help with e and f. I would appreciate verification for the rest

[sharp junco]

im a little rusty on volume bc i havent studied it sincel last year

but i can try

are the bounds on your final answer from c 0 to 1?

[calm coral]

@wraith shuttle Has your question been resolved?

[wraith shuttle]

yeah the bounds are [0,1]

The bounds for part c) are [0,5] though

[sharp junco]

i could be wrong but wont c need two integrals as indicated by the question having that s at the end

from 0 to 5 you can just use y/5 and from 5 to 6 you can just use sqrt(6-y)

[wraith shuttle]

I think the s just encompasses both integrals when using either washer or disk but I'm honestly not sure

[sharp junco]

<@&286206848099549185>

[calm coral]

@wraith shuttle Has your question been resolved?

[wraith shuttle]

:(

<@&286206848099549185>

[pearl skiff]

Hello there blank, do you still need help with your question?

[wraith shuttle]

Yes

[pearl skiff]

iirc, you are using disk/washer in part (b) and (c) right?

[wraith shuttle]

:(

[pearl skiff]

if that's the case, (c) would be incorrect

[wraith shuttle]

well

[pearl skiff]

yea?

[wraith shuttle]

I was just saying well to express my disappointment

[pearl skiff]

oh...

[pearl skiff]

I thought you have an updated version of this lol

oh well

[wraith shuttle]

I skipped it tbh

[pearl skiff]

ah

[wraith shuttle]

I did the rest of what I needed to

[pearl skiff]

i see i see

lemme try to draw something

[wraith shuttle]

Is part d at least correct?

[pearl skiff]

so, iirc, this would be disk/washer, right?

if thatst the case, you'll have to split into two integrals

[wraith shuttle]

So

Sorry, should it be minus

[wraith shuttle]

.

.close

[calm coral]

Channel closed

Closed by @wraith shuttle

Use .reopen if this was a mistake.

[calm coral]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[astral mural]

Hello

[astral mural]

How do I do 5c)?

[swift laurel]

first factor the denominator

[astral mural]

Like how

Newton's Method of factorization?

[swift laurel]

you can try grouping terms

[astral mural]

Like howww

[swift laurel]

x^3 - x + x^2 - 1

[astral mural]

What next tho

[swift laurel]

notice any common factors?

[astral mural]

(x - 1)(x + 1)?

x(x^2 - 1)?

Oh

(x^2 - 1)(x + 1)?

(x - 1)(x + 1)^2

[swift laurel]

great, now you can use that

[astral mural]

Ohhh make sense

Tysm!

.close

[calm coral]

Channel closed

Closed by @astral mural

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wild marten]

Hi, Im learning fixed point iteration and I have a question regarding the convergence theorem:

The theorem states that if |g'(root)| < 1 then a fixed point exists. Does this mean I need to know the root to test out convergence?

[old falcon]

no, but an area might be nice

well, lets say it more clearly as you'd need a neighborhood

[wild marten]

So like somewhere around the root

but not exactly the root

[old falcon]

yea, if you know that some region contains a root

and the condition is satisfied there

then youre good

[wild marten]

Ok so I would just plug in a number above and under, and if its less than 1 then the function converges?

[old falcon]

ideally you should be able to calculate |g'|

and bound it on that interval

[wild marten]

So lets say im trying to solve this:

I narrow it down to two g(x) equations

How would I know which one converges?

Take the derivitive and plug in random numbers near a root?

[old falcon]

you have two equations there

whats your candidate region

something to start with

you have a rough idea where the root is?

[wild marten]

No clue

the question is to find the root with around a 5% relitive error

[old falcon]

lets say it werent +1

x^3+2x

wheres the root

[wild marten]

0?

[old falcon]

yea

now i add one

which direction does the root go

[wild marten]

Gets higher

[old falcon]

youre thinking the function is moving up the y axis

an dyoure right

but im asking about the x intercept

not the y intercept

[wild marten]

oh hmm

It converges lower then im guessing because its moving up in the y axies

[old falcon]

the root moves to a more negative number right

[wild marten]

Yeah

[old falcon]

okay

lets take a shoot in the dark

[wild marten]

wait yeah x^3+2x=-1

-1 and 0 as intervals?

[old falcon]

yea i think thats a pretty good guess

i mean we could check like

at x=-1

x^3 +2x + 1 is like

-1 -2 + 1

so -2

so theres a sign change somewhere in there

okay, candidate region (-1, 0)

[wild marten]

Makes sense, use ivt to find one pos one neg and so the root it somewhere in the middle

Alr

[old falcon]

ou have two equations

try to look at their magnitude on this region

lets start with the easier one

$\frac{1+x^3}{2}$

[potent lotus]

jan Niku

[wild marten]

Dont forget the neg

lmao I did that twice

[old falcon]

actually, well be looking at the magnitude

so it wont matter

but good point

[wild marten]

Yeah makes sense

[old falcon]

$\qty| \frac{1+x^3}{2} |$

[potent lotus]

jan Niku

[wild marten]

ok cool

[old falcon]

okay, now we gotta answer

whats the biggest this can be

we get to pick any x between -1 and 0

how big can we make it

[wild marten]

oh 0

[old falcon]

yea, i think so

[wild marten]

so 1/2

[old falcon]

because x^3 is gonna go from ... 0 to -1

so it cant possibly be any bigger than 1/2

[wild marten]

yup

[old falcon]

oh but we want g'

[wild marten]

lmaoo

i mean thats light

[old falcon]

you maybe see the game, now

[wild marten]

1/2+x^3/2

3/2x(^2)

[old falcon]

what do you think

3/2 x^2 on that region

[wild marten]

I forgor latex any shot you can put it in the cool fraction thing

[old falcon]

we wanna make it as big as possible

[wild marten]

-1

[old falcon]

$\qty| \frac 32 x^2 |$

[potent lotus]

jan Niku

[wild marten]

Yeah -1 would be the biggest

so you get 3/2

[old falcon]

what value does it take there

yea

[wild marten]

which is >1

[old falcon]

it is

[wild marten]

so it diverges?

[old falcon]

with this region

we have choices

we can refine the region

you might use something like, bisection

what you do is take your region

-1 to 0

and you turn this into two regions

-1 to -1/2 and -1/2 to 0

[wild marten]

find where the root is and refine bounds

[old falcon]

yea, halve the region

and hope it helps

[wild marten]

Ik bisection lol im trying to learn this one :(

[old falcon]

thats fine, were just using it to help ourselves

it wont answer the question for us

[wild marten]

im lost as to how I am supposed to test for convergance

without like

trying so many bounds

[old falcon]

okay, lets say the region is -1/2 to 0

[wild marten]

ok

[old falcon]

maybe we check the value of the function at -1/4 and -3/4

[wild marten]

0 becomes 0 so thats good

[old falcon]

whats 1/2 become

[wild marten]

1/2 becomes like

.5/2

[old falcon]

no

$\frac 32 x^2$

this is g'

[potent lotus]

jan Niku

[old falcon]

whats g'(-1/2)

[wild marten]

1.5/2

so

[old falcon]

no

[wild marten]

.75

[old falcon]

its not

[wild marten]

wait am i tripping

3*.5 = 1.5

1.5/2 = 0.75

[old falcon]

$\frac 32 \qty( - \frac 12 )^2$

[potent lotus]

jan Niku

[old falcon]

3/8

[wild marten]

bro i forgot to ^2

[old falcon]

thats fine

[wild marten]

ok continue

[old falcon]

well, were done

this is as big as g' can be

[wild marten]

ok yeah its less than 1

so it exists in that point

[old falcon]

so assuming the root is actually between -1/2 and 0

this will converge

[wild marten]

ok wait so

this is what my book says

just so im understanding, for every time i used fixed point itteration

I find the seperate equations

find as close an interval around the root as I can get

and see if it converges via the derivitive?

[old falcon]

we're kind of doing it backwards, but this is easier to understand

at least with the intervals

whatd you probably like to do instead is to start with $g' = \frac 32 x^2$

[potent lotus]

jan Niku

[old falcon]

and find where the magnitude of this is under 1

then, go searching for a root

because now you know where it has to be

[wild marten]

ohhhhh

[old falcon]

unless you otherwise know where it is already

[wild marten]

but some equations always diverge right

oh wait

can i plug my starting guess in to see if it diverges?

[old falcon]

like to test?

[wild marten]

yes

[old falcon]

i would just code it lol

or use a calculator

theres plenty pre-coded

or maybe youve made one

[wild marten]

For a midterm or exams lol

I matlabed this

[old falcon]

they can be screwy

i mean iterative methods

they might act really strangely

thats the hard part

[wild marten]

Like will the left function always diverge

[old falcon]

it might look like its converging then do something wacky

[wild marten]

or is there a starting guess I could have used to make it converge

thats kinda my question

[old falcon]

sorry whats the left one lmc

[wild marten]

cubic root of -2x-1

[old falcon]

$g(x) = \sqrt[3]{-2x-1}$

[potent lotus]

jan Niku

[wild marten]

yup

[old falcon]

,w D[ (-2x-1)^(1/3), x ]

[potent lotus]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by janniku

[wild marten]

if its und it also diverges?

[old falcon]

,w plot 2/3 * (-2x-1)^(-2/3) from x=-1 to x=0

[potent lotus]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by janniku

[old falcon]

i dont like the pole

,w plot 2/3 * (-2x-1)^(-2/3) from x=-1/2 to x=0

[wild marten]

so like what im trying to unserstand is

[potent lotus]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by janniku

[old falcon]

right, its negative there

[wild marten]

will every equation always converge at a point

or are there some that will never work

[old falcon]

If i understand what youre asking then no, a bunch will shoot off to infinity